How to create an array of structs of arbitrary size cython The Next CEO of Stack OverflowCython: creating an array throws “not allowed in a constant expression”Cython recursive struct declarationsgetting struct elements in CythonCreating C structs in CythonHow to use a cython definition file (pxd) without making it an extension ?Cython Memoryviews — From Array of Structs?Cython C-array initializationCython: create struct and only keep pointer to itReturning an array of structs in CythonIssue converting a python program to cython for speedupHow to initialize a struct to NULL in cython?
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How to create an array of structs of arbitrary size cython
The Next CEO of Stack OverflowCython: creating an array throws “not allowed in a constant expression”Cython recursive struct declarationsgetting struct elements in CythonCreating C structs in CythonHow to use a cython definition file (pxd) without making it an extension ?Cython Memoryviews — From Array of Structs?Cython C-array initializationCython: create struct and only keep pointer to itReturning an array of structs in CythonIssue converting a python program to cython for speedupHow to initialize a struct to NULL in cython?
I would like to know how can I create an array of structs in Cython that I can populate and make computations afterwards.
Example
Here I have the Cython code
%%cython
cimport numpy as cnp
cimport cython
from collections import namedtuple
Couple = namedtuple('Couple', ['female', 'male'], verbose=False)
cdef struct CyCouple:
int female
int male
cpdef int np_cy_count_women_earning_more2(list py_couples):
cdef:
int count = 0, r, N
CyCouple cy_couples[100_0000] # THIS IS HARDCODED
N = len(py_couples)
make_CyCouple_array(py_couples, cy_couples, N)
for n in range(N):
r = cy_couples[n].female > cy_couples[n].male
count += r
return count
I would like to have a general versions instead of the definition in # THIS IS HARDCODED.
What could I do?
cython
add a comment |
I would like to know how can I create an array of structs in Cython that I can populate and make computations afterwards.
Example
Here I have the Cython code
%%cython
cimport numpy as cnp
cimport cython
from collections import namedtuple
Couple = namedtuple('Couple', ['female', 'male'], verbose=False)
cdef struct CyCouple:
int female
int male
cpdef int np_cy_count_women_earning_more2(list py_couples):
cdef:
int count = 0, r, N
CyCouple cy_couples[100_0000] # THIS IS HARDCODED
N = len(py_couples)
make_CyCouple_array(py_couples, cy_couples, N)
for n in range(N):
r = cy_couples[n].female > cy_couples[n].male
count += r
return count
I would like to have a general versions instead of the definition in # THIS IS HARDCODED.
What could I do?
cython
There is a lot of unnecessary code, if all you want to know is how to dynamically allocate cy_couples!
– ead
Mar 21 at 19:30
Possible duplicate of Cython: creating an array throws "not allowed in a constant expression"
– DavidW
Mar 21 at 19:42
add a comment |
I would like to know how can I create an array of structs in Cython that I can populate and make computations afterwards.
Example
Here I have the Cython code
%%cython
cimport numpy as cnp
cimport cython
from collections import namedtuple
Couple = namedtuple('Couple', ['female', 'male'], verbose=False)
cdef struct CyCouple:
int female
int male
cpdef int np_cy_count_women_earning_more2(list py_couples):
cdef:
int count = 0, r, N
CyCouple cy_couples[100_0000] # THIS IS HARDCODED
N = len(py_couples)
make_CyCouple_array(py_couples, cy_couples, N)
for n in range(N):
r = cy_couples[n].female > cy_couples[n].male
count += r
return count
I would like to have a general versions instead of the definition in # THIS IS HARDCODED.
What could I do?
cython
I would like to know how can I create an array of structs in Cython that I can populate and make computations afterwards.
Example
Here I have the Cython code
%%cython
cimport numpy as cnp
cimport cython
from collections import namedtuple
Couple = namedtuple('Couple', ['female', 'male'], verbose=False)
cdef struct CyCouple:
int female
int male
cpdef int np_cy_count_women_earning_more2(list py_couples):
cdef:
int count = 0, r, N
CyCouple cy_couples[100_0000] # THIS IS HARDCODED
N = len(py_couples)
make_CyCouple_array(py_couples, cy_couples, N)
for n in range(N):
r = cy_couples[n].female > cy_couples[n].male
count += r
return count
I would like to have a general versions instead of the definition in # THIS IS HARDCODED.
What could I do?
cython
cython
edited Mar 21 at 19:33
David Buchaca
asked Mar 21 at 19:09
David BuchacaDavid Buchaca
1113
1113
There is a lot of unnecessary code, if all you want to know is how to dynamically allocate cy_couples!
– ead
Mar 21 at 19:30
Possible duplicate of Cython: creating an array throws "not allowed in a constant expression"
– DavidW
Mar 21 at 19:42
add a comment |
There is a lot of unnecessary code, if all you want to know is how to dynamically allocate cy_couples!
– ead
Mar 21 at 19:30
Possible duplicate of Cython: creating an array throws "not allowed in a constant expression"
– DavidW
Mar 21 at 19:42
There is a lot of unnecessary code, if all you want to know is how to dynamically allocate cy_couples!
– ead
Mar 21 at 19:30
There is a lot of unnecessary code, if all you want to know is how to dynamically allocate cy_couples!
– ead
Mar 21 at 19:30
Possible duplicate of Cython: creating an array throws "not allowed in a constant expression"
– DavidW
Mar 21 at 19:42
Possible duplicate of Cython: creating an array throws "not allowed in a constant expression"
– DavidW
Mar 21 at 19:42
add a comment |
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There is a lot of unnecessary code, if all you want to know is how to dynamically allocate cy_couples!
– ead
Mar 21 at 19:30
Possible duplicate of Cython: creating an array throws "not allowed in a constant expression"
– DavidW
Mar 21 at 19:42