Can i access MVC model properties in a separate js file referenced in the .cshtml fileHow can I upload files asynchronously?Can an ASP.NET MVC controller return an Image?How to change a model property from a javascript function inside a view?File Upload ASP.NET MVC 3.0How should a model be structured in MVC?Separation of business logic and data access in djangoBest pratice for completing MVC model properties which aren't bound?Jquery Set Bound Model Property MVCAccess ViewData & Session Variable in JS FileBinding ASP.Net MVC model with dates in custom format

What should I discuss with my DM prior to my first game?

What would prevent chimeras from reproducing with each other?

Why is Na5 not played in this line of the French Defense, Advance Variation?

Can we completely replace inheritance using strategy pattern and dependency injection?

How to write sign "|" (or) in LaTeX?

Use 1 9 6 2 in this order to make 75

What is the reason for setting flaps 1 on the ground at high temperatures?

The origin of the Russian proverb about two hares

Can a human be transformed into a Mind Flayer?

Can the removal of a duty-free sales trolley result in a measurable reduction in emissions?

Why Does Mama Coco Look Old After Going to the Other World?

How to avoid typing 'git' at the begining of every Git command

How can I remove material from this wood beam?

Diatonic chords of a pentatonic vs blues scale?

How durable are silver inlays on a blade?

Why is the length of the Kelvin unit of temperature equal to that of the Celsius unit?

Could a person damage a jet airliner - from the outside - with their bare hands?

Was planting UN flag on Moon ever discussed?

Housemarks (superimposed & combined letters, heraldry)

How do free-speech protections in the United States apply in public to corporate misrepresentations?

The significance of kelvin as a unit of absolute temperature

Strange outlet behavior

Latex - unable to get proper boxes

Why do radiation hardened IC packages often have long leads?



Can i access MVC model properties in a separate js file referenced in the .cshtml file


How can I upload files asynchronously?Can an ASP.NET MVC controller return an Image?How to change a model property from a javascript function inside a view?File Upload ASP.NET MVC 3.0How should a model be structured in MVC?Separation of business logic and data access in djangoBest pratice for completing MVC model properties which aren't bound?Jquery Set Bound Model Property MVCAccess ViewData & Session Variable in JS FileBinding ASP.Net MVC model with dates in custom format






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;








1















I am working on an MVC project which uses model binding. I need to access the whole model in a javascript file which is referenced in the view page.
I tried JSON encoding the whole model inside a script tag in the view page.



var model = @Html.Raw(Json.Encode(Model));
console.log(model);


which works fine.



In my case, the entire script has to stay in a separate page ie. Not inside the view page itself. How can I access the entire model from that script page?



A single property can be bound to a hidden input field, and the value can be accessed from js by its id i.e.:



<input type="hidden" id="modelObject" value="@model.property")/>
var model = $("#modelObject").val();


I need the whole model in the js page. How can this can be achieved?.



Thanks in Advance.










share|improve this question
























  • is my answer usefull for you?

    – Daniël Tulp
    Mar 24 at 20:25











  • check out the src attribute of the script element.

    – Sam Axe
    Mar 24 at 21:05

















1















I am working on an MVC project which uses model binding. I need to access the whole model in a javascript file which is referenced in the view page.
I tried JSON encoding the whole model inside a script tag in the view page.



var model = @Html.Raw(Json.Encode(Model));
console.log(model);


which works fine.



In my case, the entire script has to stay in a separate page ie. Not inside the view page itself. How can I access the entire model from that script page?



A single property can be bound to a hidden input field, and the value can be accessed from js by its id i.e.:



<input type="hidden" id="modelObject" value="@model.property")/>
var model = $("#modelObject").val();


I need the whole model in the js page. How can this can be achieved?.



Thanks in Advance.










share|improve this question
























  • is my answer usefull for you?

    – Daniël Tulp
    Mar 24 at 20:25











  • check out the src attribute of the script element.

