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Javascript split error : Uncaught TypeError: Cannot read property 'split' of undefined [closed]

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;

-1

1

I write codes for split array values. But I get this error.

 var modeOfSending = $('#retrieveValueSupplier').val(); 
 var arrayBuild = modeOfSending.split(',');

javascript jquery

share|improve this question

edited Mar 22 at 4:34

Siong Thye Goh

1,74511016

asked Mar 22 at 3:50

HuseinHusein

113

closed as off-topic by CertainPerformance, SherylHohman, JumpingJezza, Shiladitya, Tiw Mar 22 at 5:50

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a clear problem statement are not useful to other readers. See: How to create a Minimal, Complete, and Verifiable example." – CertainPerformance, SherylHohman, JumpingJezza, Shiladitya, Tiw

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Please add your HTML code.
  
  – Jack Bashford
  Mar 22 at 3:52
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Before split check if modeOfSending has any value. Add if condition.
  
  – randomSoul
  Mar 22 at 3:53
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  i'm sorry... i delete my input text id= "retrieveValueSupplier" before :v....Thanks bro
  
  – Husein
  Mar 22 at 4:13
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @JackBashford yes, i forgot my input text id = "retrieveValueSupplier"..thx broo
  
  – Husein
  Mar 22 at 4:16
  

  
  
  
  

add a comment | 

-1

1

I write codes for split array values. But I get this error.

 var modeOfSending = $('#retrieveValueSupplier').val(); 
 var arrayBuild = modeOfSending.split(',');

javascript jquery

share|improve this question

edited Mar 22 at 4:34

Siong Thye Goh

1,74511016

asked Mar 22 at 3:50

HuseinHusein

113

closed as off-topic by CertainPerformance, SherylHohman, JumpingJezza, Shiladitya, Tiw Mar 22 at 5:50

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a clear problem statement are not useful to other readers. See: How to create a Minimal, Complete, and Verifiable example." – CertainPerformance, SherylHohman, JumpingJezza, Shiladitya, Tiw

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Please add your HTML code.
  
  – Jack Bashford
  Mar 22 at 3:52
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Before split check if modeOfSending has any value. Add if condition.
  
  – randomSoul
  Mar 22 at 3:53
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  i'm sorry... i delete my input text id= "retrieveValueSupplier" before :v....Thanks bro
  
  – Husein
  Mar 22 at 4:13
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @JackBashford yes, i forgot my input text id = "retrieveValueSupplier"..thx broo
  
  – Husein
  Mar 22 at 4:16
  

  
  
  
  

add a comment | 

I write codes for split array values. But I get this error.

 var modeOfSending = $('#retrieveValueSupplier').val(); 
 var arrayBuild = modeOfSending.split(',');

javascript jquery

share|improve this question

edited Mar 22 at 4:34

Siong Thye Goh

1,74511016

asked Mar 22 at 3:50

HuseinHusein

113

 var modeOfSending = $('#retrieveValueSupplier').val(); 
 var arrayBuild = modeOfSending.split(',');

share|improve this question

edited Mar 22 at 4:34

Siong Thye Goh

1,74511016

asked Mar 22 at 3:50

HuseinHusein

113

share|improve this question

edited Mar 22 at 4:34

Siong Thye Goh

1,74511016

asked Mar 22 at 3:50

HuseinHusein

113

edited Mar 22 at 4:34

Siong Thye Goh

1,74511016

edited Mar 22 at 4:34

Siong Thye Goh

1,74511016

asked Mar 22 at 3:50

HuseinHusein

113

asked Mar 22 at 3:50

HuseinHusein

113

2 Answers
2

active

oldest

votes

0

this is because modeOfSending is undefined.. have you try debug the value of $('#retrieveValueSupplier').val(); ?

share|improve this answer

answered Mar 22 at 3:56

surya surakhmansurya surakhman

342

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  yes, i forgot my input text id = "retrieveValueSupplier"..thx broo
  
  – Husein
  Mar 22 at 4:41
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I did nothing..
  
  – surya surakhman
  Mar 22 at 8:14
  

  
  
  
  

add a comment | 

0

Before split check if modeOfSending has any value and is not undefined or null.

let val;

val.split(",");

let val = "Hello,world";

if(val) 
 console.log(val.split(","));
;

share|improve this answer

answered Mar 22 at 3:57

randomSoulrandomSoul

833614

add a comment | 

0

this is because modeOfSending is undefined.. have you try debug the value of $('#retrieveValueSupplier').val(); ?

share|improve this answer

answered Mar 22 at 3:56

surya surakhmansurya surakhman

342

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  yes, i forgot my input text id = "retrieveValueSupplier"..thx broo
  
  – Husein
  Mar 22 at 4:41
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I did nothing..
  
  – surya surakhman
  Mar 22 at 8:14
  

  
  
  
  

add a comment | 

0

this is because modeOfSending is undefined.. have you try debug the value of $('#retrieveValueSupplier').val(); ?

share|improve this answer

answered Mar 22 at 3:56

surya surakhmansurya surakhman

342

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  yes, i forgot my input text id = "retrieveValueSupplier"..thx broo
  
  – Husein
  Mar 22 at 4:41
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I did nothing..
  
  – surya surakhman
  Mar 22 at 8:14
  

  
  
  
  

add a comment | 

this is because modeOfSending is undefined.. have you try debug the value of $('#retrieveValueSupplier').val(); ?

share|improve this answer

answered Mar 22 at 3:56

surya surakhmansurya surakhman

342

share|improve this answer

answered Mar 22 at 3:56

surya surakhmansurya surakhman

342

answered Mar 22 at 3:56

surya surakhmansurya surakhman

342

answered Mar 22 at 3:56

surya surakhmansurya surakhman

342

0

Before split check if modeOfSending has any value and is not undefined or null.

let val;

val.split(",");

let val = "Hello,world";

if(val) 
 console.log(val.split(","));
;

share|improve this answer

answered Mar 22 at 3:57

randomSoulrandomSoul

833614

add a comment | 

0

Before split check if modeOfSending has any value and is not undefined or null.

let val;

val.split(",");

let val = "Hello,world";

if(val) 
 console.log(val.split(","));
;

share|improve this answer

answered Mar 22 at 3:57

randomSoulrandomSoul

833614

add a comment | 

Before split check if modeOfSending has any value and is not undefined or null.

let val;

val.split(",");

let val = "Hello,world";

if(val) 
 console.log(val.split(","));
;

share|improve this answer

answered Mar 22 at 3:57

randomSoulrandomSoul

833614

let val;

val.split(",");

let val = "Hello,world";

if(val) 
 console.log(val.split(","));
;

let val;

val.split(",");

let val;

val.split(",");

let val = "Hello,world";

if(val) 
 console.log(val.split(","));
;

let val = "Hello,world";

if(val) 
 console.log(val.split(","));
;

share|improve this answer

answered Mar 22 at 3:57

randomSoulrandomSoul

833614

answered Mar 22 at 3:57

randomSoulrandomSoul

833614

answered Mar 22 at 3:57

randomSoulrandomSoul

833614