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getops $OPTARG is empty if flag value contains brackets


How to check if a string contains a substring in BashUsing getopts within user-defined-function in bourne shellCheck if a Bash array contains a valueHow to create a flag with getopts to run a commandgetopts: optional $OPT_ARGJMESPath query expression with bash variableHow to throw error to only use one option flag when using getopts in bash script?getopts - if a flag is empty getopts use the next flagbash getopts ignores options unless they are specified in a certain waybash echo environment variable containing escaped characters






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








1















When I pass a flag containing [...] to my bash script, getops gives me an empty string when I try to grab the value with $OPTARG.



shopt -s nullglob
while getopts ":f:" opt; do
case $opt in
f)
str=$OPTARG
;;
esac
done
echo $str


Running the script:



$ script.sh -f [0.0.0.0]
<blank line>


How can I get the original value back inside the script?










share|improve this question
























  • A bash script should start with #!/bin/bash - what happened when you add this line to your script?

    – Yaron
    Mar 26 at 12:45






  • 1





    note that when I execute the script I got the following output: [0.0.0.0]

    – Yaron
    Mar 26 at 12:46











  • I found the cause but don't know how to handle it. The script is much bigger, this is just small part. There was a shopt -s nullglob at the top. This breaks the script.

    – Gilrich
    Mar 26 at 13:02











  • Assumiong that shopt -s nullglob is needed - your can disable it when your run your small part of the code. what happened when you add shopt -u nullglob before your small part of the code, and shopt -s nullglob after your code?

    – Yaron
    Mar 26 at 13:15












  • I can put it after the flag switch-statement but not after the echo command. As soon as I put the shopt -s nullglob the variable evaluates to the empty string.

    – Gilrich
    Mar 26 at 13:33

















1















When I pass a flag containing [...] to my bash script, getops gives me an empty string when I try to grab the value with $OPTARG.



shopt -s nullglob
while getopts ":f:" opt; do
case $opt in
f)
str=$OPTARG
;;
esac
done
echo $str


Running the script:



$ script.sh -f [0.0.0.0]
<blank line>


How can I get the original value back inside the script?










share|improve this question
























  • A bash script should start with #!/bin/bash - what happened when you add this line to your script?

    – Yaron
    Mar 26 at 12:45






  • 1





    note that when I execute the script I got the following output: [0.0.0.0]

    – Yaron
    Mar 26 at 12:46











  • I found the cause but don't know how to handle it. The script is much bigger, this is just small part. There was a shopt -s nullglob at the top. This breaks the script.

    – Gilrich
    Mar 26 at 13:02











  • Assumiong that shopt -s nullglob is needed - your can disable it when your run your small part of the code. what happened when you add shopt -u nullglob before your small part of the code, and shopt -s nullglob after your code?

    – Yaron
    Mar 26 at 13:15












  • I can put it after the flag switch-statement but not after the echo command. As soon as I put the shopt -s nullglob the variable evaluates to the empty string.

    – Gilrich
    Mar 26 at 13:33













1












1








1


0






When I pass a flag containing [...] to my bash script, getops gives me an empty string when I try to grab the value with $OPTARG.



shopt -s nullglob
while getopts ":f:" opt; do
case $opt in
f)
str=$OPTARG
;;
esac
done
echo $str


Running the script:



$ script.sh -f [0.0.0.0]
<blank line>


How can I get the original value back inside the script?










share|improve this question
















When I pass a flag containing [...] to my bash script, getops gives me an empty string when I try to grab the value with $OPTARG.



shopt -s nullglob
while getopts ":f:" opt; do
case $opt in
f)
str=$OPTARG
;;
esac
done
echo $str


Running the script:



$ script.sh -f [0.0.0.0]
<blank line>


How can I get the original value back inside the script?







bash echo getopts






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 26 at 14:25









Yaron

6,2276 gold badges32 silver badges45 bronze badges




6,2276 gold badges32 silver badges45 bronze badges










asked Mar 26 at 12:37









GilrichGilrich

878 bronze badges




878 bronze badges












  • A bash script should start with #!/bin/bash - what happened when you add this line to your script?