    – Sam Axe
    Mar 24 at 21:05













1












1








1








I am working on an MVC project which uses model binding. I need to access the whole model in a javascript file which is referenced in the view page.
I tried JSON encoding the whole model inside a script tag in the view page.



var model = @Html.Raw(Json.Encode(Model));
console.log(model);


which works fine.



In my case, the entire script has to stay in a separate page ie. Not inside the view page itself. How can I access the entire model from that script page?



A single property can be bound to a hidden input field, and the value can be accessed from js by its id i.e.:



<input type="hidden" id="modelObject" value="@model.property")/>
var model = $("#modelObject").val();


I need the whole model in the js page. How can this can be achieved?.



Thanks in Advance.










share|improve this question
















I am working on an MVC project which uses model binding. I need to access the whole model in a javascript file which is referenced in the view page.
I tried JSON encoding the whole model inside a script tag in the view page.



var model = @Html.Raw(Json.Encode(Model));
console.log(model);


which works fine.



In my case, the entire script has to stay in a separate page ie. Not inside the view page itself. How can I access the entire model from that script page?



A single property can be bound to a hidden input field, and the value can be accessed from js by its id i.e.:



<input type="hidden" id="modelObject" value="@model.property")/>
var model = $("#modelObject").val();


I need the whole model in the js page. How can this can be achieved?.



Thanks in Advance.







jquery asp.net asp.net-mvc model-view-controller model-binding






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 19 at 13:47







Yadukrishnan M

















asked Mar 19 at 12:35









Yadukrishnan MYadukrishnan M

8611




8611












  • is my answer usefull for you?

    – Daniël Tulp
    Mar 24 at 20:25











  • check out the src attribute of the script element.

    – Sam Axe
    Mar 24 at 21:05

















  • is my answer usefull for you?

    – Daniël Tulp
    Mar 24 at 20:25











  • check out the src attribute of the script element.

    – Sam Axe
    Mar 24 at 21:05
















is my answer usefull for you?

– Daniël Tulp
Mar 24 at 20:25





is my answer usefull for you?

– Daniël Tulp
Mar 24 at 20:25













check out the src attribute of the script element.

– Sam Axe
Mar 24 at 21:05





check out the src attribute of the script element.

– Sam Axe
Mar 24 at 21:05












2 Answers
2






active

oldest

votes


















0














Razor templates output text, which can typically be a "page" (html/css/js) served with a content type of text/html. But you can serve other content types, like text/javascript, if you want.



First, create a controller action decorated with the ActionName attribute:



public class ScriptsController 
[ActionName("model.js")]
public ActionResult ModelJs()
var model = new Object(); // your actual model here.
return View();




Then you create your view, which is just like your script tag in your current page:



var model = @Html.Raw(Json.Encode(Model));


make sure you remove the script element from your current page.



Then reference the new js view in your page:



<script type="text/javascript" src="@Url.Action("model.js", "Scripts")"></script>





share|improve this answer























  • better to return Json from the controller instead of converting it with .Raw and Encode to Json in the view

    – Daniël Tulp
    Mar 25 at 8:40











  • "Better" must always be defined.

    – Sam Axe
    Mar 26 at 9:12











  • I am just always very hesitant to using Html.Raw as it renders unencoded data in the view, of course you have covered this with the Json.Encode, but why not just do that encoding on the server and pass the pure Json to the client, looks like a better separation of concerns to me, and it also makes sure developers do not use Html.Raw incorrectly/insecure when you just agree not to use it at all.

    – Daniël Tulp
    Mar 27 at 9:46











  • I think either method will work fine. Returning json from the controller is great for the simplicity. Returning json from the view is great if you need to customize what gets returned.. like say, add some functions to the file, or encapsulate the json in a function. Either way, what I most disagree with is the idea that just because something has the potential for misuse people believe it shouldn't be used at all. Dangerous things should be used appropriately, and not misused. But Html.Raw has a purpose and an acceptable use.

    – Sam Axe
    Mar 27 at 20:52


















-1














You can create a constructor for your JavasScript model and then instantiate that with razor code.



