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accurate conversion (currency and it cents with fmod)
weird output when printing data of custom string (c++ newbie)recursive trailing return types visual studio 2010Difference between c++ functions 'remainder' and 'fmod'?Searchable Enum-like object with string and int conversionC++: perfect transparent wrapping of base types into a class?C++ , A code to get an amount of money to convert into quarters, dimes , nickels, penniesStack returning copy because of inheritance?How to stop C++ from automatically converting double to int?Converting dollars to cents in c++Currency format in C++
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If I convert 5 USD to Euro, it should be 4.45 or 4 euro and 45 cent
the problem is that I get 4 and 0.55 instead of 0.45 or is there a way to get 45 cent??
enter code here
int main()
double usd = 0, euro = 0;
double fixeuro = 0.89;
cout << "Please add amount to convert itn";
cin >> usd;
int conv = usd * fixeuro;
cout << conv << "n";
cout << fmod(usd,fixeuro);
return 0;
c++11
asked Mar 24 at 21:43
adamadam
12
add a comment |
If I convert 5 USD to Euro, it should be 4.45 or 4 euro and 45 cent
the problem is that I get 4 and 0.55 instead of 0.45 or is there a way to get 45 cent??
enter code here
int main()
double usd = 0, euro = 0;
double fixeuro = 0.89;
cout << "Please add amount to convert itn";
cin >> usd;
int conv = usd * fixeuro;
cout << conv << "n";
cout << fmod(usd,fixeuro);
return 0;
c++11
asked Mar 24 at 21:43
adamadam
12
Did you already check if theusdvalue has been read correctly? (cout << usd)
– Martin Rosenau
Mar 24 at 21:48
sorry I meant 4 instead of 5 (already corrected it)
– adam
Mar 24 at 21:51
I am really sorry I have just corrected every thing
– adam
Mar 24 at 21:58
add a comment |
If I convert 5 USD to Euro, it should be 4.45 or 4 euro and 45 cent
the problem is that I get 4 and 0.55 instead of 0.45 or is there a way to get 45 cent??
enter code here
int main()
double usd = 0, euro = 0;
double fixeuro = 0.89;
cout << "Please add amount to convert itn";
cin >> usd;
int conv = usd * fixeuro;
cout << conv << "n";
cout << fmod(usd,fixeuro);
return 0;
c++11
asked Mar 24 at 21:43
adamadam
12
If I convert 5 USD to Euro, it should be 4.45 or 4 euro and 45 cent
the problem is that I get 4 and 0.55 instead of 0.45 or is there a way to get 45 cent??
enter code here
int main()
double usd = 0, euro = 0;
double fixeuro = 0.89;
cout << "Please add amount to convert itn";
cin >> usd;
int conv = usd * fixeuro;
cout << conv << "n";
cout << fmod(usd,fixeuro);
return 0;
c++11
c++11
asked Mar 24 at 21:43
adamadam
12
asked Mar 24 at 21:43
adamadam
12
edited Mar 24 at 21:57
adam
asked Mar 24 at 21:43
adamadam
12
asked Mar 24 at 21:43
adamadam
12
asked Mar 24 at 21:43
adamadam
12
12
Did you already check if theusdvalue has been read correctly? (cout << usd)
– Martin Rosenau
Mar 24 at 21:48
sorry I meant 4 instead of 5 (already corrected it)
– adam
Mar 24 at 21:51
I am really sorry I have just corrected every thing
– adam
Mar 24 at 21:58
add a comment |
Did you already check if theusdvalue has been read correctly? (cout << usd)
– Martin Rosenau
Mar 24 at 21:48
sorry I meant 4 instead of 5 (already corrected it)
– adam
Mar 24 at 21:51
I am really sorry I have just corrected every thing
– adam
Mar 24 at 21:58
Did you already check if the
usd value has been read correctly? (cout << usd)– Martin Rosenau
Mar 24 at 21:48
Did you already check if the
usd value has been read correctly? (cout << usd)– Martin Rosenau
Mar 24 at 21:48
sorry I meant 4 instead of 5 (already corrected it)
– adam
Mar 24 at 21:51
sorry I meant 4 instead of 5 (already corrected it)
– adam
Mar 24 at 21:51
I am really sorry I have just corrected every thing
– adam
Mar 24 at 21:58
I am really sorry I have just corrected every thing
– adam
Mar 24 at 21:58
add a comment |
1 Answer
1
active
oldest
votes
The way to get the correct amount is double conv = usd * fixeuro; Then if you want to get just the euros, that's int euros = conv; and just the eurocents is int eurocents = 100 * (conv - euros); Or, if you want, you can use 100 * fmod(conv, 1.0).
fmod(usd,fixeuro) doesn't appear to have any obvious meaning. It's what you are left with when you have 5 USD and start throwing away exactly 89 cents at a time until you have less than 89 cents. 89 US cents do not correspond to any interesting amount in euros, and US cents are not eurocents, so it isn't quite clear what you get from this.
answered Mar 24 at 22:07
n.m.n.m.
