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How to convert scientific notation stored as string to int in pandas dataframe?


How do I parse a string to a float or int?Converting string into datetimeConvert bytes to a string?Converting integer to string?Selecting multiple columns in a pandas dataframeAdding new column to existing DataFrame in Python pandasDelete column from pandas DataFrameHow to iterate over rows in a DataFrame in Pandas?Select rows from a DataFrame based on values in a column in pandasGet list from pandas DataFrame column headers






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1















I have a column in a dataframe in pandas that is storing scientific notations as strings. I want to convert them strings to integers. But i am running into an issue that is best described by the code snippet below



Expected behavior:



print(int(float('9.01E+26')))
output:
901000000000000035886465024


Behaviour i am getting:



a = pd.Series('a':'9.01E+26')
print(a.astype(float).astype(int))
output:
a -9223372036854775808
dtype: int64


How do i go about achieving the expected behavior?










share|improve this question
























  • Interesting. I assume this is on Windows (edit: nevermind, you would have got dtype: int32 if it was). The default int type used by numpy is 32 bit on Windows, but indeed this overflows np.int64 too. It's not clear how to get python int behaviour that doesn't overflow

    – roganjosh
    Mar 27 at 20:40












  • In fact, I'm suspecting that you simply cannot work with integers of this size in numpy. You'd either need floats or work with python list comprehensions instead. Could be wrong, though.

    – roganjosh
    Mar 27 at 20:45












  • .apply would be the way to go then i guess?

    – MiloMinderbinder
    Mar 27 at 20:46











  • That will give you OverflowError: int too big to convert. There must be some interim dtype going from np.float to a regular Python int that simply blocks the conversion

    – roganjosh
    Mar 27 at 20:48











  • ohh that so? i was thinking that since int(float('9.01E+26')) works... .apply would work too

    – MiloMinderbinder
    Mar 27 at 20:49

















1















I have a column in a dataframe in pandas that is storing scientific notations as strings. I want to convert them strings to integers. But i am running into an issue that is best described by the code snippet below



Expected behavior:



print(int(float('9.01E+26')))
output:
901000000000000035886465024


Behaviour i am getting:



a = pd.Series('a':'9.01E+26')
print(a.astype(float).astype(int))
output:
a -9223372036854775808
dtype: int64


How do i go about achieving the expected behavior?










share|improve this question
























  • Interesting. I assume this is on Windows (edit: nevermind, you would have got dtype: int32 if it was). The default int type used by numpy is 32 bit on Windows, but indeed this overflows np.int64 too. It's not clear how to get python int behaviour that doesn't overflow

    – roganjosh
    Mar 27 at 20:40












  • In fact, I'm suspecting that you simply cannot work with integers of this size in numpy. You'd either need floats or work with python list comprehensions instead. Could be wrong, though.

    – roganjosh
    Mar 27 at 20:45












  • .apply would be the way to go then i guess?

    – MiloMinderbinder
    Mar 27 at 20:46











  • That will give you OverflowError: int too big to convert. There must be some interim dtype going from np.float to a regular Python int that simply blocks the conversion

    – roganjosh
    Mar 27 at 20:48











  • ohh that so? i was thinking that since int(float('9.01E+26')) works... .apply would work too

    – MiloMinderbinder
    Mar 27 at 20:49













1












1








1








I have a column in a dataframe in pandas that is storing scientific notations as strings. I want to convert them strings to integers. But i am running into an issue that is best described by the code snippet below



Expected behavior:



print(int(float('9.01E+26')))
output:
901000000000000035886465024


Behaviour i am getting:



a = pd.Series('a':'9.01E+26')
print(a.astype(float).astype(int))
output:
a -9223372036854775808
dtype: int64


How do i go about achieving the expected behavior?










share|improve this question














I have a column in a dataframe in pandas that is storing scientific notations as strings. I want to convert them strings to integers. But i am running into an issue that is best described by the code snippet below



