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Java 8 Split String and Create Map inside Map
Is Java “pass-by-reference” or “pass-by-value”?How do I efficiently iterate over each entry in a Java Map?Create ArrayList from arrayHow do I iterate over the words of a string?How do I read / convert an InputStream into a String in Java?How do I split a string on a delimiter in Bash?How to split a string in JavaHow do I convert a String to an int in Java?Creating a memory leak with JavaJava 8 List<V> into Map<K, V>
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I have a String like 101-1-5,101-2-4,102-1-5,102-2-5,102-3-5,103-1-4.
I want to add this in to a Map<String, Map<String, String>>.
Like: 101=1=5, 2=4, 102=1=5, 2=5, 3=5, 103=1=4
How to do this using Java 8 stream?
I tried using normal Java. And it works fine.
public class Util
public static void main(String[] args)
String samp = "101-1-5,101-2-4,102-1-5,102-2-5,102-3-5,103-1-4";
Map<String, Map<String, String>> m1 = new HashMap<>();
Map<String, String> m2 = null;
String[] items = samp.split(",");
for(int i=0; i<items.length; i++)
System.out.println(m1);
java split java-8 java-stream
edited Mar 21 at 23:46
Samuel Philipp
3,7891729
asked Mar 21 at 20:34
ShakthiShakthi
204317
add a comment |
I have a String like 101-1-5,101-2-4,102-1-5,102-2-5,102-3-5,103-1-4.
I want to add this in to a Map<String, Map<String, String>>.
Like: 101=1=5, 2=4, 102=1=5, 2=5, 3=5, 103=1=4
How to do this using Java 8 stream?
I tried using normal Java. And it works fine.
public class Util
public static void main(String[] args)
String samp = "101-1-5,101-2-4,102-1-5,102-2-5,102-3-5,103-1-4";
Map<String, Map<String, String>> m1 = new HashMap<>();
Map<String, String> m2 = null;
String[] items = samp.split(",");
for(int i=0; i<items.length; i++)
System.out.println(m1);
java split java-8 java-stream
edited Mar 21 at 23:46
Samuel Philipp
3,7891729
asked Mar 21 at 20:34
ShakthiShakthi
204317
add a comment |
I have a String like 101-1-5,101-2-4,102-1-5,102-2-5,102-3-5,103-1-4.
I want to add this in to a Map<String, Map<String, String>>.
Like: 101=1=5, 2=4, 102=1=5, 2=5, 3=5, 103=1=4
How to do this using Java 8 stream?
I tried using normal Java. And it works fine.
public class Util
public static void main(String[] args)
String samp = "101-1-5,101-2-4,102-1-5,102-2-5,102-3-5,103-1-4";
Map<String, Map<String, String>> m1 = new HashMap<>();
Map<String, String> m2 = null;
String[] items = samp.split(",");
for(int i=0; i<items.length; i++)
System.out.println(m1);
java split java-8 java-stream
edited Mar 21 at 23:46
Samuel Philipp
3,7891729
asked Mar 21 at 20:34
ShakthiShakthi
204317
I have a String like 101-1-5,101-2-4,102-1-5,102-2-5,102-3-5,103-1-4.
I want to add this in to a Map<String, Map<String, String>>.
Like: 101=1=5, 2=4, 102=1=5, 2=5, 3=5, 103=1=4
How to do this using Java 8 stream?
I tried using normal Java. And it works fine.
public class Util
public static void main(String[] args)
String samp = "101-1-5,101-2-4,102-1-5,102-2-5,102-3-5,103-1-4";
Map<String, Map<String, String>> m1 = new HashMap<>();
Map<String, String> m2 = null;
String[] items = samp.split(",");
for(int i=0; i<items.length; i++)
System.out.println(m1);
java split java-8 java-stream
java split java-8 java-stream
edited Mar 21 at 23:46
Samuel Philipp
3,7891729
asked Mar 21 at 20:34
ShakthiShakthi
204317
edited Mar 21 at 23:46
Samuel Philipp
3,7891729
asked Mar 21 at 20:34
ShakthiShakthi
204317
edited Mar 21 at 23:46
Samuel Philipp
3,7891729
edited Mar 21 at 23:46
Samuel Philipp
3,7891729
edited Mar 21 at 23:46
Samuel Philipp
3,7891729
3,7891729
asked Mar 21 at 20:34
ShakthiShakthi
204317
asked Mar 21 at 20:34
ShakthiShakthi
204317
asked Mar 21 at 20:34
ShakthiShakthi
204317
204317
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
You can use the following snippet for this:
Map<String, Map<String, String>> result = Arrays.stream(samp.split(","))
.map(i -> i.split("-"))
.collect(Collectors.groupingBy(a -> a[0], Collectors.toMap(a -> a[1], a -> a[2])));
First it creates a Stream of your items, which are mapped to a stream of arrays, containing the subitems. At the end you collect all by using group by on the first subitem and create an inner map with the second value as key and the last one as value.
The result is:
101=1=5, 2=4, 102=1=5, 2=5, 3=5, 103=1=4
edited Mar 23 at 11:06
marc_s
584k13011241270
answered Mar 21 at 22:53
Samuel PhilippSamuel Philipp
3,7891729
add a comment |
Map<String, Map<String, String>> map = Arrays.stream(samp.split(","))
.map(s -> s.split("-"))
.collect(Collectors.toMap(
o -> o[0],
o -> Map.of(o[1], o[2]),
(m1, m2) -> Stream.concat(m1.entrySet().stream(), m2.entrySet().stream())
.collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue))));
Map.of is from Java 9, you can use AbstractMap.SimpleEntry if you are on Java 8.
