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67

26

function (data) 
 //add values based on activity type
 //data = JSON.parse(data);
 //alert(abc.Phone1);

 alert(data.myName)

 alert(data.toString());
 if (activityType == "Phone") 
 
 return;

,

As you can see this callback function of $.ajax taking JSON data from controller.

For example:

["name":"myName" ,"address": "myAddress" ]

In this case my first alert giving me undefined and second/third alert popup comes up with:

["name":"myName" ,"address": "myAddress" ]

How can I access value by name so that my first alert filled out with myName which is value of name?

jquery ajax json asp.net-mvc-3

share|improve this question

edited Jul 7 '15 at 7:41

dspacejs

1,17222 gold badges1414 silver badges2323 bronze badges

asked Jun 5 '12 at 10:05

RollerCostaRollerCosta

2,74766 gold badges4141 silver badges6565 bronze badges

add a comment | 

67

26

function (data) 
 //add values based on activity type
 //data = JSON.parse(data);
 //alert(abc.Phone1);

 alert(data.myName)

 alert(data.toString());
 if (activityType == "Phone") 
 
 return;

,

As you can see this callback function of $.ajax taking JSON data from controller.

For example:

["name":"myName" ,"address": "myAddress" ]

In this case my first alert giving me undefined and second/third alert popup comes up with:

["name":"myName" ,"address": "myAddress" ]

How can I access value by name so that my first alert filled out with myName which is value of name?

jquery ajax json asp.net-mvc-3

share|improve this question

edited Jul 7 '15 at 7:41

dspacejs

1,17222 gold badges1414 silver badges2323 bronze badges

asked Jun 5 '12 at 10:05

RollerCostaRollerCosta

2,74766 gold badges4141 silver badges6565 bronze badges

add a comment | 

function (data) 
 //add values based on activity type
 //data = JSON.parse(data);
 //alert(abc.Phone1);

 alert(data.myName)

 alert(data.toString());
 if (activityType == "Phone") 
 
 return;

,

As you can see this callback function of $.ajax taking JSON data from controller.

For example:

["name":"myName" ,"address": "myAddress" ]

In this case my first alert giving me undefined and second/third alert popup comes up with:

["name":"myName" ,"address": "myAddress" ]

How can I access value by name so that my first alert filled out with myName which is value of name?

jquery ajax json asp.net-mvc-3

share|improve this question

edited Jul 7 '15 at 7:41

dspacejs

1,17222 gold badges1414 silver badges2323 bronze badges

asked Jun 5 '12 at 10:05

RollerCostaRollerCosta

2,74766 gold badges4141 silver badges6565 bronze badges

function (data) 
 //add values based on activity type
 //data = JSON.parse(data);
 //alert(abc.Phone1);

 alert(data.myName)

 alert(data.toString());
 if (activityType == "Phone") 
 
 return;

,

share|improve this question

edited Jul 7 '15 at 7:41

dspacejs

1,17222 gold badges1414 silver badges2323 bronze badges

asked Jun 5 '12 at 10:05

RollerCostaRollerCosta

2,74766 gold badges4141 silver badges6565 bronze badges

share|improve this question

edited Jul 7 '15 at 7:41

dspacejs

1,17222 gold badges1414 silver badges2323 bronze badges

asked Jun 5 '12 at 10:05

RollerCostaRollerCosta

2,74766 gold badges4141 silver badges6565 bronze badges

edited Jul 7 '15 at 7:41

dspacejs

1,17222 gold badges1414 silver badges2323 bronze badges

edited Jul 7 '15 at 7:41

dspacejs

1,17222 gold badges1414 silver badges2323 bronze badges

asked Jun 5 '12 at 10:05

RollerCostaRollerCosta

2,74766 gold badges4141 silver badges6565 bronze badges

asked Jun 5 '12 at 10:05

RollerCostaRollerCosta

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8 Answers
8

active

oldest

votes

99

In stead of parsing JSON you can do like followng:

$.ajax(
 ..
 dataType: 'json' // using json, jquery will make parse for you
);

To access a property of your JSON do following:

data[0].name;

data[0].address;

---

Why you need data[0] because data is an array, so to its content retrieve you need data[0] (first element), which gives you an object "name":"myName" ,"address": "myAddress" .

