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How to split multiple file name and get last name in output
How do you split a list into evenly sized chunks?How do I split a string with multiple separators in javascript?How to split a string into a list?How do I split a string on a delimiter in Bash?Split Strings into words with multiple word boundary delimitersHow to split a string in shell and get the last fieldSplit string with multiple delimiters in PythonUbuntu bash script: how to split path by last slash?splitting name into first, middle, lastSplit string and get last element
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
I have to split the path names I get from another function. I don't want to use any module. My current code is
my $val ="@missing";
foreach($val)
my f= split '/', $val;
say ($f[1]);
Output
xyz/c.html xyz/i/x.gif
I want only the file name like this.
c.html
x.gif
perl split
|
show 2 more comments
I have to split the path names I get from another function. I don't want to use any module. My current code is
my $val ="@missing";
foreach($val)
my f= split '/', $val;
say ($f[1]);
Output
xyz/c.html xyz/i/x.gif
I want only the file name like this.
c.html
x.gif
perl split
perldoc File::Basename
– toolic
Mar 26 at 12:21
@toolic I want the output without lib using.
– Jack
Mar 26 at 12:23
1
File::Basename
is a core module. No need to reinvent the wheel.
– dgw
Mar 26 at 12:28
@dgw How can i used that one?
– Jack
Mar 26 at 12:29
Why don't you want to use any module? Is it because you can't install any? Because you don't want too many dependencies? Because this is homework and that's a requirement?
– Dada
Mar 26 at 12:40
|
show 2 more comments
I have to split the path names I get from another function. I don't want to use any module. My current code is
my $val ="@missing";
foreach($val)
my f= split '/', $val;
say ($f[1]);
Output
xyz/c.html xyz/i/x.gif
I want only the file name like this.
c.html
x.gif
perl split
I have to split the path names I get from another function. I don't want to use any module. My current code is
my $val ="@missing";
foreach($val)
my f= split '/', $val;
say ($f[1]);
Output
xyz/c.html xyz/i/x.gif
I want only the file name like this.
c.html
x.gif
perl split
perl split
edited Mar 26 at 12:58
Jack
asked Mar 26 at 12:20
JackJack
16 bronze badges
16 bronze badges
perldoc File::Basename
– toolic
Mar 26 at 12:21
@toolic I want the output without lib using.
– Jack
Mar 26 at 12:23
1
File::Basename
is a core module. No need to reinvent the wheel.
– dgw
Mar 26 at 12:28
@dgw How can i used that one?
– Jack
Mar 26 at 12:29
Why don't you want to use any module? Is it because you can't install any? Because you don't want too many dependencies? Because this is homework and that's a requirement?
– Dada
Mar 26 at 12:40
|
show 2 more comments
perldoc File::Basename
– toolic
Mar 26 at 12:21
@toolic I want the output without lib using.
– Jack
Mar 26 at 12:23
1
File::Basename
is a core module. No need to reinvent the wheel.
– dgw
Mar 26 at 12:28
@dgw How can i used that one?
– Jack
Mar 26 at 12:29
Why don't you want to use any module? Is it because you can't install any? Because you don't want too many dependencies? Because this is homework and that's a requirement?
– Dada
Mar 26 at 12:40
perldoc File::Basename
– toolic
Mar 26 at 12:21
perldoc File::Basename
– toolic
Mar 26 at 12:21
@toolic I want the output without lib using.
– Jack
Mar 26 at 12:23
@toolic I want the output without lib using.
– Jack
Mar 26 at 12:23
1
1
File::Basename
is a core module. No need to reinvent the wheel.– dgw
Mar 26 at 12:28
File::Basename
is a core module. No need to reinvent the wheel.– dgw
Mar 26 at 12:28
@dgw How can i used that one?
– Jack
Mar 26 at 12:29
@dgw How can i used that one?
– Jack
Mar 26 at 12:29
Why don't you want to use any module? Is it because you can't install any? Because you don't want too many dependencies? Because this is homework and that's a requirement?
– Dada
Mar 26 at 12:40
Why don't you want to use any module? Is it because you can't install any? Because you don't want too many dependencies? Because this is homework and that's a requirement?
