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Electron app load external URL on application close


PHP Logout Script with 4 frames in framesetOpen external file with ElectronUsing console.log() in Electron appDetect multiple tabs or windows of the same session in a web applicationPHP header(Location:'index.php') and javascript not being executedLoad Electron application from URLCannot read property on of undefined. Electron BrowserWindow objecthow to make a conditional ajax call triggered by onbeforeload based on a variable's valueAngular / Electron using the renderer.js with angular componentsLoading div from external site in Electron app






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;








0















I am trying to load a log-out URL once the app close button is hit,



Something like the following. Problem is that I am receiving an error that the window is already closed and can't load. Any help achieve this will be appreciated.



app.on('ready', function () 
// Create new window
mainWindow = new BrowserWindow(webPreferences:
nodeIntegration: false
);

// Load php index into window
mainWindow.setTitle('Test');
mainWindow.loadURL('http://www.url.com/index.php');
//mainWindow.webContents.openDevTools();
mainWindow.setMenu(null);
mainWindow.on('closed', () =>
mainWindow.loadURL('https://www.url.com/logout.php?logout=true');
mainWindow = null;
app.quit();
);
);









share|improve this question

















  • 1





    Doesn't make sense. It's like saying ... when I close my browser go to a different web site. Perhaps all you need is to make an a ajax request?

    – charlietfl
    Mar 24 at 19:04












  • Well, the idea is closing the browser window first, than trigger the URL to log out and that to close the app. Thought that with simple link visit will be easier than ajax request. And with Ajax might face problems with cors cross domain.

    – John Siniger
    Mar 24 at 19:27

















0















I am trying to load a log-out URL once the app close button is hit,



Something like the following. Problem is that I am receiving an error that the window is already closed and can't load. Any help achieve this will be appreciated.



app.on('ready', function () 
// Create new window
mainWindow = new BrowserWindow(webPreferences:
nodeIntegration: false
);

// Load php index into window
mainWindow.setTitle('Test');
mainWindow.loadURL('http://www.url.com/index.php');
//mainWindow.webContents.openDevTools();
mainWindow.setMenu(null);
mainWindow.on('closed', () =>
mainWindow.loadURL('https://www.url.com/logout.php?logout=true');
mainWindow = null;
app.quit();
);
);









share|improve this question

















  • 1





    Doesn't make sense. It's like saying ... when I close my browser go to a different web site. Perhaps all you need is to make an a ajax request?

    – charlietfl
    Mar 24 at 19:04












  • Well, the idea is closing the browser window first, than trigger the URL to log out and that to close the app. Thought that with simple link visit will be easier than ajax request. And with Ajax might face problems with cors cross domain.

    – John Siniger
    Mar 24 at 19:27













0












0








0








I am trying to load a log-out URL once the app close button is hit,



Something like the following. Problem is that I am receiving an error that the window is already closed and can't load. Any help achieve this will be appreciated.



app.on('ready', function () 
// Create new window
mainWindow = new BrowserWindow(webPreferences:
nodeIntegration: false
);

// Load php index into window
mainWindow.setTitle('Test');
mainWindow.loadURL('http://www.url.com/index.php');
//mainWindow.webContents.openDevTools();
mainWindow.setMenu(null);
mainWindow.on('closed', () =>
mainWindow.loadURL('https://www.url.com/logout.php?logout=true');
mainWindow = null;
app.quit();
);
);









share|improve this question














I am trying to load a log-out URL once the app close button is hit,



Something like the following. Problem is that I am receiving an error that the window is already closed and can't load. Any help achieve this will be appreciated.



app.on('ready', function () 
// Create new window
mainWindow = new BrowserWindow(webPreferences:
nodeIntegration: false
);

// Load php index into window
mainWindow.setTitle('Test');
mainWindow.loadURL('http://www.url.com/index.php');
//mainWindow.webContents.openDevTools();
mainWindow.setMenu(null);
mainWindow.on('closed', () =>
mainWindow.loadURL('https://www.url.com/logout.php?logout=true');
mainWindow = null;
app.quit();
);
);






javascript electron






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 24 at 18:59









John SinigerJohn Siniger

5371926




5371926







  • 1





    Doesn't make sense. It's like saying ... when I close my browser go to a different web site. Perhaps all you need is to make an a ajax request?

    – charlietfl
    Mar 24 at 19:04












  • Well, the idea is closing the browser window first, than trigger the URL to log out and that to close the app. Thought that with simple link visit will be easier than ajax request. And with Ajax might face problems with cors cross domain.

    – John Siniger
    Mar 24 at 19:27












  • 1





    Doesn't make sense. It's like saying ... when I close my browser go to a different web site. Perhaps all you need is to make an a ajax request?

