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Validation to ensure value entered is a integer


Validate decimal numbers in JavaScript - IsNumeric()How to validate an email address in JavaScriptA potentially dangerous Request.Form value was detected from the clientA comprehensive regex for phone number validation(Built-in) way in JavaScript to check if a string is a valid numberHow to validate an email address using a regular expression?What is the maximum length of a valid email address?Conversion from string “” to type 'Integer' is not valid on a for each statementObject enter event “string to decimal not valid”Re-prompt user if entered value is negative for multiple inputs






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








1















I want a validation method that ensures that value entered is valid, it must be a integer (can include negative) and must not be blank. I have written this code, however not correct, can someone help me please. Thank you



If (b <> Integer Or " ") Then
Console.WriteLine("Value entered must be a number")
End If


new code:
Line98:
Console.WriteLine("Please input the value of, B:")
b = Console.ReadLine()
If Not Integer.TryParse(b, New Integer) Then
Console.WriteLine("Value entered must be a number")
GoTo Line98
End If


so i used a select statement, and if a user enters "abckak" any non numerical data i get an error Unhandled Exception: System.InvalidCastException: Conversion from string "gakjdg" to type 'Integer' is not valid.



how could this be fixed, this is a quick example of my code



 Console.WriteLine("..........Main Menu..........")
Console.WriteLine("Please input 1 ")
Console.WriteLine("Please input 2")
Console.WriteLine("Please input 3 ")
Console.WriteLine("Please input 4 ")
Console.WriteLine("Please input 5 for Help")
Console.WriteLine("Please input 6 to Exit")

Console.WriteLine("Please enter your choice: ")

Choice = Console.ReadLine()
Select Case Choice

case1; etc

Case Else
Console.WriteLine("Error: " & Choice & " is not a option, Please try again")









share|improve this question





















  • 1





    If Not Integer.TryParse(b, New Integer) Then.... This is a quick solution and would suit what you are looking for. Please see more there about the TryParse...

    – Çöđěxěŕ
    Mar 27 at 20:40












  • @Çöđěxěŕ, i tried that however, and i input f lets just say, i get error Unhandled Exception: System.InvalidCastException: Conversion from string "f" to type 'Integer' is not valid

    – loco3424
    Mar 27 at 20:56


















1















I want a validation method that ensures that value entered is valid, it must be a integer (can include negative) and must not be blank. I have written this code, however not correct, can someone help me please. Thank you



If (b <> Integer Or " ") Then
Console.WriteLine("Value entered must be a number")
End If


new code:
Line98:
Console.WriteLine("Please input the value of, B:")
b = Console.ReadLine()
If Not Integer.TryParse(b, New Integer) Then
Console.WriteLine("Value entered must be a number")
GoTo Line98
End If


so i used a select statement, and if a user enters "abckak" any non numerical data i get an error Unhandled Exception: System.InvalidCastException: Conversion from string "gakjdg" to type 'Integer' is not valid.



how could this be fixed, this is a quick example of my code



 Console.WriteLine("..........Main Menu..........")
Console.WriteLine("Please input 1 ")
Console.WriteLine("Please input 2")
Console.WriteLine("Please input 3 ")
Console.WriteLine("Please input 4 ")
Console.WriteLine("Please input 5 for Help")
Console.WriteLine("Please input 6 to Exit")

Console.WriteLine("Please enter your choice: ")

Choice = Console.ReadLine()
Select Case Choice

case1; etc

Case Else
Console.WriteLine("Error: " & Choice & " is not a option, Please try again")









share|improve this question





















  • 1





    If Not Integer.TryParse(b, New Integer) Then.... This is a quick solution and would suit what you are looking for. Please see more there about the TryParse...

