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fn:boolean What does it for?
How does one parse XML files?Simplest way to have a configuration file in a Windows Forms C# ApplicationWhat characters do I need to escape in XML documents?What does “xmlns” in XML mean?What does <![CDATA[]]> in XML mean?What does the 'standalone' directive mean in XML?Oracle 11g: Extracting and Counting XML elementsDocx or XPS(or ooxml in general) Relationship transform exampleIs it possible to use OR on a where clause in XQuery?Where to find where a function originates in eclipse, using XML? (MAC)
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
I have already read some articles but I am still confused about the "fn:boolean"in XQuery3.0...Is this a function to
This is where I look at:
http://www.xqueryfunctions.com/xq/fn_boolean.html
For instance:
If I put fn:boolean ((1,2) > (5000,6,1)), it is true.
If I put fn:boolean ((6,1) > (1,99,22)), it is true as well!
I am really confused about this function even though the article online stating that this function is rarely called but I still want to figure out what does it for...
xml xquery
asked Mar 26 at 12:35
PeterPeter
92 bronze badges
add a comment |
I have already read some articles but I am still confused about the "fn:boolean"in XQuery3.0...Is this a function to
This is where I look at:
http://www.xqueryfunctions.com/xq/fn_boolean.html
For instance:
If I put fn:boolean ((1,2) > (5000,6,1)), it is true.
If I put fn:boolean ((6,1) > (1,99,22)), it is true as well!
I am really confused about this function even though the article online stating that this function is rarely called but I still want to figure out what does it for...
xml xquery
asked Mar 26 at 12:35
PeterPeter
92 bronze badges
add a comment |
I have already read some articles but I am still confused about the "fn:boolean"in XQuery3.0...Is this a function to
This is where I look at:
http://www.xqueryfunctions.com/xq/fn_boolean.html
For instance:
If I put fn:boolean ((1,2) > (5000,6,1)), it is true.
If I put fn:boolean ((6,1) > (1,99,22)), it is true as well!
I am really confused about this function even though the article online stating that this function is rarely called but I still want to figure out what does it for...
xml xquery
asked Mar 26 at 12:35
PeterPeter
92 bronze badges
I have already read some articles but I am still confused about the "fn:boolean"in XQuery3.0...Is this a function to
This is where I look at:
http://www.xqueryfunctions.com/xq/fn_boolean.html
For instance:
If I put fn:boolean ((1,2) > (5000,6,1)), it is true.
If I put fn:boolean ((6,1) > (1,99,22)), it is true as well!
I am really confused about this function even though the article online stating that this function is rarely called but I still want to figure out what does it for...
xml xquery
xml xquery
asked Mar 26 at 12:35
PeterPeter
92 bronze badges
asked Mar 26 at 12:35
PeterPeter
92 bronze badges
asked Mar 26 at 12:35
PeterPeter
92 bronze badges
asked Mar 26 at 12:35
PeterPeter
92 bronze badges
asked Mar 26 at 12:35
PeterPeter
92 bronze badges
92 bronze badges
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
The function fn:boolean(X) returns the effective boolean value of X. For example, the effective boolean value of 1 is true, 0 is false, "true" is true, "" is false, "false" is (wait for it) true. The EBV of a node (or a non-empty node-sequence) is true, which is what makes expressions like X[following-sibling::X] work.
The effective boolean value of a boolean is the boolean unchanged: and that's the case with your example.
There are two cases where a call to fn:boolean is pointless:
where the argument to the function is already a boolean, as in your example
where the call appears in a context, such as the condition of an XPath 2.0 "if" expression, or a predicate in square brackets, or the
testattribute ofxsl:if, where there is in effect an implicit call onfn:boolean()already.
In other contexts, for example where you are supplying an argument to a function or binding the value of an XSLT or XQuery variable, calling fn:boolean explicitly can be useful to force the value to the right type. It can also help the reader of your code to understand that there is a type conversion happening.
answered Mar 26 at 15:02
Michael KayMichael Kay
115k6 gold badges64 silver badges122 bronze badges
add a comment |
Well, what do you think is the result of (6,1) > (1,99,22) in XQuery? That gives a boolean value already so maybe you should start figuring out to understand comparison of sequences first: https://www.w3.org/TR/xquery-31/#id-general-comparisons says "The result of the comparison is true if and only if there is a pair of atomic values, one in the first operand sequence and the other in the second operand sequence, that have the required magnitude relationship". So as 6 from the first sequence on the left is greater than 1 in the second sequence the comparison gives true.