For example:



Model



public class Car
public string Brand get; set;
public string Fuel get; set;



Javascript file in module pattern, but you can use something else as well:



var car = (function(jsonModel)
var runs = "My " + jsonModel.Brand + " runs on " + jsonModel.Fuel;
return
Runs : runs

);


Razor view



@model Car

<!--load the javascript file somewhere-->

<script type="text/javascript">
$(function()
var myFord = new car(@Html.Raw(Json.Encode(@Model)) );
alert(myFord.Runs);
);
</script>


.NET fiddle I could not add an external javascript file, but you will probably get the point



Although I should say that using @Html.Raw is not recommended as it makes you vulnerable to XSS attacks (read more on the internet after a search). It is better to return the JSON object from your controller.



Edit



Here is an example how to use the JsonResult on .Net fiddle
controller



 [HttpGet]
public JsonResult Car()

return Json(new Car("ford","gasoline"), JsonRequestBehavior.AllowGet);



razor view JS to get the json result and instantiate your JS module



$(function()
var model = $.ajax(
url: "@Url.Action("Car","Home")",
dataType: 'json',
contentType: 'application/json; charset=utf-8',
).done(function(response)
console.log(response);
var myFord = new car(response);
alert(myFord.Runs);
);
);





share|improve this answer

























  • This answer does not address the OPs question.

    – Sam Axe
    Mar 24 at 21:06











  • I think it does, as I read it the OP wants to have an entire model send to a JS file, as I mentioned I could not reference a separate file, that is why the JavaScript was inline in the Razor view, but you can of course place this in a separate file and then include the file from the view

    – Daniël Tulp
    Mar 25 at 8:38











Your Answer






StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");

StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);



);













draft saved

draft discarded


















StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55241236%2fcan-i-access-mvc-model-properties-in-a-separate-js-file-referenced-in-the-cshtm%23new-answer', 'question_page');

);

Post as a guest















Required, but never shown

























2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














Razor templates output text, which can typically be a "page" (html/css/js) served with a content type of text/html. But you can serve other content types, like text/javascript, if you want.



First, create a controller action decorated with the ActionName attribute:



public class ScriptsController 
[ActionName("model.js")]
public ActionResult ModelJs()
var model = new Object(); // your actual model here.
return View();




Then you create your view, which is just like your script tag in your current page:



var model = @Html.Raw(Json.Encode(Model));


make sure you remove the script element from your current page.



Then reference the new js view in your page:



<script type="text/javascript" src="@Url.Action("model.js", "Scripts")"></script>





share|improve this answer























  • better to return Json from the controller instead of converting it with .Raw and Encode to Json in the view

    – Daniël Tulp
    Mar 25 at 8:40











  • "Better" must always be defined.

    – Sam Axe
    Mar 26 at 9:12











  • I am just always very hesitant to using Html.Raw as it renders unencoded data in the view, of course you have covered this with the Json.Encode, but why not just do that encoding on the server and pass the pure Json to the client, looks like a better separation of concerns to me, and it also makes sure developers do not use Html.Raw incorrectly/insecure when you just agree not to use it at all.

    – Daniël Tulp
    Mar 27 at 9:46











  • I think either method will work fine. Returning json from the controller is great for the simplicity. Returning json from the view is great if you need to customize what gets returned.. like say, add some functions to the file, or encapsulate the json in a function. Either way, what I most disagree with is the idea that just because something has the potential for misuse people believe it shouldn't be used at all. Dangerous things should be used appropriately, and not misused. But Html.Raw has a purpose and an acceptable use.

    – Sam Axe
    Mar 27 at 20:52















0














Razor templates output text, which can typically be a "page" (html/css/js) served with a content type of text/html. But you can serve other content types, like text/javascript, if you want.



First, create a controller action decorated with the ActionName attribute:



public class ScriptsController 
[ActionName("model.js")]
public ActionResult ModelJs()
var model = new Object(); // your actual model here.
return View();




Then you create your view, which is just like your script tag in your current page:



var model = @Html.Raw(Json.Encode(Model));


make sure you remove the script element from your current page.



