tikz grid without top edgeTikZ (finite) grid with character in each cellLaTeX equivalent of ConTeXt buffersHow to define the default vertical distance between nodes?Numerical conditional within tikz keys?TikZ/ERD: node (=Entity) label on the insideWhy do I get an extra white page before my TikZ picture?TikZ: Drawing an arc from an intersection to an intersectionHow to prevent rounded and duplicated tick labels in pgfplots with fixed precision?Drawing rectilinear curves in Tikz, aka an Etch-a-Sketch drawingLine up nested tikz enviroments or how to get rid of themHow to draw a square and its diagonals with arrows?
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tikz grid without top edge
TikZ (finite) grid with character in each cellLaTeX equivalent of ConTeXt buffersHow to define the default vertical distance between nodes?Numerical conditional within tikz keys?TikZ/ERD: node (=Entity) label on the insideWhy do I get an extra white page before my TikZ picture?TikZ: Drawing an arc from an intersection to an intersectionHow to prevent rounded and duplicated tick labels in pgfplots with fixed precision?Drawing rectilinear curves in Tikz, aka an Etch-a-Sketch drawingLine up nested tikz enviroments or how to get rid of themHow to draw a square and its diagonals with arrows?
In this code from TikZ (finite) grid with character in each cell
documentclassarticle
usepackagetikz
usetikzlibrarymatrix
begindocument
begintikzpicture
draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
matrix[matrix of nodes,nodes=inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm]
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\;
endtikzpicture
enddocument
I would like to delete the top and left edges of the grid.
I have found solutions using nodes but much prefer this one with a matrix.
tikz-pgf
asked Mar 25 at 13:31
Ethan BolkerEthan Bolker
6,7183 gold badges26 silver badges53 bronze badges
add a comment |
In this code from TikZ (finite) grid with character in each cell
documentclassarticle
usepackagetikz
usetikzlibrarymatrix
begindocument
begintikzpicture
draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
matrix[matrix of nodes,nodes=inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm]
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\;
endtikzpicture
enddocument
I would like to delete the top and left edges of the grid.
I have found solutions using nodes but much prefer this one with a matrix.
tikz-pgf
asked Mar 25 at 13:31
Ethan BolkerEthan Bolker
6,7183 gold badges26 silver badges53 bronze badges
Off topic: You have a very nice reputation number :)
– user156344
Mar 25 at 13:35
@JouleV Indeed, It won't survive any votes on this question.
– Ethan Bolker
Mar 25 at 13:36
add a comment |
In this code from TikZ (finite) grid with character in each cell
documentclassarticle
usepackagetikz
usetikzlibrarymatrix
begindocument
begintikzpicture
draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
matrix[matrix of nodes,nodes=inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm]
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\;
endtikzpicture
enddocument
I would like to delete the top and left edges of the grid.
I have found solutions using nodes but much prefer this one with a matrix.
tikz-pgf
asked Mar 25 at 13:31
Ethan BolkerEthan Bolker
6,7183 gold badges26 silver badges53 bronze badges
In this code from TikZ (finite) grid with character in each cell
documentclassarticle
usepackagetikz
usetikzlibrarymatrix
begindocument
begintikzpicture
draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
matrix[matrix of nodes,nodes=inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm]
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\;
endtikzpicture
enddocument
I would like to delete the top and left edges of the grid.
I have found solutions using nodes but much prefer this one with a matrix.
tikz-pgf
tikz-pgf
asked Mar 25 at 13:31
Ethan BolkerEthan Bolker
6,7183 gold badges26 silver badges53 bronze badges
asked Mar 25 at 13:31
Ethan BolkerEthan Bolker
6,7183 gold badges26 silver badges53 bronze badges
asked Mar 25 at 13:31
Ethan BolkerEthan Bolker
6,7183 gold badges26 silver badges53 bronze badges
asked Mar 25 at 13:31
Ethan BolkerEthan Bolker
6,7183 gold badges26 silver badges53 bronze badges
asked Mar 25 at 13:31
Ethan BolkerEthan Bolker
6,7183 gold badges26 silver badges53 bronze badges
6,7183 gold badges26 silver badges53 bronze badges
Off topic: You have a very nice reputation number :)
– user156344
Mar 25 at 13:35
@JouleV Indeed, It won't survive any votes on this question.
– Ethan Bolker
Mar 25 at 13:36
add a comment |
Off topic: You have a very nice reputation number :)
– user156344
Mar 25 at 13:35
@JouleV Indeed, It won't survive any votes on this question.