    – Yaron
    Mar 26 at 12:45






  • 1





    note that when I execute the script I got the following output: [0.0.0.0]

    – Yaron
    Mar 26 at 12:46











  • I found the cause but don't know how to handle it. The script is much bigger, this is just small part. There was a shopt -s nullglob at the top. This breaks the script.

    – Gilrich
    Mar 26 at 13:02











  • Assumiong that shopt -s nullglob is needed - your can disable it when your run your small part of the code. what happened when you add shopt -u nullglob before your small part of the code, and shopt -s nullglob after your code?

    – Yaron
    Mar 26 at 13:15












  • I can put it after the flag switch-statement but not after the echo command. As soon as I put the shopt -s nullglob the variable evaluates to the empty string.

    – Gilrich
    Mar 26 at 13:33

















  • A bash script should start with #!/bin/bash - what happened when you add this line to your script?

    – Yaron
    Mar 26 at 12:45






  • 1





    note that when I execute the script I got the following output: [0.0.0.0]

    – Yaron
    Mar 26 at 12:46











  • I found the cause but don't know how to handle it. The script is much bigger, this is just small part. There was a shopt -s nullglob at the top. This breaks the script.

    – Gilrich
    Mar 26 at 13:02











  • Assumiong that shopt -s nullglob is needed - your can disable it when your run your small part of the code. what happened when you add shopt -u nullglob before your small part of the code, and shopt -s nullglob after your code?

    – Yaron
    Mar 26 at 13:15












  • I can put it after the flag switch-statement but not after the echo command. As soon as I put the shopt -s nullglob the variable evaluates to the empty string.

    – Gilrich
    Mar 26 at 13:33
















A bash script should start with #!/bin/bash - what happened when you add this line to your script?

– Yaron
Mar 26 at 12:45





A bash script should start with #!/bin/bash - what happened when you add this line to your script?

– Yaron
Mar 26 at 12:45




1




1





note that when I execute the script I got the following output: [0.0.0.0]

– Yaron
Mar 26 at 12:46





note that when I execute the script I got the following output: [0.0.0.0]

– Yaron
Mar 26 at 12:46













I found the cause but don't know how to handle it. The script is much bigger, this is just small part. There was a shopt -s nullglob at the top. This breaks the script.

– Gilrich
Mar 26 at 13:02





I found the cause but don't know how to handle it. The script is much bigger, this is just small part. There was a shopt -s nullglob at the top. This breaks the script.

– Gilrich
Mar 26 at 13:02













Assumiong that shopt -s nullglob is needed - your can disable it when your run your small part of the code. what happened when you add shopt -u nullglob before your small part of the code, and shopt -s nullglob after your code?

– Yaron
Mar 26 at 13:15






Assumiong that shopt -s nullglob is needed - your can disable it when your run your small part of the code. what happened when you add shopt -u nullglob before your small part of the code, and shopt -s nullglob after your code?

– Yaron
Mar 26 at 13:15














I can put it after the flag switch-statement but not after the echo command. As soon as I put the shopt -s nullglob the variable evaluates to the empty string.

– Gilrich
Mar 26 at 13:33





I can put it after the flag switch-statement but not after the echo command. As soon as I put the shopt -s nullglob the variable evaluates to the empty string.

– Gilrich
Mar 26 at 13:33












2 Answers
2






active

oldest

votes


















1














Short summary: Double-quote your variable references. And use shellcheck.net.



Long explanation: When you use a variable without double-quotes around it (e.g. echo $str), the shell tries to split its value into words, and expand anything that looks like a wildcard expression into a list of matching files. In the case of [0.0.0.0], the brackets make it a wildcard expression that'll match either the character "0" or "." (equivalent to [0.]). If you had a file named "0", it would expand to that string. With no matching file(s), it's normally left unexpanded, but with the nullglob set it expands to ... null.



Turning off nullglob solves the problem if there are no matching files, but isn't really the right way do it. I remember (but can't find right now) a question we had about a script that failed on one particular computer, and it turned out the reason was that one computer happened to have a file that matched a bracket expression in an unquoted variable's value.



