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Am having a problem with my JavaScript log out code

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-3

1

I am trying to logout a user using a JavaScript code but it keeps loading without logging out.What have I done wrong?

I have tried changing the function itself but it still wouldn't log out.The loader just keeps on running.

this is the code

logout.html(loader);
 $.get("modules/"+role+"/"+role+".php",
 ,function(pagedata)
 logout.show().html(pagedata); 
 );

I'm expecting the code to logout and take me back to the login page.

javascript

share|improve this question

asked Mar 24 at 21:57

Moses WayodiMoses Wayodi

1

add a comment | 

-3

1

I am trying to logout a user using a JavaScript code but it keeps loading without logging out.What have I done wrong?

I have tried changing the function itself but it still wouldn't log out.The loader just keeps on running.

this is the code

logout.html(loader);
 $.get("modules/"+role+"/"+role+".php",
 ,function(pagedata)
 logout.show().html(pagedata); 
 );

I'm expecting the code to logout and take me back to the login page.

javascript

share|improve this question

asked Mar 24 at 21:57

Moses WayodiMoses Wayodi

1

add a comment | 

I am trying to logout a user using a JavaScript code but it keeps loading without logging out.What have I done wrong?

I have tried changing the function itself but it still wouldn't log out.The loader just keeps on running.

this is the code

logout.html(loader);
 $.get("modules/"+role+"/"+role+".php",
 ,function(pagedata)
 logout.show().html(pagedata); 
 );

I'm expecting the code to logout and take me back to the login page.

javascript

share|improve this question

asked Mar 24 at 21:57

Moses WayodiMoses Wayodi

1

this is the code

logout.html(loader);
 $.get("modules/"+role+"/"+role+".php",
 ,function(pagedata)
 logout.show().html(pagedata); 
 );

share|improve this question

asked Mar 24 at 21:57

Moses WayodiMoses Wayodi

1

share|improve this question

asked Mar 24 at 21:57

Moses WayodiMoses Wayodi

1

asked Mar 24 at 21:57

Moses WayodiMoses Wayodi

1

asked Mar 24 at 21:57

Moses WayodiMoses Wayodi

1

1 Answer
1

active

oldest

votes

0

The

$.get()

method requests data from the server with an HTTP GET request.
The required URL parameter specifies the URL you wish to request.
The optional callback parameter is the name of a function to be executed if the request succeeds.

$.get(URL,callback);

so change your code :

 logout.html(loader);
 $.get("modules/"+role+"/"+role+".php",function(pagedata)
 logout.show().html(pagedata); 
 );

share|improve this answer

answered Mar 24 at 22:14

Razmik GhookasRazmik Ghookas

854

add a comment | 

Your Answer

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0

The

$.get()

method requests data from the server with an HTTP GET request.
The required URL parameter specifies the URL you wish to request.
The optional callback parameter is the name of a function to be executed if the request succeeds.

$.get(URL,callback);

so change your code :

 logout.html(loader);
 $.get("modules/"+role+"/"+role+".php",function(pagedata)
 logout.show().html(pagedata); 
 );

share|improve this answer

answered Mar 24 at 22:14

Razmik GhookasRazmik Ghookas

854

add a comment | 

0

The

$.get()

method requests data from the server with an HTTP GET request.
The required URL parameter specifies the URL you wish to request.
The optional callback parameter is the name of a function to be executed if the request succeeds.

$.get(URL,callback);

so change your code :

 logout.html(loader);
 $.get("modules/"+role+"/"+role+".php",function(pagedata)
 logout.show().html(pagedata); 
 );

share|improve this answer

answered Mar 24 at 22:14

Razmik GhookasRazmik Ghookas

854

add a comment | 

The

$.get()

method requests data from the server with an HTTP GET request.
The required URL parameter specifies the URL you wish to request.
The optional callback parameter is the name of a function to be executed if the request succeeds.

$.get(URL,callback);

so change your code :

 logout.html(loader);
 $.get("modules/"+role+"/"+role+".php",function(pagedata)
 logout.show().html(pagedata); 
 );

share|improve this answer

answered Mar 24 at 22:14

Razmik GhookasRazmik Ghookas

854

$.get()

$.get(URL,callback);

 logout.html(loader);
 $.get("modules/"+role+"/"+role+".php",function(pagedata)
 logout.show().html(pagedata); 
 );

share|improve this answer

answered Mar 24 at 22:14

Razmik GhookasRazmik Ghookas

854

answered Mar 24 at 22:14

Razmik GhookasRazmik Ghookas

854

answered Mar 24 at 22:14

Razmik GhookasRazmik Ghookas

854