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How do I define in which format `datetime` values are shown when a DataFrame is displayed on the Python console?


Given a DateTime object, how do I get an ISO 8601 date in string format?How do you set a default value for a MySQL Datetime column?How do I convert datetime to date (in Python)?How can I print literal curly-brace characters in python string and also use .format on it?How to drop rows of Pandas DataFrame whose value in certain columns is NaN“Large data” work flows using pandasNaN values when new column added to pandas DataFrameHow to check if any value is NaN in a Pandas DataFrameHow to change datetime format in dataframe with using pandas?Shifting datetime based off date value in dataframe Python






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








0















I have a pandas DataFrame df with a few datetime columns. In the Python console a sample of the frame is displayed like this:



>>> df

action dt_completed dt_created dt_modified
39 update 2010-11-07 22:04:48.668 2010-06-07 07:23:40.536 2017-07-17 06:12:48.059
6056 release 2010-03-25 10:44:42.575 2010-03-24 17:21:54.751 2017-07-17 NaN
5913 publish 2018-12-15 11:12:13.000 2018-12-14 00:30:58.393 2018-12-15 11:12:17.441
7589 create 2011-09-03 22:55:23.656 2011-08-11 12:48:23.543 2011-09-03 22:55:23.656


When I explore the DataFrame I'm only interested in seeing the date portion of the datetime value. How can I tell pandas to display a DataFrame on the console only with the date portions of datetime values?



I looking for something like display.precision, but for datetimes not for floats. Or some way to (globally?) overwrite pandas' datetime-to-string conversion function.




Please note: I'm not after changing the values in the datetime columns to dates or after adding new columns with shortened fields, but rather I'm looking to alter the display of the datetime columns in the console only.












share|improve this question






























    0















    I have a pandas DataFrame df with a few datetime columns. In the Python console a sample of the frame is displayed like this:



    >>> df

    action dt_completed dt_created dt_modified
    39 update 2010-11-07 22:04:48.668 2010-06-07 07:23:40.536 2017-07-17 06:12:48.059
    6056 release 2010-03-25 10:44:42.575 2010-03-24 17:21:54.751 2017-07-17 NaN
    5913 publish 2018-12-15 11:12:13.000 2018-12-14 00:30:58.393 2018-12-15 11:12:17.441
    7589 create 2011-09-03 22:55:23.656 2011-08-11 12:48:23.543 2011-09-03 22:55:23.656


    When I explore the DataFrame I'm only interested in seeing the date portion of the datetime value. How can I tell pandas to display a DataFrame on the console only with the date portions of datetime values?



    I looking for something like display.precision, but for datetimes not for floats. Or some way to (globally?) overwrite pandas' datetime-to-string conversion function.




    Please note: I'm not after changing the values in the datetime columns to dates or after adding new columns with shortened fields, but rather I'm looking to alter the display of the datetime columns in the console only.












    share|improve this question


























      0












      0








      0








      I have a pandas DataFrame df with a few datetime columns. In the Python console a sample of the frame is displayed like this:



      >>> df

      action dt_completed dt_created dt_modified
      39 update 2010-11-07 22:04:48.668 2010-06-07 07:23:40.536 2017-07-17 06:12:48.059
      6056 release 2010-03-25 10:44:42.575 2010-03-24 17:21:54.751 2017-07-17 NaN
      5913 publish 2018-12-15 11:12:13.000 2018-12-14 00:30:58.393 2018-12-15 11:12:17.441
      7589 create 2011-09-03 22:55:23.656 2011-08-11 12:48:23.543 2011-09-03 22:55:23.656


      When I explore the DataFrame I'm only interested in seeing the date portion of the datetime value. How can I tell pandas to display a DataFrame on the console only with the date portions of datetime values?



      I looking for something like display.precision, but for datetimes not for floats. Or some way to (globally?) overwrite pandas' datetime-to-string conversion function.




      Please note: I'm not after changing the values in the datetime columns to dates or after adding new columns with shortened fields, but rather I'm looking to alter the display of the datetime columns in the console only.












      share|improve this question
















      I have a pandas DataFrame df with a few datetime columns. In the Python console a sample of the frame is displayed like this:



      >>> df

      action dt_completed dt_created dt_modified
      39 update 2010-11-07 22:04:48.668 2010-06-07 07:23:40.536 2017-07-17 06:12:48.059
      6056 release 2010-03-25 10:44:42.575 2010-03-24 17:21:54.751 2017-07-17 NaN
      5913 publish 2018-12-15 11:12:13.000 2018-12-14 00:30:58.393 2018-12-15 11:12:17.441
      7589 create 2011-09-03 22:55:23.656 2011-08-11 12:48:23.543 2011-09-03 22:55:23.656


      When I explore the DataFrame I'm only interested in seeing the date portion of the datetime value. How can I tell pandas to display a DataFrame on the console only with the date portions of datetime values?