    – Çöđěxěŕ
    Mar 27 at 20:40












  • @Çöđěxěŕ, i tried that however, and i input f lets just say, i get error Unhandled Exception: System.InvalidCastException: Conversion from string "f" to type 'Integer' is not valid

    – loco3424
    Mar 27 at 20:56














1












1








1








I want a validation method that ensures that value entered is valid, it must be a integer (can include negative) and must not be blank. I have written this code, however not correct, can someone help me please. Thank you



If (b <> Integer Or " ") Then
Console.WriteLine("Value entered must be a number")
End If


new code:
Line98:
Console.WriteLine("Please input the value of, B:")
b = Console.ReadLine()
If Not Integer.TryParse(b, New Integer) Then
Console.WriteLine("Value entered must be a number")
GoTo Line98
End If


so i used a select statement, and if a user enters "abckak" any non numerical data i get an error Unhandled Exception: System.InvalidCastException: Conversion from string "gakjdg" to type 'Integer' is not valid.



how could this be fixed, this is a quick example of my code



 Console.WriteLine("..........Main Menu..........")
Console.WriteLine("Please input 1 ")
Console.WriteLine("Please input 2")
Console.WriteLine("Please input 3 ")
Console.WriteLine("Please input 4 ")
Console.WriteLine("Please input 5 for Help")
Console.WriteLine("Please input 6 to Exit")

Console.WriteLine("Please enter your choice: ")

Choice = Console.ReadLine()
Select Case Choice

case1; etc

Case Else
Console.WriteLine("Error: " & Choice & " is not a option, Please try again")









share|improve this question
















I want a validation method that ensures that value entered is valid, it must be a integer (can include negative) and must not be blank. I have written this code, however not correct, can someone help me please. Thank you



If (b <> Integer Or " ") Then
Console.WriteLine("Value entered must be a number")
End If


new code:
Line98:
Console.WriteLine("Please input the value of, B:")
b = Console.ReadLine()
If Not Integer.TryParse(b, New Integer) Then
Console.WriteLine("Value entered must be a number")
GoTo Line98
End If


so i used a select statement, and if a user enters "abckak" any non numerical data i get an error Unhandled Exception: System.InvalidCastException: Conversion from string "gakjdg" to type 'Integer' is not valid.



how could this be fixed, this is a quick example of my code



 Console.WriteLine("..........Main Menu..........")
Console.WriteLine("Please input 1 ")
Console.WriteLine("Please input 2")
Console.WriteLine("Please input 3 ")
Console.WriteLine("Please input 4 ")
Console.WriteLine("Please input 5 for Help")
Console.WriteLine("Please input 6 to Exit")

Console.WriteLine("Please enter your choice: ")

Choice = Console.ReadLine()
Select Case Choice

case1; etc

Case Else
Console.WriteLine("Error: " & Choice & " is not a option, Please try again")






vb.net validation






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 27 at 21:46







loco3424

















asked Mar 27 at 20:22









loco3424loco3424

104 bronze badges




104 bronze badges










  • 1





    If Not Integer.TryParse(b, New Integer) Then.... This is a quick solution and would suit what you are looking for. Please see more there about the TryParse...

    – Çöđěxěŕ
    Mar 27 at 20:40












  • @Çöđěxěŕ, i tried that however, and i input f lets just say, i get error Unhandled Exception: System.InvalidCastException: Conversion from string "f" to type 'Integer' is not valid

    – loco3424
    Mar 27 at 20:56













  • 1





    If Not Integer.TryParse(b, New Integer) Then.... This is a quick solution and would suit what you are looking for. Please see more there about the TryParse...

    – Çöđěxěŕ
    Mar 27 at 20:40












  • @Çöđěxěŕ, i tried that however, and i input f lets just say, i get error Unhandled Exception: System.InvalidCastException: Conversion from string "f" to type 'Integer' is not valid

    – loco3424
    Mar 27 at 20:56








1




1





If Not Integer.TryParse(b, New Integer) Then.... This is a quick solution and would suit what you are looking for. Please see more there about the TryParse...

– Çöđěxěŕ
Mar 27 at 20:40






If Not Integer.TryParse(b, New Integer) Then.... This is a quick solution and would suit what you are looking for. Please see more there about the TryParse...

– Çöđěxěŕ
Mar 27 at 20:40














@Çöđěxěŕ, i tried that however, and i input f lets just say, i get error Unhandled Exception: System.InvalidCastException: Conversion from string "f" to type 'Integer' is not valid

– loco3424
Mar 27 at 20:56






@Çöđěxěŕ, i tried that however, and i input f lets just say, i get error Unhandled Exception: System.InvalidCastException: Conversion from string "f" to type 'Integer' is not valid

– loco3424
Mar 27 at 20:56













1 Answer
1






active

oldest

votes


















0















Look into Integer.TryParse, it will try and parse the string into a integer if it can, if it can't it wont throw an exception...