75.1k887173
Thanks that was the solution , my goal using fmod is same as modulo, I thought I would get whats left after comma
– adam
Mar 24 at 22:20
add a comment |
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1 Answer
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1 Answer
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active
oldest
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oldest
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oldest
votes
The way to get the correct amount is double conv = usd * fixeuro; Then if you want to get just the euros, that's int euros = conv; and just the eurocents is int eurocents = 100 * (conv - euros); Or, if you want, you can use 100 * fmod(conv, 1.0).
fmod(usd,fixeuro) doesn't appear to have any obvious meaning. It's what you are left with when you have 5 USD and start throwing away exactly 89 cents at a time until you have less than 89 cents. 89 US cents do not correspond to any interesting amount in euros, and US cents are not eurocents, so it isn't quite clear what you get from this.
answered Mar 24 at 22:07
n.m.n.m.
75.1k887173
Thanks that was the solution , my goal using fmod is same as modulo, I thought I would get whats left after comma
– adam
Mar 24 at 22:20
add a comment |
The way to get the correct amount is double conv = usd * fixeuro; Then if you want to get just the euros, that's int euros = conv; and just the eurocents is int eurocents = 100 * (conv - euros); Or, if you want, you can use 100 * fmod(conv, 1.0).
fmod(usd,fixeuro) doesn't appear to have any obvious meaning. It's what you are left with when you have 5 USD and start throwing away exactly 89 cents at a time until you have less than 89 cents. 89 US cents do not correspond to any interesting amount in euros, and US cents are not eurocents, so it isn't quite clear what you get from this.
answered Mar 24 at 22:07
n.m.n.m.
75.1k887173
Thanks that was the solution , my goal using fmod is same as modulo, I thought I would get whats left after comma
– adam
Mar 24 at 22:20
add a comment |
The way to get the correct amount is double conv = usd * fixeuro; Then if you want to get just the euros, that's int euros = conv; and just the eurocents is int eurocents = 100 * (conv - euros); Or, if you want, you can use 100 * fmod(conv, 1.0).
fmod(usd,fixeuro) doesn't appear to have any obvious meaning. It's what you are left with when you have 5 USD and start throwing away exactly 89 cents at a time until you have less than 89 cents. 89 US cents do not correspond to any interesting amount in euros, and US cents are not eurocents, so it isn't quite clear what you get from this.
answered Mar 24 at 22:07
n.m.n.m.
75.1k887173
The way to get the correct amount is double conv = usd * fixeuro; Then if you want to get just the euros, that's int euros = conv; and just the eurocents is int eurocents = 100 * (conv - euros); Or, if you want, you can use 100 * fmod(conv, 1.0).
fmod(usd,fixeuro) doesn't appear to have any obvious meaning. It's what you are left with when you have 5 USD and start throwing away exactly 89 cents at a time until you have less than 89 cents. 89 US cents do not correspond to any interesting amount in euros, and US cents are not eurocents, so it isn't quite clear what you get from this.
answered Mar 24 at 22:07
n.m.n.m.
75.1k887173
answered Mar 24 at 22:07
n.m.n.m.
75.1k887173
answered Mar 24 at 22:07
n.m.n.m.
75.1k887173
answered Mar 24 at 22:07
n.m.n.m.
75.1k887173
75.1k887173
Thanks that was the solution , my goal using fmod is same as modulo, I thought I would get whats left after comma
– adam
Mar 24 at 22:20
add a comment |
Thanks that was the solution , my goal using fmod is same as modulo, I thought I would get whats left after comma
– adam
Mar 24 at 22:20
Thanks that was the solution , my goal using fmod is same as modulo, I thought I would get whats left after comma
– adam
Mar 24 at 22:20
Thanks that was the solution , my goal using fmod is same as modulo, I thought I would get whats left after comma
– adam
Mar 24 at 22:20
add a comment |
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Did you already check if the
usdvalue has been read correctly? (cout << usd)– Martin Rosenau
Mar 24 at 21:48
sorry I meant 4 instead of 5 (already corrected it)
– adam
Mar 24 at 21:51
I am really sorry I have just corrected every thing
– adam
Mar 24 at 21:58