Samuel's answer is better though, much concise.
answered Mar 21 at 22:50
KartikKartik
4,52231537
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use the following snippet for this:
Map<String, Map<String, String>> result = Arrays.stream(samp.split(","))
.map(i -> i.split("-"))
.collect(Collectors.groupingBy(a -> a[0], Collectors.toMap(a -> a[1], a -> a[2])));
First it creates a Stream of your items, which are mapped to a stream of arrays, containing the subitems. At the end you collect all by using group by on the first subitem and create an inner map with the second value as key and the last one as value.
The result is:
101=1=5, 2=4, 102=1=5, 2=5, 3=5, 103=1=4
edited Mar 23 at 11:06
marc_s
584k13011241270
answered Mar 21 at 22:53
Samuel PhilippSamuel Philipp
3,7891729
add a comment |
You can use the following snippet for this:
Map<String, Map<String, String>> result = Arrays.stream(samp.split(","))
.map(i -> i.split("-"))
.collect(Collectors.groupingBy(a -> a[0], Collectors.toMap(a -> a[1], a -> a[2])));
First it creates a Stream of your items, which are mapped to a stream of arrays, containing the subitems. At the end you collect all by using group by on the first subitem and create an inner map with the second value as key and the last one as value.
The result is:
101=1=5, 2=4, 102=1=5, 2=5, 3=5, 103=1=4
edited Mar 23 at 11:06
marc_s
584k13011241270
answered Mar 21 at 22:53
Samuel PhilippSamuel Philipp
3,7891729
add a comment |
You can use the following snippet for this:
Map<String, Map<String, String>> result = Arrays.stream(samp.split(","))
.map(i -> i.split("-"))
.collect(Collectors.groupingBy(a -> a[0], Collectors.toMap(a -> a[1], a -> a[2])));
First it creates a Stream of your items, which are mapped to a stream of arrays, containing the subitems. At the end you collect all by using group by on the first subitem and create an inner map with the second value as key and the last one as value.
The result is:
101=1=5, 2=4, 102=1=5, 2=5, 3=5, 103=1=4
edited Mar 23 at 11:06
marc_s
584k13011241270
answered Mar 21 at 22:53
Samuel PhilippSamuel Philipp
3,7891729
You can use the following snippet for this:
Map<String, Map<String, String>> result = Arrays.stream(samp.split(","))
.map(i -> i.split("-"))
.collect(Collectors.groupingBy(a -> a[0], Collectors.toMap(a -> a[1], a -> a[2])));
First it creates a Stream of your items, which are mapped to a stream of arrays, containing the subitems. At the end you collect all by using group by on the first subitem and create an inner map with the second value as key and the last one as value.
The result is:
101=1=5, 2=4, 102=1=5, 2=5, 3=5, 103=1=4
edited Mar 23 at 11:06
marc_s
584k13011241270
answered Mar 21 at 22:53
Samuel PhilippSamuel Philipp
3,7891729
edited Mar 23 at 11:06
marc_s
584k13011241270
edited Mar 23 at 11:06
marc_s
584k13011241270
edited Mar 23 at 11:06
marc_s
584k13011241270
584k13011241270
answered Mar 21 at 22:53
Samuel PhilippSamuel Philipp
3,7891729
answered Mar 21 at 22:53
Samuel PhilippSamuel Philipp
3,7891729
answered Mar 21 at 22:53
Samuel PhilippSamuel Philipp
3,7891729
3,7891729
add a comment |
add a comment |
Map<String, Map<String, String>> map = Arrays.stream(samp.split(","))
.map(s -> s.split("-"))
.collect(Collectors.toMap(
o -> o[0],
o -> Map.of(o[1], o[2]),
(m1, m2) -> Stream.concat(m1.entrySet().stream(), m2.entrySet().stream())
.collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue))));
Map.of is from Java 9, you can use AbstractMap.SimpleEntry if you are on Java 8.
Samuel's answer is better though, much concise.
answered Mar 21 at 22:50
KartikKartik
4,52231537
add a comment |
Map<String, Map<String, String>> map = Arrays.stream(samp.split(","))
.map(s -> s.split("-"))
.collect(Collectors.toMap(
o -> o[0],
o -> Map.of(o[1], o[2]),
(m1, m2) -> Stream.concat(m1.entrySet().stream(), m2.entrySet().stream())
.collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue))));
Map.of is from Java 9, you can use AbstractMap.SimpleEntry if you are on Java 8.
Samuel's answer is better though, much concise.
answered Mar 21 at 22:50
KartikKartik
4,52231537
add a comment |
Map<String, Map<String, String>> map = Arrays.stream(samp.split(","))
.map(s -> s.split("-"))
.collect(Collectors.toMap(
o -> o[0],
o -> Map.of(o[1], o[2]),
(m1, m2) -> Stream.concat(m1.entrySet().stream(), m2.entrySet().stream())
.collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue))));
Map.of is from Java 9, you can use AbstractMap.SimpleEntry if you are on Java 8.
Samuel's answer is better though, much concise.
answered Mar 21 at 22:50
KartikKartik
4,52231537
Map<String, Map<String, String>> map = Arrays.stream(samp.split(","))
.map(s -> s.split("-"))
.collect(Collectors.toMap(
o -> o[0],
o -> Map.of(o[1], o[2]),
(m1, m2) -> Stream.concat(m1.entrySet().stream(), m2.entrySet().stream())
.collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue))));
Map.of is from Java 9, you can use AbstractMap.SimpleEntry if you are on Java 8.
Samuel's answer is better though, much concise.
answered Mar 21 at 22:50
KartikKartik
4,52231537
edited Mar 21 at 23:03
answered Mar 21 at 22:50
KartikKartik
4,52231537
answered Mar 21 at 22:50
KartikKartik
4,52231537
answered Mar 21 at 22:50
KartikKartik
4,52231537
4,52231537
add a comment |
add a comment |
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