And to access property of an object rule is:

Object.property

or sometimes

Object["property"] // in some case

So you need

data[0].name and so on to get what you want.

---

If you not

set dataType: json then you need to parse them using $.parseJSON() and to retrieve data like above.

share|improve this answer

edited Jun 5 '12 at 10:22

answered Jun 5 '12 at 10:09

thecodeparadoxthecodeparadox

72.9k1818 gold badges125125 silver badges158158 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  maps.googleapis.com/maps/api/geocode/… from this url how should get "formatted_address" field value in a variable? success : function(data) address = data['formatted_address']; throws an error
  
  – user3816325
  Apr 14 '16 at 9:50
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  is there a more optimized way to do so? if I have a json list of more than 20 names and i need to display their value, but I don't know if which one of them will be returned in the json, it could be ony one or 3 or 10 or all 20 of them, should I repeat the same for each one of them, for example: if data[0].name : console.log(data[0].name); if data[0].adress : console.log(data[0].adress); ..
  
  – Armance
  Nov 30 '16 at 10:09
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  could data[0].[0] work, to access name? Looking at it like an array.
  
  – Malcolm Salvador
  Mar 8 '17 at 0:15
  

  
  
  
  

add a comment | 

28

The JSON you are receiving is in string. You have to convert it into JSON object
You have commented the most important line of code

data = JSON.parse(data);

Or if you are using jQuery

data = $.parseJSON(data)

share|improve this answer

answered Jun 5 '12 at 10:08

Obi-Wan SpockObi-Wan Spock

6,31455 gold badges3030 silver badges5252 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  even on uncommenting the line i receive undefined
  
  – RollerCosta
  Jun 5 '12 at 10:14
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  data = $.parseJSON(data) for that i received an error
  
  – RollerCosta
  Jun 5 '12 at 10:14
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  That is because your JSON is an array. Try data[0].name instead of data.name. And make sure you access property not value i.e. data[0].name (property) instead of what you are doing in your question data.myName(which is value)
  
  – Obi-Wan Spock
  Jun 5 '12 at 10:18
  
  

  
  
  
  

add a comment | 

9

If you response is like 'customer':'first_name':'John','last_name':'Cena'

var d = JSON.parse(response);
alert(d.customer.first_name); // contains "John"

Thanks,

share|improve this answer

answered Nov 27 '14 at 15:19

Mahendran SakkaraiMahendran Sakkarai

5,99733 gold badges3131 silver badges6262 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Hi, If I wanted to extract 'customer' how would I do that where customer is the actual thing I want. In my case I want to extract aboutme.jpg that below as a string b'"_id":"2","_rev":"5-760e627e77645e960c5cc40ea6cf03a2","_attachments":"aboutme.jpg":"content_type":"image/jpeg","revpos":3,"digest":"md5-mG5uU4IRGuY/f9PbZ8AIbQ==","length":98831,"stub":truen'
  
  – Andrew Irwin
  Nov 26 '16 at 22:11
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  stackoverflow.com/a/16068794/3049065 I think that answer will help you.
  
  – Mahendran Sakkarai
  Nov 26 '16 at 22:27
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  stackoverflow.com/a/28670472/3049065 this one too..
  
  – Mahendran Sakkarai
  Nov 26 '16 at 22:28
  

  
  
  
  

add a comment | 

6

You should do

alert(data[0].name); //Take the property name of the first array

and not

 alert(data.myName)

jQuery should be able to sniff the dataType for you even if you don't set it so no need for JSON.parse.

fiddle here

http://jsfiddle.net/H2yN6/

share|improve this answer

answered Jun 5 '12 at 10:09

Nicola PeluchettiNicola Peluchetti

63.8k2727 gold badges120120 silver badges171171 bronze badges

add a comment | 

4

Try this code..

function (data) 


var json = jQuery.parseJSON(data);
alert( json.name );

share|improve this answer

answered Jun 5 '12 at 10:09

Kabilan SKabilan S

93833 gold badges1313 silver badges2828 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  var json = jQuery.parseJSON(data); not working for me
  
  – RollerCosta
  Jun 5 '12 at 10:11
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  i tried it before and getting an error Microsoft JScript runtime error: Object doesn't support property or method 'parseJSON'
  
  – RollerCosta
  Jun 5 '12 at 10:11
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  are you not using Jquery ?
  