      I looking for something like display.precision, but for datetimes not for floats. Or some way to (globally?) overwrite pandas' datetime-to-string conversion function.




      Please note: I'm not after changing the values in the datetime columns to dates or after adding new columns with shortened fields, but rather I'm looking to alter the display of the datetime columns in the console only.









      python pandas datetime dataframe datetime-format






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Mar 27 at 23:49







      halloleo

















      asked Mar 26 at 2:42









      halloleohalloleo

      2,6895 gold badges29 silver badges63 bronze badges




      2,6895 gold badges29 silver badges63 bronze badges






















          2 Answers
          2






          active

          oldest

          votes


















          1














          Try something like this....



          Lets create some date.... (Sorry I am too lazy)



          import pandas as pd
          from datetime import datetime
          data='1':[datetime.now(),datetime.now()],
          '2':[datetime.now(),datetime.now()],
          '3':[datetime.now(),datetime.now()]

          df=pd.DataFrame.from_dict(data,orient='index')
          df.columns=['date1','date2']


          I can see the data ....



          df.head()


          Something like



           date1 date2
          1 2019-03-26 12:28:51.080622 2019-03-26 12:28:51.080627
          2 2019-03-26 12:28:51.080628 2019-03-26 12:28:51.080628
          3 2019-03-26 12:28:51.080629 2019-03-26 12:28:51.080630


          I use a custom style



          def mydateformat(date):
          return "--".format(date.year, date.month, date.day)

          df2=df.style.format('date1':mydateformat)
          df2


          Which shows



           date1 date2
          1 2019-3-26 2019-03-26 12:41:02.834557
          2 2019-3-26 2019-03-26 12:41:02.834558
          3 2019-3-26 2019-03-26 12:41:02.834560


          To check it has not altered the date1 column



          df['diff']=-1
          df['diff']=df.date1-df.date2


          And to view again ....



          df2 


          I see - which is the new Column in df with style in df2.



           date1 date2
          1 2019-3-26 2019-03-26 12:42:14.417441 -1 days +23:59:59.999995
          2 2019-3-26 2019-03-26 12:42:14.417443 -1 days +23:59:59.999999
          3 2019-3-26 2019-03-26 12:42:14.417444 -1 days +23:59:59.999999


          The slight rounding caused by the timestamp accuracy.... not the roungind on the date1 column.



          Hope that helps.






          share|improve this answer

























          • Very Interesting! Not exactly what I was hoping for, but pretty close if it works. Will check it out.

            – halloleo
            Mar 26 at 6:58











          • Mmmh, doesn't seem to work: After customising df with the df.style... declaration, displaying df still shows the full format for date1. And why do you issue df.style... a second time below creating the diff column?

            – halloleo
            Mar 26 at 7:31












          • @halloleo Try.... df2=df.style.format('date1':mydateformat) That seems to hold the value - you can modify df.... and still keep the reformatted data in df2

            – Tim Seed
            Mar 26 at 7:49











          • When I use exactly your example typing df2 on the command line outputs "<pandas.io.formats.style.Styler object at 0x7fca8965a0b8>". df2 is not a DataFrame, but a Styler object. I'm using Python 3.6.4 and pandas 0.24.2.

            – halloleo
            Mar 26 at 23:58











          • @halloleo Yes df2 is a html view of the data. So no .head() or Column mainipulations. More info at pandas.pydata.org/pandas-docs/stable/user_guide/style.html

            – Tim Seed
            Mar 27 at 2:32


















          -1














          import pandas as pd
          from datetime import datetime

          data='1':[datetime.now(),datetime.now()],
          '2':[datetime.now(),datetime.now()],
          '3':[datetime.now(),datetime.now()]

          df=pd.DataFrame.from_dict(data,orient='index')
          df.columns=['date1','date2']
          df['date3'] = df['date1'].apply(datetime.date)
          df['date4'] = df['date2'].apply(datetime.date)
          df





          share|improve this answer























          • This solution does not list the existing datetime columns in the way I am asking for. It just ads new columns.

            – halloleo
            Mar 26 at 6:32











          • Here, date1, date2 are the existing columns and the date3, date4 are the new columns which are holding the values without time details. It is not having your data to work with, but you can try it with your data as well.

            – Himmat
            Mar 27 at 7:22













          Your Answer






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          2 Answers
          2






          active

          oldest

          votes








          2 Answers
          2






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          Try something like this....



