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Sql: cannot drop foreign key due to auto-generated constraint
Show constraints on tables commandHow to add a column and make it a foreign key in single MySQL statement?How can foreign key constraints be temporarily disabled using T-SQL?Mysql error 1452 - Cannot add or update a child row: a foreign key constraint failsForce drop mysql bypassing foreign key constraintBogus foreign key constraint failMySQL DROP all tables, ignoring foreign keysForeign key constraints: When to use ON UPDATE and ON DELETEAdd Foreign Key to existing table(Mysql Error: #1215 - Cannot add foreign key constraint) for my programCannot add foreign key constraintLaravel migration - Integrity constraint violation: 1452 Cannot add or update a child row: a foreign key constraint fails
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
I have a foreign key that was generated with the following command in an old and already deployed migration:
ALTER TABLE `job_template`
ADD COLUMN `parent_id` BIGINT,
ADD FOREIGN KEY fk_job_template_parent_id(parent_id) REFERENCES job_template(id) ON DELETE CASCADE;
Now I am trying to drop this foreign key with following command:
ALTER TABLE job_template DROP FOREIGN KEY fk_job_template_parent_id;
The problem is that this works for mariaDB but not for mySQL and I need a migration that would work in both cases
If I list the SHOW CREATE TABLE command (before the deleting of the foreign key) from both environments I get the following:
mariaDB:
constraint fk_job_template_parent_id foreign key (parent_id) references job_template (id) on delete cascade,
mysql:
constraint job_template_ibfk_5 foreign key (parent_id) references job_template (id) on delete cascade,
The constraint names are different in the 2 environments, and thus I have no way to write a migration that would consistently drop this foreign key.
Is there any way to get around this situation?
mysql foreign-keys mariadb
add a comment |
I have a foreign key that was generated with the following command in an old and already deployed migration:
ALTER TABLE `job_template`
ADD COLUMN `parent_id` BIGINT,
ADD FOREIGN KEY fk_job_template_parent_id(parent_id) REFERENCES job_template(id) ON DELETE CASCADE;
Now I am trying to drop this foreign key with following command:
ALTER TABLE job_template DROP FOREIGN KEY fk_job_template_parent_id;
The problem is that this works for mariaDB but not for mySQL and I need a migration that would work in both cases
If I list the SHOW CREATE TABLE command (before the deleting of the foreign key) from both environments I get the following:
mariaDB:
constraint fk_job_template_parent_id foreign key (parent_id) references job_template (id) on delete cascade,
mysql:
constraint job_template_ibfk_5 foreign key (parent_id) references job_template (id) on delete cascade,
The constraint names are different in the 2 environments, and thus I have no way to write a migration that would consistently drop this foreign key.
Is there any way to get around this situation?
mysql foreign-keys mariadb
add a comment |
I have a foreign key that was generated with the following command in an old and already deployed migration:
ALTER TABLE `job_template`
ADD COLUMN `parent_id` BIGINT,
ADD FOREIGN KEY fk_job_template_parent_id(parent_id) REFERENCES job_template(id) ON DELETE CASCADE;
Now I am trying to drop this foreign key with following command:
ALTER TABLE job_template DROP FOREIGN KEY fk_job_template_parent_id;
The problem is that this works for mariaDB but not for mySQL and I need a migration that would work in both cases
If I list the SHOW CREATE TABLE command (before the deleting of the foreign key) from both environments I get the following:
mariaDB:
constraint fk_job_template_parent_id foreign key (parent_id) references job_template (id) on delete cascade,
mysql:
constraint job_template_ibfk_5 foreign key (parent_id) references job_template (id) on delete cascade,
The constraint names are different in the 2 environments, and thus I have no way to write a migration that would consistently drop this foreign key.
Is there any way to get around this situation?
mysql foreign-keys mariadb
I have a foreign key that was generated with the following command in an old and already deployed migration:
ALTER TABLE `job_template`
ADD COLUMN `parent_id` BIGINT,
ADD FOREIGN KEY fk_job_template_parent_id(parent_id) REFERENCES job_template(id) ON DELETE CASCADE;
Now I am trying to drop this foreign key with following command:
ALTER TABLE job_template DROP FOREIGN KEY fk_job_template_parent_id;
The problem is that this works for mariaDB but not for mySQL and I need a migration that would work in both cases
If I list the SHOW CREATE TABLE command (before the deleting of the foreign key) from both environments I get the following:
mariaDB:
constraint fk_job_template_parent_id foreign key (parent_id) references job_template (id) on delete cascade,
mysql:
constraint job_template_ibfk_5 foreign key (parent_id) references job_template (id) on delete cascade,
The constraint names are different in the 2 environments, and thus I have no way to write a migration that would consistently drop this foreign key.