  – Kabilan S
  Jun 5 '12 at 10:13
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  yes i am using it
  
  – RollerCosta
  Jun 5 '12 at 10:32
  

  
  
  
  

add a comment | 

2

I think you should mention dataType: 'json' in ajax config and to access that value:

data[0].name

share|improve this answer

answered Jun 5 '12 at 10:15

The System RestartThe System Restart

2,6131313 silver badges2626 bronze badges

add a comment | 

1

You might want to try this approach:

var str =" "name" : "user"";
var jsonData = JSON.parse(str); 
console.log(jsonData.name)
//Array Object
str ="[ "name" : "user", "name" : "user2"]";
jsonData = JSON.parse(str); 
console.log(jsonData[0].name)

share|improve this answer

edited Mar 26 at 12:33

baduker

1,22244 gold badges1111 silver badges2121 bronze badges

answered Mar 26 at 11:57

Mansuri NurulhudaMansuri Nurulhuda

2111 bronze badge

add a comment | 

0

Here is a friendly piece of advice. Use something like Chrome Developer Tools or Firebug for Firefox to inspect your Ajax calls and results.

You may also want to invest some time in understanding a helper library like Underscore, which complements jQuery and gives you 60+ useful functions for manipulating data objects with JavaScript.

share|improve this answer

answered Jun 5 '12 at 10:27

ButifarraButifarra

97466 silver badges1212 bronze badges

add a comment | 

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99

In stead of parsing JSON you can do like followng:

$.ajax(
 ..
 dataType: 'json' // using json, jquery will make parse for you
);

To access a property of your JSON do following:

data[0].name;

data[0].address;

---

Why you need data[0] because data is an array, so to its content retrieve you need data[0] (first element), which gives you an object "name":"myName" ,"address": "myAddress" .

And to access property of an object rule is:

Object.property

or sometimes

Object["property"] // in some case

So you need

data[0].name and so on to get what you want.

---

If you not

set dataType: json then you need to parse them using $.parseJSON() and to retrieve data like above.

share|improve this answer

edited Jun 5 '12 at 10:22

answered Jun 5 '12 at 10:09

thecodeparadoxthecodeparadox

72.9k1818 gold badges125125 silver badges158158 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  maps.googleapis.com/maps/api/geocode/… from this url how should get "formatted_address" field value in a variable? success : function(data) address = data['formatted_address']; throws an error
  
  – user3816325
  Apr 14 '16 at 9:50
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  is there a more optimized way to do so? if I have a json list of more than 20 names and i need to display their value, but I don't know if which one of them will be returned in the json, it could be ony one or 3 or 10 or all 20 of them, should I repeat the same for each one of them, for example: if data[0].name : console.log(data[0].name); if data[0].adress : console.log(data[0].adress); ..
  
  – Armance
  Nov 30 '16 at 10:09
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  could data[0].[0] work, to access name? Looking at it like an array.
  
  – Malcolm Salvador
  Mar 8 '17 at 0:15
  

  
  
  
  

add a comment | 

99

In stead of parsing JSON you can do like followng:

$.ajax(
 ..
 dataType: 'json' // using json, jquery will make parse for you
);

To access a property of your JSON do following:

data[0].name;

data[0].address;

---

Why you need data[0] because data is an array, so to its content retrieve you need data[0] (first element), which gives you an object "name":"myName" ,"address": "myAddress" .

And to access property of an object rule is:

Object.property

or sometimes

Object["property"] // in some case

So you need

data[0].name and so on to get what you want.

---

If you not

set dataType: json then you need to parse them using $.parseJSON() and to retrieve data like above.

share|improve this answer

edited Jun 5 '12 at 10:22

answered Jun 5 '12 at 10:09

thecodeparadoxthecodeparadox

72.9k1818 gold badges125125 silver badges158158 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  maps.googleapis.com/maps/api/geocode/… from this url how should get "formatted_address" field value in a variable? success : function(data) address = data['formatted_address']; throws an error
  
  – user3816325
  Apr 14 '16 at 9:50
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  is there a more optimized way to do so? if I have a json list of more than 20 names and i need to display their value, but I don't know if which one of them will be returned in the json, it could be ony one or 3 or 10 or all 20 of them, should I repeat the same for each one of them, for example: if data[0].name : console.log(data[0].name); if data[0].adress : console.log(data[0].adress); ..
  
