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How do I tell if the value of a particular key in my dictionary is a dictionary so that I can solve programming questions based on this recursively?
How do you sort a dictionary by value?How do I sort a list of dictionaries by a value of the dictionary?Getting key with maximum value in dictionary?How to return multiple values from a function?How do I sort a dictionary by value?How to keep keys/values in same order as declared?How can I get dictionary key as variable directly in Python (not by searching from value)?Get key by value in dictionaryHow can I sort a dictionary by key?How to remove a key from a Python dictionary?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
So I want to make sure that a particular value of key is a primitive data type i.e not a dictionary. If it is a dictionary, I want to recursively check till I reach the end. ( base case-: no dictionary in the values) Let's say I have this code
dict =
"Roll No" : "1",
"Car" :
"Ferrari" : "12",
"Pontiac" : "15"`
,
"Budget" : "3"
How do I get "Car" as the key which has the datatype of the values to be a dictionary?
And how do I access the sub-dictionary ?
"Car":
"Ferrari":"12",
"Pontiac":"15"
,
python dictionary object
edited Mar 25 at 4:17
Kingsley
4,03641431
asked Mar 25 at 4:11
Yash ShahYash Shah
123
add a comment |
So I want to make sure that a particular value of key is a primitive data type i.e not a dictionary. If it is a dictionary, I want to recursively check till I reach the end. ( base case-: no dictionary in the values) Let's say I have this code
dict =
"Roll No" : "1",
"Car" :
"Ferrari" : "12",
"Pontiac" : "15"`
,
"Budget" : "3"
How do I get "Car" as the key which has the datatype of the values to be a dictionary?
And how do I access the sub-dictionary ?
"Car":
"Ferrari":"12",
"Pontiac":"15"
,
python dictionary object
edited Mar 25 at 4:17
Kingsley
4,03641431
asked Mar 25 at 4:11
Yash ShahYash Shah
123
What's wrong withdict['Car']?
– AkshayNevrekar
Mar 25 at 4:16
I dont think it would work. I mean I want to do it recursively so if there's subdictionaries possible within Car then I'd be stuck? if Car can be it's own dictionary which I can access then it'd work!
– Yash Shah
Mar 25 at 4:18
@AkshayNevrekar Actually dict['Car'] will be useful to get the values and check if they are in fact a dictionary and not a string. Thanks!
– Yash Shah
Mar 25 at 7:54
add a comment |
So I want to make sure that a particular value of key is a primitive data type i.e not a dictionary. If it is a dictionary, I want to recursively check till I reach the end. ( base case-: no dictionary in the values) Let's say I have this code
dict =
"Roll No" : "1",
"Car" :
"Ferrari" : "12",
"Pontiac" : "15"`
,
"Budget" : "3"
How do I get "Car" as the key which has the datatype of the values to be a dictionary?
And how do I access the sub-dictionary ?
"Car":
"Ferrari":"12",
"Pontiac":"15"
,
python dictionary object
edited Mar 25 at 4:17
Kingsley
4,03641431
asked Mar 25 at 4:11
Yash ShahYash Shah
123
So I want to make sure that a particular value of key is a primitive data type i.e not a dictionary. If it is a dictionary, I want to recursively check till I reach the end. ( base case-: no dictionary in the values) Let's say I have this code
dict =
"Roll No" : "1",
"Car" :
"Ferrari" : "12",
"Pontiac" : "15"`
,
"Budget" : "3"
How do I get "Car" as the key which has the datatype of the values to be a dictionary?
And how do I access the sub-dictionary ?
"Car":
"Ferrari":"12",
"Pontiac":"15"
,
python dictionary object
python dictionary object
edited Mar 25 at 4:17
Kingsley
4,03641431
asked Mar 25 at 4:11
Yash ShahYash Shah
123
edited Mar 25 at 4:17
Kingsley
4,03641431
asked Mar 25 at 4:11
Yash ShahYash Shah
123
edited Mar 25 at 4:17
Kingsley
4,03641431
edited Mar 25 at 4:17
Kingsley
4,03641431
edited Mar 25 at 4:17
Kingsley
4,03641431
4,03641431
asked Mar 25 at 4:11
Yash ShahYash Shah
123
asked Mar 25 at 4:11
Yash ShahYash Shah
123
asked Mar 25 at 4:11
Yash ShahYash Shah
123
123
What's wrong withdict['Car']?
– AkshayNevrekar
Mar 25 at 4:16
I dont think it would work. I mean I want to do it recursively so if there's subdictionaries possible within Car then I'd be stuck? if Car can be it's own dictionary which I can access then it'd work!
– Yash Shah
Mar 25 at 4:18
@AkshayNevrekar Actually dict['Car'] will be useful to get the values and check if they are in fact a dictionary and not a string. Thanks!
– Yash Shah
Mar 25 at 7:54
add a comment |
What's wrong withdict['Car']?
– AkshayNevrekar
Mar 25 at 4:16
I dont think it would work. I mean I want to do it recursively so if there's subdictionaries possible within Car then I'd be stuck? if Car can be it's own dictionary which I can access then it'd work!