Then reference the new js view in your page:



<script type="text/javascript" src="@Url.Action("model.js", "Scripts")"></script>





share|improve this answer























  • better to return Json from the controller instead of converting it with .Raw and Encode to Json in the view

    – Daniël Tulp
    Mar 25 at 8:40











  • "Better" must always be defined.

    – Sam Axe
    Mar 26 at 9:12











  • I am just always very hesitant to using Html.Raw as it renders unencoded data in the view, of course you have covered this with the Json.Encode, but why not just do that encoding on the server and pass the pure Json to the client, looks like a better separation of concerns to me, and it also makes sure developers do not use Html.Raw incorrectly/insecure when you just agree not to use it at all.

    – Daniël Tulp
    Mar 27 at 9:46











  • I think either method will work fine. Returning json from the controller is great for the simplicity. Returning json from the view is great if you need to customize what gets returned.. like say, add some functions to the file, or encapsulate the json in a function. Either way, what I most disagree with is the idea that just because something has the potential for misuse people believe it shouldn't be used at all. Dangerous things should be used appropriately, and not misused. But Html.Raw has a purpose and an acceptable use.

    – Sam Axe
    Mar 27 at 20:52













0












0








0







Razor templates output text, which can typically be a "page" (html/css/js) served with a content type of text/html. But you can serve other content types, like text/javascript, if you want.



First, create a controller action decorated with the ActionName attribute:



public class ScriptsController 
[ActionName("model.js")]
public ActionResult ModelJs()
var model = new Object(); // your actual model here.
return View();




Then you create your view, which is just like your script tag in your current page:



var model = @Html.Raw(Json.Encode(Model));


make sure you remove the script element from your current page.



Then reference the new js view in your page:



<script type="text/javascript" src="@Url.Action("model.js", "Scripts")"></script>





share|improve this answer













Razor templates output text, which can typically be a "page" (html/css/js) served with a content type of text/html. But you can serve other content types, like text/javascript, if you want.



First, create a controller action decorated with the ActionName attribute:



public class ScriptsController 
[ActionName("model.js")]
public ActionResult ModelJs()
var model = new Object(); // your actual model here.
return View();




Then you create your view, which is just like your script tag in your current page:



var model = @Html.Raw(Json.Encode(Model));


make sure you remove the script element from your current page.



Then reference the new js view in your page:



<script type="text/javascript" src="@Url.Action("model.js", "Scripts")"></script>






share|improve this answer












share|improve this answer



share|improve this answer










answered Mar 24 at 21:15









Sam AxeSam Axe

27.5k74575




27.5k74575












  • better to return Json from the controller instead of converting it with .Raw and Encode to Json in the view

    – Daniël Tulp
    Mar 25 at 8:40











  • "Better" must always be defined.

    – Sam Axe
    Mar 26 at 9:12











  • I am just always very hesitant to using Html.Raw as it renders unencoded data in the view, of course you have covered this with the Json.Encode, but why not just do that encoding on the server and pass the pure Json to the client, looks like a better separation of concerns to me, and it also makes sure developers do not use Html.Raw incorrectly/insecure when you just agree not to use it at all.

    – Daniël Tulp
    Mar 27 at 9:46











  • I think either method will work fine. Returning json from the controller is great for the simplicity. Returning json from the view is great if you need to customize what gets returned.. like say, add some functions to the file, or encapsulate the json in a function. Either way, what I most disagree with is the idea that just because something has the potential for misuse people believe it shouldn't be used at all. Dangerous things should be used appropriately, and not misused. But Html.Raw has a purpose and an acceptable use.

    – Sam Axe
    Mar 27 at 20:52

















  • better to return Json from the controller instead of converting it with .Raw and Encode to Json in the view

    – Daniël Tulp
    Mar 25 at 8:40











  • "Better" must always be defined.