  – Armance
  Nov 30 '16 at 10:09
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  could data[0].[0] work, to access name? Looking at it like an array.
  
  – Malcolm Salvador
  Mar 8 '17 at 0:15
  

  
  
  
  

add a comment | 

In stead of parsing JSON you can do like followng:

$.ajax(
 ..
 dataType: 'json' // using json, jquery will make parse for you
);

To access a property of your JSON do following:

data[0].name;

data[0].address;

---

Why you need data[0] because data is an array, so to its content retrieve you need data[0] (first element), which gives you an object "name":"myName" ,"address": "myAddress" .

And to access property of an object rule is:

Object.property

or sometimes

Object["property"] // in some case

So you need

data[0].name and so on to get what you want.

---

If you not

set dataType: json then you need to parse them using $.parseJSON() and to retrieve data like above.

share|improve this answer

edited Jun 5 '12 at 10:22

answered Jun 5 '12 at 10:09

thecodeparadoxthecodeparadox

72.9k1818 gold badges125125 silver badges158158 bronze badges

$.ajax(
 ..
 dataType: 'json' // using json, jquery will make parse for you
);

data[0].name;

data[0].address;

Object.property

Object["property"] // in some case

share|improve this answer

edited Jun 5 '12 at 10:22

answered Jun 5 '12 at 10:09

thecodeparadoxthecodeparadox

72.9k1818 gold badges125125 silver badges158158 bronze badges

answered Jun 5 '12 at 10:09

thecodeparadoxthecodeparadox

72.9k1818 gold badges125125 silver badges158158 bronze badges

answered Jun 5 '12 at 10:09

thecodeparadoxthecodeparadox

72.9k1818 gold badges125125 silver badges158158 bronze badges

28

The JSON you are receiving is in string. You have to convert it into JSON object
You have commented the most important line of code

data = JSON.parse(data);

Or if you are using jQuery

data = $.parseJSON(data)

share|improve this answer

answered Jun 5 '12 at 10:08

Obi-Wan SpockObi-Wan Spock

6,31455 gold badges3030 silver badges5252 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  even on uncommenting the line i receive undefined
  
  – RollerCosta
  Jun 5 '12 at 10:14
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  data = $.parseJSON(data) for that i received an error
  
  – RollerCosta
  Jun 5 '12 at 10:14
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  That is because your JSON is an array. Try data[0].name instead of data.name. And make sure you access property not value i.e. data[0].name (property) instead of what you are doing in your question data.myName(which is value)
  
  – Obi-Wan Spock
  Jun 5 '12 at 10:18
  
  

  
  
  
  

add a comment | 

28

The JSON you are receiving is in string. You have to convert it into JSON object
You have commented the most important line of code

data = JSON.parse(data);

Or if you are using jQuery

data = $.parseJSON(data)

share|improve this answer

answered Jun 5 '12 at 10:08

Obi-Wan SpockObi-Wan Spock

6,31455 gold badges3030 silver badges5252 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  even on uncommenting the line i receive undefined
  
  – RollerCosta
  Jun 5 '12 at 10:14
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  data = $.parseJSON(data) for that i received an error
  
  – RollerCosta
  Jun 5 '12 at 10:14
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  That is because your JSON is an array. Try data[0].name instead of data.name. And make sure you access property not value i.e. data[0].name (property) instead of what you are doing in your question data.myName(which is value)
  
  – Obi-Wan Spock
  Jun 5 '12 at 10:18
  
  

  
  
  
  

add a comment | 

The JSON you are receiving is in string. You have to convert it into JSON object
You have commented the most important line of code

data = JSON.parse(data);