Calling boolean then on that value does not change that as that function for boolean values does not give anything but the boolean value passed in.
answered Mar 26 at 12:45
Martin HonnenMartin Honnen
116k6 gold badges63 silver badges82 bronze badges
So how about the ((1,2) > (5000,6,1))? 1 is way smaller than 5000 and the "greater than"is not true at all...
– Peter
Mar 26 at 13:03
Edit: I think I figured it out and please correct me if my concept is wrong.. If any number of the left is greater than the right, it is "True"..So If I put ((2,3) > (90,99,100)) , the return is "False".
– Peter
Mar 26 at 13:11
Yes, you are right, "there is a pair of (..) values, one in the first operand sequence and the other in the second operand sequence, that have the required magnitude relationship" for your case with>could be expressed as "any number on the left is greater than the right" or perhaps as "there is at least one number on the left greater than at least one number on the right".
– Martin Honnen
Mar 26 at 14:49
add a comment |
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2 Answers
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active
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2 Answers
2
active
oldest
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active
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active
oldest
votes
The function fn:boolean(X) returns the effective boolean value of X. For example, the effective boolean value of 1 is true, 0 is false, "true" is true, "" is false, "false" is (wait for it) true. The EBV of a node (or a non-empty node-sequence) is true, which is what makes expressions like X[following-sibling::X] work.
The effective boolean value of a boolean is the boolean unchanged: and that's the case with your example.
There are two cases where a call to fn:boolean is pointless:
where the argument to the function is already a boolean, as in your example
where the call appears in a context, such as the condition of an XPath 2.0 "if" expression, or a predicate in square brackets, or the
testattribute ofxsl:if, where there is in effect an implicit call onfn:boolean()already.
In other contexts, for example where you are supplying an argument to a function or binding the value of an XSLT or XQuery variable, calling fn:boolean explicitly can be useful to force the value to the right type. It can also help the reader of your code to understand that there is a type conversion happening.
answered Mar 26 at 15:02
Michael KayMichael Kay
115k6 gold badges64 silver badges122 bronze badges
add a comment |
The function fn:boolean(X) returns the effective boolean value of X. For example, the effective boolean value of 1 is true, 0 is false, "true" is true, "" is false, "false" is (wait for it) true. The EBV of a node (or a non-empty node-sequence) is true, which is what makes expressions like X[following-sibling::X] work.
The effective boolean value of a boolean is the boolean unchanged: and that's the case with your example.
There are two cases where a call to fn:boolean is pointless:
where the argument to the function is already a boolean, as in your example
where the call appears in a context, such as the condition of an XPath 2.0 "if" expression, or a predicate in square brackets, or the
testattribute ofxsl:if, where there is in effect an implicit call onfn:boolean()already.
In other contexts, for example where you are supplying an argument to a function or binding the value of an XSLT or XQuery variable, calling fn:boolean explicitly can be useful to force the value to the right type. It can also help the reader of your code to understand that there is a type conversion happening.
answered Mar 26 at 15:02
Michael KayMichael Kay
115k6 gold badges64 silver badges122 bronze badges
add a comment |
The function fn:boolean(X) returns the effective boolean value of X. For example, the effective boolean value of 1 is true, 0 is false, "true" is true, "" is false, "false" is (wait for it) true. The EBV of a node (or a non-empty node-sequence) is true, which is what makes expressions like X[following-sibling::X] work.
The effective boolean value of a boolean is the boolean unchanged: and that's the case with your example.
There are two cases where a call to fn:boolean is pointless:
where the argument to the function is already a boolean, as in your example
where the call appears in a context, such as the condition of an XPath 2.0 "if" expression, or a predicate in square brackets, or the
testattribute ofxsl:if, where there is in effect an implicit call onfn:boolean()already.
In other contexts, for example where you are supplying an argument to a function or binding the value of an XSLT or XQuery variable, calling fn:boolean explicitly can be useful to force the value to the right type. It can also help the reader of your code to understand that there is a type conversion happening.
answered Mar 26 at 15:02
Michael KayMichael Kay
115k6 gold badges64 silver badges122 bronze badges
The function fn:boolean(X) returns the effective boolean value of X. For example, the effective boolean value of 1 is true, 0 is false, "true" is true, "" is false, "false" is (wait for it) true. The EBV of a node (or a non-empty node-sequence) is true, which is what makes expressions like X[following-sibling::X] work.