Expected behavior:



print(int(float('9.01E+26')))
output:
901000000000000035886465024


Behaviour i am getting:



a = pd.Series('a':'9.01E+26')
print(a.astype(float).astype(int))
output:
a -9223372036854775808
dtype: int64


How do i go about achieving the expected behavior?







python pandas






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 27 at 20:37









MiloMinderbinderMiloMinderbinder

7887 silver badges16 bronze badges




7887 silver badges16 bronze badges















  • Interesting. I assume this is on Windows (edit: nevermind, you would have got dtype: int32 if it was). The default int type used by numpy is 32 bit on Windows, but indeed this overflows np.int64 too. It's not clear how to get python int behaviour that doesn't overflow

    – roganjosh
    Mar 27 at 20:40












  • In fact, I'm suspecting that you simply cannot work with integers of this size in numpy. You'd either need floats or work with python list comprehensions instead. Could be wrong, though.

    – roganjosh
    Mar 27 at 20:45












  • .apply would be the way to go then i guess?

    – MiloMinderbinder
    Mar 27 at 20:46











  • That will give you OverflowError: int too big to convert. There must be some interim dtype going from np.float to a regular Python int that simply blocks the conversion

    – roganjosh
    Mar 27 at 20:48











  • ohh that so? i was thinking that since int(float('9.01E+26')) works... .apply would work too

    – MiloMinderbinder
    Mar 27 at 20:49

















  • Interesting. I assume this is on Windows (edit: nevermind, you would have got dtype: int32 if it was). The default int type used by numpy is 32 bit on Windows, but indeed this overflows np.int64 too. It's not clear how to get python int behaviour that doesn't overflow

    – roganjosh
    Mar 27 at 20:40












  • In fact, I'm suspecting that you simply cannot work with integers of this size in numpy. You'd either need floats or work with python list comprehensions instead. Could be wrong, though.

    – roganjosh
    Mar 27 at 20:45












  • .apply would be the way to go then i guess?

    – MiloMinderbinder
    Mar 27 at 20:46











  • That will give you OverflowError: int too big to convert. There must be some interim dtype going from np.float to a regular Python int that simply blocks the conversion

    – roganjosh
    Mar 27 at 20:48











  • ohh that so? i was thinking that since int(float('9.01E+26')) works... .apply would work too

    – MiloMinderbinder
    Mar 27 at 20:49
















Interesting. I assume this is on Windows (edit: nevermind, you would have got dtype: int32 if it was). The default int type used by numpy is 32 bit on Windows, but indeed this overflows np.int64 too. It's not clear how to get python int behaviour that doesn't overflow

– roganjosh
Mar 27 at 20:40






Interesting. I assume this is on Windows (edit: nevermind, you would have got dtype: int32 if it was). The default int type used by numpy is 32 bit on Windows, but indeed this overflows np.int64 too. It's not clear how to get python int behaviour that doesn't overflow

– roganjosh
Mar 27 at 20:40














In fact, I'm suspecting that you simply cannot work with integers of this size in numpy. You'd either need floats or work with python list comprehensions instead. Could be wrong, though.

– roganjosh
Mar 27 at 20:45






In fact, I'm suspecting that you simply cannot work with integers of this size in numpy. You'd either need floats or work with python list comprehensions instead. Could be wrong, though.

– roganjosh
Mar 27 at 20:45














.apply would be the way to go then i guess?

– MiloMinderbinder
Mar 27 at 20:46





.apply would be the way to go then i guess?

– MiloMinderbinder
Mar 27 at 20:46













That will give you OverflowError: int too big to convert. There must be some interim dtype going from np.float to a regular Python int that simply blocks the conversion

– roganjosh
Mar 27 at 20:48





That will give you OverflowError: int too big to convert. There must be some interim dtype going from np.float to a regular Python int that simply blocks the conversion

– roganjosh
Mar 27 at 20:48













ohh that so? i was thinking that since int(float('9.01E+26')) works... .apply would work too

– MiloMinderbinder
Mar 27 at 20:49





ohh that so? i was thinking that since int(float('9.01E+26')) works... .apply would work too

– MiloMinderbinder
Mar 27 at 20:49












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