– Ethan Bolker
Mar 25 at 13:36
Off topic: You have a very nice reputation number :)
– user156344
Mar 25 at 13:35
Off topic: You have a very nice reputation number :)
– user156344
Mar 25 at 13:35
@JouleV Indeed, It won't survive any votes on this question.
– Ethan Bolker
Mar 25 at 13:36
@JouleV Indeed, It won't survive any votes on this question.
– Ethan Bolker
Mar 25 at 13:36
add a comment |
2 Answers
2
active
oldest
votes
We can use foreach:
documentclass[tikz]standalone
usetikzlibrarymatrix
begindocument
begintikzpicture
%draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
foreach i in -0.5,0,0.5,1
draw[gray] (-1,-i)--(1,-i);
draw[gray] (i,-1)--(i,1);
matrix[matrix of nodes,nodes=inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm]
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\;
endtikzpicture
enddocument
Honestly I don't think nodes or matrices have any thing to do here.
This approach is based on marmot's creative way, which is nicer and more tricky:
documentclass[tikz]standalone
usetikzlibrarymatrix
begindocument
begintikzpicture
draw[step=0.5cm,color=gray] (-1cm+0.2pt,-1) grid (1cm,1cm-0.2pt);
matrix[matrix of nodes,nodes=inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm]
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\;
endtikzpicture
enddocument
1
Thanks. There is a "matrix" in the code. Other answers to my original question used nodes.
– Ethan Bolker
Mar 25 at 13:46
@EthanBolker No problem. You are welcome ;)
– user156344
Mar 25 at 13:47
Maybe mention alsodraw[step=0.5cm,color=gray] (-0.99,-1) grid (1,0.99);which is shorter and gives (for all practical purposes) the same output.
– marmot
Mar 25 at 15:15
@marmot Ohh your way is wonderfully creative :)) I did not even think of that. However they are not mathematically correct.
– user156344
Mar 25 at 15:17
@JouleV What do you mean by "not mathematically correct"? It is as correct as a truncated grid can be.
– marmot
Mar 25 at 15:18
|
show 4 more comments
Another solution. It draws the grid with a matrix of drawn nodes. After that, left and top border are deleted with a white supperposed line.
documentclass[tikz,border=2mm]standalone
usetikzlibrarymatrix
begindocument
begintikzpicture
matrix[matrix of nodes,nodes=draw=gray, anchor=center, minimum size=.6cm, column sep=-pgflinewidth, row sep=-pgflinewidth] (A)
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\;
draw[white] ([xshift=.5pgflinewidth]A-4-1.south west)|-([yshift=-.5pgflinewidth]A-1-4.north east);
endtikzpicture
enddocument
answered Mar 25 at 16:03
IgnasiIgnasi
98k6 gold badges180 silver badges329 bronze badges
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
We can use foreach:
documentclass[tikz]standalone
usetikzlibrarymatrix
begindocument
begintikzpicture
%draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
foreach i in -0.5,0,0.5,1
draw[gray] (-1,-i)--(1,-i);
draw[gray] (i,-1)--(i,1);
matrix[matrix of nodes,nodes=inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm]
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\;
endtikzpicture
enddocument
Honestly I don't think nodes or matrices have any thing to do here.
This approach is based on marmot's creative way, which is nicer and more tricky:
documentclass[tikz]standalone
usetikzlibrarymatrix
begindocument
begintikzpicture
draw[step=0.5cm,color=gray] (-1cm+0.2pt,-1) grid (1cm,1cm-0.2pt);
matrix[matrix of nodes,nodes=inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm]
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\;
endtikzpicture
enddocument
1
Thanks. There is a "matrix" in the code. Other answers to my original question used nodes.
– Ethan Bolker
Mar 25 at 13:46
@EthanBolker No problem. You are welcome ;)
– user156344
Mar 25 at 13:47
Maybe mention alsodraw[step=0.5cm,color=gray] (-0.99,-1) grid (1,0.99);which is shorter and gives (for all practical purposes) the same output.
– marmot
Mar 25 at 15:15
@marmot Ohh your way is wonderfully creative :)) I did not even think of that. However they are not mathematically correct.
– user156344
Mar 25 at 15:17
@JouleV What do you mean by "not mathematically correct"? It is as correct as a truncated grid can be.
– marmot
Mar 25 at 15:18
|
show 4 more comments
We can use foreach:
documentclass[tikz]standalone
usetikzlibrarymatrix
begindocument
begintikzpicture
%draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
foreach i in -0.5,0,0.5,1
draw[gray] (-1,-i)--(1,-i);
draw[gray] (i,-1)--(i,1);
matrix[matrix of nodes,nodes=inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm]
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\;
endtikzpicture
enddocument
Honestly I don't think nodes or matrices have any thing to do here.
