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How do I make my device discover-able to nearby device without confirmation dialog via Bluetooth?
Android error: Failed to install *.apk on device *: timeoutCan the Android Layout folder contain subfolders?Send Email IntentAndroid 4.3 Bluetooth Low Energy unstableDilemma: when to use Fragments vs Activities:ADB Android Device UnauthorizedDetect all Bluetooth devices (headsets, phones etc) nearby, without forcing the devices in discoverable modeHow to differentiate the connected bluetooth device in android programmatically?Android Bluetooth cannot discover nearby devicesDiscover devices using bluetooth with xamarin
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I had make an application related to Bluetooth connection in Android, every time when I enable Bluetooth, it shows a confirmation dialog that make your device discover able no near by device.
Is there any way to make device discover able without confirmation dialog.
I had used this:
Intent Intent= new Intent(BluetoothAdapter.ACTION_REQUEST_DISCOVERABLE);
Intent.putExtra(BluetoothAdapter.EXTRA_DISCOVERABLE_DURATION, 300);
android 
android-intent bluetooth android-bluetooth asked Mar 25 at 4:09
DhruvDhruv
415
add a comment |
I had make an application related to Bluetooth connection in Android, every time when I enable Bluetooth, it shows a confirmation dialog that make your device discover able no near by device.
Is there any way to make device discover able without confirmation dialog.
I had used this:
Intent Intent= new Intent(BluetoothAdapter.ACTION_REQUEST_DISCOVERABLE);
Intent.putExtra(BluetoothAdapter.EXTRA_DISCOVERABLE_DURATION, 300);
asked Mar 25 at 4:09
DhruvDhruv
415
Based on my understanding there is not any way around this. Probably an Android security reason, or maybe just related to how Android allows the user to interact with making the device discoverable. The negative thing about making the device discoverable without a dialog or the user being explicitly shown it is that it drains battery/resources and allows your device to be more vulnerable since people can see your device (that is the security reason from my understanding).
– Zachariah Rabatah
Apr 3 at 12:43
1
Okay, thanks @ZachariahRabatah
– Dhruv
Apr 9 at 5:32
add a comment |
I had make an application related to Bluetooth connection in Android, every time when I enable Bluetooth, it shows a confirmation dialog that make your device discover able no near by device.
Is there any way to make device discover able without confirmation dialog.
I had used this:
Intent Intent= new Intent(BluetoothAdapter.ACTION_REQUEST_DISCOVERABLE);
Intent.putExtra(BluetoothAdapter.EXTRA_DISCOVERABLE_DURATION, 300);
asked Mar 25 at 4:09
DhruvDhruv
415
I had make an application related to Bluetooth connection in Android, every time when I enable Bluetooth, it shows a confirmation dialog that make your device discover able no near by device.
Is there any way to make device discover able without confirmation dialog.
I had used this:
Intent Intent= new Intent(BluetoothAdapter.ACTION_REQUEST_DISCOVERABLE);
Intent.putExtra(BluetoothAdapter.EXTRA_DISCOVERABLE_DURATION, 300);
asked Mar 25 at 4:09
DhruvDhruv
415
asked Mar 25 at 4:09
DhruvDhruv
415
edited Mar 25 at 9:13
Dhruv
asked Mar 25 at 4:09
DhruvDhruv
415
asked Mar 25 at 4:09
DhruvDhruv
415
asked Mar 25 at 4:09
DhruvDhruv
415
415
Based on my understanding there is not any way around this. Probably an Android security reason, or maybe just related to how Android allows the user to interact with making the device discoverable. The negative thing about making the device discoverable without a dialog or the user being explicitly shown it is that it drains battery/resources and allows your device to be more vulnerable since people can see your device (that is the security reason from my understanding).
– Zachariah Rabatah
Apr 3 at 12:43
1
Okay, thanks @ZachariahRabatah
– Dhruv
Apr 9 at 5:32
add a comment |
Based on my understanding there is not any way around this. Probably an Android security reason, or maybe just related to how Android allows the user to interact with making the device discoverable. The negative thing about making the device discoverable without a dialog or the user being explicitly shown it is that it drains battery/resources and allows your device to be more vulnerable since people can see your device (that is the security reason from my understanding).
– Zachariah Rabatah
Apr 3 at 12:43
1
Okay, thanks @ZachariahRabatah
– Dhruv
Apr 9 at 5:32
Based on my understanding there is not any way around this. Probably an Android security reason, or maybe just related to how Android allows the user to interact with making the device discoverable. The negative thing about making the device discoverable without a dialog or the user being explicitly shown it is that it drains battery/resources and allows your device to be more vulnerable since people can see your device (that is the security reason from my understanding).
– Zachariah Rabatah
Apr 3 at 12:43
Based on my understanding there is not any way around this. Probably an Android security reason, or maybe just related to how Android allows the user to interact with making the device discoverable. The negative thing about making the device discoverable without a dialog or the user being explicitly shown it is that it drains battery/resources and allows your device to be more vulnerable since people can see your device (that is the security reason from my understanding).