Or if you are using jQuery

data = $.parseJSON(data)

share|improve this answer

answered Jun 5 '12 at 10:08

Obi-Wan SpockObi-Wan Spock

6,31455 gold badges3030 silver badges5252 bronze badges

data = JSON.parse(data);

data = $.parseJSON(data)

share|improve this answer

answered Jun 5 '12 at 10:08

Obi-Wan SpockObi-Wan Spock

6,31455 gold badges3030 silver badges5252 bronze badges

answered Jun 5 '12 at 10:08

Obi-Wan SpockObi-Wan Spock

6,31455 gold badges3030 silver badges5252 bronze badges

answered Jun 5 '12 at 10:08

Obi-Wan SpockObi-Wan Spock

6,31455 gold badges3030 silver badges5252 bronze badges

9

If you response is like 'customer':'first_name':'John','last_name':'Cena'

var d = JSON.parse(response);
alert(d.customer.first_name); // contains "John"

Thanks,

share|improve this answer

answered Nov 27 '14 at 15:19

Mahendran SakkaraiMahendran Sakkarai

5,99733 gold badges3131 silver badges6262 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Hi, If I wanted to extract 'customer' how would I do that where customer is the actual thing I want. In my case I want to extract aboutme.jpg that below as a string b'"_id":"2","_rev":"5-760e627e77645e960c5cc40ea6cf03a2","_attachments":"aboutme.jpg":"content_type":"image/jpeg","revpos":3,"digest":"md5-mG5uU4IRGuY/f9PbZ8AIbQ==","length":98831,"stub":truen'
  
  – Andrew Irwin
  Nov 26 '16 at 22:11
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  stackoverflow.com/a/16068794/3049065 I think that answer will help you.
  
  – Mahendran Sakkarai
  Nov 26 '16 at 22:27
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  stackoverflow.com/a/28670472/3049065 this one too..
  
  – Mahendran Sakkarai
  Nov 26 '16 at 22:28
  

  
  
  
  

add a comment | 

9

If you response is like 'customer':'first_name':'John','last_name':'Cena'

var d = JSON.parse(response);
alert(d.customer.first_name); // contains "John"

Thanks,

share|improve this answer

answered Nov 27 '14 at 15:19

Mahendran SakkaraiMahendran Sakkarai

5,99733 gold badges3131 silver badges6262 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Hi, If I wanted to extract 'customer' how would I do that where customer is the actual thing I want. In my case I want to extract aboutme.jpg that below as a string b'"_id":"2","_rev":"5-760e627e77645e960c5cc40ea6cf03a2","_attachments":"aboutme.jpg":"content_type":"image/jpeg","revpos":3,"digest":"md5-mG5uU4IRGuY/f9PbZ8AIbQ==","length":98831,"stub":truen'
  
  – Andrew Irwin
  Nov 26 '16 at 22:11
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  stackoverflow.com/a/16068794/3049065 I think that answer will help you.
  
  – Mahendran Sakkarai
  Nov 26 '16 at 22:27
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  stackoverflow.com/a/28670472/3049065 this one too..
  
  – Mahendran Sakkarai
  Nov 26 '16 at 22:28
  

  
  
  
  

add a comment | 

If you response is like 'customer':'first_name':'John','last_name':'Cena'

var d = JSON.parse(response);
alert(d.customer.first_name); // contains "John"

Thanks,

share|improve this answer

answered Nov 27 '14 at 15:19

Mahendran SakkaraiMahendran Sakkarai

5,99733 gold badges3131 silver badges6262 bronze badges

var d = JSON.parse(response);
alert(d.customer.first_name); // contains "John"

share|improve this answer

answered Nov 27 '14 at 15:19

Mahendran SakkaraiMahendran Sakkarai

5,99733 gold badges3131 silver badges6262 bronze badges

answered Nov 27 '14 at 15:19

Mahendran SakkaraiMahendran Sakkarai

5,99733 gold badges3131 silver badges6262 bronze badges

answered Nov 27 '14 at 15:19

Mahendran SakkaraiMahendran Sakkarai

5,99733 gold badges3131 silver badges6262 bronze badges

6

You should do

alert(data[0].name); //Take the property name of the first array

and not

 alert(data.myName)

jQuery should be able to sniff the dataType for you even if you don't set it so no need for JSON.parse.

