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How to split multiple file name and get last name in output


How do you split a list into evenly sized chunks?How do I split a string with multiple separators in javascript?How to split a string into a list?How do I split a string on a delimiter in Bash?Split Strings into words with multiple word boundary delimitersHow to split a string in shell and get the last fieldSplit string with multiple delimiters in PythonUbuntu bash script: how to split path by last slash?splitting name into first, middle, lastSplit string and get last element






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








-3















I have to split the path names I get from another function. I don't want to use any module. My current code is



my $val ="@missing";
foreach($val)
my f= split '/', $val;
say ($f[1]);



Output



xyz/c.html xyz/i/x.gif


I want only the file name like this.



c.html
x.gif









share|improve this question
























  • perldoc File::Basename

    – toolic
    Mar 26 at 12:21











  • @toolic I want the output without lib using.

    – Jack
    Mar 26 at 12:23






  • 1





    File::Basename is a core module. No need to reinvent the wheel.

    – dgw
    Mar 26 at 12:28











  • @dgw How can i used that one?

    – Jack
    Mar 26 at 12:29












  • Why don't you want to use any module? Is it because you can't install any? Because you don't want too many dependencies? Because this is homework and that's a requirement?

    – Dada
    Mar 26 at 12:40

















-3















I have to split the path names I get from another function. I don't want to use any module. My current code is



my $val ="@missing";
foreach($val)
my f= split '/', $val;
say ($f[1]);



Output



xyz/c.html xyz/i/x.gif


I want only the file name like this.



c.html
x.gif









share|improve this question
























  • perldoc File::Basename

    – toolic
    Mar 26 at 12:21











  • @toolic I want the output without lib using.

    – Jack
    Mar 26 at 12:23






  • 1





    File::Basename is a core module. No need to reinvent the wheel.

    – dgw
    Mar 26 at 12:28











  • @dgw How can i used that one?

    – Jack
    Mar 26 at 12:29












  • Why don't you want to use any module? Is it because you can't install any? Because you don't want too many dependencies? Because this is homework and that's a requirement?

    – Dada
    Mar 26 at 12:40













-3












-3








-3








I have to split the path names I get from another function. I don't want to use any module. My current code is



my $val ="@missing";
foreach($val)
my f= split '/', $val;
say ($f[1]);



Output



xyz/c.html xyz/i/x.gif


I want only the file name like this.



c.html
x.gif









share|improve this question
















I have to split the path names I get from another function. I don't want to use any module. My current code is



my $val ="@missing";
foreach($val)
my f= split '/', $val;
say ($f[1]);



Output



xyz/c.html xyz/i/x.gif


I want only the file name like this.



c.html
x.gif






perl split






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 26 at 12:58







Jack

















asked Mar 26 at 12:20









JackJack

16 bronze badges




16 bronze badges












  • perldoc File::Basename

    – toolic
    Mar 26 at 12:21











  • @toolic I want the output without lib using.

    – Jack
    Mar 26 at 12:23






  • 1





    File::Basename is a core module. No need to reinvent the wheel.

    – dgw
    Mar 26 at 12:28











  • @dgw How can i used that one?

    – Jack
    Mar 26 at 12:29












  • Why don't you want to use any module? Is it because you can't install any? Because you don't want too many dependencies? Because this is homework and that's a requirement?

    – Dada
    Mar 26 at 12:40

















  • perldoc File::Basename

    – toolic
    Mar 26 at 12:21











  • @toolic I want the output without lib using.

    – Jack
    Mar 26 at 12:23






  • 1





    File::Basename is a core module. No need to reinvent the wheel.

    – dgw
    Mar 26 at 12:28











  • @dgw How can i used that one?

    – Jack
    Mar 26 at 12:29












  • Why don't you want to use any module? Is it because you can't install any? Because you don't want too many dependencies? Because this is homework and that's a requirement?

    – Dada
    Mar 26 at 12:40
















perldoc File::Basename

– toolic
Mar 26 at 12:21





perldoc File::Basename

– toolic
Mar 26 at 12:21













@toolic I want the output without lib using.

– Jack
Mar 26 at 12:23





@toolic I want the output without lib using.

– Jack
Mar 26 at 12:23




1




1





File::Basename is a core module. No need to reinvent the wheel.

– dgw
Mar 26 at 12:28





File::Basename is a core module. No need to reinvent the wheel.

– dgw
Mar 26 at 12:28













@dgw How can i used that one?

– Jack
Mar 26 at 12:29






@dgw How can i used that one?

– Jack
Mar 26 at 12:29














Why don't you want to use any module? Is it because you can't install any? Because you don't want too many dependencies? Because this is homework and that's a requirement?

– Dada
Mar 26 at 12:40





Why don't you want to use any module? Is it because you can't install any? Because you don't want too many dependencies? Because this is homework and that's a requirement?