This approach is based on marmot's creative way, which is nicer and more tricky:
documentclass[tikz]standalone
usetikzlibrarymatrix
begindocument
begintikzpicture
draw[step=0.5cm,color=gray] (-1cm+0.2pt,-1) grid (1cm,1cm-0.2pt);
matrix[matrix of nodes,nodes=inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm]
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\;
endtikzpicture
enddocument
1
Thanks. There is a "matrix" in the code. Other answers to my original question used nodes.
– Ethan Bolker
Mar 25 at 13:46
@EthanBolker No problem. You are welcome ;)
– user156344
Mar 25 at 13:47
Maybe mention alsodraw[step=0.5cm,color=gray] (-0.99,-1) grid (1,0.99);which is shorter and gives (for all practical purposes) the same output.
– marmot
Mar 25 at 15:15
@marmot Ohh your way is wonderfully creative :)) I did not even think of that. However they are not mathematically correct.
– user156344
Mar 25 at 15:17
@JouleV What do you mean by "not mathematically correct"? It is as correct as a truncated grid can be.
– marmot
Mar 25 at 15:18
|
show 4 more comments
We can use foreach:
documentclass[tikz]standalone
usetikzlibrarymatrix
begindocument
begintikzpicture
%draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
foreach i in -0.5,0,0.5,1
draw[gray] (-1,-i)--(1,-i);
draw[gray] (i,-1)--(i,1);
matrix[matrix of nodes,nodes=inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm]
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\;
endtikzpicture
enddocument
Honestly I don't think nodes or matrices have any thing to do here.
This approach is based on marmot's creative way, which is nicer and more tricky:
documentclass[tikz]standalone
usetikzlibrarymatrix
begindocument
begintikzpicture
draw[step=0.5cm,color=gray] (-1cm+0.2pt,-1) grid (1cm,1cm-0.2pt);
matrix[matrix of nodes,nodes=inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm]
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\;
endtikzpicture
enddocument
We can use foreach:
documentclass[tikz]standalone
usetikzlibrarymatrix
begindocument
begintikzpicture
%draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
foreach i in -0.5,0,0.5,1
draw[gray] (-1,-i)--(1,-i);
draw[gray] (i,-1)--(i,1);
matrix[matrix of nodes,nodes=inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm]
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\;
endtikzpicture
enddocument
Honestly I don't think nodes or matrices have any thing to do here.
This approach is based on marmot's creative way, which is nicer and more tricky:
documentclass[tikz]standalone
usetikzlibrarymatrix
begindocument
begintikzpicture
draw[step=0.5cm,color=gray] (-1cm+0.2pt,-1) grid (1cm,1cm-0.2pt);
matrix[matrix of nodes,nodes=inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm]
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\;
endtikzpicture
enddocument
edited Mar 25 at 15:25
answered Mar 25 at 13:39
user156344
1
Thanks. There is a "matrix" in the code. Other answers to my original question used nodes.
– Ethan Bolker
Mar 25 at 13:46
@EthanBolker No problem. You are welcome ;)
– user156344
Mar 25 at 13:47
Maybe mention alsodraw[step=0.5cm,color=gray] (-0.99,-1) grid (1,0.99);which is shorter and gives (for all practical purposes) the same output.
– marmot
Mar 25 at 15:15
@marmot Ohh your way is wonderfully creative :)) I did not even think of that. However they are not mathematically correct.
– user156344
Mar 25 at 15:17
@JouleV What do you mean by "not mathematically correct"? It is as correct as a truncated grid can be.
– marmot
Mar 25 at 15:18
|
show 4 more comments
1
Thanks. There is a "matrix" in the code. Other answers to my original question used nodes.
– Ethan Bolker
Mar 25 at 13:46
@EthanBolker No problem. You are welcome ;)
– user156344
Mar 25 at 13:47
Maybe mention alsodraw[step=0.5cm,color=gray] (-0.99,-1) grid (1,0.99);which is shorter and gives (for all practical purposes) the same output.
– marmot
Mar 25 at 15:15
@marmot Ohh your way is wonderfully creative :)) I did not even think of that. However they are not mathematically correct.
– user156344
Mar 25 at 15:17
@JouleV What do you mean by "not mathematically correct"? It is as correct as a truncated grid can be.
– marmot
Mar 25 at 15:18
1
1
Thanks. There is a "matrix" in the code. Other answers to my original question used nodes.
– Ethan Bolker
Mar 25 at 13:46
Thanks. There is a "matrix" in the code. Other answers to my original question used nodes.