    – Sam Axe
    Mar 26 at 9:12











  • I am just always very hesitant to using Html.Raw as it renders unencoded data in the view, of course you have covered this with the Json.Encode, but why not just do that encoding on the server and pass the pure Json to the client, looks like a better separation of concerns to me, and it also makes sure developers do not use Html.Raw incorrectly/insecure when you just agree not to use it at all.

    – Daniël Tulp
    Mar 27 at 9:46











  • I think either method will work fine. Returning json from the controller is great for the simplicity. Returning json from the view is great if you need to customize what gets returned.. like say, add some functions to the file, or encapsulate the json in a function. Either way, what I most disagree with is the idea that just because something has the potential for misuse people believe it shouldn't be used at all. Dangerous things should be used appropriately, and not misused. But Html.Raw has a purpose and an acceptable use.

    – Sam Axe
    Mar 27 at 20:52
















better to return Json from the controller instead of converting it with .Raw and Encode to Json in the view

– Daniël Tulp
Mar 25 at 8:40





better to return Json from the controller instead of converting it with .Raw and Encode to Json in the view

– Daniël Tulp
Mar 25 at 8:40













"Better" must always be defined.

– Sam Axe
Mar 26 at 9:12





"Better" must always be defined.

– Sam Axe
Mar 26 at 9:12













I am just always very hesitant to using Html.Raw as it renders unencoded data in the view, of course you have covered this with the Json.Encode, but why not just do that encoding on the server and pass the pure Json to the client, looks like a better separation of concerns to me, and it also makes sure developers do not use Html.Raw incorrectly/insecure when you just agree not to use it at all.

– Daniël Tulp
Mar 27 at 9:46





I am just always very hesitant to using Html.Raw as it renders unencoded data in the view, of course you have covered this with the Json.Encode, but why not just do that encoding on the server and pass the pure Json to the client, looks like a better separation of concerns to me, and it also makes sure developers do not use Html.Raw incorrectly/insecure when you just agree not to use it at all.

– Daniël Tulp
Mar 27 at 9:46













I think either method will work fine. Returning json from the controller is great for the simplicity. Returning json from the view is great if you need to customize what gets returned.. like say, add some functions to the file, or encapsulate the json in a function. Either way, what I most disagree with is the idea that just because something has the potential for misuse people believe it shouldn't be used at all. Dangerous things should be used appropriately, and not misused. But Html.Raw has a purpose and an acceptable use.

– Sam Axe
Mar 27 at 20:52





I think either method will work fine. Returning json from the controller is great for the simplicity. Returning json from the view is great if you need to customize what gets returned.. like say, add some functions to the file, or encapsulate the json in a function. Either way, what I most disagree with is the idea that just because something has the potential for misuse people believe it shouldn't be used at all. Dangerous things should be used appropriately, and not misused. But Html.Raw has a purpose and an acceptable use.

– Sam Axe
Mar 27 at 20:52













-1














You can create a constructor for your JavasScript model and then instantiate that with razor code.



For example:



Model



public class Car
public string Brand get; set;
public string Fuel get; set;



Javascript file in module pattern, but you can use something else as well:



var car = (function(jsonModel)
var runs = "My " + jsonModel.Brand + " runs on " + jsonModel.Fuel;
return
Runs : runs

);


Razor view



@model Car

<!--load the javascript file somewhere-->

<script type="text/javascript">
$(function()
var myFord = new car(@Html.Raw(Json.Encode(@Model)) );
alert(myFord.Runs);
);
</script>


.NET fiddle I could not add an external javascript file, but you will probably get the point



Although I should say that using @Html.Raw is not recommended as it makes you vulnerable to XSS attacks (read more on the internet after a search). It is better to return the JSON object from your controller.



Edit



Here is an example how to use the JsonResult on .Net fiddle
controller



 [HttpGet]
public JsonResult Car()

return Json(new Car("ford","gasoline"), JsonRequestBehavior.AllowGet);



razor view JS to get the json result and instantiate your JS module



$(function()
var model = $.ajax(
url: "@Url.Action("Car","Home")",
dataType: 'json',
contentType: 'application/json; charset=utf-8',
).done(function(response)
console.log(response);
var myFord = new car(response);
alert(myFord.Runs);
);
);





share|improve this answer

























  • This answer does not address the OPs question.

