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Syntax error near unexpected token 'elif' in Bash

if, elif, else statement issues in BashUbuntu BASH syntax error near unexpected tokenmakefile in ubuntu giving bash syntax error near unexpected token `(syntax error in bash “if.. elif” scriptBash Script if elif elif not workingsh.exe": syntax error near unexpected token `('Bash: Syntax Error Near Unexpected Token `(' When Using Wgrib2BASH: syntax error near unexpected token `(' in .bashrcBash scripting: syntax error near unexpected token `done'Getting an error syntax error near unexpected token `then'bash: syntax error near unexpected token `)'

0

I'm using a new language, I think it's linux but to be honest I have no clue; we're connecting to some server through a program called putty to do this programming. As part of an assignment I have to create a calculator program that takes two numbers and an operator as arugments but I'm getting a bunch of unexpected token errors. I'm very lost and neither my text no my professor is helpful so far

#!/bin/bash

function add 
 echo $(( $1 + $2 ))


function subtract 
 echo $(( $1 - $2 ))


function multiply 
 echo $(( $1 x $2 ))


function divide 
 echo $(( $1 / $2 ))


if [ $3 = '+' ] then add

so far I'm just trying to get it so I can get 2 from the command ./calc.sh 1 1 + but I keep getting unexpected token error on line 20 syntax error near unexpected token 'elif' [ $3 = '-' ] then subtract

linux bash

share|improve this question

edited Mar 25 at 16:44

jww

56.1k4242 gold badges247247 silver badges540540 bronze badges

asked Mar 25 at 16:29

emma brainemma brain

3199 bronze badges

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  
  You didn't include the code that the error is referencing.
  
  – Carcigenicate
  Mar 25 at 16:33
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  The language you are mentioning is not "linux", it's "bash".
  
  – Jona
  Mar 25 at 16:36
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Please show the relevant code. Please state where the error is encountered. Also see if, elif, else statement issues in Bash and How to create a Minimal, Complete, and Verifiable example.
  
  – jww
  Mar 25 at 16:41
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Also see How to use Shellcheck, How to debug a bash script? (U&L.SE), How to debug a bash script? (SO), How to debug bash script? (AskU), Debugging Bash scripts, etc.
  
  – jww
  Mar 25 at 16:41
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Your error messages gives elif but there is no elif in the code you show.
  
  – cdarke
  Mar 25 at 16:45
  

  
  
  
  

add a comment | 

0

I'm using a new language, I think it's linux but to be honest I have no clue; we're connecting to some server through a program called putty to do this programming. As part of an assignment I have to create a calculator program that takes two numbers and an operator as arugments but I'm getting a bunch of unexpected token errors. I'm very lost and neither my text no my professor is helpful so far

#!/bin/bash

function add 
 echo $(( $1 + $2 ))


function subtract 
 echo $(( $1 - $2 ))


function multiply 
 echo $(( $1 x $2 ))


function divide 
 echo $(( $1 / $2 ))


if [ $3 = '+' ] then add

so far I'm just trying to get it so I can get 2 from the command ./calc.sh 1 1 + but I keep getting unexpected token error on line 20 syntax error near unexpected token 'elif' [ $3 = '-' ] then subtract

linux bash

share|improve this question

edited Mar 25 at 16:44

jww

56.1k4242 gold badges247247 silver badges540540 bronze badges

asked Mar 25 at 16:29

emma brainemma brain

3199 bronze badges

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  
  You didn't include the code that the error is referencing.
  
  – Carcigenicate
  Mar 25 at 16:33
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  The language you are mentioning is not "linux", it's "bash".
  
  – Jona
  Mar 25 at 16:36
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Please show the relevant code. Please state where the error is encountered. Also see if, elif, else statement issues in Bash and How to create a Minimal, Complete, and Verifiable example.
  
  – jww
  Mar 25 at 16:41
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Also see How to use Shellcheck, How to debug a bash script? (U&L.SE), How to debug a bash script? (SO), How to debug bash script? (AskU), Debugging Bash scripts, etc.
  
  – jww
  Mar 25 at 16:41
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Your error messages gives elif but there is no elif in the code you show.
  
  – cdarke
  Mar 25 at 16:45
  

  
  
  
  

add a comment | 

I'm using a new language, I think it's linux but to be honest I have no clue; we're connecting to some server through a program called putty to do this programming. As part of an assignment I have to create a calculator program that takes two numbers and an operator as arugments but I'm getting a bunch of unexpected token errors. I'm very lost and neither my text no my professor is helpful so far