Is there any way to get around this situation?
mysql foreign-keys mariadb
mysql foreign-keys mariadb
asked Mar 27 at 10:21
Alkis MavridisAlkis Mavridis
3882 silver badges12 bronze badges
3882 silver badges12 bronze badges
add a comment |
add a comment |
1 Answer
1
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Your problem is that you are not explicitly naming your constraints. This leaves each database to pick a name for you. The trick here is to name your foreign key constraints explicitly, when you create the actual tables on both MySQL and MariaDB:
CREATE TABLE job_template (
...,
parent_id int NOT NULL,
CONSTRAINT your_constraint FOREIGN KEY fk_name (parent_id)
REFERENCES job_template(id) ON DELETE CASCADE
);
But fixing your immediate situation would require more work. One option would be to query the information schema table, for the table involved, to find out the actual constraint names:
USE INFORMATION_SCHEMA;
SELECT
TABLE_NAME,
COLUMN_NAME,
CONSTRAINT_NAME,
REFERENCED_TABLE_NAME,
REFERENCED_COLUMN_NAME
FROM KEY_COLUMN_USAGE
WHERE
TABLE_SCHEMA = 'your_db' AND
TABLE_NAME = 'job_template' AND
REFERENCED_COLUMN_NAME IS NOT NULL;
This should return one record for every column and constraint. With this information, you should be able to run your current alter statements.
This is easy enough to do using a tool like Java, or something similar. If you want to do this directly from the database, then you would need dynamic SQL, which probably means writing a stored procedure.
Right, I will use this in the future. But can I somehow solve the current situation?
– Alkis Mavridis
Mar 27 at 10:32
That might not be so easy. You might have to query one of the information schema tables to find the actual constraint name, and then drop it. But that would take dynamic SQL.
– Tim Biegeleisen
Mar 27 at 10:34
dynamic SQL is unfortunately no option. Thanks for the answer, anyway.
– Alkis Mavridis
Mar 27 at 10:44
As I described, the create statement is already deployed and I cannot modify it. Thus, I am hoping that someone can suggest a solution or workaround for my current situation. You comment is a very good advice for the future and thanks for that, but it is not really an answer to my question.
– Alkis Mavridis
Mar 27 at 10:52
1
See here to get started. If you have access to something like Java, it would not be too much trouble to write a short script to handle this.
– Tim Biegeleisen
Mar 27 at 10:56
|
show 3 more comments
Your Answer
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Your problem is that you are not explicitly naming your constraints. This leaves each database to pick a name for you. The trick here is to name your foreign key constraints explicitly, when you create the actual tables on both MySQL and MariaDB:
CREATE TABLE job_template (
...,
parent_id int NOT NULL,
CONSTRAINT your_constraint FOREIGN KEY fk_name (parent_id)
REFERENCES job_template(id) ON DELETE CASCADE
);
But fixing your immediate situation would require more work. One option would be to query the information schema table, for the table involved, to find out the actual constraint names:
USE INFORMATION_SCHEMA;
SELECT
TABLE_NAME,
COLUMN_NAME,
CONSTRAINT_NAME,
REFERENCED_TABLE_NAME,
REFERENCED_COLUMN_NAME
FROM KEY_COLUMN_USAGE
WHERE
TABLE_SCHEMA = 'your_db' AND
TABLE_NAME = 'job_template' AND
REFERENCED_COLUMN_NAME IS NOT NULL;
This should return one record for every column and constraint. With this information, you should be able to run your current alter statements.
This is easy enough to do using a tool like Java, or something similar. If you want to do this directly from the database, then you would need dynamic SQL, which probably means writing a stored procedure.
Right, I will use this in the future. But can I somehow solve the current situation?
– Alkis Mavridis
Mar 27 at 10:32
That might not be so easy. You might have to query one of the information schema tables to find the actual constraint name, and then drop it. But that would take dynamic SQL.
– Tim Biegeleisen
Mar 27 at 10:34
dynamic SQL is unfortunately no option. Thanks for the answer, anyway.
