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pass array to includes() javascript

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1

I'm trying to find out if a string includes multiple strings stored in array with .includes()

So I've tried

let string = 'hello james';

console.log(string.includes(['hello', 'james']));

but it is being returned as false.. when I know the string includes 'hello' or 'james' is this even possible?? how can I tell if a string contains either the word 'hello' or 'james'

So in pseudo code this would look like string.includes('hello' || 'james');

javascript

share|improve this question

edited Mar 25 at 4:23

Smokey Dawson

asked Mar 25 at 4:11

Smokey DawsonSmokey Dawson

1,94811855

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  hello and james should both be in the string to be true?
  
  – Eddie
  Mar 25 at 4:13
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Eddie more like or so in pseudo code string.includes('hello' || 'james');
  
  – Smokey Dawson
  Mar 25 at 4:14
  

  
  
  
  

add a comment | 

1

I'm trying to find out if a string includes multiple strings stored in array with .includes()

So I've tried

let string = 'hello james';

console.log(string.includes(['hello', 'james']));

but it is being returned as false.. when I know the string includes 'hello' or 'james' is this even possible?? how can I tell if a string contains either the word 'hello' or 'james'

So in pseudo code this would look like string.includes('hello' || 'james');

javascript

share|improve this question

edited Mar 25 at 4:23

Smokey Dawson

asked Mar 25 at 4:11

Smokey DawsonSmokey Dawson

1,94811855

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  hello and james should both be in the string to be true?
  
  – Eddie
  Mar 25 at 4:13
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Eddie more like or so in pseudo code string.includes('hello' || 'james');
  
  – Smokey Dawson
  Mar 25 at 4:14
  

  
  
  
  

add a comment | 

I'm trying to find out if a string includes multiple strings stored in array with .includes()

So I've tried

let string = 'hello james';

console.log(string.includes(['hello', 'james']));

but it is being returned as false.. when I know the string includes 'hello' or 'james' is this even possible?? how can I tell if a string contains either the word 'hello' or 'james'

So in pseudo code this would look like string.includes('hello' || 'james');

javascript

share|improve this question

edited Mar 25 at 4:23

Smokey Dawson

asked Mar 25 at 4:11

Smokey DawsonSmokey Dawson

1,94811855

let string = 'hello james';

console.log(string.includes(['hello', 'james']));

share|improve this question

edited Mar 25 at 4:23

Smokey Dawson

asked Mar 25 at 4:11

Smokey DawsonSmokey Dawson

1,94811855

share|improve this question

edited Mar 25 at 4:23

Smokey Dawson

asked Mar 25 at 4:11

Smokey DawsonSmokey Dawson

1,94811855

asked Mar 25 at 4:11

Smokey DawsonSmokey Dawson

1,94811855

asked Mar 25 at 4:11

Smokey DawsonSmokey Dawson

1,94811855

2 Answers
2

active

oldest

votes

3

Based on the docs, includes first parameter is a string and not an array.

You can do:

If you want to check if each and every string in the array is present on the string, you can use every and includes combo

let string = 'hello james';
let toCheck = ['hello', 'james'];

let result = toCheck.every(o => string.includes(o));

console.log(result);

You can use some instead of every if you want to check at least one entry in the array is present on the string.

let string = 'hello james';
let toCheck = ['hello', 'james1'];

let result = toCheck.some(o => string.includes(o));

console.log(result);

share|improve this answer

edited Mar 25 at 4:19

answered Mar 25 at 4:17

EddieEddie

22.8k51942

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Yes thank you this is what I was looking for
  
  – Smokey Dawson
  Mar 25 at 4:19
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  Beat me to it :|
  
  – Aditya Gupta
  Mar 25 at 4:23
  

  
  
  
  

add a comment | 

0

According to the documentation, the str.includes takes a string as the first parameter.

So when you pass an array instead, it converts the array of strings to a single string, and uses that string as the first parameter of the includes function.

Just to demonstrate this point,

let string = "hello,james";
var array = ["hello", "james"]

console.log(string.includes(array)); // returns true, as array would be converted to "hello,james"

share|improve this answer

answered Mar 25 at 4:26

Swanky CoderSwanky Coder

316212

add a comment | 

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3

Based on the docs, includes first parameter is a string and not an array.