    – charlietfl
    Mar 24 at 19:04












  • Well, the idea is closing the browser window first, than trigger the URL to log out and that to close the app. Thought that with simple link visit will be easier than ajax request. And with Ajax might face problems with cors cross domain.

    – John Siniger
    Mar 24 at 19:27







1




1





Doesn't make sense. It's like saying ... when I close my browser go to a different web site. Perhaps all you need is to make an a ajax request?

– charlietfl
Mar 24 at 19:04






Doesn't make sense. It's like saying ... when I close my browser go to a different web site. Perhaps all you need is to make an a ajax request?

– charlietfl
Mar 24 at 19:04














Well, the idea is closing the browser window first, than trigger the URL to log out and that to close the app. Thought that with simple link visit will be easier than ajax request. And with Ajax might face problems with cors cross domain.

– John Siniger
Mar 24 at 19:27





Well, the idea is closing the browser window first, than trigger the URL to log out and that to close the app. Thought that with simple link visit will be easier than ajax request. And with Ajax might face problems with cors cross domain.

– John Siniger
Mar 24 at 19:27












1 Answer
1






active

oldest

votes


















2














I'm a little confused by what you're trying to do, but it sounds like you can just load the URL when the close event is triggered, cancel the event to prevent closed from firing, and then when the page has loaded, you could close again, but this time for real.



mainWindow.on('close', (e) => 
mainWindow.webContents.on('did-finish-load', logOutPageLoaded);
mainWindow.loadURL('https://www.url.com/logout.php?logout=true');
e.preventDefault();
);

function logOutPageLoaded()
mainWindow.destroy();


mainWindow.on('closed', () =>
mainWindow = null;
app.quit();
);





share|improve this answer























  • This is exactly what I needed!

    – John Siniger
    Mar 25 at 12:08











Your Answer






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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









2














I'm a little confused by what you're trying to do, but it sounds like you can just load the URL when the close event is triggered, cancel the event to prevent closed from firing, and then when the page has loaded, you could close again, but this time for real.



mainWindow.on('close', (e) => 
mainWindow.webContents.on('did-finish-load', logOutPageLoaded);
mainWindow.loadURL('https://www.url.com/logout.php?logout=true');
e.preventDefault();
);

function logOutPageLoaded()
mainWindow.destroy();


mainWindow.on('closed', () =>
mainWindow = null;
app.quit();
);





share|improve this answer























  • This is exactly what I needed!

    – John Siniger
    Mar 25 at 12:08















2














I'm a little confused by what you're trying to do, but it sounds like you can just load the URL when the close event is triggered, cancel the event to prevent closed from firing, and then when the page has loaded, you could close again, but this time for real.



mainWindow.on('close', (e) => 
mainWindow.webContents.on('did-finish-load', logOutPageLoaded);
mainWindow.loadURL('https://www.url.com/logout.php?logout=true');
e.preventDefault();
);

function logOutPageLoaded()
mainWindow.destroy();


mainWindow.on('closed', () =>
mainWindow = null;
app.quit();
);





share|improve this answer























  • This is exactly what I needed!

    – John Siniger
    Mar 25 at 12:08













2












2








2







I'm a little confused by what you're trying to do, but it sounds like you can just load the URL when the close event is triggered, cancel the event to prevent closed from firing, and then when the page has loaded, you could close again, but this time for real.



mainWindow.on('close', (e) => 
mainWindow.webContents.on('did-finish-load', logOutPageLoaded);
mainWindow.loadURL('https://www.url.com/logout.php?logout=true');
e.preventDefault();
);

function logOutPageLoaded()
mainWindow.destroy();


mainWindow.on('closed', () =>
mainWindow = null;
app.quit();
);





share|improve this answer













I'm a little confused by what you're trying to do, but it sounds like you can just load the URL when the close event is triggered, cancel the event to prevent closed from firing, and then when the page has loaded, you could close again, but this time for real.



mainWindow.on('close', (e) => 
mainWindow.webContents.on('did-finish-load', logOutPageLoaded);
mainWindow.loadURL('https://www.url.com/logout.php?logout=true');
e.preventDefault();
);

function logOutPageLoaded()
mainWindow.destroy();


mainWindow.on('closed', () =>
mainWindow = null;
app.quit();
);






share|improve this answer












share|improve this answer



share|improve this answer










answered Mar 25 at 0:13









pushkinpushkin

4,806123056




4,806123056












  • This is exactly what I needed!

    – John Siniger
    Mar 25 at 12:08

















  • This is exactly what I needed!

    – John Siniger
    Mar 25 at 12:08
















This is exactly what I needed!

– John Siniger
Mar 25 at 12:08





This is exactly what I needed!

– John Siniger
Mar 25 at 12:08



















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