 Dim b As Integer
Console.WriteLine("Please input the value of, B:")
If Not Integer.TryParse(Console.ReadLine(), b) Then
Console.WriteLine("Value entered must be a number")
GoTo Line98
End If


If it can parse the input from the user, then b would be the value from the parse, otherwise the value of b is still 0...



Edit Per Comment



Dim b As Integer
Do Until b > 0
Console.WriteLine("Please input the value of, B:")
If Not Integer.TryParse(Console.ReadLine(), b) OrElse b <= 0 Then
Console.WriteLine("Value entered must be a number and not equal 0")
GoTo Line98
End If
Loop





share|improve this answer



























  • @codexer one more question bro, If (a = 0) Then Console.WriteLine("Error, number can not be 0, Please Try Again!") GoTo line93 'This will ask for input A again, and repeat the process until a is not 0 End If If Not Integer.TryParse(Console.ReadLine(), a) Then Console.WriteLine(vbLf & "Error: Value entered must be a number") GoTo line93 End If, how would i combine these two

    – loco3424
    Mar 27 at 21:06











  • @loco3424 with that statement than a/b can be less than 0. In your post you said numbers could be negative... Also if you have further questions please ask another one seperate from the original. Also if this has helped, please vote and accept if this solved your issue so others know this worked.

    – Çöđěxěŕ
    Mar 27 at 21:16











  • @codexer, yes sorry a can not be a negative, however problem with your code if i input a valid number it tells me Value entered must be a number and greater than 0 then continues, please help

    – loco3424
    Mar 27 at 21:18











  • I am confused, it seems you keep changing what you are asking. The current code will make sure a user enters a valid number and also make sure that number is greater than 0, if not it loops again...

    – Çöđěxěŕ
    Mar 27 at 21:22











  • @codexer, yes however before continuing it tells me Value entered must be a number and greater than 0 then continues despite me entering 9

    – loco3424
    Mar 27 at 21:23










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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0















Look into Integer.TryParse, it will try and parse the string into a integer if it can, if it can't it wont throw an exception...



 Dim b As Integer
Console.WriteLine("Please input the value of, B:")
If Not Integer.TryParse(Console.ReadLine(), b) Then
Console.WriteLine("Value entered must be a number")
GoTo Line98
End If


If it can parse the input from the user, then b would be the value from the parse, otherwise the value of b is still 0...



Edit Per Comment



Dim b As Integer
Do Until b > 0
Console.WriteLine("Please input the value of, B:")
If Not Integer.TryParse(Console.ReadLine(), b) OrElse b <= 0 Then
Console.WriteLine("Value entered must be a number and not equal 0")
GoTo Line98
End If
Loop





share|improve this answer



























  • @codexer one more question bro, If (a = 0) Then Console.WriteLine("Error, number can not be 0, Please Try Again!") GoTo line93 'This will ask for input A again, and repeat the process until a is not 0 End If If Not Integer.TryParse(Console.ReadLine(), a) Then Console.WriteLine(vbLf & "Error: Value entered must be a number") GoTo line93 End If, how would i combine these two

    – loco3424
    Mar 27 at 21:06











  • @loco3424 with that statement than a/b can be less than 0. In your post you said numbers could be negative... Also if you have further questions please ask another one seperate from the original. Also if this has helped, please vote and accept if this solved your issue so others know this worked.

    – Çöđěxěŕ
    Mar 27 at 21:16











  • @codexer, yes sorry a can not be a negative, however problem with your code if i input a valid number it tells me Value entered must be a number and greater than 0 then continues, please help

    – loco3424
    Mar 27 at 21:18











  • I am confused, it seems you keep changing what you are asking. The current code will make sure a user enters a valid number and also make sure that number is greater than 0, if not it loops again...

    – Çöđěxěŕ
    Mar 27 at 21:22











  • @codexer, yes however before continuing it tells me Value entered must be a number and greater than 0 then continues despite me entering 9

    – loco3424
    Mar 27 at 21:23















0















Look into Integer.TryParse, it will try and parse the string into a integer if it can, if it can't it wont throw an exception...



 Dim b As Integer
Console.WriteLine("Please input the value of, B:")
If Not Integer.TryParse(Console.ReadLine(), b) Then
Console.WriteLine("Value entered must be a number")
GoTo Line98
End If


If it can parse the input from the user, then b would be the value from the parse, otherwise the value of b is still 0...