#!/bin/bash

function add 
 echo $(( $1 + $2 ))


function subtract 
 echo $(( $1 - $2 ))


function multiply 
 echo $(( $1 x $2 ))


function divide 
 echo $(( $1 / $2 ))


if [ $3 = '+' ] then add

so far I'm just trying to get it so I can get 2 from the command ./calc.sh 1 1 + but I keep getting unexpected token error on line 20 syntax error near unexpected token 'elif' [ $3 = '-' ] then subtract

linux bash

share|improve this question

edited Mar 25 at 16:44

jww

56.1k4242 gold badges247247 silver badges540540 bronze badges

asked Mar 25 at 16:29

emma brainemma brain

3199 bronze badges

#!/bin/bash

function add 
 echo $(( $1 + $2 ))


function subtract 
 echo $(( $1 - $2 ))


function multiply 
 echo $(( $1 x $2 ))


function divide 
 echo $(( $1 / $2 ))


if [ $3 = '+' ] then add

share|improve this question

edited Mar 25 at 16:44

jww

56.1k4242 gold badges247247 silver badges540540 bronze badges

asked Mar 25 at 16:29

emma brainemma brain

3199 bronze badges

share|improve this question

edited Mar 25 at 16:44

jww

56.1k4242 gold badges247247 silver badges540540 bronze badges

asked Mar 25 at 16:29

emma brainemma brain

3199 bronze badges

edited Mar 25 at 16:44

jww

56.1k4242 gold badges247247 silver badges540540 bronze badges

edited Mar 25 at 16:44

jww

56.1k4242 gold badges247247 silver badges540540 bronze badges

asked Mar 25 at 16:29

emma brainemma brain

3199 bronze badges

asked Mar 25 at 16:29

emma brainemma brain

3199 bronze badges

2 Answers
2

active

oldest

votes

0

This will do what you want:

#!/bin/bash

function add 
 echo $(( $1 + $2 ))


if [ $3 = '+' ]; then add $1 $2
fi

share|improve this answer

answered Mar 25 at 16:43

JonaJona

29311 gold badge22 silver badges1010 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @emma-brain If any of the answers solved your question, it's also a good practice to upvote. ;-)
  
  – Jona
  Mar 26 at 9:18
  

  
  
  
  

add a comment | 

0

There are a number of issues in just what we can see, in the last visible line.

You need either a line break or a semi colon after if [ $3 = '+' ]
And while it is possible that it is just where it chose to stop pasting, your functions need to be passed arguments, so "add $1 $2" vs "add"

share|improve this answer

answered Mar 25 at 16:38

CorvarCorvar

1

add a comment | 

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0

This will do what you want:

#!/bin/bash

function add 
 echo $(( $1 + $2 ))


if [ $3 = '+' ]; then add $1 $2
fi

share|improve this answer

answered Mar 25 at 16:43

JonaJona

29311 gold badge22 silver badges1010 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @emma-brain If any of the answers solved your question, it's also a good practice to upvote. ;-)
  
  – Jona
  Mar 26 at 9:18
  

  
  
  
  

add a comment | 

0

This will do what you want:

#!/bin/bash

function add 
 echo $(( $1 + $2 ))


if [ $3 = '+' ]; then add $1 $2
fi

share|improve this answer

answered Mar 25 at 16:43

JonaJona

29311 gold badge22 silver badges1010 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @emma-brain If any of the answers solved your question, it's also a good practice to upvote. ;-)
  
  – Jona
  Mar 26 at 9:18
  

  
  
  
  

add a comment | 

This will do what you want:

#!/bin/bash

function add 
 echo $(( $1 + $2 ))


if [ $3 = '+' ]; then add $1 $2
fi

share|improve this answer

answered Mar 25 at 16:43

JonaJona

29311 gold badge22 silver badges1010 bronze badges

#!/bin/bash

function add 
 echo $(( $1 + $2 ))


if [ $3 = '+' ]; then add $1 $2
fi

share|improve this answer

answered Mar 25 at 16:43

JonaJona

29311 gold badge22 silver badges1010 bronze badges

answered Mar 25 at 16:43

JonaJona

29311 gold badge22 silver badges1010 bronze badges

answered Mar 25 at 16:43

JonaJona

29311 gold badge22 silver badges1010 bronze badges

0

There are a number of issues in just what we can see, in the last visible line.

You need either a line break or a semi colon after if [ $3 = '+' ]
And while it is possible that it is just where it chose to stop pasting, your functions need to be passed arguments, so "add $1 $2" vs "add"

share|improve this answer

answered Mar 25 at 16:38

CorvarCorvar

1

add a comment | 

0

There are a number of issues in just what we can see, in the last visible line.

You need either a line break or a semi colon after if [ $3 = '+' ]
And while it is possible that it is just where it chose to stop pasting, your functions need to be passed arguments, so "add $1 $2" vs "add"

share|improve this answer

answered Mar 25 at 16:38

CorvarCorvar

1

add a comment | 

There are a number of issues in just what we can see, in the last visible line.

You need either a line break or a semi colon after if [ $3 = '+' ]
And while it is possible that it is just where it chose to stop pasting, your functions need to be passed arguments, so "add $1 $2" vs "add"

share|improve this answer

answered Mar 25 at 16:38

CorvarCorvar

1

share|improve this answer

answered Mar 25 at 16:38

CorvarCorvar

1

answered Mar 25 at 16:38

CorvarCorvar

1

answered Mar 25 at 16:38

CorvarCorvar

1