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How to read in multiple characters from a file, multiply the character into a grid and print back to a new file

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0

I am trying to read multiple characters from a file multiply each character so that when I print it to a new file they appear in a grid like format.

 int num = 4;
 String fileStr = "";

 scnrIn.useDelimiter("zzzzzzzzz");

 while(scnrIn.hasNextLine()) 
 fileStr = scnrIn.nextLine();

 char[] charArray = fileStr.toCharArray();

 for(int i = 0; i < charArray.length; ++i) 
 for(int j = 0; j < Math.sqrt(num); ++j) 
 writer.write(charArray[i]);
 for(int k = 1; k < Math.sqrt(num); ++k) 
 writer.write(charArray[i]);
 
 writer.newLine();
 writer.flush();
 
 
 


}

}

If my txt file contains the characters @#$ and my mulitplier is 4 I expect the new txt file to print:

@@##$$
@@##$$

but instead I get:

@@
@@
##
##
$$
$$

I feel like the issue is tied to writer.newLine(); but if I take it away or comment it out then it won't print it in a grid. I am not sure how to get around the need for a new line to print in a grid.

java

share|improve this question

asked Mar 24 at 21:49

TimidTomatoTimidTomato

52

add a comment | 

0

I am trying to read multiple characters from a file multiply each character so that when I print it to a new file they appear in a grid like format.

 int num = 4;
 String fileStr = "";

 scnrIn.useDelimiter("zzzzzzzzz");

 while(scnrIn.hasNextLine()) 
 fileStr = scnrIn.nextLine();

 char[] charArray = fileStr.toCharArray();

 for(int i = 0; i < charArray.length; ++i) 
 for(int j = 0; j < Math.sqrt(num); ++j) 
 writer.write(charArray[i]);
 for(int k = 1; k < Math.sqrt(num); ++k) 
 writer.write(charArray[i]);
 
 writer.newLine();
 writer.flush();
 
 
 


}

}

If my txt file contains the characters @#$ and my mulitplier is 4 I expect the new txt file to print:

@@##$$
@@##$$

but instead I get:

@@
@@
##
##
$$
$$

I feel like the issue is tied to writer.newLine(); but if I take it away or comment it out then it won't print it in a grid. I am not sure how to get around the need for a new line to print in a grid.

java

share|improve this question

asked Mar 24 at 21:49

TimidTomatoTimidTomato

52

add a comment | 

I am trying to read multiple characters from a file multiply each character so that when I print it to a new file they appear in a grid like format.

 int num = 4;
 String fileStr = "";

 scnrIn.useDelimiter("zzzzzzzzz");

 while(scnrIn.hasNextLine()) 
 fileStr = scnrIn.nextLine();

 char[] charArray = fileStr.toCharArray();

 for(int i = 0; i < charArray.length; ++i) 
 for(int j = 0; j < Math.sqrt(num); ++j) 
 writer.write(charArray[i]);
 for(int k = 1; k < Math.sqrt(num); ++k) 
 writer.write(charArray[i]);
 
 writer.newLine();
 writer.flush();
 
 
 


}

}

If my txt file contains the characters @#$ and my mulitplier is 4 I expect the new txt file to print:

@@##$$
@@##$$

but instead I get:

@@
@@
##
##
$$
$$

I feel like the issue is tied to writer.newLine(); but if I take it away or comment it out then it won't print it in a grid. I am not sure how to get around the need for a new line to print in a grid.

java

share|improve this question

asked Mar 24 at 21:49

TimidTomatoTimidTomato

52

 int num = 4;
 String fileStr = "";

 scnrIn.useDelimiter("zzzzzzzzz");

 while(scnrIn.hasNextLine()) 
 fileStr = scnrIn.nextLine();

 char[] charArray = fileStr.toCharArray();

 for(int i = 0; i < charArray.length; ++i) 
 for(int j = 0; j < Math.sqrt(num); ++j) 
 writer.write(charArray[i]);
 for(int k = 1; k < Math.sqrt(num); ++k) 
 writer.write(charArray[i]);
 
 writer.newLine();
 writer.flush();
 
 
 


}

@@##$$
@@##$$

@@
@@
##
##
$$
$$

share|improve this question

asked Mar 24 at 21:49

TimidTomatoTimidTomato

52

share|improve this question

asked Mar 24 at 21:49

TimidTomatoTimidTomato

52

asked Mar 24 at 21:49

TimidTomatoTimidTomato

52

asked Mar 24 at 21:49

TimidTomatoTimidTomato

52

1 Answer
1

active

oldest

votes

0

Your problem is related to the nesting of your for loops. If you follow what your code is doing, you are writing out the one current character at i in a grid and then going on to the next character in the charArray.

Instead what you should be doing is going by the rows and printing out the current character's number of columns for each character before going to a new line. This mainly requires switching the two most outer for loops and then fixing how often you call write.