– Dada
Mar 26 at 12:40
|
show 2 more comments
1 Answer
1
active
oldest
votes
You could substitute everything up to the last slash (/
). But that approach is non-portable. Perl core comes with File::Spec which allows you to write portable code:
#!/usr/bin/perl
use warnings;
use strict;
my @paths = (
"xyz/c.html",
"xyz/i/x.gif",
);
# Non-portable code using regex
foreach my $path (@paths)
(my $basename = $path) =~ s,.*/,,;
print "$path -> $basenamen";
# Portable implementation using Perl core modules
use File::Spec;
foreach my $path (@paths)
my(undef, undef, $basename) = File::Spec->splitpath($path);
print "$path -> $basenamen";
exit 0;
Test run:
$ perl dummy.pl
xyz/c.html -> c.html
xyz/i/x.gif -> x.gif
xyz/c.html -> c.html
xyz/i/x.gif -> x.gif
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You could substitute everything up to the last slash (/
). But that approach is non-portable. Perl core comes with File::Spec which allows you to write portable code:
#!/usr/bin/perl
use warnings;
use strict;
my @paths = (
"xyz/c.html",
"xyz/i/x.gif",
);
# Non-portable code using regex
foreach my $path (@paths)
(my $basename = $path) =~ s,.*/,,;
print "$path -> $basenamen";
# Portable implementation using Perl core modules
use File::Spec;
foreach my $path (@paths)
my(undef, undef, $basename) = File::Spec->splitpath($path);
print "$path -> $basenamen";
exit 0;
Test run:
$ perl dummy.pl
xyz/c.html -> c.html
xyz/i/x.gif -> x.gif
xyz/c.html -> c.html
xyz/i/x.gif -> x.gif
add a comment |
You could substitute everything up to the last slash (/
). But that approach is non-portable. Perl core comes with File::Spec which allows you to write portable code:
#!/usr/bin/perl
use warnings;
use strict;
my @paths = (
"xyz/c.html",
"xyz/i/x.gif",
);
# Non-portable code using regex
foreach my $path (@paths)
(my $basename = $path) =~ s,.*/,,;
print "$path -> $basenamen";
# Portable implementation using Perl core modules
use File::Spec;
foreach my $path (@paths)
my(undef, undef, $basename) = File::Spec->splitpath($path);
print "$path -> $basenamen";
exit 0;
Test run:
$ perl dummy.pl
xyz/c.html -> c.html
xyz/i/x.gif -> x.gif
xyz/c.html -> c.html
xyz/i/x.gif -> x.gif
add a comment |
You could substitute everything up to the last slash (/
). But that approach is non-portable. Perl core comes with File::Spec which allows you to write portable code:
#!/usr/bin/perl
use warnings;
use strict;
my @paths = (
"xyz/c.html",
"xyz/i/x.gif",
);
# Non-portable code using regex
foreach my $path (@paths)
(my $basename = $path) =~ s,.*/,,;
print "$path -> $basenamen";
# Portable implementation using Perl core modules
use File::Spec;
foreach my $path (@paths)
my(undef, undef, $basename) = File::Spec->splitpath($path);
print "$path -> $basenamen";
exit 0;
Test run:
$ perl dummy.pl
xyz/c.html -> c.html
xyz/i/x.gif -> x.gif
xyz/c.html -> c.html
xyz/i/x.gif -> x.gif
You could substitute everything up to the last slash (/
). But that approach is non-portable. Perl core comes with File::Spec which allows you to write portable code:
#!/usr/bin/perl
use warnings;
use strict;
my @paths = (
"xyz/c.html",
"xyz/i/x.gif",
);
# Non-portable code using regex
foreach my $path (@paths)
(my $basename = $path) =~ s,.*/,,;
print "$path -> $basenamen";
# Portable implementation using Perl core modules
use File::Spec;
foreach my $path (@paths)
my(undef, undef, $basename) = File::Spec->splitpath($path);
print "$path -> $basenamen";
exit 0;
Test run:
$ perl dummy.pl
xyz/c.html -> c.html
xyz/i/x.gif -> x.gif
xyz/c.html -> c.html
xyz/i/x.gif -> x.gif
answered Mar 26 at 12:36
Stefan BeckerStefan Becker
4,5813 gold badges11 silver badges25 bronze badges
4,5813 gold badges11 silver badges25 bronze badges
add a comment |
add a comment |
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perldoc File::Basename
– toolic
Mar 26 at 12:21
@toolic I want the output without lib using.
– Jack
Mar 26 at 12:23
1
File::Basename
is a core module. No need to reinvent the wheel.– dgw
Mar 26 at 12:28
@dgw How can i used that one?
– Jack
Mar 26 at 12:29
Why don't you want to use any module? Is it because you can't install any? Because you don't want too many dependencies? Because this is homework and that's a requirement?
– Dada
Mar 26 at 12:40