fiddle here

http://jsfiddle.net/H2yN6/

share|improve this answer

answered Jun 5 '12 at 10:09

Nicola PeluchettiNicola Peluchetti

63.8k2727 gold badges120120 silver badges171171 bronze badges

add a comment | 

6

You should do

alert(data[0].name); //Take the property name of the first array

and not

 alert(data.myName)

jQuery should be able to sniff the dataType for you even if you don't set it so no need for JSON.parse.

fiddle here

http://jsfiddle.net/H2yN6/

share|improve this answer

answered Jun 5 '12 at 10:09

Nicola PeluchettiNicola Peluchetti

63.8k2727 gold badges120120 silver badges171171 bronze badges

add a comment | 

You should do

alert(data[0].name); //Take the property name of the first array

and not

 alert(data.myName)

jQuery should be able to sniff the dataType for you even if you don't set it so no need for JSON.parse.

fiddle here

http://jsfiddle.net/H2yN6/

share|improve this answer

answered Jun 5 '12 at 10:09

Nicola PeluchettiNicola Peluchetti

63.8k2727 gold badges120120 silver badges171171 bronze badges

alert(data[0].name); //Take the property name of the first array

 alert(data.myName)

share|improve this answer

answered Jun 5 '12 at 10:09

Nicola PeluchettiNicola Peluchetti

63.8k2727 gold badges120120 silver badges171171 bronze badges

answered Jun 5 '12 at 10:09

Nicola PeluchettiNicola Peluchetti

63.8k2727 gold badges120120 silver badges171171 bronze badges

answered Jun 5 '12 at 10:09

Nicola PeluchettiNicola Peluchetti

63.8k2727 gold badges120120 silver badges171171 bronze badges

4

Try this code..

function (data) 


var json = jQuery.parseJSON(data);
alert( json.name );

share|improve this answer

answered Jun 5 '12 at 10:09

Kabilan SKabilan S

93833 gold badges1313 silver badges2828 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  var json = jQuery.parseJSON(data); not working for me
  
  – RollerCosta
  Jun 5 '12 at 10:11
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  i tried it before and getting an error Microsoft JScript runtime error: Object doesn't support property or method 'parseJSON'
  
  – RollerCosta
  Jun 5 '12 at 10:11
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  are you not using Jquery ?
  
  – Kabilan S
  Jun 5 '12 at 10:13
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  yes i am using it
  
  – RollerCosta
  Jun 5 '12 at 10:32
  

  
  
  
  

add a comment | 

4

Try this code..

function (data) 


var json = jQuery.parseJSON(data);
alert( json.name );

share|improve this answer

answered Jun 5 '12 at 10:09

Kabilan SKabilan S

93833 gold badges1313 silver badges2828 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  var json = jQuery.parseJSON(data); not working for me
  
  – RollerCosta
  Jun 5 '12 at 10:11
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  i tried it before and getting an error Microsoft JScript runtime error: Object doesn't support property or method 'parseJSON'
  
  – RollerCosta
  Jun 5 '12 at 10:11
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  are you not using Jquery ?
  
  – Kabilan S
  Jun 5 '12 at 10:13
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  yes i am using it
  
  – RollerCosta
  Jun 5 '12 at 10:32
  

  
  
  
  

add a comment | 

Try this code..

function (data) 


var json = jQuery.parseJSON(data);
alert( json.name );

share|improve this answer

answered Jun 5 '12 at 10:09

Kabilan SKabilan S

93833 gold badges1313 silver badges2828 bronze badges

function (data) 


var json = jQuery.parseJSON(data);
alert( json.name );

share|improve this answer

answered Jun 5 '12 at 10:09

Kabilan SKabilan S

93833 gold badges1313 silver badges2828 bronze badges

answered Jun 5 '12 at 10:09

Kabilan SKabilan S

93833 gold badges1313 silver badges2828 bronze badges

answered Jun 5 '12 at 10:09

Kabilan SKabilan S

93833 gold badges1313 silver badges2828 bronze badges

2

I think you should mention dataType: 'json' in ajax config and to access that value:

data[0].name

share|improve this answer

answered Jun 5 '12 at 10:15

The System RestartThe System Restart

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