Here is the code working as expected:

int num = 4; 
int cols = (int) Math.sqrt(num); //easier to read the code when stored in a variable
int rows = cols;

String fileStr = "";

scnrIn.useDelimiter("zzzzzzzzz");

while(scnrIn.hasNextLine()) 
 fileStr = scnrIn.nextLine();
 char[] charArray = fileStr.toCharArray();

 for (int i = 0; i < rows; i++) 
 for (int j = 0; j < charArray.length; j++) 
 char curChar = charArray[j]; //this is the current character we want to write out for the number of columns times

 for (int k = 0; k < cols; k++) 
 writer.write(curChar);
 
 
 writer.newLine(); //create a new line after every row
 
 writer.flush(); //better to only flush output when fully done

share|improve this answer

answered Mar 24 at 22:16

KarlKarl

1,3152717

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you. I got hung up on the wrong places. Thank you for your assistance.
  
  – TimidTomato
  Mar 24 at 22:34
  

  
  
  
  

add a comment | 

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0

Your problem is related to the nesting of your for loops. If you follow what your code is doing, you are writing out the one current character at i in a grid and then going on to the next character in the charArray.

Instead what you should be doing is going by the rows and printing out the current character's number of columns for each character before going to a new line. This mainly requires switching the two most outer for loops and then fixing how often you call write.

Here is the code working as expected:

int num = 4; 
int cols = (int) Math.sqrt(num); //easier to read the code when stored in a variable
int rows = cols;

String fileStr = "";

scnrIn.useDelimiter("zzzzzzzzz");

while(scnrIn.hasNextLine()) 
 fileStr = scnrIn.nextLine();
 char[] charArray = fileStr.toCharArray();

 for (int i = 0; i < rows; i++) 
 for (int j = 0; j < charArray.length; j++) 
 char curChar = charArray[j]; //this is the current character we want to write out for the number of columns times

 for (int k = 0; k < cols; k++) 
 writer.write(curChar);
 
 
 writer.newLine(); //create a new line after every row
 
 writer.flush(); //better to only flush output when fully done

share|improve this answer

answered Mar 24 at 22:16

KarlKarl

1,3152717

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you. I got hung up on the wrong places. Thank you for your assistance.
  
  – TimidTomato
  Mar 24 at 22:34
  

  
  
  
  

add a comment | 

0

Your problem is related to the nesting of your for loops. If you follow what your code is doing, you are writing out the one current character at i in a grid and then going on to the next character in the charArray.

Instead what you should be doing is going by the rows and printing out the current character's number of columns for each character before going to a new line. This mainly requires switching the two most outer for loops and then fixing how often you call write.

Here is the code working as expected:

int num = 4; 
int cols = (int) Math.sqrt(num); //easier to read the code when stored in a variable
int rows = cols;

String fileStr = "";

scnrIn.useDelimiter("zzzzzzzzz");

while(scnrIn.hasNextLine()) 
 fileStr = scnrIn.nextLine();
 char[] charArray = fileStr.toCharArray();

 for (int i = 0; i < rows; i++) 
 for (int j = 0; j < charArray.length; j++) 
 char curChar = charArray[j]; //this is the current character we want to write out for the number of columns times

 for (int k = 0; k < cols; k++) 
 writer.write(curChar);
 
 
 writer.newLine(); //create a new line after every row
 
 writer.flush(); //better to only flush output when fully done

share|improve this answer

answered Mar 24 at 22:16

KarlKarl

1,3152717

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you. I got hung up on the wrong places. Thank you for your assistance.
  
  – TimidTomato
  Mar 24 at 22:34
  

  
  
  
  

add a comment | 

Your problem is related to the nesting of your for loops. If you follow what your code is doing, you are writing out the one current character at i in a grid and then going on to the next character in the charArray.

Instead what you should be doing is going by the rows and printing out the current character's number of columns for each character before going to a new line. This mainly requires switching the two most outer for loops and then fixing how often you call write.

Here is the code working as expected:

int num = 4; 
int cols = (int) Math.sqrt(num); //easier to read the code when stored in a variable
int rows = cols;

String fileStr = "";

scnrIn.useDelimiter("zzzzzzzzz");

while(scnrIn.hasNextLine()) 
 fileStr = scnrIn.nextLine();
 char[] charArray = fileStr.toCharArray();

 for (int i = 0; i < rows; i++) 
 for (int j = 0; j < charArray.length; j++) 
 char curChar = charArray[j]; //this is the current character we want to write out for the number of columns times

 for (int k = 0; k < cols; k++) 
 writer.write(curChar);
 
 
 writer.newLine(); //create a new line after every row
 
 writer.flush(); //better to only flush output when fully done

share|improve this answer

answered Mar 24 at 22:16

KarlKarl

1,3152717

int num = 4; 
int cols = (int) Math.sqrt(num); //easier to read the code when stored in a variable
int rows = cols;

String fileStr = "";

scnrIn.useDelimiter("zzzzzzzzz");

while(scnrIn.hasNextLine()) 
 fileStr = scnrIn.nextLine();
 char[] charArray = fileStr.toCharArray();

 for (int i = 0; i < rows; i++) 
 for (int j = 0; j < charArray.length; j++) 
 char curChar = charArray[j]; //this is the current character we want to write out for the number of columns times

 for (int k = 0; k < cols; k++) 
 writer.write(curChar);
 
 
 writer.newLine(); //create a new line after every row
 
 writer.flush(); //better to only flush output when fully done

share|improve this answer

answered Mar 24 at 22:16

KarlKarl

1,3152717

answered Mar 24 at 22:16

KarlKarl

1,3152717

answered Mar 24 at 22:16

KarlKarl

1,3152717