You can do:

If you want to check if each and every string in the array is present on the string, you can use every and includes combo

let string = 'hello james';
let toCheck = ['hello', 'james'];

let result = toCheck.every(o => string.includes(o));

console.log(result);

You can use some instead of every if you want to check at least one entry in the array is present on the string.

let string = 'hello james';
let toCheck = ['hello', 'james1'];

let result = toCheck.some(o => string.includes(o));

console.log(result);

share|improve this answer

edited Mar 25 at 4:19

answered Mar 25 at 4:17

EddieEddie

22.8k51942

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Yes thank you this is what I was looking for
  
  – Smokey Dawson
  Mar 25 at 4:19
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  Beat me to it :|
  
  – Aditya Gupta
  Mar 25 at 4:23
  

  
  
  
  

add a comment | 

3

Based on the docs, includes first parameter is a string and not an array.

You can do:

If you want to check if each and every string in the array is present on the string, you can use every and includes combo

let string = 'hello james';
let toCheck = ['hello', 'james'];

let result = toCheck.every(o => string.includes(o));

console.log(result);

You can use some instead of every if you want to check at least one entry in the array is present on the string.

let string = 'hello james';
let toCheck = ['hello', 'james1'];

let result = toCheck.some(o => string.includes(o));

console.log(result);

share|improve this answer

edited Mar 25 at 4:19

answered Mar 25 at 4:17

EddieEddie

22.8k51942

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Yes thank you this is what I was looking for
  
  – Smokey Dawson
  Mar 25 at 4:19
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  Beat me to it :|
  
  – Aditya Gupta
  Mar 25 at 4:23
  

  
  
  
  

add a comment | 

Based on the docs, includes first parameter is a string and not an array.

You can do:

If you want to check if each and every string in the array is present on the string, you can use every and includes combo

let string = 'hello james';
let toCheck = ['hello', 'james'];

let result = toCheck.every(o => string.includes(o));

console.log(result);

You can use some instead of every if you want to check at least one entry in the array is present on the string.

let string = 'hello james';
let toCheck = ['hello', 'james1'];

let result = toCheck.some(o => string.includes(o));

console.log(result);

share|improve this answer

edited Mar 25 at 4:19

answered Mar 25 at 4:17

EddieEddie

22.8k51942

let string = 'hello james';
let toCheck = ['hello', 'james'];

let result = toCheck.every(o => string.includes(o));

console.log(result);

let string = 'hello james';
let toCheck = ['hello', 'james1'];

let result = toCheck.some(o => string.includes(o));

console.log(result);

let string = 'hello james';
let toCheck = ['hello', 'james'];

let result = toCheck.every(o => string.includes(o));

console.log(result);

let string = 'hello james';
let toCheck = ['hello', 'james'];

let result = toCheck.every(o => string.includes(o));

console.log(result);

let string = 'hello james';
let toCheck = ['hello', 'james1'];

let result = toCheck.some(o => string.includes(o));

console.log(result);

let string = 'hello james';
let toCheck = ['hello', 'james1'];

let result = toCheck.some(o => string.includes(o));

console.log(result);

share|improve this answer

edited Mar 25 at 4:19

answered Mar 25 at 4:17

EddieEddie

22.8k51942

answered Mar 25 at 4:17

EddieEddie

22.8k51942

answered Mar 25 at 4:17

EddieEddie

22.8k51942

0

According to the documentation, the str.includes takes a string as the first parameter.

So when you pass an array instead, it converts the array of strings to a single string, and uses that string as the first parameter of the includes function.

Just to demonstrate this point,

let string = "hello,james";
var array = ["hello", "james"]

console.log(string.includes(array)); // returns true, as array would be converted to "hello,james"

share|improve this answer

answered Mar 25 at 4:26

Swanky CoderSwanky Coder

316212

add a comment | 

0

According to the documentation, the str.includes takes a string as the first parameter.

So when you pass an array instead, it converts the array of strings to a single string, and uses that string as the first parameter of the includes function.

Just to demonstrate this point,

let string = "hello,james";
var array = ["hello", "james"]

console.log(string.includes(array)); // returns true, as array would be converted to "hello,james"

share|improve this answer

answered Mar 25 at 4:26

Swanky CoderSwanky Coder

316212

add a comment | 

According to the documentation, the str.includes takes a string as the first parameter.

So when you pass an array instead, it converts the array of strings to a single string, and uses that string as the first parameter of the includes function.

Just to demonstrate this point,

let string = "hello,james";
var array = ["hello", "james"]

console.log(string.includes(array)); // returns true, as array would be converted to "hello,james"

share|improve this answer

answered Mar 25 at 4:26

Swanky CoderSwanky Coder

316212

let string = "hello,james";
var array = ["hello", "james"]

console.log(string.includes(array)); // returns true, as array would be converted to "hello,james"

share|improve this answer

answered Mar 25 at 4:26

Swanky CoderSwanky Coder

316212

answered Mar 25 at 4:26

Swanky CoderSwanky Coder

316212

answered Mar 25 at 4:26

Swanky CoderSwanky Coder

316212