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Catching only *one* KeyboardInterruptException
Catch multiple exceptions at once?The case against checked exceptionsGlobally catch exceptions in a WPF application?Catching / blocking SIGINT during system callCan I catch multiple Java exceptions in the same catch clause?Catch multiple exceptions in one line (except block)grep, but only certain file extensionsa custom interrupt handler for mpirunHow to ignore keyboardInterrupt Exception in a module and deal with it in higher level in winpexpet?python picamera, keyboard ctrl+c/sigint not caught
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I have a long-running task that may be interrupted because an exception is raised inside it, or because Control+C is pressed signaling a SIGINT, raising a KeyboardInterruptException.
In both of these cases, the path to follow is to store the results that are already processed by the task, to prevent the lose of the computing time. This store takes some time, as it may need to process a good amount of information. The problem appears when Control+C is pressed again when the interrupt has already been caught.
Example:
task = SomeTask()
try:
task.start()
except KeyboardInterruptException:
print("Keyboard interrupted")
except Exception as e:
print_exception(e) # To show what happened
finally:
task.store_results() # If Control-C is pressed here, data gets corrupted
I need a way to catch the interrupt, launch the store process and prevent another interrupt from happening.
python unix exception keyboardinterrupt
asked Mar 22 at 17:36
0xfede7c80xfede7c8
31
add a comment |
I have a long-running task that may be interrupted because an exception is raised inside it, or because Control+C is pressed signaling a SIGINT, raising a KeyboardInterruptException.
In both of these cases, the path to follow is to store the results that are already processed by the task, to prevent the lose of the computing time. This store takes some time, as it may need to process a good amount of information. The problem appears when Control+C is pressed again when the interrupt has already been caught.
Example:
task = SomeTask()
try:
task.start()
except KeyboardInterruptException:
print("Keyboard interrupted")
except Exception as e:
print_exception(e) # To show what happened
finally:
task.store_results() # If Control-C is pressed here, data gets corrupted
I need a way to catch the interrupt, launch the store process and prevent another interrupt from happening.
python unix exception keyboardinterrupt
asked Mar 22 at 17:36
0xfede7c80xfede7c8
31
Suggest you add and OS tag to your question—because handlingSIGINTvaries depending on what operating system you're using.
– martineau
Mar 22 at 18:15
add a comment |
I have a long-running task that may be interrupted because an exception is raised inside it, or because Control+C is pressed signaling a SIGINT, raising a KeyboardInterruptException.
In both of these cases, the path to follow is to store the results that are already processed by the task, to prevent the lose of the computing time. This store takes some time, as it may need to process a good amount of information. The problem appears when Control+C is pressed again when the interrupt has already been caught.
Example:
task = SomeTask()
try:
task.start()
except KeyboardInterruptException:
print("Keyboard interrupted")
except Exception as e:
print_exception(e) # To show what happened
finally:
task.store_results() # If Control-C is pressed here, data gets corrupted
I need a way to catch the interrupt, launch the store process and prevent another interrupt from happening.
python unix exception keyboardinterrupt
asked Mar 22 at 17:36
0xfede7c80xfede7c8
31
I have a long-running task that may be interrupted because an exception is raised inside it, or because Control+C is pressed signaling a SIGINT, raising a KeyboardInterruptException.
In both of these cases, the path to follow is to store the results that are already processed by the task, to prevent the lose of the computing time. This store takes some time, as it may need to process a good amount of information. The problem appears when Control+C is pressed again when the interrupt has already been caught.
Example:
task = SomeTask()
try:
task.start()
except KeyboardInterruptException:
print("Keyboard interrupted")
except Exception as e:
print_exception(e) # To show what happened
finally:
task.store_results() # If Control-C is pressed here, data gets corrupted
I need a way to catch the interrupt, launch the store process and prevent another interrupt from happening.
python unix exception keyboardinterrupt
python unix exception keyboardinterrupt
asked Mar 22 at 17:36
0xfede7c80xfede7c8
31
asked Mar 22 at 17:36
0xfede7c80xfede7c8
31
edited Mar 22 at 19:16
0xfede7c8
asked Mar 22 at 17:36
0xfede7c80xfede7c8
31
asked Mar 22 at 17:36
0xfede7c80xfede7c8
31
asked Mar 22 at 17:36
0xfede7c80xfede7c8
31
31
Suggest you add and OS tag to your question—because handlingSIGINTvaries depending on what operating system you're using.
– martineau
Mar 22 at 18:15
add a comment |
Suggest you add and OS tag to your question—because handlingSIGINTvaries depending on what operating system you're using.