Edit Per Comment



Dim b As Integer
Do Until b > 0
Console.WriteLine("Please input the value of, B:")
If Not Integer.TryParse(Console.ReadLine(), b) OrElse b <= 0 Then
Console.WriteLine("Value entered must be a number and not equal 0")
GoTo Line98
End If
Loop





share|improve this answer



























  • @codexer one more question bro, If (a = 0) Then Console.WriteLine("Error, number can not be 0, Please Try Again!") GoTo line93 'This will ask for input A again, and repeat the process until a is not 0 End If If Not Integer.TryParse(Console.ReadLine(), a) Then Console.WriteLine(vbLf & "Error: Value entered must be a number") GoTo line93 End If, how would i combine these two

    – loco3424
    Mar 27 at 21:06











  • @loco3424 with that statement than a/b can be less than 0. In your post you said numbers could be negative... Also if you have further questions please ask another one seperate from the original. Also if this has helped, please vote and accept if this solved your issue so others know this worked.

    – Çöđěxěŕ
    Mar 27 at 21:16











  • @codexer, yes sorry a can not be a negative, however problem with your code if i input a valid number it tells me Value entered must be a number and greater than 0 then continues, please help

    – loco3424
    Mar 27 at 21:18











  • I am confused, it seems you keep changing what you are asking. The current code will make sure a user enters a valid number and also make sure that number is greater than 0, if not it loops again...

    – Çöđěxěŕ
    Mar 27 at 21:22











  • @codexer, yes however before continuing it tells me Value entered must be a number and greater than 0 then continues despite me entering 9

    – loco3424
    Mar 27 at 21:23













0














0










0









Look into Integer.TryParse, it will try and parse the string into a integer if it can, if it can't it wont throw an exception...



 Dim b As Integer
Console.WriteLine("Please input the value of, B:")
If Not Integer.TryParse(Console.ReadLine(), b) Then
Console.WriteLine("Value entered must be a number")
GoTo Line98
End If


If it can parse the input from the user, then b would be the value from the parse, otherwise the value of b is still 0...



Edit Per Comment



Dim b As Integer
Do Until b > 0
Console.WriteLine("Please input the value of, B:")
If Not Integer.TryParse(Console.ReadLine(), b) OrElse b <= 0 Then
Console.WriteLine("Value entered must be a number and not equal 0")
GoTo Line98
End If
Loop





share|improve this answer















Look into Integer.TryParse, it will try and parse the string into a integer if it can, if it can't it wont throw an exception...



 Dim b As Integer
Console.WriteLine("Please input the value of, B:")
If Not Integer.TryParse(Console.ReadLine(), b) Then
Console.WriteLine("Value entered must be a number")
GoTo Line98
End If


If it can parse the input from the user, then b would be the value from the parse, otherwise the value of b is still 0...



Edit Per Comment



Dim b As Integer
Do Until b > 0
Console.WriteLine("Please input the value of, B:")
If Not Integer.TryParse(Console.ReadLine(), b) OrElse b <= 0 Then
Console.WriteLine("Value entered must be a number and not equal 0")
GoTo Line98
End If
Loop






share|improve this answer














share|improve this answer



share|improve this answer








edited Mar 27 at 21:20

























answered Mar 27 at 20:58









ÇöđěxěŕÇöđěxěŕ

5,4315 gold badges21 silver badges44 bronze badges




5,4315 gold badges21 silver badges44 bronze badges















  • @codexer one more question bro, If (a = 0) Then Console.WriteLine("Error, number can not be 0, Please Try Again!") GoTo line93 'This will ask for input A again, and repeat the process until a is not 0 End If If Not Integer.TryParse(Console.ReadLine(), a) Then Console.WriteLine(vbLf & "Error: Value entered must be a number") GoTo line93 End If, how would i combine these two

    – loco3424
    Mar 27 at 21:06











  • @loco3424 with that statement than a/b can be less than 0. In your post you said numbers could be negative... Also if you have further questions please ask another one seperate from the original. Also if this has helped, please vote and accept if this solved your issue so others know this worked.