The right solution is to put double-quotes around the variable reference. This tells the shell to skip word splitting and wildcard expansion. Here's an interactive example:



$ str='[0.0.0.0]' # Quotes aren't actually needed here, but they don't hurt
$ echo $str # This works without nullglob or a matching file
[0.0.0.0]
$ shopt -s nullglob
$ echo $str # This fails because of nullglob

$ shopt -u nullglob
$ touch 0
$ echo $str # This fails because of a matching file
0
$ echo "$str" # This just works, no matter whether file(s) match and/or nullglob is set
[0.0.0.0]


So in your script, simply change the last line to:



echo "$str"


Note that double-quotes are not required in either case $opt in or str=$OPTARG because variables in those specific contexts aren't subject to word splitting or wildcard expansion. But IMO keeping track of which contexts it's safe to leave the double-quotes off is more hassle than it's worth, and you should just double-quote 'em all.



BTW, shellcheck.net is good at spotting common mistakes like this; I recommend feeding your scripts through it, since this is probably not the only place you have this problem.






share|improve this answer

























  • Great, in-depth answer! However, your proposed solution looks exactly like the line I already have. (see last line of my code block)

    – Gilrich
    Mar 26 at 16:32











  • @Gilrich D'Oh! After copying the original line, I just clean forgot to actually apply the fix. I've edited it to correct...

    – Gordon Davisson
    Mar 26 at 16:40


















1














Assuming that shopt -s nullglob is needed in the bigger script.

You can temporary disable shopt -s nullglob using shopt -u nullglob



shopt -s nullglob
shopt -u nullglob
while getopts ":f:" opt; do
case $opt in
f)
str=$OPTARG
;;
esac
done
echo $str

shopt -s nullglob





share|improve this answer

























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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    Short summary: Double-quote your variable references. And use shellcheck.net.



    Long explanation: When you use a variable without double-quotes around it (e.g. echo $str), the shell tries to split its value into words, and expand anything that looks like a wildcard expression into a list of matching files. In the case of [0.0.0.0], the brackets make it a wildcard expression that'll match either the character "0" or "." (equivalent to [0.]). If you had a file named "0", it would expand to that string. With no matching file(s), it's normally left unexpanded, but with the nullglob set it expands to ... null.



    Turning off nullglob solves the problem if there are no matching files, but isn't really the right way do it. I remember (but can't find right now) a question we had about a script that failed on one particular computer, and it turned out the reason was that one computer happened to have a file that matched a bracket expression in an unquoted variable's value.



    The right solution is to put double-quotes around the variable reference. This tells the shell to skip word splitting and wildcard expansion. Here's an interactive example:



    $ str='[0.0.0.0]' # Quotes aren't actually needed here, but they don't hurt
    $ echo $str # This works without nullglob or a matching file
    [0.0.0.0]
    $ shopt -s nullglob
    $ echo $str # This fails because of nullglob

    $ shopt -u nullglob
    $ touch 0
    $ echo $str # This fails because of a matching file
    0
    $ echo "$str" # This just works, no matter whether file(s) match and/or nullglob is set
    [0.0.0.0]


    So in your script, simply change the last line to:



    echo "$str"


    Note that double-quotes are not required in either case $opt in or str=$OPTARG because variables in those specific contexts aren't subject to word splitting or wildcard expansion. But IMO keeping track of which contexts it's safe to leave the double-quotes off is more hassle than it's worth, and you should just double-quote 'em all.



    BTW, shellcheck.net is good at spotting common mistakes like this; I recommend feeding your scripts through it, since this is probably not the only place you have this problem.






    share|improve this answer

























    • Great, in-depth answer! However, your proposed solution looks exactly like the line I already have. (see last line of my code block)

      – Gilrich
      Mar 26 at 16:32











    • @Gilrich D'Oh! After copying the original line, I just clean forgot to actually apply the fix. I've edited it to correct...

      – Gordon Davisson
      Mar 26 at 16:40















    1














    Short summary: Double-quote your variable references. And use shellcheck.net.



    Long explanation: When you use a variable without double-quotes around it (e.g. echo $str), the shell tries to split its value into words, and expand anything that looks like a wildcard expression into a list of matching files. In the case of [0.0.0.0], the brackets make it a wildcard expression that'll match either the character "0" or "." (equivalent to [0.]). If you had a file named "0", it would expand to that string. With no matching file(s), it's normally left unexpanded, but with the nullglob set it expands to ... null.