– martineau
Mar 22 at 18:15
Suggest you add and OS tag to your question—because handling
SIGINT varies depending on what operating system you're using.– martineau
Mar 22 at 18:15
Suggest you add and OS tag to your question—because handling
SIGINT varies depending on what operating system you're using.– martineau
Mar 22 at 18:15
add a comment |
1 Answer
1
active
oldest
votes
Just set the signal handler:
import signal
task = SomeTask()
try:
task.start()
except KeyboardInterruptException:
print("Keyboard interrupted")
except Exception as e:
print_exception(e) # To show what happened
finally:
signal.signal(signal.SIGINT, lamda *_: print('Wait!'))
task.store_results() # If Control-C is pressed here, data gets corrupted
Source: https://pythonadventures.wordpress.com/2012/11/21/handle-ctrlc-in-your-script/
answered Mar 22 at 17:50
ADRADR
767315
This did the trick for me. It has less side effects because the first time it enters through the try/except and then it disables the interrupt :) Thanks
– 0xfede7c8
Mar 22 at 19:17
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Just set the signal handler:
import signal
task = SomeTask()
try:
task.start()
except KeyboardInterruptException:
print("Keyboard interrupted")
except Exception as e:
print_exception(e) # To show what happened
finally:
signal.signal(signal.SIGINT, lamda *_: print('Wait!'))
task.store_results() # If Control-C is pressed here, data gets corrupted
Source: https://pythonadventures.wordpress.com/2012/11/21/handle-ctrlc-in-your-script/
answered Mar 22 at 17:50
ADRADR
767315
This did the trick for me. It has less side effects because the first time it enters through the try/except and then it disables the interrupt :) Thanks
– 0xfede7c8
Mar 22 at 19:17
add a comment |
Just set the signal handler:
import signal
task = SomeTask()
try:
task.start()
except KeyboardInterruptException:
print("Keyboard interrupted")
except Exception as e:
print_exception(e) # To show what happened
finally:
signal.signal(signal.SIGINT, lamda *_: print('Wait!'))
task.store_results() # If Control-C is pressed here, data gets corrupted
Source: https://pythonadventures.wordpress.com/2012/11/21/handle-ctrlc-in-your-script/
answered Mar 22 at 17:50
ADRADR
767315
This did the trick for me. It has less side effects because the first time it enters through the try/except and then it disables the interrupt :) Thanks
– 0xfede7c8
Mar 22 at 19:17
add a comment |
Just set the signal handler:
import signal
task = SomeTask()
try:
task.start()
except KeyboardInterruptException:
print("Keyboard interrupted")
except Exception as e:
print_exception(e) # To show what happened
finally:
signal.signal(signal.SIGINT, lamda *_: print('Wait!'))
task.store_results() # If Control-C is pressed here, data gets corrupted
Source: https://pythonadventures.wordpress.com/2012/11/21/handle-ctrlc-in-your-script/
answered Mar 22 at 17:50
ADRADR
767315
Just set the signal handler:
import signal
task = SomeTask()
try:
task.start()
except KeyboardInterruptException:
print("Keyboard interrupted")
except Exception as e:
print_exception(e) # To show what happened
finally:
signal.signal(signal.SIGINT, lamda *_: print('Wait!'))
task.store_results() # If Control-C is pressed here, data gets corrupted
Source: https://pythonadventures.wordpress.com/2012/11/21/handle-ctrlc-in-your-script/
answered Mar 22 at 17:50
ADRADR
767315
answered Mar 22 at 17:50
ADRADR
767315
answered Mar 22 at 17:50
ADRADR
767315
answered Mar 22 at 17:50
ADRADR
767315
767315
This did the trick for me. It has less side effects because the first time it enters through the try/except and then it disables the interrupt :) Thanks
– 0xfede7c8
Mar 22 at 19:17
add a comment |
This did the trick for me. It has less side effects because the first time it enters through the try/except and then it disables the interrupt :) Thanks
– 0xfede7c8
Mar 22 at 19:17
This did the trick for me. It has less side effects because the first time it enters through the try/except and then it disables the interrupt :) Thanks
– 0xfede7c8
Mar 22 at 19:17
This did the trick for me. It has less side effects because the first time it enters through the try/except and then it disables the interrupt :) Thanks
– 0xfede7c8
Mar 22 at 19:17
add a comment |
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Suggest you add and OS tag to your question—because handling
SIGINTvaries depending on what operating system you're using.– martineau
Mar 22 at 18:15