– Dada
Mar 26 at 12:40












1 Answer
1






active

oldest

votes


















2














You could substitute everything up to the last slash (/). But that approach is non-portable. Perl core comes with File::Spec which allows you to write portable code:



#!/usr/bin/perl
use warnings;
use strict;

my @paths = (
"xyz/c.html",
"xyz/i/x.gif",
);

# Non-portable code using regex
foreach my $path (@paths)
(my $basename = $path) =~ s,.*/,,;
print "$path -> $basenamen";


# Portable implementation using Perl core modules
use File::Spec;

foreach my $path (@paths)
my(undef, undef, $basename) = File::Spec->splitpath($path);
print "$path -> $basenamen";


exit 0;


Test run:



$ perl dummy.pl
xyz/c.html -> c.html
xyz/i/x.gif -> x.gif
xyz/c.html -> c.html
xyz/i/x.gif -> x.gif





share|improve this answer






















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    oldest

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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    2














    You could substitute everything up to the last slash (/). But that approach is non-portable. Perl core comes with File::Spec which allows you to write portable code:



    #!/usr/bin/perl
    use warnings;
    use strict;

    my @paths = (
    "xyz/c.html",
    "xyz/i/x.gif",
    );

    # Non-portable code using regex
    foreach my $path (@paths)
    (my $basename = $path) =~ s,.*/,,;
    print "$path -> $basenamen";


    # Portable implementation using Perl core modules
    use File::Spec;

    foreach my $path (@paths)
    my(undef, undef, $basename) = File::Spec->splitpath($path);
    print "$path -> $basenamen";


    exit 0;


    Test run:



    $ perl dummy.pl
    xyz/c.html -> c.html
    xyz/i/x.gif -> x.gif
    xyz/c.html -> c.html
    xyz/i/x.gif -> x.gif





    share|improve this answer



























      2














      You could substitute everything up to the last slash (/). But that approach is non-portable. Perl core comes with File::Spec which allows you to write portable code:



      #!/usr/bin/perl
      use warnings;
      use strict;

      my @paths = (
      "xyz/c.html",
      "xyz/i/x.gif",
      );

      # Non-portable code using regex
      foreach my $path (@paths)
      (my $basename = $path) =~ s,.*/,,;
      print "$path -> $basenamen";


      # Portable implementation using Perl core modules
      use File::Spec;

      foreach my $path (@paths)
      my(undef, undef, $basename) = File::Spec->splitpath($path);
      print "$path -> $basenamen";


      exit 0;


      Test run:



      $ perl dummy.pl
      xyz/c.html -> c.html
      xyz/i/x.gif -> x.gif
      xyz/c.html -> c.html
      xyz/i/x.gif -> x.gif





      share|improve this answer

























        2












        2








        2







        You could substitute everything up to the last slash (/). But that approach is non-portable. Perl core comes with File::Spec which allows you to write portable code:



        #!/usr/bin/perl
        use warnings;
        use strict;

        my @paths = (
        "xyz/c.html",
        "xyz/i/x.gif",
        );

        # Non-portable code using regex
        foreach my $path (@paths)
        (my $basename = $path) =~ s,.*/,,;
        print "$path -> $basenamen";


        # Portable implementation using Perl core modules
        use File::Spec;

        foreach my $path (@paths)
        my(undef, undef, $basename) = File::Spec->splitpath($path);
        print "$path -> $basenamen";


        exit 0;


        Test run:



        $ perl dummy.pl
        xyz/c.html -> c.html
        xyz/i/x.gif -> x.gif
        xyz/c.html -> c.html
        xyz/i/x.gif -> x.gif





        share|improve this answer













        You could substitute everything up to the last slash (/). But that approach is non-portable. Perl core comes with File::Spec which allows you to write portable code:



        #!/usr/bin/perl
        use warnings;
        use strict;

        my @paths = (
        "xyz/c.html",
        "xyz/i/x.gif",
        );

        # Non-portable code using regex
        foreach my $path (@paths)
        (my $basename = $path) =~ s,.*/,,;
        print "$path -> $basenamen";


        # Portable implementation using Perl core modules
        use File::Spec;

        foreach my $path (@paths)
        my(undef, undef, $basename) = File::Spec->splitpath($path);
        print "$path -> $basenamen";


        exit 0;


        Test run:



        $ perl dummy.pl
        xyz/c.html -> c.html
        xyz/i/x.gif -> x.gif
        xyz/c.html -> c.html
        xyz/i/x.gif -> x.gif






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Mar 26 at 12:36









        Stefan BeckerStefan Becker

        4,5813 gold badges11 silver badges25 bronze badges




        4,5813 gold badges11 silver badges25 bronze badges
















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