– Yash Shah
Mar 25 at 4:18
@AkshayNevrekar Actually dict['Car'] will be useful to get the values and check if they are in fact a dictionary and not a string. Thanks!
– Yash Shah
Mar 25 at 7:54
What's wrong with
dict['Car'] ?– AkshayNevrekar
Mar 25 at 4:16
What's wrong with
dict['Car'] ?– AkshayNevrekar
Mar 25 at 4:16
I dont think it would work. I mean I want to do it recursively so if there's subdictionaries possible within Car then I'd be stuck? if Car can be it's own dictionary which I can access then it'd work!
– Yash Shah
Mar 25 at 4:18
I dont think it would work. I mean I want to do it recursively so if there's subdictionaries possible within Car then I'd be stuck? if Car can be it's own dictionary which I can access then it'd work!
– Yash Shah
Mar 25 at 4:18
@AkshayNevrekar Actually dict['Car'] will be useful to get the values and check if they are in fact a dictionary and not a string. Thanks!
– Yash Shah
Mar 25 at 7:54
@AkshayNevrekar Actually dict['Car'] will be useful to get the values and check if they are in fact a dictionary and not a string. Thanks!
– Yash Shah
Mar 25 at 7:54
add a comment |
1 Answer
1
active
oldest
votes
You can use python's type() function to decide if the element is a dictionary, and thus when to recurse:
searchDictionary( haystack, needle ):
for key in haystack.keys():
if type( haystack[key] ) is dict:
searchDictionary( haystack[key], needle )
elif type( haystack[key] ) is str:
# TODO - match string
if ( haystack[key] == needle ):
print( "Found at "+str(key) )
elif type( haystack[key] ) is int:
# TODO - match integer
pass
There's a bunch of other ways to iterate over the dictionary, but I chose this method to illustrate the answer in a readable manner.
answered Mar 25 at 4:25
KingsleyKingsley
4,03641431
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use python's type() function to decide if the element is a dictionary, and thus when to recurse:
searchDictionary( haystack, needle ):
for key in haystack.keys():
if type( haystack[key] ) is dict:
searchDictionary( haystack[key], needle )
elif type( haystack[key] ) is str:
# TODO - match string
if ( haystack[key] == needle ):
print( "Found at "+str(key) )
elif type( haystack[key] ) is int:
# TODO - match integer
pass
There's a bunch of other ways to iterate over the dictionary, but I chose this method to illustrate the answer in a readable manner.
answered Mar 25 at 4:25
KingsleyKingsley
4,03641431
add a comment |
You can use python's type() function to decide if the element is a dictionary, and thus when to recurse:
searchDictionary( haystack, needle ):
for key in haystack.keys():
if type( haystack[key] ) is dict:
searchDictionary( haystack[key], needle )
elif type( haystack[key] ) is str:
# TODO - match string
if ( haystack[key] == needle ):
print( "Found at "+str(key) )
elif type( haystack[key] ) is int:
# TODO - match integer
pass
There's a bunch of other ways to iterate over the dictionary, but I chose this method to illustrate the answer in a readable manner.
answered Mar 25 at 4:25
KingsleyKingsley
4,03641431
add a comment |
You can use python's type() function to decide if the element is a dictionary, and thus when to recurse:
searchDictionary( haystack, needle ):
for key in haystack.keys():
if type( haystack[key] ) is dict:
searchDictionary( haystack[key], needle )
elif type( haystack[key] ) is str:
# TODO - match string
if ( haystack[key] == needle ):
print( "Found at "+str(key) )
elif type( haystack[key] ) is int:
# TODO - match integer
pass
There's a bunch of other ways to iterate over the dictionary, but I chose this method to illustrate the answer in a readable manner.
answered Mar 25 at 4:25
KingsleyKingsley
4,03641431
You can use python's type() function to decide if the element is a dictionary, and thus when to recurse:
searchDictionary( haystack, needle ):
for key in haystack.keys():
if type( haystack[key] ) is dict:
searchDictionary( haystack[key], needle )
elif type( haystack[key] ) is str:
# TODO - match string
if ( haystack[key] == needle ):
print( "Found at "+str(key) )
elif type( haystack[key] ) is int:
# TODO - match integer
pass
There's a bunch of other ways to iterate over the dictionary, but I chose this method to illustrate the answer in a readable manner.
answered Mar 25 at 4:25
KingsleyKingsley
4,03641431
answered Mar 25 at 4:25
KingsleyKingsley
4,03641431
answered Mar 25 at 4:25
KingsleyKingsley
4,03641431
answered Mar 25 at 4:25
KingsleyKingsley
4,03641431
4,03641431
add a comment |
add a comment |
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What's wrong with
dict['Car']?– AkshayNevrekar
Mar 25 at 4:16
I dont think it would work. I mean I want to do it recursively so if there's subdictionaries possible within Car then I'd be stuck? if Car can be it's own dictionary which I can access then it'd work!
– Yash Shah
Mar 25 at 4:18
@AkshayNevrekar Actually dict['Car'] will be useful to get the values and check if they are in fact a dictionary and not a string. Thanks!
– Yash Shah
Mar 25 at 7:54