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how i can parse link in herf = javascript:void(0) which is hidden using python


Web-scraping JavaScript page with PythonHidden features of PythonWhich “href” value should I use for JavaScript links, “#” or “javascript:void(0)”?How can I upload files asynchronously?How do I check if an element is hidden in jQuery?How can I safely create a nested directory?How do I parse a string to a float or int in Python?How to get the current time in PythonHow can I make a time delay in Python?How can I know which radio button is selected via jQuery?How can I get query string values in JavaScript?






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;








0















i am try to parse a link which is hidden in herf = javascript:void(0) and get link button is disable class="btn btn-success btn-lg get-link disabled". after some second link is appear <a href="http://googledrivedirectlink.xyz/download.php?id=QllDSWJsSGV1M3RRd0c3N1o0QmVWdUpoZVdJUjZ4ZE9iWkx6ZHgvZllmNlc=" class="btn btn-success btn-lg get-link">Get Link</a>. how i can solve this how i can use Selenium for parse href link



i have already tried it with BeautifulSoup but its not working nothing show its say



<a href="javascript: void(0)" class="btn btn-success btn-lg get-link disabled">
Please wait...
</a>


how i can resolve it



here is my code



import requests
from bs4 import BeautifulSoup
url=requests.get('http://linkblend.icu/p8AzvIvi').text
soup=BeautifulSoup(url,'html.parser')
soup.findAll('a')


Here is my code output



<a href="javascript: void(0)" class="btn btn-success btn-lg get-link disabled">
Please wait...
</a>









share|improve this question
























  • So, what are you trying to get exactly? What is your desired output?

    – FailSafe
    Mar 24 at 10:00











  • Following link can help you I guess: stackoverflow.com/questions/8049520/… Basically you need to wait for the Javascript of the page to run completely before reading the link href

    – Keerthi Kumar P
    Mar 24 at 10:10












  • thanks for reply. sir i want href link which i have described . using parsing in python.

    – usama riaz
    Mar 24 at 10:11











  • @KeerthiKumarP thanks for reply. yeah i want to make some wait requests for javascript for rum completely . for getting href link.. but how i can get it with code in python please have you some idea

    – usama riaz
    Mar 24 at 10:14












  • Yeah, the link in my comment has many options for that. Particularly this answer seems to be clear: stackoverflow.com/a/26440563/6016779 Kindly try them and raise a separate thread if you have any issues in them.

    – Keerthi Kumar P
    Mar 24 at 10:49

















0















i am try to parse a link which is hidden in herf = javascript:void(0) and get link button is disable class="btn btn-success btn-lg get-link disabled". after some second link is appear <a href="http://googledrivedirectlink.xyz/download.php?id=QllDSWJsSGV1M3RRd0c3N1o0QmVWdUpoZVdJUjZ4ZE9iWkx6ZHgvZllmNlc=" class="btn btn-success btn-lg get-link">Get Link</a>. how i can solve this how i can use Selenium for parse href link



i have already tried it with BeautifulSoup but its not working nothing show its say



<a href="javascript: void(0)" class="btn btn-success btn-lg get-link disabled">
Please wait...
</a>


how i can resolve it



here is my code



import requests
from bs4 import BeautifulSoup
url=requests.get('http://linkblend.icu/p8AzvIvi').text
soup=BeautifulSoup(url,'html.parser')
soup.findAll('a')


Here is my code output



<a href="javascript: void(0)" class="btn btn-success btn-lg get-link disabled">
Please wait...
</a>









share|improve this question
























  • So, what are you trying to get exactly? What is your desired output?

    – FailSafe
    Mar 24 at 10:00











  • Following link can help you I guess: stackoverflow.com/questions/8049520/… Basically you need to wait for the Javascript of the page to run completely before reading the link href

    – Keerthi Kumar P
    Mar 24 at 10:10












  • thanks for reply. sir i want href link which i have described . using parsing in python.

    – usama riaz
    Mar 24 at 10:11











  • @KeerthiKumarP thanks for reply. yeah i want to make some wait requests for javascript for rum completely . for getting href link.. but how i can get it with code in python please have you some idea

    – usama riaz
    Mar 24 at 10:14












  • Yeah, the link in my comment has many options for that. Particularly this answer seems to be clear: stackoverflow.com/a/26440563/6016779 Kindly try them and raise a separate thread if you have any issues in them.

