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cant progress with php 5 integer passing from a page
Deleting an element from an array in PHPSend email using the GMail SMTP server from a PHP pagePHP Pass variable to next pageConverting an integer to a string in PHPReturning JSON from a PHP ScriptPassing NULL from PHP to MySQL for auto incrementmysqli: PHP Fatal error: Call to a member function fetch_array()How to pass variables and data from PHP to JavaScript?PHP randomly decrements large integers by 1how to get the value from database to textbox in php
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is_int in php 5 doesn't recognize a GET integer when it's passed to it
$blog_ident=$_GET['blog_id'];
if (is_int($blog_ident))
$sql="SELECT * FROM blog WHERE blog_id='$blog_id'";
$result = mysqli_query($db,$sql);
if (!$result)
die('Sorry there was a problem reading the blog.');
// If we get a result back
while ( $row = $result->fetch_array(MYSQLI_ASSOC) )
@extract($row);
else
die ('Problem with the blog');
http://mydomain/blog_edit.php?blog_id=1
This always ends in 'Problem with the blog'. I can't get it to recognize the 1 as an int and proceed to the database query
php
edited Mar 24 at 10:13
Johan
2,5681719
asked Mar 24 at 10:02
user3046711user3046711
53
add a comment |
is_int in php 5 doesn't recognize a GET integer when it's passed to it
$blog_ident=$_GET['blog_id'];
if (is_int($blog_ident))
$sql="SELECT * FROM blog WHERE blog_id='$blog_id'";
$result = mysqli_query($db,$sql);
if (!$result)
die('Sorry there was a problem reading the blog.');
// If we get a result back
while ( $row = $result->fetch_array(MYSQLI_ASSOC) )
@extract($row);
else
die ('Problem with the blog');
http://mydomain/blog_edit.php?blog_id=1
This always ends in 'Problem with the blog'. I can't get it to recognize the 1 as an int and proceed to the database query
php
edited Mar 24 at 10:13
Johan
2,5681719
asked Mar 24 at 10:02
user3046711user3046711
53
all parameters are passed as string. php does not know which data type you expect. You should stick withfilter_var- php.net/manual/en/function.filter-var.php
– kuh-chan
Mar 24 at 10:08
and btw - you should upgrade to a newer version (e.g. 7.3)
– kuh-chan
Mar 24 at 10:09
your code is wide open to SQL injection attacks - use parameterised statements, or tell your users in advance that their data has been breached - because it will be.
– Franz Gleichmann
Mar 24 at 10:48
add a comment |
is_int in php 5 doesn't recognize a GET integer when it's passed to it
$blog_ident=$_GET['blog_id'];
if (is_int($blog_ident))
$sql="SELECT * FROM blog WHERE blog_id='$blog_id'";
$result = mysqli_query($db,$sql);
if (!$result)
die('Sorry there was a problem reading the blog.');
// If we get a result back
while ( $row = $result->fetch_array(MYSQLI_ASSOC) )
@extract($row);
else
die ('Problem with the blog');
http://mydomain/blog_edit.php?blog_id=1
This always ends in 'Problem with the blog'. I can't get it to recognize the 1 as an int and proceed to the database query
php
edited Mar 24 at 10:13
Johan
2,5681719
asked Mar 24 at 10:02
user3046711user3046711
53
is_int in php 5 doesn't recognize a GET integer when it's passed to it
$blog_ident=$_GET['blog_id'];
if (is_int($blog_ident))
$sql="SELECT * FROM blog WHERE blog_id='$blog_id'";
$result = mysqli_query($db,$sql);
if (!$result)
die('Sorry there was a problem reading the blog.');
// If we get a result back
while ( $row = $result->fetch_array(MYSQLI_ASSOC) )
@extract($row);
else
die ('Problem with the blog');
http://mydomain/blog_edit.php?blog_id=1
This always ends in 'Problem with the blog'. I can't get it to recognize the 1 as an int and proceed to the database query
php
php
edited Mar 24 at 10:13
Johan
2,5681719
asked Mar 24 at 10:02
user3046711user3046711
53
edited Mar 24 at 10:13
Johan
2,5681719
asked Mar 24 at 10:02
user3046711user3046711
53
edited Mar 24 at 10:13
Johan
2,5681719
edited Mar 24 at 10:13
Johan
2,5681719
edited Mar 24 at 10:13
Johan
2,5681719
2,5681719
asked Mar 24 at 10:02
user3046711user3046711
53
asked Mar 24 at 10:02
user3046711user3046711
53
asked Mar 24 at 10:02
user3046711user3046711
53
53
all parameters are passed as string. php does not know which data type you expect. You should stick withfilter_var- php.net/manual/en/function.filter-var.php
– kuh-chan
Mar 24 at 10:08
and btw - you should upgrade to a newer version (e.g. 7.3)
– kuh-chan
Mar 24 at 10:09
your code is wide open to SQL injection attacks - use parameterised statements, or tell your users in advance that their data has been breached - because it will be.