– Alkis Mavridis
Mar 27 at 10:44
As I described, the create statement is already deployed and I cannot modify it. Thus, I am hoping that someone can suggest a solution or workaround for my current situation. You comment is a very good advice for the future and thanks for that, but it is not really an answer to my question.
– Alkis Mavridis
Mar 27 at 10:52
1
See here to get started. If you have access to something like Java, it would not be too much trouble to write a short script to handle this.
– Tim Biegeleisen
Mar 27 at 10:56
|
show 3 more comments
Your problem is that you are not explicitly naming your constraints. This leaves each database to pick a name for you. The trick here is to name your foreign key constraints explicitly, when you create the actual tables on both MySQL and MariaDB:
CREATE TABLE job_template (
...,
parent_id int NOT NULL,
CONSTRAINT your_constraint FOREIGN KEY fk_name (parent_id)
REFERENCES job_template(id) ON DELETE CASCADE
);
But fixing your immediate situation would require more work. One option would be to query the information schema table, for the table involved, to find out the actual constraint names:
USE INFORMATION_SCHEMA;
SELECT
TABLE_NAME,
COLUMN_NAME,
CONSTRAINT_NAME,
REFERENCED_TABLE_NAME,
REFERENCED_COLUMN_NAME
FROM KEY_COLUMN_USAGE
WHERE
TABLE_SCHEMA = 'your_db' AND
TABLE_NAME = 'job_template' AND
REFERENCED_COLUMN_NAME IS NOT NULL;
This should return one record for every column and constraint. With this information, you should be able to run your current alter statements.
This is easy enough to do using a tool like Java, or something similar. If you want to do this directly from the database, then you would need dynamic SQL, which probably means writing a stored procedure.
Right, I will use this in the future. But can I somehow solve the current situation?
– Alkis Mavridis
Mar 27 at 10:32
That might not be so easy. You might have to query one of the information schema tables to find the actual constraint name, and then drop it. But that would take dynamic SQL.
– Tim Biegeleisen
Mar 27 at 10:34
dynamic SQL is unfortunately no option. Thanks for the answer, anyway.
– Alkis Mavridis
Mar 27 at 10:44
As I described, the create statement is already deployed and I cannot modify it. Thus, I am hoping that someone can suggest a solution or workaround for my current situation. You comment is a very good advice for the future and thanks for that, but it is not really an answer to my question.
– Alkis Mavridis
Mar 27 at 10:52
1
See here to get started. If you have access to something like Java, it would not be too much trouble to write a short script to handle this.
– Tim Biegeleisen
Mar 27 at 10:56
|
show 3 more comments
Your problem is that you are not explicitly naming your constraints. This leaves each database to pick a name for you. The trick here is to name your foreign key constraints explicitly, when you create the actual tables on both MySQL and MariaDB:
CREATE TABLE job_template (
...,
parent_id int NOT NULL,
CONSTRAINT your_constraint FOREIGN KEY fk_name (parent_id)
REFERENCES job_template(id) ON DELETE CASCADE
);
But fixing your immediate situation would require more work. One option would be to query the information schema table, for the table involved, to find out the actual constraint names:
USE INFORMATION_SCHEMA;
SELECT
TABLE_NAME,
COLUMN_NAME,
CONSTRAINT_NAME,
REFERENCED_TABLE_NAME,
REFERENCED_COLUMN_NAME
FROM KEY_COLUMN_USAGE
WHERE
TABLE_SCHEMA = 'your_db' AND
TABLE_NAME = 'job_template' AND
REFERENCED_COLUMN_NAME IS NOT NULL;
This should return one record for every column and constraint. With this information, you should be able to run your current alter statements.
This is easy enough to do using a tool like Java, or something similar. If you want to do this directly from the database, then you would need dynamic SQL, which probably means writing a stored procedure.
Your problem is that you are not explicitly naming your constraints. This leaves each database to pick a name for you. The trick here is to name your foreign key constraints explicitly, when you create the actual tables on both MySQL and MariaDB:
CREATE TABLE job_template (
...,
parent_id int NOT NULL,
CONSTRAINT your_constraint FOREIGN KEY fk_name (parent_id)
REFERENCES job_template(id) ON DELETE CASCADE
);
But fixing your immediate situation would require more work. One option would be to query the information schema table, for the table involved, to find out the actual constraint names:
USE INFORMATION_SCHEMA;
SELECT
TABLE_NAME,
COLUMN_NAME,
CONSTRAINT_NAME,
REFERENCED_TABLE_NAME,
REFERENCED_COLUMN_NAME
FROM KEY_COLUMN_USAGE
WHERE
TABLE_SCHEMA = 'your_db' AND
TABLE_NAME = 'job_template' AND
REFERENCED_COLUMN_NAME IS NOT NULL;
This should return one record for every column and constraint. With this information, you should be able to run your current alter statements.