    – Sam Axe
    Mar 24 at 21:06











  • I think it does, as I read it the OP wants to have an entire model send to a JS file, as I mentioned I could not reference a separate file, that is why the JavaScript was inline in the Razor view, but you can of course place this in a separate file and then include the file from the view

    – Daniël Tulp
    Mar 25 at 8:38















-1














You can create a constructor for your JavasScript model and then instantiate that with razor code.



For example:



Model



public class Car
public string Brand get; set;
public string Fuel get; set;



Javascript file in module pattern, but you can use something else as well:



var car = (function(jsonModel)
var runs = "My " + jsonModel.Brand + " runs on " + jsonModel.Fuel;
return
Runs : runs

);


Razor view



@model Car

<!--load the javascript file somewhere-->

<script type="text/javascript">
$(function()
var myFord = new car(@Html.Raw(Json.Encode(@Model)) );
alert(myFord.Runs);
);
</script>


.NET fiddle I could not add an external javascript file, but you will probably get the point



Although I should say that using @Html.Raw is not recommended as it makes you vulnerable to XSS attacks (read more on the internet after a search). It is better to return the JSON object from your controller.



Edit



Here is an example how to use the JsonResult on .Net fiddle
controller



 [HttpGet]
public JsonResult Car()

return Json(new Car("ford","gasoline"), JsonRequestBehavior.AllowGet);



razor view JS to get the json result and instantiate your JS module



$(function()
var model = $.ajax(
url: "@Url.Action("Car","Home")",
dataType: 'json',
contentType: 'application/json; charset=utf-8',
).done(function(response)
console.log(response);
var myFord = new car(response);
alert(myFord.Runs);
);
);





share|improve this answer

























  • This answer does not address the OPs question.

    – Sam Axe
    Mar 24 at 21:06











  • I think it does, as I read it the OP wants to have an entire model send to a JS file, as I mentioned I could not reference a separate file, that is why the JavaScript was inline in the Razor view, but you can of course place this in a separate file and then include the file from the view

    – Daniël Tulp
    Mar 25 at 8:38













-1












-1








-1







You can create a constructor for your JavasScript model and then instantiate that with razor code.



For example:



Model



public class Car
public string Brand get; set;
public string Fuel get; set;



Javascript file in module pattern, but you can use something else as well:



var car = (function(jsonModel)
var runs = "My " + jsonModel.Brand + " runs on " + jsonModel.Fuel;
return
Runs : runs

);


Razor view



@model Car

<!--load the javascript file somewhere-->

<script type="text/javascript">
$(function()
var myFord = new car(@Html.Raw(Json.Encode(@Model)) );
alert(myFord.Runs);
);
</script>


.NET fiddle I could not add an external javascript file, but you will probably get the point



Although I should say that using @Html.Raw is not recommended as it makes you vulnerable to XSS attacks (read more on the internet after a search). It is better to return the JSON object from your controller.



Edit



Here is an example how to use the JsonResult on .Net fiddle
controller



 [HttpGet]
public JsonResult Car()

return Json(new Car("ford","gasoline"), JsonRequestBehavior.AllowGet);



razor view JS to get the json result and instantiate your JS module



$(function()
var model = $.ajax(
url: "@Url.Action("Car","Home")",
dataType: 'json',
contentType: 'application/json; charset=utf-8',
).done(function(response)
console.log(response);
var myFord = new car(response);
alert(myFord.Runs);
);
);





share|improve this answer















You can create a constructor for your JavasScript model and then instantiate that with razor code.