– Franz Gleichmann
Mar 24 at 10:48
add a comment |
all parameters are passed as string. php does not know which data type you expect. You should stick withfilter_var- php.net/manual/en/function.filter-var.php
– kuh-chan
Mar 24 at 10:08
and btw - you should upgrade to a newer version (e.g. 7.3)
– kuh-chan
Mar 24 at 10:09
your code is wide open to SQL injection attacks - use parameterised statements, or tell your users in advance that their data has been breached - because it will be.
– Franz Gleichmann
Mar 24 at 10:48
all parameters are passed as string. php does not know which data type you expect. You should stick with
filter_var - php.net/manual/en/function.filter-var.php– kuh-chan
Mar 24 at 10:08
all parameters are passed as string. php does not know which data type you expect. You should stick with
filter_var - php.net/manual/en/function.filter-var.php– kuh-chan
Mar 24 at 10:08
and btw - you should upgrade to a newer version (e.g. 7.3)
– kuh-chan
Mar 24 at 10:09
and btw - you should upgrade to a newer version (e.g. 7.3)
– kuh-chan
Mar 24 at 10:09
your code is wide open to SQL injection attacks - use parameterised statements, or tell your users in advance that their data has been breached - because it will be.
– Franz Gleichmann
Mar 24 at 10:48
your code is wide open to SQL injection attacks - use parameterised statements, or tell your users in advance that their data has been breached - because it will be.
– Franz Gleichmann
Mar 24 at 10:48
add a comment |
2 Answers
2
active
oldest
votes
Values in the $_GET and $_POST super globals are always strings. You may either cast it as an INT or use is_numeric to see if the value is a number.
answered Mar 24 at 10:09
DaveDave
3,09291932
add a comment |
The problem is in the second line of code, more specifically is_int(...). The docs page for is_int states its functionality as the following:
Find whether the type of a variable is integer
The problem here is that the type of $blog_ident is a string even though the value is a number, because the contents of $_GET is always of the type string. is_int only checks the type of the variable, not its content. If you continue to read on the docs page for is_int you'll find this part.
To test if a variable is a number or a numeric string (such as form input, which is always a string), you must use is_numeric().
If you replace is_int($blog_ident) line to the following you should ger the desired result:
if (is_numeric($blog_ident)){
answered Mar 24 at 10:10
JohanJohan
2,5681719
is_numericalso recognizes float
– kuh-chan
Mar 24 at 10:15
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Values in the $_GET and $_POST super globals are always strings. You may either cast it as an INT or use is_numeric to see if the value is a number.
answered Mar 24 at 10:09
DaveDave
3,09291932
add a comment |
Values in the $_GET and $_POST super globals are always strings. You may either cast it as an INT or use is_numeric to see if the value is a number.
answered Mar 24 at 10:09
DaveDave
3,09291932
add a comment |
Values in the $_GET and $_POST super globals are always strings. You may either cast it as an INT or use is_numeric to see if the value is a number.
answered Mar 24 at 10:09
DaveDave
3,09291932
Values in the $_GET and $_POST super globals are always strings. You may either cast it as an INT or use is_numeric to see if the value is a number.
