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How to replace a `norm some string ` by `| some string|` quickly? [duplicate]

Find and replace strings in vim on multiple linesVim - Capture strings on Search and use on ReplaceHow to match string within parentheses (nested) in Java?How to replace a character by a newline in VimIndent multiple lines quickly in viHow to replace all occurrences of a string in JavaScriptWhat is your most productive shortcut with Vim?How to do case insensitive search in VimHow do I make Git use the editor of my choice for commits?How does the vim “write with sudo” trick work?MySQL string replaceHow do I exit the Vim editor?Move cursor to end of file in vim

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;

0

This question already has an answer here:

• 
  Find and replace strings in vim on multiple lines
  
  9 answers
  
  


• 
  Vim - Capture strings on Search and use on Replace
  
  4 answers
  
  

I am editing a markdown file with vim. This file exist many string norm some string . I want to replace them by | some string |. Does there exist any quick way? Thanks very much.

The answer in Find and replace strings in vim on multiple lines can not answer my question. It just talk about general replacing for one line and multi line. Here I want to replace a surrounding and keep the string in the surrounding.

vim replace

share|improve this question

edited Mar 24 at 21:56

Huayi Wei

asked Mar 24 at 21:43

Huayi WeiHuayi Wei

3521213

marked as duplicate by Stephen Kennedy, rene, eyllanesc, Doktor OSwaldo, Pearly Spencer Mar 25 at 18:48

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The some string may include some bracket pair .
  
  – Huayi Wei
  Mar 24 at 21:45
  

  
  
  
  

add a comment | 

0

This question already has an answer here:

• 
  Find and replace strings in vim on multiple lines
  
  9 answers
  
  


• 
  Vim - Capture strings on Search and use on Replace
  
  4 answers
  
  

I am editing a markdown file with vim. This file exist many string norm some string . I want to replace them by | some string |. Does there exist any quick way? Thanks very much.

The answer in Find and replace strings in vim on multiple lines can not answer my question. It just talk about general replacing for one line and multi line. Here I want to replace a surrounding and keep the string in the surrounding.

vim replace

share|improve this question

edited Mar 24 at 21:56

Huayi Wei

asked Mar 24 at 21:43

Huayi WeiHuayi Wei

3521213

marked as duplicate by Stephen Kennedy, rene, eyllanesc, Doktor OSwaldo, Pearly Spencer Mar 25 at 18:48

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The some string may include some bracket pair .
  
  – Huayi Wei
  Mar 24 at 21:45
  

  
  
  
  

add a comment | 

This question already has an answer here:

• 
  Find and replace strings in vim on multiple lines
  
  9 answers
  
  


• 
  Vim - Capture strings on Search and use on Replace
  
  4 answers
  
  

I am editing a markdown file with vim. This file exist many string norm some string . I want to replace them by | some string |. Does there exist any quick way? Thanks very much.

The answer in Find and replace strings in vim on multiple lines can not answer my question. It just talk about general replacing for one line and multi line. Here I want to replace a surrounding and keep the string in the surrounding.

vim replace

share|improve this question

edited Mar 24 at 21:56

Huayi Wei

asked Mar 24 at 21:43

Huayi WeiHuayi Wei

3521213

share|improve this question

edited Mar 24 at 21:56

Huayi Wei

asked Mar 24 at 21:43

Huayi WeiHuayi Wei

3521213

share|improve this question

edited Mar 24 at 21:56

Huayi Wei

asked Mar 24 at 21:43

Huayi WeiHuayi Wei

3521213

asked Mar 24 at 21:43

Huayi WeiHuayi Wei

3521213

asked Mar 24 at 21:43

Huayi WeiHuayi Wei

3521213

2 Answers
2

active

oldest

votes

1

What you're looking for are so-called capture groups and backreferences. Provided there are no nested forms (curly braces inside do not mean a problem in themselves) and forms spanning multiple lines, a quick solution could be: %s/\norm (.*)/\|1\|/g.

The 1 in the substitution part refers to the group captured by (.*), i.e. the original content inside the outermost pair of curly braces. See e.g. http://www.vimregex.com/#backreferences for more.

share|improve this answer

edited Mar 25 at 22:33

answered Mar 24 at 23:50

pamacspamacs

586

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks for your reply. This reply can partially answer my question. There exist some in my case, eg. norm A^-1 .
  