For example:



Model



public class Car
public string Brand get; set;
public string Fuel get; set;



Javascript file in module pattern, but you can use something else as well:



var car = (function(jsonModel)
var runs = "My " + jsonModel.Brand + " runs on " + jsonModel.Fuel;
return
Runs : runs

);


Razor view



@model Car

<!--load the javascript file somewhere-->

<script type="text/javascript">
$(function()
var myFord = new car(@Html.Raw(Json.Encode(@Model)) );
alert(myFord.Runs);
);
</script>


.NET fiddle I could not add an external javascript file, but you will probably get the point



Although I should say that using @Html.Raw is not recommended as it makes you vulnerable to XSS attacks (read more on the internet after a search). It is better to return the JSON object from your controller.



Edit



Here is an example how to use the JsonResult on .Net fiddle
controller



 [HttpGet]
public JsonResult Car()

return Json(new Car("ford","gasoline"), JsonRequestBehavior.AllowGet);



razor view JS to get the json result and instantiate your JS module



$(function()
var model = $.ajax(
url: "@Url.Action("Car","Home")",
dataType: 'json',
contentType: 'application/json; charset=utf-8',
).done(function(response)
console.log(response);
var myFord = new car(response);
alert(myFord.Runs);
);
);






share|improve this answer














share|improve this answer



share|improve this answer








edited Mar 24 at 20:33

























answered Mar 19 at 14:06









Daniël TulpDaniël Tulp

91921345




91921345












  • This answer does not address the OPs question.

    – Sam Axe
    Mar 24 at 21:06











  • I think it does, as I read it the OP wants to have an entire model send to a JS file, as I mentioned I could not reference a separate file, that is why the JavaScript was inline in the Razor view, but you can of course place this in a separate file and then include the file from the view

    – Daniël Tulp
    Mar 25 at 8:38

















  • This answer does not address the OPs question.

    – Sam Axe
    Mar 24 at 21:06











  • I think it does, as I read it the OP wants to have an entire model send to a JS file, as I mentioned I could not reference a separate file, that is why the JavaScript was inline in the Razor view, but you can of course place this in a separate file and then include the file from the view

    – Daniël Tulp
    Mar 25 at 8:38
















This answer does not address the OPs question.

– Sam Axe
Mar 24 at 21:06





This answer does not address the OPs question.

– Sam Axe
Mar 24 at 21:06













I think it does, as I read it the OP wants to have an entire model send to a JS file, as I mentioned I could not reference a separate file, that is why the JavaScript was inline in the Razor view, but you can of course place this in a separate file and then include the file from the view

– Daniël Tulp
Mar 25 at 8:38





I think it does, as I read it the OP wants to have an entire model send to a JS file, as I mentioned I could not reference a separate file, that is why the JavaScript was inline in the Razor view, but you can of course place this in a separate file and then include the file from the view

– Daniël Tulp
Mar 25 at 8:38

















draft saved

draft discarded
















































Thanks for contributing an answer to Stack Overflow!


  • Please be sure to answer the question. Provide details and share your research!

But avoid


  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55241236%2fcan-i-access-mvc-model-properties-in-a-separate-js-file-referenced-in-the-cshtm%23new-answer', 'question_page');

);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

SQL error code 1064 with creating Laravel foreign keysForeign key constraints: When to use ON UPDATE and ON DELETEDropping column with foreign key Laravel error: General error: 1025 Error on renameLaravel SQL Can't create tableLaravel Migration foreign key errorLaravel php artisan migrate:refresh giving a syntax errorSQLSTATE[42S01]: Base table or view already exists or Base table or view already exists: 1050 Tableerror in migrating laravel file to xampp serverSyntax error or access violation: 1064:syntax to use near 'unsigned not null, modelName varchar(191) not null, title varchar(191) not nLaravel cannot create new table field in mysqlLaravel 5.7:Last migration creates table but is not registered in the migration table

용인 삼성생명 블루밍스 목차 통계 역대 감독 선수단 응원단 경기장 같이 보기 외부 링크 둘러보기 메뉴samsungblueminx.comeh선수 명단용인 삼성생명 블루밍스용인 삼성생명 블루밍스ehsamsungblueminx.comeheheheh

155 수학 과학 기타 둘러보기 메뉴eh추가해eh문서를 완성해