The effective boolean value of a boolean is the boolean unchanged: and that's the case with your example.
There are two cases where a call to fn:boolean is pointless:
where the argument to the function is already a boolean, as in your example
where the call appears in a context, such as the condition of an XPath 2.0 "if" expression, or a predicate in square brackets, or the
testattribute ofxsl:if, where there is in effect an implicit call onfn:boolean()already.
In other contexts, for example where you are supplying an argument to a function or binding the value of an XSLT or XQuery variable, calling fn:boolean explicitly can be useful to force the value to the right type. It can also help the reader of your code to understand that there is a type conversion happening.
answered Mar 26 at 15:02
Michael KayMichael Kay
115k6 gold badges64 silver badges122 bronze badges
answered Mar 26 at 15:02
Michael KayMichael Kay
115k6 gold badges64 silver badges122 bronze badges
answered Mar 26 at 15:02
Michael KayMichael Kay
115k6 gold badges64 silver badges122 bronze badges
answered Mar 26 at 15:02
Michael KayMichael Kay
115k6 gold badges64 silver badges122 bronze badges
115k6 gold badges64 silver badges122 bronze badges
add a comment |
add a comment |
Well, what do you think is the result of (6,1) > (1,99,22) in XQuery? That gives a boolean value already so maybe you should start figuring out to understand comparison of sequences first: https://www.w3.org/TR/xquery-31/#id-general-comparisons says "The result of the comparison is true if and only if there is a pair of atomic values, one in the first operand sequence and the other in the second operand sequence, that have the required magnitude relationship". So as 6 from the first sequence on the left is greater than 1 in the second sequence the comparison gives true.
Calling boolean then on that value does not change that as that function for boolean values does not give anything but the boolean value passed in.
answered Mar 26 at 12:45
Martin HonnenMartin Honnen
116k6 gold badges63 silver badges82 bronze badges
So how about the ((1,2) > (5000,6,1))? 1 is way smaller than 5000 and the "greater than"is not true at all...
– Peter
Mar 26 at 13:03
Edit: I think I figured it out and please correct me if my concept is wrong.. If any number of the left is greater than the right, it is "True"..So If I put ((2,3) > (90,99,100)) , the return is "False".
– Peter
Mar 26 at 13:11
Yes, you are right, "there is a pair of (..) values, one in the first operand sequence and the other in the second operand sequence, that have the required magnitude relationship" for your case with>could be expressed as "any number on the left is greater than the right" or perhaps as "there is at least one number on the left greater than at least one number on the right".
– Martin Honnen
Mar 26 at 14:49
add a comment |
Well, what do you think is the result of (6,1) > (1,99,22) in XQuery? That gives a boolean value already so maybe you should start figuring out to understand comparison of sequences first: https://www.w3.org/TR/xquery-31/#id-general-comparisons says "The result of the comparison is true if and only if there is a pair of atomic values, one in the first operand sequence and the other in the second operand sequence, that have the required magnitude relationship". So as 6 from the first sequence on the left is greater than 1 in the second sequence the comparison gives true.
Calling boolean then on that value does not change that as that function for boolean values does not give anything but the boolean value passed in.
answered Mar 26 at 12:45
Martin HonnenMartin Honnen
116k6 gold badges63 silver badges82 bronze badges
So how about the ((1,2) > (5000,6,1))? 1 is way smaller than 5000 and the "greater than"is not true at all...
– Peter
Mar 26 at 13:03
Edit: I think I figured it out and please correct me if my concept is wrong.. If any number of the left is greater than the right, it is "True"..So If I put ((2,3) > (90,99,100)) , the return is "False".
– Peter
Mar 26 at 13:11
Yes, you are right, "there is a pair of (..) values, one in the first operand sequence and the other in the second operand sequence, that have the required magnitude relationship" for your case with>could be expressed as "any number on the left is greater than the right" or perhaps as "there is at least one number on the left greater than at least one number on the right".
– Martin Honnen
Mar 26 at 14:49
add a comment |
Well, what do you think is the result of (6,1) > (1,99,22) in XQuery? That gives a boolean value already so maybe you should start figuring out to understand comparison of sequences first: https://www.w3.org/TR/xquery-31/#id-general-comparisons says "The result of the comparison is true if and only if there is a pair of atomic values, one in the first operand sequence and the other in the second operand sequence, that have the required magnitude relationship". So as 6 from the first sequence on the left is greater than 1 in the second sequence the comparison gives true.