This is easy enough to do using a tool like Java, or something similar. If you want to do this directly from the database, then you would need dynamic SQL, which probably means writing a stored procedure.
edited Mar 27 at 11:13
answered Mar 27 at 10:30
Tim BiegeleisenTim Biegeleisen
266k13 gold badges114 silver badges175 bronze badges
266k13 gold badges114 silver badges175 bronze badges
Right, I will use this in the future. But can I somehow solve the current situation?
– Alkis Mavridis
Mar 27 at 10:32
That might not be so easy. You might have to query one of the information schema tables to find the actual constraint name, and then drop it. But that would take dynamic SQL.
– Tim Biegeleisen
Mar 27 at 10:34
dynamic SQL is unfortunately no option. Thanks for the answer, anyway.
– Alkis Mavridis
Mar 27 at 10:44
As I described, the create statement is already deployed and I cannot modify it. Thus, I am hoping that someone can suggest a solution or workaround for my current situation. You comment is a very good advice for the future and thanks for that, but it is not really an answer to my question.
– Alkis Mavridis
Mar 27 at 10:52
1
See here to get started. If you have access to something like Java, it would not be too much trouble to write a short script to handle this.
– Tim Biegeleisen
Mar 27 at 10:56
|
show 3 more comments
Right, I will use this in the future. But can I somehow solve the current situation?
– Alkis Mavridis
Mar 27 at 10:32
That might not be so easy. You might have to query one of the information schema tables to find the actual constraint name, and then drop it. But that would take dynamic SQL.
– Tim Biegeleisen
Mar 27 at 10:34
dynamic SQL is unfortunately no option. Thanks for the answer, anyway.
– Alkis Mavridis
Mar 27 at 10:44
As I described, the create statement is already deployed and I cannot modify it. Thus, I am hoping that someone can suggest a solution or workaround for my current situation. You comment is a very good advice for the future and thanks for that, but it is not really an answer to my question.
– Alkis Mavridis
Mar 27 at 10:52
1
See here to get started. If you have access to something like Java, it would not be too much trouble to write a short script to handle this.
– Tim Biegeleisen
Mar 27 at 10:56
Right, I will use this in the future. But can I somehow solve the current situation?
– Alkis Mavridis
Mar 27 at 10:32
Right, I will use this in the future. But can I somehow solve the current situation?
– Alkis Mavridis
Mar 27 at 10:32
That might not be so easy. You might have to query one of the information schema tables to find the actual constraint name, and then drop it. But that would take dynamic SQL.
– Tim Biegeleisen
Mar 27 at 10:34
That might not be so easy. You might have to query one of the information schema tables to find the actual constraint name, and then drop it. But that would take dynamic SQL.
– Tim Biegeleisen
Mar 27 at 10:34
dynamic SQL is unfortunately no option. Thanks for the answer, anyway.
– Alkis Mavridis
Mar 27 at 10:44
dynamic SQL is unfortunately no option. Thanks for the answer, anyway.
– Alkis Mavridis
Mar 27 at 10:44
As I described, the create statement is already deployed and I cannot modify it. Thus, I am hoping that someone can suggest a solution or workaround for my current situation. You comment is a very good advice for the future and thanks for that, but it is not really an answer to my question.
– Alkis Mavridis
Mar 27 at 10:52
As I described, the create statement is already deployed and I cannot modify it. Thus, I am hoping that someone can suggest a solution or workaround for my current situation. You comment is a very good advice for the future and thanks for that, but it is not really an answer to my question.
– Alkis Mavridis
Mar 27 at 10:52
1
1
See here to get started. If you have access to something like Java, it would not be too much trouble to write a short script to handle this.
– Tim Biegeleisen
Mar 27 at 10:56
See here to get started. If you have access to something like Java, it would not be too much trouble to write a short script to handle this.
– Tim Biegeleisen
Mar 27 at 10:56
|
show 3 more comments
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