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How to find and replace string In many files
How can I prevent SQL injection in PHP?How do I get PHP errors to display?How do I get a YouTube video thumbnail from the YouTube API?How do you parse and process HTML/XML in PHP?How do I check if a string contains a specific word?`require': no such file to load — mkmf (LoadError)How does PHP 'foreach' actually work?Reference - What does this error mean in PHP?How to list directories, sub-directories and all files in phpHow to get PHP files and their path changed after a date
What I need Is to go thru a directory that contains subdirectories. In each second level directory has a third level directory that contains a file with same file name for every second level directory.
In each of those files made in PHP there Is a variable that contains like: appversion = 'YYYYMMDD'. I need to modify this date for each appearance To eg appversion = '20190301'.
How to do this In Shell or with PHP?
Edit: sorry for the malformed question, this is what defines better what I need to do really
I am afraid the question was a little malformed.
What I need to do is:
1. To find in all subdirectories a file called "productver.php".
2. In each "productver.php" file find a variable called 'appversion'.
3. Replace the value with a given value that i provide.
Example: I provide a date that is "20190324" and I want to change this to the value of all 'appversion' variables. E.g. 'appversion = 20180121' ==> 'appversion = 20190324'. For this reason, I am afraid simple replace is not enough as I only need to replace the part which is on the right side of the "=" character. And I cannot seek for a specific date, because the dates of this variable change. All I know is that I need to replace those dates, on the right side of the "=" sign of variable 'appversion'.
php ubuntu
add a comment |
What I need Is to go thru a directory that contains subdirectories. In each second level directory has a third level directory that contains a file with same file name for every second level directory.
In each of those files made in PHP there Is a variable that contains like: appversion = 'YYYYMMDD'. I need to modify this date for each appearance To eg appversion = '20190301'.
How to do this In Shell or with PHP?
Edit: sorry for the malformed question, this is what defines better what I need to do really
I am afraid the question was a little malformed.
What I need to do is:
1. To find in all subdirectories a file called "productver.php".
2. In each "productver.php" file find a variable called 'appversion'.
3. Replace the value with a given value that i provide.
Example: I provide a date that is "20190324" and I want to change this to the value of all 'appversion' variables. E.g. 'appversion = 20180121' ==> 'appversion = 20190324'. For this reason, I am afraid simple replace is not enough as I only need to replace the part which is on the right side of the "=" character. And I cannot seek for a specific date, because the dates of this variable change. All I know is that I need to replace those dates, on the right side of the "=" sign of variable 'appversion'.
php ubuntu
is it a one time issue or you need an automation? This can be done using IDE (Search and Replace or Refactor..). Otherwise a shell script using sed would be perfect.
– Nik
Mar 25 at 16:37
PHPstr_replace('YYYYMMDD', '20190301', $string)
,sed
could be used in shell.
– user3783243
Mar 25 at 16:40
Did you look at unix.stackexchange.com/questions/112023/…?
– tk421
Mar 25 at 19:00
Please see my edit on the main question. Sorry for the mess...
– Alyssa Skogs
Mar 25 at 19:30
add a comment |
What I need Is to go thru a directory that contains subdirectories. In each second level directory has a third level directory that contains a file with same file name for every second level directory.
In each of those files made in PHP there Is a variable that contains like: appversion = 'YYYYMMDD'. I need to modify this date for each appearance To eg appversion = '20190301'.
How to do this In Shell or with PHP?
Edit: sorry for the malformed question, this is what defines better what I need to do really
I am afraid the question was a little malformed.
What I need to do is:
1. To find in all subdirectories a file called "productver.php".
2. In each "productver.php" file find a variable called 'appversion'.
3. Replace the value with a given value that i provide.
Example: I provide a date that is "20190324" and I want to change this to the value of all 'appversion' variables. E.g. 'appversion = 20180121' ==> 'appversion = 20190324'. For this reason, I am afraid simple replace is not enough as I only need to replace the part which is on the right side of the "=" character. And I cannot seek for a specific date, because the dates of this variable change. All I know is that I need to replace those dates, on the right side of the "=" sign of variable 'appversion'.
php ubuntu
What I need Is to go thru a directory that contains subdirectories. In each second level directory has a third level directory that contains a file with same file name for every second level directory.