  – Huayi Wei
  Mar 25 at 2:08
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @HuayiWei he's giving you the resources to find what you need to figure out how to do it yourself, he's not going to give you the exact regex.
  
  – Stun Brick
  Mar 25 at 8:41
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @StunBrick Thanks for your suggestion.
  
  – Huayi Wei
  Mar 25 at 8:48
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @HuayiWei Sorry, that was a typo, "do not mean a problem" was intended. If yout try it, you can see that it works with your example, and the result will be | A^-1 |. The case which this regex cannot handle is e.g. norm ... norm ... (but you could do multiple rounds :) ). If you have arbitrary levels of nesting, that actually cannot be handled by a simple regex form at all, since you need some form of recursion for that. See for this e.g.: stackoverflow.com/questions/17759004/….
  
  – pamacs
  Mar 25 at 9:29
  
  

  
  
  
  

add a comment | 

0

You could also use a macro to accomplish what you want.

Place your cursor on the first line that have the pattern you want to substitute. Then start recording the macro:

qq0ldwr|$xi|ESCjq

Meaning:

qq = start recording a macro (q) in register q
0 = move to the beginning of the line
l = move one char to the right
dw = delete the word
r| = substitute what is under the cursor with a "|"
$ = move to the end of line
x = delete last char of the line
i = insert mode
| = insert chars "|"
ESC = exit insert mode
j = move to next line
q = stop recording

Execute the macro with:

@q

Execute the macro once again:

@@

Keep doing it for as many lines as needed, or use:

<number>@@
ex. 100@@

To execute the macro number times.

share|improve this answer

answered Mar 25 at 17:53

DoktornDoktorn

54737

add a comment | 

1

What you're looking for are so-called capture groups and backreferences. Provided there are no nested forms (curly braces inside do not mean a problem in themselves) and forms spanning multiple lines, a quick solution could be: %s/\norm (.*)/\|1\|/g.

The 1 in the substitution part refers to the group captured by (.*), i.e. the original content inside the outermost pair of curly braces. See e.g. http://www.vimregex.com/#backreferences for more.

share|improve this answer

edited Mar 25 at 22:33

answered Mar 24 at 23:50

pamacspamacs

586

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks for your reply. This reply can partially answer my question. There exist some in my case, eg. norm A^-1 .
  
  – Huayi Wei
  Mar 25 at 2:08
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @HuayiWei he's giving you the resources to find what you need to figure out how to do it yourself, he's not going to give you the exact regex.
  
  – Stun Brick
  Mar 25 at 8:41
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @StunBrick Thanks for your suggestion.
  
  – Huayi Wei
  Mar 25 at 8:48
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @HuayiWei Sorry, that was a typo, "do not mean a problem" was intended. If yout try it, you can see that it works with your example, and the result will be | A^-1 |. The case which this regex cannot handle is e.g. norm ... norm ... (but you could do multiple rounds :) ). If you have arbitrary levels of nesting, that actually cannot be handled by a simple regex form at all, since you need some form of recursion for that. See for this e.g.: stackoverflow.com/questions/17759004/….
  
  – pamacs
  Mar 25 at 9:29
  
  

  
  
  
  

add a comment | 

1

What you're looking for are so-called capture groups and backreferences. Provided there are no nested forms (curly braces inside do not mean a problem in themselves) and forms spanning multiple lines, a quick solution could be: %s/\norm (.*)/\|1\|/g.

The 1 in the substitution part refers to the group captured by (.*), i.e. the original content inside the outermost pair of curly braces. See e.g. http://www.vimregex.com/#backreferences for more.

share|improve this answer

edited Mar 25 at 22:33

answered Mar 24 at 23:50

pamacspamacs

586

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks for your reply. This reply can partially answer my question. There exist some in my case, eg. norm A^-1 .
  
  – Huayi Wei
  Mar 25 at 2:08
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @HuayiWei he's giving you the resources to find what you need to figure out how to do it yourself, he's not going to give you the exact regex.
  
  – Stun Brick
  Mar 25 at 8:41
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @StunBrick Thanks for your suggestion.
  
