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preprocessor macro for universal framework in header file


Git ignore file for Xcode projectsHow can I Remove .DS_Store files from a Git repository?Differences between Framework and non-Framework builds of Python on Mac OS XLinker Error in Hybrid Mac / iPhone ProjectHow can I disable ARC for a single file in a project?LLVM 6 : Prefix Header vs Preprocessor Macros Not Used in Precompiled HeadersSwift: Using Preprocessor MacrosUmbrella Header Not Found When Changing Target Name or Product Name of FrameworkXcode picks wrong version of header file with same nameUse native framework inside Unity in standalone build













0















I'm on a legacy project and there's one codebase to build different frameworks for iOS, macOS, etc. In one of the public header files that is copied into the framework product, there is a preprocessor macro like this



 // MyObject.h
#ifdef TARGET_IOS
@import UIKit;
#endif


In the same header file, if I try to do



#ifdef TARGET_IOS
@property (nonatomic, strong) UIView *containerView;
#endif


The framework builds fine. However when I try to test out the framework in a separate app project, the compiler doesn't know what type containerView is on the type MyObject.



But of course if I just do



@property (nonatomic, strong) UIView *containerView;


without the preprocessor macro, in the separate app, it knows what type containerView is. Why is that? I thought that you tell the compiler on what to build with preprocessor macros. And then since that framework is built with that property containerView defined, it would work. But maybe I'm misunderstanding something?



Edited:
TARGET_IOS=1 in Preprocessor Macros of Build Settings for Debug and Release configurations.










share|improve this question
























  • Where is TARGET_IOS being defined?

    – Mobile Ben
    Mar 21 at 22:53











  • @MobileBen It's being defined as TARGET_IOS=1 in Preprocessor Macros for both Debug and Release configurations.

    – Crystal
    Mar 22 at 3:09















0















I'm on a legacy project and there's one codebase to build different frameworks for iOS, macOS, etc. In one of the public header files that is copied into the framework product, there is a preprocessor macro like this



 // MyObject.h
#ifdef TARGET_IOS
@import UIKit;
#endif


In the same header file, if I try to do



#ifdef TARGET_IOS
@property (nonatomic, strong) UIView *containerView;
#endif


The framework builds fine. However when I try to test out the framework in a separate app project, the compiler doesn't know what type containerView is on the type MyObject.



But of course if I just do



@property (nonatomic, strong) UIView *containerView;


without the preprocessor macro, in the separate app, it knows what type containerView is. Why is that? I thought that you tell the compiler on what to build with preprocessor macros. And then since that framework is built with that property containerView defined, it would work. But maybe I'm misunderstanding something?



Edited:
TARGET_IOS=1 in Preprocessor Macros of Build Settings for Debug and Release configurations.










share|improve this question
























  • Where is TARGET_IOS being defined?

    – Mobile Ben
    Mar 21 at 22:53











  • @MobileBen It's being defined as TARGET_IOS=1 in Preprocessor Macros for both Debug and Release configurations.

    – Crystal
    Mar 22 at 3:09













0












0








0








I'm on a legacy project and there's one codebase to build different frameworks for iOS, macOS, etc. In one of the public header files that is copied into the framework product, there is a preprocessor macro like this



 // MyObject.h
#ifdef TARGET_IOS
@import UIKit;
#endif


In the same header file, if I try to do



#ifdef TARGET_IOS
@property (nonatomic, strong) UIView *containerView;
#endif


The framework builds fine. However when I try to test out the framework in a separate app project, the compiler doesn't know what type containerView is on the type MyObject.



But of course if I just do



@property (nonatomic, strong) UIView *containerView;


without the preprocessor macro, in the separate app, it knows what type containerView is. Why is that? I thought that you tell the compiler on what to build with preprocessor macros. And then since that framework is built with that property containerView defined, it would work. But maybe I'm misunderstanding something?



Edited:
TARGET_IOS=1 in Preprocessor Macros of Build Settings for Debug and Release configurations.










share|improve this question
















I'm on a legacy project and there's one codebase to build different frameworks for iOS, macOS, etc. In one of the public header files that is copied into the framework product, there is a preprocessor macro like this



 // MyObject.h
#ifdef TARGET_IOS
@import UIKit;
#endif


In the same header file, if I try to do



#ifdef TARGET_IOS
@property (nonatomic, strong) UIView *containerView;
#endif


The framework builds fine. However when I try to test out the framework in a separate app project, the compiler doesn't know what type containerView is on the type MyObject.



But of course if I just do



@property (nonatomic, strong) UIView *containerView;


without the preprocessor macro, in the separate app, it knows what type containerView is. Why is that? I thought that you tell the compiler on what to build with preprocessor macros. And then since that framework is built with that property containerView defined, it would work. But maybe I'm misunderstanding something?



Edited:
TARGET_IOS=1 in Preprocessor Macros of Build Settings for Debug and Release configurations.







ios objective-c macos






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 22 at 3:09







Crystal

















asked Mar 21 at 21:10









CrystalCrystal

11.2k45180343




11.2k45180343












  • Where is TARGET_IOS being defined?

    – Mobile Ben
    Mar 21 at 22:53











  • @MobileBen It's being defined as TARGET_IOS=1 in Preprocessor Macros for both Debug and Release configurations.

    – Crystal
    Mar 22 at 3:09

















  • Where is TARGET_IOS being defined?

    – Mobile Ben
    Mar 21 at 22:53











  • @MobileBen It's being defined as TARGET_IOS=1 in Preprocessor Macros for both Debug and Release configurations.

    – Crystal
    Mar 22 at 3:09
















Where is TARGET_IOS being defined?

– Mobile Ben
Mar 21 at 22:53





Where is TARGET_IOS being defined?

– Mobile Ben
Mar 21 at 22:53













@MobileBen It's being defined as TARGET_IOS=1 in Preprocessor Macros for both Debug and Release configurations.

– Crystal
Mar 22 at 3:09





@MobileBen It's being defined as TARGET_IOS=1 in Preprocessor Macros for both Debug and Release configurations.

– Crystal
Mar 22 at 3:09












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