In each of those files made in PHP there Is a variable that contains like: appversion = 'YYYYMMDD'. I need to modify this date for each appearance To eg appversion = '20190301'.
How to do this In Shell or with PHP?
Edit: sorry for the malformed question, this is what defines better what I need to do really
I am afraid the question was a little malformed.
What I need to do is:
1. To find in all subdirectories a file called "productver.php".
2. In each "productver.php" file find a variable called 'appversion'.
3. Replace the value with a given value that i provide.
Example: I provide a date that is "20190324" and I want to change this to the value of all 'appversion' variables. E.g. 'appversion = 20180121' ==> 'appversion = 20190324'. For this reason, I am afraid simple replace is not enough as I only need to replace the part which is on the right side of the "=" character. And I cannot seek for a specific date, because the dates of this variable change. All I know is that I need to replace those dates, on the right side of the "=" sign of variable 'appversion'.
php ubuntu
php ubuntu
edited Mar 25 at 19:30
Alyssa Skogs
asked Mar 25 at 16:34
Alyssa SkogsAlyssa Skogs
92 bronze badges
92 bronze badges
is it a one time issue or you need an automation? This can be done using IDE (Search and Replace or Refactor..). Otherwise a shell script using sed would be perfect.
– Nik
Mar 25 at 16:37
PHPstr_replace('YYYYMMDD', '20190301', $string)
,sed
could be used in shell.
– user3783243
Mar 25 at 16:40
Did you look at unix.stackexchange.com/questions/112023/…?
– tk421
Mar 25 at 19:00
Please see my edit on the main question. Sorry for the mess...
– Alyssa Skogs
Mar 25 at 19:30
add a comment |
is it a one time issue or you need an automation? This can be done using IDE (Search and Replace or Refactor..). Otherwise a shell script using sed would be perfect.
– Nik
Mar 25 at 16:37
PHPstr_replace('YYYYMMDD', '20190301', $string)
,sed
could be used in shell.
– user3783243
Mar 25 at 16:40
Did you look at unix.stackexchange.com/questions/112023/…?
– tk421
Mar 25 at 19:00
Please see my edit on the main question. Sorry for the mess...
– Alyssa Skogs
Mar 25 at 19:30
is it a one time issue or you need an automation? This can be done using IDE (Search and Replace or Refactor..). Otherwise a shell script using sed would be perfect.
– Nik
Mar 25 at 16:37
is it a one time issue or you need an automation? This can be done using IDE (Search and Replace or Refactor..). Otherwise a shell script using sed would be perfect.
– Nik
Mar 25 at 16:37
PHP
str_replace('YYYYMMDD', '20190301', $string)
, sed
could be used in shell.– user3783243
Mar 25 at 16:40
PHP
str_replace('YYYYMMDD', '20190301', $string)
, sed
could be used in shell.– user3783243
Mar 25 at 16:40
Did you look at unix.stackexchange.com/questions/112023/…?
– tk421
Mar 25 at 19:00
Did you look at unix.stackexchange.com/questions/112023/…?
– tk421
Mar 25 at 19:00
Please see my edit on the main question. Sorry for the mess...
– Alyssa Skogs
Mar 25 at 19:30
Please see my edit on the main question. Sorry for the mess...
– Alyssa Skogs
Mar 25 at 19:30
add a comment |
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is it a one time issue or you need an automation? This can be done using IDE (Search and Replace or Refactor..). Otherwise a shell script using sed would be perfect.
– Nik
Mar 25 at 16:37
PHP
str_replace('YYYYMMDD', '20190301', $string)
,sed
could be used in shell.– user3783243
Mar 25 at 16:40
Did you look at unix.stackexchange.com/questions/112023/…?
– tk421
Mar 25 at 19:00
Please see my edit on the main question. Sorry for the mess...
– Alyssa Skogs
Mar 25 at 19:30