answered Mar 24 at 10:09
DaveDave
3,09291932
answered Mar 24 at 10:09
DaveDave
3,09291932
answered Mar 24 at 10:09
DaveDave
3,09291932
answered Mar 24 at 10:09
DaveDave
3,09291932
3,09291932
add a comment |
add a comment |
The problem is in the second line of code, more specifically is_int(...). The docs page for is_int states its functionality as the following:
Find whether the type of a variable is integer
The problem here is that the type of $blog_ident is a string even though the value is a number, because the contents of $_GET is always of the type string. is_int only checks the type of the variable, not its content. If you continue to read on the docs page for is_int you'll find this part.
To test if a variable is a number or a numeric string (such as form input, which is always a string), you must use is_numeric().
If you replace is_int($blog_ident) line to the following you should ger the desired result:
if (is_numeric($blog_ident)){
answered Mar 24 at 10:10
JohanJohan
2,5681719
is_numericalso recognizes float
– kuh-chan
Mar 24 at 10:15
add a comment |
The problem is in the second line of code, more specifically is_int(...). The docs page for is_int states its functionality as the following:
Find whether the type of a variable is integer
The problem here is that the type of $blog_ident is a string even though the value is a number, because the contents of $_GET is always of the type string. is_int only checks the type of the variable, not its content. If you continue to read on the docs page for is_int you'll find this part.
To test if a variable is a number or a numeric string (such as form input, which is always a string), you must use is_numeric().
If you replace is_int($blog_ident) line to the following you should ger the desired result:
if (is_numeric($blog_ident)){
answered Mar 24 at 10:10
JohanJohan
2,5681719
is_numericalso recognizes float
– kuh-chan
Mar 24 at 10:15
add a comment |
The problem is in the second line of code, more specifically is_int(...). The docs page for is_int states its functionality as the following:
Find whether the type of a variable is integer
The problem here is that the type of $blog_ident is a string even though the value is a number, because the contents of $_GET is always of the type string. is_int only checks the type of the variable, not its content. If you continue to read on the docs page for is_int you'll find this part.
To test if a variable is a number or a numeric string (such as form input, which is always a string), you must use is_numeric().
If you replace is_int($blog_ident) line to the following you should ger the desired result:
if (is_numeric($blog_ident)){
answered Mar 24 at 10:10
JohanJohan
2,5681719
The problem is in the second line of code, more specifically is_int(...). The docs page for is_int states its functionality as the following:
Find whether the type of a variable is integer
The problem here is that the type of $blog_ident is a string even though the value is a number, because the contents of $_GET is always of the type string. is_int only checks the type of the variable, not its content. If you continue to read on the docs page for is_int you'll find this part.
To test if a variable is a number or a numeric string (such as form input, which is always a string), you must use is_numeric().
If you replace is_int($blog_ident) line to the following you should ger the desired result:
if (is_numeric($blog_ident)){
answered Mar 24 at 10:10
JohanJohan
2,5681719
edited Mar 24 at 10:15
answered Mar 24 at 10:10
JohanJohan
2,5681719
answered Mar 24 at 10:10
JohanJohan
2,5681719
answered Mar 24 at 10:10
JohanJohan
2,5681719
2,5681719
is_numericalso recognizes float
– kuh-chan
Mar 24 at 10:15
add a comment |
is_numericalso recognizes float
– kuh-chan
Mar 24 at 10:15
is_numeric also recognizes float– kuh-chan
Mar 24 at 10:15
is_numeric also recognizes float– kuh-chan
Mar 24 at 10:15
add a comment |
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all parameters are passed as string. php does not know which data type you expect. You should stick with
filter_var- php.net/manual/en/function.filter-var.php– kuh-chan
Mar 24 at 10:08
and btw - you should upgrade to a newer version (e.g. 7.3)
– kuh-chan
Mar 24 at 10:09
your code is wide open to SQL injection attacks - use parameterised statements, or tell your users in advance that their data has been breached - because it will be.
– Franz Gleichmann
Mar 24 at 10:48