    – Çöđěxěŕ
    Mar 27 at 21:16











  • @codexer, yes sorry a can not be a negative, however problem with your code if i input a valid number it tells me Value entered must be a number and greater than 0 then continues, please help

    – loco3424
    Mar 27 at 21:18











  • I am confused, it seems you keep changing what you are asking. The current code will make sure a user enters a valid number and also make sure that number is greater than 0, if not it loops again...

    – Çöđěxěŕ
    Mar 27 at 21:22











  • @codexer, yes however before continuing it tells me Value entered must be a number and greater than 0 then continues despite me entering 9

    – loco3424
    Mar 27 at 21:23

















  • @codexer one more question bro, If (a = 0) Then Console.WriteLine("Error, number can not be 0, Please Try Again!") GoTo line93 'This will ask for input A again, and repeat the process until a is not 0 End If If Not Integer.TryParse(Console.ReadLine(), a) Then Console.WriteLine(vbLf & "Error: Value entered must be a number") GoTo line93 End If, how would i combine these two

    – loco3424
    Mar 27 at 21:06











  • @loco3424 with that statement than a/b can be less than 0. In your post you said numbers could be negative... Also if you have further questions please ask another one seperate from the original. Also if this has helped, please vote and accept if this solved your issue so others know this worked.

    – Çöđěxěŕ
    Mar 27 at 21:16











  • @codexer, yes sorry a can not be a negative, however problem with your code if i input a valid number it tells me Value entered must be a number and greater than 0 then continues, please help

    – loco3424
    Mar 27 at 21:18











  • I am confused, it seems you keep changing what you are asking. The current code will make sure a user enters a valid number and also make sure that number is greater than 0, if not it loops again...

    – Çöđěxěŕ
    Mar 27 at 21:22











  • @codexer, yes however before continuing it tells me Value entered must be a number and greater than 0 then continues despite me entering 9

    – loco3424
    Mar 27 at 21:23
















@codexer one more question bro, If (a = 0) Then Console.WriteLine("Error, number can not be 0, Please Try Again!") GoTo line93 'This will ask for input A again, and repeat the process until a is not 0 End If If Not Integer.TryParse(Console.ReadLine(), a) Then Console.WriteLine(vbLf & "Error: Value entered must be a number") GoTo line93 End If, how would i combine these two

– loco3424
Mar 27 at 21:06





@codexer one more question bro, If (a = 0) Then Console.WriteLine("Error, number can not be 0, Please Try Again!") GoTo line93 'This will ask for input A again, and repeat the process until a is not 0 End If If Not Integer.TryParse(Console.ReadLine(), a) Then Console.WriteLine(vbLf & "Error: Value entered must be a number") GoTo line93 End If, how would i combine these two

– loco3424
Mar 27 at 21:06













@loco3424 with that statement than a/b can be less than 0. In your post you said numbers could be negative... Also if you have further questions please ask another one seperate from the original. Also if this has helped, please vote and accept if this solved your issue so others know this worked.

– Çöđěxěŕ
Mar 27 at 21:16





@loco3424 with that statement than a/b can be less than 0. In your post you said numbers could be negative... Also if you have further questions please ask another one seperate from the original. Also if this has helped, please vote and accept if this solved your issue so others know this worked.

– Çöđěxěŕ
Mar 27 at 21:16













@codexer, yes sorry a can not be a negative, however problem with your code if i input a valid number it tells me Value entered must be a number and greater than 0 then continues, please help

– loco3424
Mar 27 at 21:18





@codexer, yes sorry a can not be a negative, however problem with your code if i input a valid number it tells me Value entered must be a number and greater than 0 then continues, please help

– loco3424
Mar 27 at 21:18













I am confused, it seems you keep changing what you are asking. The current code will make sure a user enters a valid number and also make sure that number is greater than 0, if not it loops again...

– Çöđěxěŕ
Mar 27 at 21:22





I am confused, it seems you keep changing what you are asking. The current code will make sure a user enters a valid number and also make sure that number is greater than 0, if not it loops again...

– Çöđěxěŕ
Mar 27 at 21:22













@codexer, yes however before continuing it tells me Value entered must be a number and greater than 0 then continues despite me entering 9

– loco3424
Mar 27 at 21:23





@codexer, yes however before continuing it tells me Value entered must be a number and greater than 0 then continues despite me entering 9

– loco3424
Mar 27 at 21:23








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