– Ethan Bolker
Mar 25 at 13:46
@EthanBolker No problem. You are welcome ;)
– user156344
Mar 25 at 13:47
@EthanBolker No problem. You are welcome ;)
– user156344
Mar 25 at 13:47
Maybe mention also
draw[step=0.5cm,color=gray] (-0.99,-1) grid (1,0.99); which is shorter and gives (for all practical purposes) the same output.– marmot
Mar 25 at 15:15
Maybe mention also
draw[step=0.5cm,color=gray] (-0.99,-1) grid (1,0.99); which is shorter and gives (for all practical purposes) the same output.– marmot
Mar 25 at 15:15
@marmot Ohh your way is wonderfully creative :)) I did not even think of that. However they are not mathematically correct.
– user156344
Mar 25 at 15:17
@marmot Ohh your way is wonderfully creative :)) I did not even think of that. However they are not mathematically correct.
– user156344
Mar 25 at 15:17
@JouleV What do you mean by "not mathematically correct"? It is as correct as a truncated grid can be.
– marmot
Mar 25 at 15:18
@JouleV What do you mean by "not mathematically correct"? It is as correct as a truncated grid can be.
– marmot
Mar 25 at 15:18
|
show 4 more comments
Another solution. It draws the grid with a matrix of drawn nodes. After that, left and top border are deleted with a white supperposed line.
documentclass[tikz,border=2mm]standalone
usetikzlibrarymatrix
begindocument
begintikzpicture
matrix[matrix of nodes,nodes=draw=gray, anchor=center, minimum size=.6cm, column sep=-pgflinewidth, row sep=-pgflinewidth] (A)
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\;
draw[white] ([xshift=.5pgflinewidth]A-4-1.south west)|-([yshift=-.5pgflinewidth]A-1-4.north east);
endtikzpicture
enddocument
answered Mar 25 at 16:03
IgnasiIgnasi
98k6 gold badges180 silver badges329 bronze badges
add a comment |
Another solution. It draws the grid with a matrix of drawn nodes. After that, left and top border are deleted with a white supperposed line.
documentclass[tikz,border=2mm]standalone
usetikzlibrarymatrix
begindocument
begintikzpicture
matrix[matrix of nodes,nodes=draw=gray, anchor=center, minimum size=.6cm, column sep=-pgflinewidth, row sep=-pgflinewidth] (A)
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\;
draw[white] ([xshift=.5pgflinewidth]A-4-1.south west)|-([yshift=-.5pgflinewidth]A-1-4.north east);
endtikzpicture
enddocument
answered Mar 25 at 16:03
IgnasiIgnasi
98k6 gold badges180 silver badges329 bronze badges
add a comment |
Another solution. It draws the grid with a matrix of drawn nodes. After that, left and top border are deleted with a white supperposed line.
documentclass[tikz,border=2mm]standalone
usetikzlibrarymatrix
begindocument
begintikzpicture
matrix[matrix of nodes,nodes=draw=gray, anchor=center, minimum size=.6cm, column sep=-pgflinewidth, row sep=-pgflinewidth] (A)
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\;
draw[white] ([xshift=.5pgflinewidth]A-4-1.south west)|-([yshift=-.5pgflinewidth]A-1-4.north east);
endtikzpicture
enddocument
answered Mar 25 at 16:03
IgnasiIgnasi
98k6 gold badges180 silver badges329 bronze badges
Another solution. It draws the grid with a matrix of drawn nodes. After that, left and top border are deleted with a white supperposed line.
documentclass[tikz,border=2mm]standalone
usetikzlibrarymatrix
begindocument
begintikzpicture
matrix[matrix of nodes,nodes=draw=gray, anchor=center, minimum size=.6cm, column sep=-pgflinewidth, row sep=-pgflinewidth] (A)
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\;
draw[white] ([xshift=.5pgflinewidth]A-4-1.south west)|-([yshift=-.5pgflinewidth]A-1-4.north east);
endtikzpicture
enddocument
answered Mar 25 at 16:03
IgnasiIgnasi
98k6 gold badges180 silver badges329 bronze badges
answered Mar 25 at 16:03
IgnasiIgnasi
98k6 gold badges180 silver badges329 bronze badges
answered Mar 25 at 16:03
IgnasiIgnasi
98k6 gold badges180 silver badges329 bronze badges
answered Mar 25 at 16:03
IgnasiIgnasi
98k6 gold badges180 silver badges329 bronze badges
98k6 gold badges180 silver badges329 bronze badges
add a comment |
add a comment |
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Off topic: You have a very nice reputation number :)
– user156344
Mar 25 at 13:35
@JouleV Indeed, It won't survive any votes on this question.
– Ethan Bolker
Mar 25 at 13:36