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Stripe-iOS backend method in Django to create ephemeral key?

Creating a JSON response using Django and PythonStripe: error messages when Creating a Customer &/or Charge - Ruby on RailsDjango Stripe API Key IssuesStripe Bad Request ErrorStripe cannot create Ephemeral KeyStripe Payment: Customer cus_***** does not have a linked card with ID card_*****Stripe with Firebase doesn't seem to find the ephemeral keysError 400 with Stripe iOS PaymentAndroid Stripe app crashes on adding new payment sourceStripe Integration with Parse

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0

I've been following Standard iOS Integration Guide of Stripe for my iOS app, which uses a backend written in Python-Django, to issue an ephemeral key.

This is the function I came up with in my views.py:

import stripe

stripe.api_key = "sk_test_Xf1yJ9qESRcCliM9iLoRmCIW"

def issue_key(request):
 if request.method == 'POST':
 api_version = request.POST.get('api_version')
 customerId = request.session['customerId']
 key = stripe.EphemeralKey.create(customer=customerId, api_version=api_version)
 return JsonResponse('key': key)
 else:
 return redirect("home:feed")

In my iOS app, I copied all the files from stripe-ios Standard Integration and filled in stripePublishableKey and backendBaseURL accordingly.

I'm also successfully creating a Stripe customer when a new user registers to my app, through Firebase Cloud Functions.

However, when CheckoutViewController loads, I get "Response status code was unacceptable: 404" error.

Assuming this error occurs while returning a JSON response from my backend, what is the correct code for the above method? Or am I missing something else on the Swift side?

Any suggestion or feedback will be welcomed and greatly appreciated.

Thank you.

python ios swift django stripe-payments

share|improve this question

asked Mar 22 at 17:13

steerrsteerr

3118

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You really shouldn't share secret keys on any public forum. Even if they are test keys. As for your issue, you should try to add more logging in your backend to see what is going on.
  
  – Paul Asjes
  Mar 25 at 3:27
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks for the feedback Paul. You are right about the secret key, but the key above is not the real one. I debugged further and the call doesn't hit my backend server: issue_key() doesn't run when CheckoutViewController loads. My backend base URL is steerr.com/issue-key. Any idea why?
  
  – steerr
  Mar 25 at 17:07
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Sounds like a routing problem. I'd check your backend framework and make sure that you've set it up correctly. As for the secret key, even a test key is dangerous to have in public as it allows malicious people to mess with your test data. If I were you I'd edit your question and remove the key entirely.
  
  – Paul Asjes
  Mar 26 at 4:41
  

  
  
  
  

add a comment | 

0

I've been following Standard iOS Integration Guide of Stripe for my iOS app, which uses a backend written in Python-Django, to issue an ephemeral key.

This is the function I came up with in my views.py:

import stripe

stripe.api_key = "sk_test_Xf1yJ9qESRcCliM9iLoRmCIW"

def issue_key(request):
 if request.method == 'POST':
 api_version = request.POST.get('api_version')
 customerId = request.session['customerId']
 key = stripe.EphemeralKey.create(customer=customerId, api_version=api_version)
 return JsonResponse('key': key)
 else:
 return redirect("home:feed")

In my iOS app, I copied all the files from stripe-ios Standard Integration and filled in stripePublishableKey and backendBaseURL accordingly.

I'm also successfully creating a Stripe customer when a new user registers to my app, through Firebase Cloud Functions.

However, when CheckoutViewController loads, I get "Response status code was unacceptable: 404" error.

Assuming this error occurs while returning a JSON response from my backend, what is the correct code for the above method? Or am I missing something else on the Swift side?

Any suggestion or feedback will be welcomed and greatly appreciated.

Thank you.

python ios swift django stripe-payments

share|improve this question

asked Mar 22 at 17:13

steerrsteerr

3118

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You really shouldn't share secret keys on any public forum. Even if they are test keys. As for your issue, you should try to add more logging in your backend to see what is going on.
  
  – Paul Asjes
  Mar 25 at 3:27
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks for the feedback Paul. You are right about the secret key, but the key above is not the real one. I debugged further and the call doesn't hit my backend server: issue_key() doesn't run when CheckoutViewController loads. My backend base URL is steerr.com/issue-key. Any idea why?
  
  – steerr
  Mar 25 at 17:07
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Sounds like a routing problem. I'd check your backend framework and make sure that you've set it up correctly. As for the secret key, even a test key is dangerous to have in public as it allows malicious people to mess with your test data. If I were you I'd edit your question and remove the key entirely.
  
  – Paul Asjes
  Mar 26 at 4:41
  

  
  
  
  

add a comment | 

I've been following Standard iOS Integration Guide of Stripe for my iOS app, which uses a backend written in Python-Django, to issue an ephemeral key.

This is the function I came up with in my views.py:

import stripe

stripe.api_key = "sk_test_Xf1yJ9qESRcCliM9iLoRmCIW"

def issue_key(request):
 if request.method == 'POST':
 api_version = request.POST.get('api_version')
 customerId = request.session['customerId']
 key = stripe.EphemeralKey.create(customer=customerId, api_version=api_version)
 return JsonResponse('key': key)
 else:
 return redirect("home:feed")

In my iOS app, I copied all the files from stripe-ios Standard Integration and filled in stripePublishableKey and backendBaseURL accordingly.

I'm also successfully creating a Stripe customer when a new user registers to my app, through Firebase Cloud Functions.

However, when CheckoutViewController loads, I get "Response status code was unacceptable: 404" error.

Assuming this error occurs while returning a JSON response from my backend, what is the correct code for the above method? Or am I missing something else on the Swift side?

Any suggestion or feedback will be welcomed and greatly appreciated.

Thank you.

python ios swift django stripe-payments

share|improve this question

asked Mar 22 at 17:13

steerrsteerr

3118

import stripe

stripe.api_key = "sk_test_Xf1yJ9qESRcCliM9iLoRmCIW"

def issue_key(request):
 if request.method == 'POST':
 api_version = request.POST.get('api_version')
 customerId = request.session['customerId']
 key = stripe.EphemeralKey.create(customer=customerId, api_version=api_version)
 return JsonResponse('key': key)
 else:
 return redirect("home:feed")

share|improve this question

asked Mar 22 at 17:13

steerrsteerr

3118

share|improve this question

asked Mar 22 at 17:13

steerrsteerr

3118

asked Mar 22 at 17:13

steerrsteerr

3118

asked Mar 22 at 17:13

steerrsteerr

3118