    – Keerthi Kumar P
    Mar 24 at 10:49













0












0








0








i am try to parse a link which is hidden in herf = javascript:void(0) and get link button is disable class="btn btn-success btn-lg get-link disabled". after some second link is appear <a href="http://googledrivedirectlink.xyz/download.php?id=QllDSWJsSGV1M3RRd0c3N1o0QmVWdUpoZVdJUjZ4ZE9iWkx6ZHgvZllmNlc=" class="btn btn-success btn-lg get-link">Get Link</a>. how i can solve this how i can use Selenium for parse href link



i have already tried it with BeautifulSoup but its not working nothing show its say



<a href="javascript: void(0)" class="btn btn-success btn-lg get-link disabled">
Please wait...
</a>


how i can resolve it



here is my code



import requests
from bs4 import BeautifulSoup
url=requests.get('http://linkblend.icu/p8AzvIvi').text
soup=BeautifulSoup(url,'html.parser')
soup.findAll('a')


Here is my code output



<a href="javascript: void(0)" class="btn btn-success btn-lg get-link disabled">
Please wait...
</a>









share|improve this question
















i am try to parse a link which is hidden in herf = javascript:void(0) and get link button is disable class="btn btn-success btn-lg get-link disabled". after some second link is appear <a href="http://googledrivedirectlink.xyz/download.php?id=QllDSWJsSGV1M3RRd0c3N1o0QmVWdUpoZVdJUjZ4ZE9iWkx6ZHgvZllmNlc=" class="btn btn-success btn-lg get-link">Get Link</a>. how i can solve this how i can use Selenium for parse href link



i have already tried it with BeautifulSoup but its not working nothing show its say



<a href="javascript: void(0)" class="btn btn-success btn-lg get-link disabled">
Please wait...
</a>


how i can resolve it



here is my code



import requests
from bs4 import BeautifulSoup
url=requests.get('http://linkblend.icu/p8AzvIvi').text
soup=BeautifulSoup(url,'html.parser')
soup.findAll('a')


Here is my code output



<a href="javascript: void(0)" class="btn btn-success btn-lg get-link disabled">
Please wait...
</a>






javascript python web-scraping






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 24 at 10:02







usama riaz

















asked Mar 24 at 9:56









usama riazusama riaz

15




15












  • So, what are you trying to get exactly? What is your desired output?

    – FailSafe
    Mar 24 at 10:00











  • Following link can help you I guess: stackoverflow.com/questions/8049520/… Basically you need to wait for the Javascript of the page to run completely before reading the link href

    – Keerthi Kumar P
    Mar 24 at 10:10












  • thanks for reply. sir i want href link which i have described . using parsing in python.

    – usama riaz
    Mar 24 at 10:11











  • @KeerthiKumarP thanks for reply. yeah i want to make some wait requests for javascript for rum completely . for getting href link.. but how i can get it with code in python please have you some idea

    – usama riaz
    Mar 24 at 10:14












  • Yeah, the link in my comment has many options for that. Particularly this answer seems to be clear: stackoverflow.com/a/26440563/6016779 Kindly try them and raise a separate thread if you have any issues in them.

    – Keerthi Kumar P
    Mar 24 at 10:49

















  • So, what are you trying to get exactly? What is your desired output?

    – FailSafe
    Mar 24 at 10:00











  • Following link can help you I guess: stackoverflow.com/questions/8049520/… Basically you need to wait for the Javascript of the page to run completely before reading the link href

    – Keerthi Kumar P
    Mar 24 at 10:10












  • thanks for reply. sir i want href link which i have described . using parsing in python.

    – usama riaz
    Mar 24 at 10:11











  • @KeerthiKumarP thanks for reply. yeah i want to make some wait requests for javascript for rum completely . for getting href link.. but how i can get it with code in python please have you some idea

    – usama riaz
    Mar 24 at 10:14












  • Yeah, the link in my comment has many options for that. Particularly this answer seems to be clear: stackoverflow.com/a/26440563/6016779 Kindly try them and raise a separate thread if you have any issues in them.

    – Keerthi Kumar P
    Mar 24 at 10:49
















So, what are you trying to get exactly? What is your desired output?

– FailSafe
Mar 24 at 10:00





So, what are you trying to get exactly? What is your desired output?

– FailSafe
Mar 24 at 10:00













Following link can help you I guess: stackoverflow.com/questions/8049520/… Basically you need to wait for the Javascript of the page to run completely before reading the link href

– Keerthi Kumar P
Mar 24 at 10:10






Following link can help you I guess: stackoverflow.com/questions/8049520/… Basically you need to wait for the Javascript of the page to run completely before reading the link href

– Keerthi Kumar P
Mar 24 at 10:10














thanks for reply. sir i want href link which i have described . using parsing in python.

– usama riaz
Mar 24 at 10:11





thanks for reply. sir i want href link which i have described . using parsing in python.

– usama riaz
Mar 24 at 10:11













@KeerthiKumarP thanks for reply. yeah i want to make some wait requests for javascript for rum completely . for getting href link.. but how i can get it with code in python please have you some idea

– usama riaz
Mar 24 at 10:14






@KeerthiKumarP thanks for reply. yeah i want to make some wait requests for javascript for rum completely . for getting href link.. but how i can get it with code in python please have you some idea

– usama riaz
Mar 24 at 10:14














Yeah, the link in my comment has many options for that. Particularly this answer seems to be clear: stackoverflow.com/a/26440563/6016779 Kindly try them and raise a separate thread if you have any issues in them.

– Keerthi Kumar P
Mar 24 at 10:49





Yeah, the link in my comment has many options for that. Particularly this answer seems to be clear: stackoverflow.com/a/26440563/6016779 Kindly try them and raise a separate thread if you have any issues in them.

– Keerthi Kumar P
Mar 24 at 10:49












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