    Turning off nullglob solves the problem if there are no matching files, but isn't really the right way do it. I remember (but can't find right now) a question we had about a script that failed on one particular computer, and it turned out the reason was that one computer happened to have a file that matched a bracket expression in an unquoted variable's value.



    The right solution is to put double-quotes around the variable reference. This tells the shell to skip word splitting and wildcard expansion. Here's an interactive example:



    $ str='[0.0.0.0]' # Quotes aren't actually needed here, but they don't hurt
    $ echo $str # This works without nullglob or a matching file
    [0.0.0.0]
    $ shopt -s nullglob
    $ echo $str # This fails because of nullglob

    $ shopt -u nullglob
    $ touch 0
    $ echo $str # This fails because of a matching file
    0
    $ echo "$str" # This just works, no matter whether file(s) match and/or nullglob is set
    [0.0.0.0]


    So in your script, simply change the last line to:



    echo "$str"


    Note that double-quotes are not required in either case $opt in or str=$OPTARG because variables in those specific contexts aren't subject to word splitting or wildcard expansion. But IMO keeping track of which contexts it's safe to leave the double-quotes off is more hassle than it's worth, and you should just double-quote 'em all.



    BTW, shellcheck.net is good at spotting common mistakes like this; I recommend feeding your scripts through it, since this is probably not the only place you have this problem.






    share|improve this answer

























    • Great, in-depth answer! However, your proposed solution looks exactly like the line I already have. (see last line of my code block)

      – Gilrich
      Mar 26 at 16:32











    • @Gilrich D'Oh! After copying the original line, I just clean forgot to actually apply the fix. I've edited it to correct...

      – Gordon Davisson
      Mar 26 at 16:40













    1












    1








    1







    Short summary: Double-quote your variable references. And use shellcheck.net.



    Long explanation: When you use a variable without double-quotes around it (e.g. echo $str), the shell tries to split its value into words, and expand anything that looks like a wildcard expression into a list of matching files. In the case of [0.0.0.0], the brackets make it a wildcard expression that'll match either the character "0" or "." (equivalent to [0.]). If you had a file named "0", it would expand to that string. With no matching file(s), it's normally left unexpanded, but with the nullglob set it expands to ... null.



    Turning off nullglob solves the problem if there are no matching files, but isn't really the right way do it. I remember (but can't find right now) a question we had about a script that failed on one particular computer, and it turned out the reason was that one computer happened to have a file that matched a bracket expression in an unquoted variable's value.



    The right solution is to put double-quotes around the variable reference. This tells the shell to skip word splitting and wildcard expansion. Here's an interactive example:



    $ str='[0.0.0.0]' # Quotes aren't actually needed here, but they don't hurt
    $ echo $str # This works without nullglob or a matching file
    [0.0.0.0]
    $ shopt -s nullglob
    $ echo $str # This fails because of nullglob

    $ shopt -u nullglob
    $ touch 0
    $ echo $str # This fails because of a matching file
    0
    $ echo "$str" # This just works, no matter whether file(s) match and/or nullglob is set
    [0.0.0.0]


    So in your script, simply change the last line to:



    echo "$str"


    Note that double-quotes are not required in either case $opt in or str=$OPTARG because variables in those specific contexts aren't subject to word splitting or wildcard expansion. But IMO keeping track of which contexts it's safe to leave the double-quotes off is more hassle than it's worth, and you should just double-quote 'em all.



    BTW, shellcheck.net is good at spotting common mistakes like this; I recommend feeding your scripts through it, since this is probably not the only place you have this problem.






    share|improve this answer















    Short summary: Double-quote your variable references. And use shellcheck.net.



    Long explanation: When you use a variable without double-quotes around it (e.g. echo $str), the shell tries to split its value into words, and expand anything that looks like a wildcard expression into a list of matching files. In the case of [0.0.0.0], the brackets make it a wildcard expression that'll match either the character "0" or "." (equivalent to [0.]). If you had a file named "0", it would expand to that string. With no matching file(s), it's normally left unexpanded, but with the nullglob set it expands to ... null.



    Turning off nullglob solves the problem if there are no matching files, but isn't really the right way do it. I remember (but can't find right now) a question we had about a script that failed on one particular computer, and it turned out the reason was that one computer happened to have a file that matched a bracket expression in an unquoted variable's value.