Calling boolean then on that value does not change that as that function for boolean values does not give anything but the boolean value passed in.
answered Mar 26 at 12:45
Martin HonnenMartin Honnen
116k6 gold badges63 silver badges82 bronze badges
Well, what do you think is the result of (6,1) > (1,99,22) in XQuery? That gives a boolean value already so maybe you should start figuring out to understand comparison of sequences first: https://www.w3.org/TR/xquery-31/#id-general-comparisons says "The result of the comparison is true if and only if there is a pair of atomic values, one in the first operand sequence and the other in the second operand sequence, that have the required magnitude relationship". So as 6 from the first sequence on the left is greater than 1 in the second sequence the comparison gives true.
Calling boolean then on that value does not change that as that function for boolean values does not give anything but the boolean value passed in.
answered Mar 26 at 12:45
Martin HonnenMartin Honnen
116k6 gold badges63 silver badges82 bronze badges
answered Mar 26 at 12:45
Martin HonnenMartin Honnen
116k6 gold badges63 silver badges82 bronze badges
answered Mar 26 at 12:45
Martin HonnenMartin Honnen
116k6 gold badges63 silver badges82 bronze badges
answered Mar 26 at 12:45
Martin HonnenMartin Honnen
116k6 gold badges63 silver badges82 bronze badges
116k6 gold badges63 silver badges82 bronze badges
So how about the ((1,2) > (5000,6,1))? 1 is way smaller than 5000 and the "greater than"is not true at all...
– Peter
Mar 26 at 13:03
Edit: I think I figured it out and please correct me if my concept is wrong.. If any number of the left is greater than the right, it is "True"..So If I put ((2,3) > (90,99,100)) , the return is "False".
– Peter
Mar 26 at 13:11
Yes, you are right, "there is a pair of (..) values, one in the first operand sequence and the other in the second operand sequence, that have the required magnitude relationship" for your case with>could be expressed as "any number on the left is greater than the right" or perhaps as "there is at least one number on the left greater than at least one number on the right".
– Martin Honnen
Mar 26 at 14:49
add a comment |
So how about the ((1,2) > (5000,6,1))? 1 is way smaller than 5000 and the "greater than"is not true at all...
– Peter
Mar 26 at 13:03
Edit: I think I figured it out and please correct me if my concept is wrong.. If any number of the left is greater than the right, it is "True"..So If I put ((2,3) > (90,99,100)) , the return is "False".
– Peter
Mar 26 at 13:11
Yes, you are right, "there is a pair of (..) values, one in the first operand sequence and the other in the second operand sequence, that have the required magnitude relationship" for your case with>could be expressed as "any number on the left is greater than the right" or perhaps as "there is at least one number on the left greater than at least one number on the right".
– Martin Honnen
Mar 26 at 14:49
So how about the ((1,2) > (5000,6,1))? 1 is way smaller than 5000 and the "greater than"is not true at all...
– Peter
Mar 26 at 13:03
So how about the ((1,2) > (5000,6,1))? 1 is way smaller than 5000 and the "greater than"is not true at all...
– Peter
Mar 26 at 13:03
Edit: I think I figured it out and please correct me if my concept is wrong.. If any number of the left is greater than the right, it is "True"..So If I put ((2,3) > (90,99,100)) , the return is "False".
– Peter
Mar 26 at 13:11
Edit: I think I figured it out and please correct me if my concept is wrong.. If any number of the left is greater than the right, it is "True"..So If I put ((2,3) > (90,99,100)) , the return is "False".
– Peter
Mar 26 at 13:11
Yes, you are right, "there is a pair of (..) values, one in the first operand sequence and the other in the second operand sequence, that have the required magnitude relationship" for your case with
> could be expressed as "any number on the left is greater than the right" or perhaps as "there is at least one number on the left greater than at least one number on the right".– Martin Honnen
Mar 26 at 14:49
Yes, you are right, "there is a pair of (..) values, one in the first operand sequence and the other in the second operand sequence, that have the required magnitude relationship" for your case with
> could be expressed as "any number on the left is greater than the right" or perhaps as "there is at least one number on the left greater than at least one number on the right".– Martin Honnen
Mar 26 at 14:49
add a comment |
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