– Zachariah Rabatah
Apr 3 at 12:43
1
1
Okay, thanks @ZachariahRabatah
– Dhruv
Apr 9 at 5:32
Okay, thanks @ZachariahRabatah
– Dhruv
Apr 9 at 5:32
add a comment |
1 Answer
1
active
oldest
votes
I found this helpful:
try
Method bluetoothDeviceVisibility;
bluetoothDeviceVisibility = mBluetoothAdapter.getClass().getMethod("setScanMode", int.class, int.class);
bluetoothDeviceVisibility.invoke(mBluetoothAdapter, BluetoothAdapter.SCAN_MODE_CONNECTABLE_DISCOVERABLE, 0);
catch (Exception e)
e.printStackTrace();
edited Jun 11 at 6:35
adiga
16.2k62846
answered Jun 11 at 6:24
DhruvDhruv
415
1
While this code may answer the question, providing additional context regarding why and/or how this code answers the question improves its long-term value.
– adiga
Jun 11 at 6:35
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I found this helpful:
try
Method bluetoothDeviceVisibility;
bluetoothDeviceVisibility = mBluetoothAdapter.getClass().getMethod("setScanMode", int.class, int.class);
bluetoothDeviceVisibility.invoke(mBluetoothAdapter, BluetoothAdapter.SCAN_MODE_CONNECTABLE_DISCOVERABLE, 0);
catch (Exception e)
e.printStackTrace();
edited Jun 11 at 6:35
adiga
16.2k62846
answered Jun 11 at 6:24
DhruvDhruv
415
1
While this code may answer the question, providing additional context regarding why and/or how this code answers the question improves its long-term value.
– adiga
Jun 11 at 6:35
add a comment |
I found this helpful:
try
Method bluetoothDeviceVisibility;
bluetoothDeviceVisibility = mBluetoothAdapter.getClass().getMethod("setScanMode", int.class, int.class);
bluetoothDeviceVisibility.invoke(mBluetoothAdapter, BluetoothAdapter.SCAN_MODE_CONNECTABLE_DISCOVERABLE, 0);
catch (Exception e)
e.printStackTrace();
edited Jun 11 at 6:35
adiga
16.2k62846
answered Jun 11 at 6:24
DhruvDhruv
415
1
While this code may answer the question, providing additional context regarding why and/or how this code answers the question improves its long-term value.
– adiga
Jun 11 at 6:35
add a comment |
I found this helpful:
try
Method bluetoothDeviceVisibility;
bluetoothDeviceVisibility = mBluetoothAdapter.getClass().getMethod("setScanMode", int.class, int.class);
bluetoothDeviceVisibility.invoke(mBluetoothAdapter, BluetoothAdapter.SCAN_MODE_CONNECTABLE_DISCOVERABLE, 0);
catch (Exception e)
e.printStackTrace();
edited Jun 11 at 6:35
adiga
16.2k62846
answered Jun 11 at 6:24
DhruvDhruv
415
I found this helpful:
try
Method bluetoothDeviceVisibility;
bluetoothDeviceVisibility = mBluetoothAdapter.getClass().getMethod("setScanMode", int.class, int.class);
bluetoothDeviceVisibility.invoke(mBluetoothAdapter, BluetoothAdapter.SCAN_MODE_CONNECTABLE_DISCOVERABLE, 0);
catch (Exception e)
e.printStackTrace();
edited Jun 11 at 6:35
adiga
16.2k62846
answered Jun 11 at 6:24
DhruvDhruv
415
edited Jun 11 at 6:35
adiga
16.2k62846
edited Jun 11 at 6:35
adiga
16.2k62846
edited Jun 11 at 6:35
adiga
16.2k62846
16.2k62846
answered Jun 11 at 6:24
DhruvDhruv
415
answered Jun 11 at 6:24
DhruvDhruv
415
answered Jun 11 at 6:24
DhruvDhruv
415
415
1
While this code may answer the question, providing additional context regarding why and/or how this code answers the question improves its long-term value.
– adiga
Jun 11 at 6:35
add a comment |
1
While this code may answer the question, providing additional context regarding why and/or how this code answers the question improves its long-term value.
– adiga
Jun 11 at 6:35
1
1
While this code may answer the question, providing additional context regarding why and/or how this code answers the question improves its long-term value.
– adiga
Jun 11 at 6:35
While this code may answer the question, providing additional context regarding why and/or how this code answers the question improves its long-term value.
– adiga
Jun 11 at 6:35
add a comment |
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Based on my understanding there is not any way around this. Probably an Android security reason, or maybe just related to how Android allows the user to interact with making the device discoverable. The negative thing about making the device discoverable without a dialog or the user being explicitly shown it is that it drains battery/resources and allows your device to be more vulnerable since people can see your device (that is the security reason from my understanding).
– Zachariah Rabatah
Apr 3 at 12:43
1
Okay, thanks @ZachariahRabatah
– Dhruv
Apr 9 at 5:32