    The right solution is to put double-quotes around the variable reference. This tells the shell to skip word splitting and wildcard expansion. Here's an interactive example:



    $ str='[0.0.0.0]' # Quotes aren't actually needed here, but they don't hurt
    $ echo $str # This works without nullglob or a matching file
    [0.0.0.0]
    $ shopt -s nullglob
    $ echo $str # This fails because of nullglob

    $ shopt -u nullglob
    $ touch 0
    $ echo $str # This fails because of a matching file
    0
    $ echo "$str" # This just works, no matter whether file(s) match and/or nullglob is set
    [0.0.0.0]


    So in your script, simply change the last line to:



    echo "$str"


    Note that double-quotes are not required in either case $opt in or str=$OPTARG because variables in those specific contexts aren't subject to word splitting or wildcard expansion. But IMO keeping track of which contexts it's safe to leave the double-quotes off is more hassle than it's worth, and you should just double-quote 'em all.



    BTW, shellcheck.net is good at spotting common mistakes like this; I recommend feeding your scripts through it, since this is probably not the only place you have this problem.







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Mar 26 at 16:39

























    answered Mar 26 at 15:54









    Gordon DavissonGordon Davisson

    74.9k11 gold badges80 silver badges98 bronze badges




    74.9k11 gold badges80 silver badges98 bronze badges












    • Great, in-depth answer! However, your proposed solution looks exactly like the line I already have. (see last line of my code block)

      – Gilrich
      Mar 26 at 16:32











    • @Gilrich D'Oh! After copying the original line, I just clean forgot to actually apply the fix. I've edited it to correct...

      – Gordon Davisson
      Mar 26 at 16:40

















    • Great, in-depth answer! However, your proposed solution looks exactly like the line I already have. (see last line of my code block)

      – Gilrich
      Mar 26 at 16:32











    • @Gilrich D'Oh! After copying the original line, I just clean forgot to actually apply the fix. I've edited it to correct...

      – Gordon Davisson
      Mar 26 at 16:40
















    Great, in-depth answer! However, your proposed solution looks exactly like the line I already have. (see last line of my code block)

    – Gilrich
    Mar 26 at 16:32





    Great, in-depth answer! However, your proposed solution looks exactly like the line I already have. (see last line of my code block)

    – Gilrich
    Mar 26 at 16:32













    @Gilrich D'Oh! After copying the original line, I just clean forgot to actually apply the fix. I've edited it to correct...

    – Gordon Davisson
    Mar 26 at 16:40





    @Gilrich D'Oh! After copying the original line, I just clean forgot to actually apply the fix. I've edited it to correct...

    – Gordon Davisson
    Mar 26 at 16:40













    1














    Assuming that shopt -s nullglob is needed in the bigger script.

    You can temporary disable shopt -s nullglob using shopt -u nullglob



    shopt -s nullglob
    shopt -u nullglob
    while getopts ":f:" opt; do
    case $opt in
    f)
    str=$OPTARG
    ;;
    esac
    done
    echo $str

    shopt -s nullglob





    share|improve this answer



























      1














      Assuming that shopt -s nullglob is needed in the bigger script.

      You can temporary disable shopt -s nullglob using shopt -u nullglob



      shopt -s nullglob
      shopt -u nullglob
      while getopts ":f:" opt; do
      case $opt in
      f)
      str=$OPTARG
      ;;
      esac
      done
      echo $str

      shopt -s nullglob





      share|improve this answer

























        1












        1








        1







        Assuming that shopt -s nullglob is needed in the bigger script.

        You can temporary disable shopt -s nullglob using shopt -u nullglob



        shopt -s nullglob
        shopt -u nullglob
        while getopts ":f:" opt; do
        case $opt in
        f)
        str=$OPTARG
        ;;
        esac
        done
        echo $str

        shopt -s nullglob





        share|improve this answer













        Assuming that shopt -s nullglob is needed in the bigger script.

        You can temporary disable shopt -s nullglob using shopt -u nullglob



        shopt -s nullglob
        shopt -u nullglob
        while getopts ":f:" opt; do
        case $opt in
        f)
        str=$OPTARG
        ;;
        esac
        done
        echo $str

        shopt -s nullglob






        share|improve this answer












        share|improve this answer



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        answered Mar 26 at 13:18









        YaronYaron

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