  – Huayi Wei
  Mar 25 at 8:48
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @HuayiWei Sorry, that was a typo, "do not mean a problem" was intended. If yout try it, you can see that it works with your example, and the result will be | A^-1 |. The case which this regex cannot handle is e.g. norm ... norm ... (but you could do multiple rounds :) ). If you have arbitrary levels of nesting, that actually cannot be handled by a simple regex form at all, since you need some form of recursion for that. See for this e.g.: stackoverflow.com/questions/17759004/….
  
  – pamacs
  Mar 25 at 9:29
  
  

  
  
  
  

add a comment | 

What you're looking for are so-called capture groups and backreferences. Provided there are no nested forms (curly braces inside do not mean a problem in themselves) and forms spanning multiple lines, a quick solution could be: %s/\norm (.*)/\|1\|/g.

The 1 in the substitution part refers to the group captured by (.*), i.e. the original content inside the outermost pair of curly braces. See e.g. http://www.vimregex.com/#backreferences for more.

share|improve this answer

edited Mar 25 at 22:33

answered Mar 24 at 23:50

pamacspamacs

586

share|improve this answer

edited Mar 25 at 22:33

answered Mar 24 at 23:50

pamacspamacs

586

answered Mar 24 at 23:50

pamacspamacs

586

answered Mar 24 at 23:50

pamacspamacs

586

0

You could also use a macro to accomplish what you want.

Place your cursor on the first line that have the pattern you want to substitute. Then start recording the macro:

qq0ldwr|$xi|ESCjq

Meaning:

qq = start recording a macro (q) in register q
0 = move to the beginning of the line
l = move one char to the right
dw = delete the word
r| = substitute what is under the cursor with a "|"
$ = move to the end of line
x = delete last char of the line
i = insert mode
| = insert chars "|"
ESC = exit insert mode
j = move to next line
q = stop recording

Execute the macro with:

@q

Execute the macro once again:

@@

Keep doing it for as many lines as needed, or use:

<number>@@
ex. 100@@

To execute the macro number times.

share|improve this answer

answered Mar 25 at 17:53

DoktornDoktorn

54737

add a comment | 

0

You could also use a macro to accomplish what you want.

Place your cursor on the first line that have the pattern you want to substitute. Then start recording the macro:

qq0ldwr|$xi|ESCjq

Meaning:

qq = start recording a macro (q) in register q
0 = move to the beginning of the line
l = move one char to the right
dw = delete the word
r| = substitute what is under the cursor with a "|"
$ = move to the end of line
x = delete last char of the line
i = insert mode
| = insert chars "|"
ESC = exit insert mode
j = move to next line
q = stop recording

Execute the macro with:

@q

Execute the macro once again:

@@

Keep doing it for as many lines as needed, or use:

<number>@@
ex. 100@@

To execute the macro number times.

share|improve this answer

answered Mar 25 at 17:53

DoktornDoktorn

54737

add a comment | 

You could also use a macro to accomplish what you want.

Place your cursor on the first line that have the pattern you want to substitute. Then start recording the macro:

qq0ldwr|$xi|ESCjq

Meaning:

qq = start recording a macro (q) in register q
0 = move to the beginning of the line
l = move one char to the right
dw = delete the word
r| = substitute what is under the cursor with a "|"
$ = move to the end of line
x = delete last char of the line
i = insert mode
| = insert chars "|"
ESC = exit insert mode
j = move to next line
q = stop recording

Execute the macro with:

@q

Execute the macro once again:

@@

Keep doing it for as many lines as needed, or use:

<number>@@
ex. 100@@

To execute the macro number times.

share|improve this answer

answered Mar 25 at 17:53

DoktornDoktorn

54737

qq0ldwr|$xi|ESCjq

qq = start recording a macro (q) in register q
0 = move to the beginning of the line
l = move one char to the right
dw = delete the word
r| = substitute what is under the cursor with a "|"
$ = move to the end of line
x = delete last char of the line
i = insert mode
| = insert chars "|"
ESC = exit insert mode
j = move to next line
q = stop recording

@q

@@

<number>@@
ex. 100@@

share|improve this answer

answered Mar 25 at 17:53

DoktornDoktorn

54737

answered Mar 25 at 17:53

DoktornDoktorn

54737

answered Mar 25 at 17:53

DoktornDoktorn

54737