          Lets create some date.... (Sorry I am too lazy)



          import pandas as pd
          from datetime import datetime
          data='1':[datetime.now(),datetime.now()],
          '2':[datetime.now(),datetime.now()],
          '3':[datetime.now(),datetime.now()]

          df=pd.DataFrame.from_dict(data,orient='index')
          df.columns=['date1','date2']


          I can see the data ....



          df.head()


          Something like



           date1 date2
          1 2019-03-26 12:28:51.080622 2019-03-26 12:28:51.080627
          2 2019-03-26 12:28:51.080628 2019-03-26 12:28:51.080628
          3 2019-03-26 12:28:51.080629 2019-03-26 12:28:51.080630


          I use a custom style



          def mydateformat(date):
          return "--".format(date.year, date.month, date.day)

          df2=df.style.format('date1':mydateformat)
          df2


          Which shows



           date1 date2
          1 2019-3-26 2019-03-26 12:41:02.834557
          2 2019-3-26 2019-03-26 12:41:02.834558
          3 2019-3-26 2019-03-26 12:41:02.834560


          To check it has not altered the date1 column



          df['diff']=-1
          df['diff']=df.date1-df.date2


          And to view again ....



          df2 


          I see - which is the new Column in df with style in df2.



           date1 date2
          1 2019-3-26 2019-03-26 12:42:14.417441 -1 days +23:59:59.999995
          2 2019-3-26 2019-03-26 12:42:14.417443 -1 days +23:59:59.999999
          3 2019-3-26 2019-03-26 12:42:14.417444 -1 days +23:59:59.999999


          The slight rounding caused by the timestamp accuracy.... not the roungind on the date1 column.



          Hope that helps.






          share|improve this answer

























          • Very Interesting! Not exactly what I was hoping for, but pretty close if it works. Will check it out.

            – halloleo
            Mar 26 at 6:58











          • Mmmh, doesn't seem to work: After customising df with the df.style... declaration, displaying df still shows the full format for date1. And why do you issue df.style... a second time below creating the diff column?

            – halloleo
            Mar 26 at 7:31












          • @halloleo Try.... df2=df.style.format('date1':mydateformat) That seems to hold the value - you can modify df.... and still keep the reformatted data in df2

            – Tim Seed
            Mar 26 at 7:49











          • When I use exactly your example typing df2 on the command line outputs "<pandas.io.formats.style.Styler object at 0x7fca8965a0b8>". df2 is not a DataFrame, but a Styler object. I'm using Python 3.6.4 and pandas 0.24.2.

            – halloleo
            Mar 26 at 23:58











          • @halloleo Yes df2 is a html view of the data. So no .head() or Column mainipulations. More info at pandas.pydata.org/pandas-docs/stable/user_guide/style.html

            – Tim Seed
            Mar 27 at 2:32















          1














          Try something like this....



          Lets create some date.... (Sorry I am too lazy)



          import pandas as pd
          from datetime import datetime
          data='1':[datetime.now(),datetime.now()],
          '2':[datetime.now(),datetime.now()],
          '3':[datetime.now(),datetime.now()]

          df=pd.DataFrame.from_dict(data,orient='index')
          df.columns=['date1','date2']


          I can see the data ....



          df.head()


          Something like



           date1 date2
          1 2019-03-26 12:28:51.080622 2019-03-26 12:28:51.080627
          2 2019-03-26 12:28:51.080628 2019-03-26 12:28:51.080628
          3 2019-03-26 12:28:51.080629 2019-03-26 12:28:51.080630


          I use a custom style



          def mydateformat(date):
          return "--".format(date.year, date.month, date.day)

          df2=df.style.format('date1':mydateformat)
          df2


          Which shows



           date1 date2
          1 2019-3-26 2019-03-26 12:41:02.834557
          2 2019-3-26 2019-03-26 12:41:02.834558
          3 2019-3-26 2019-03-26 12:41:02.834560


          To check it has not altered the date1 column



          df['diff']=-1
          df['diff']=df.date1-df.date2


          And to view again ....



          df2 


          I see - which is the new Column in df with style in df2.



           date1 date2
          1 2019-3-26 2019-03-26 12:42:14.417441 -1 days +23:59:59.999995
          2 2019-3-26 2019-03-26 12:42:14.417443 -1 days +23:59:59.999999
          3 2019-3-26 2019-03-26 12:42:14.417444 -1 days +23:59:59.999999


          The slight rounding caused by the timestamp accuracy.... not the roungind on the date1 column.



          Hope that helps.






          share|improve this answer

























          • Very Interesting! Not exactly what I was hoping for, but pretty close if it works. Will check it out.

            – halloleo
            Mar 26 at 6:58











          • Mmmh, doesn't seem to work: After customising df with the df.style... declaration, displaying df still shows the full format for date1. And why do you issue df.style... a second time below creating the diff column?

            – halloleo
            Mar 26 at 7:31












          • @halloleo Try.... df2=df.style.format('date1':mydateformat) That seems to hold the value - you can modify df.... and still keep the reformatted data in df2

            – Tim Seed
            Mar 26 at 7:49











          • When I use exactly your example typing df2 on the command line outputs "<pandas.io.formats.style.Styler object at 0x7fca8965a0b8>". df2 is not a DataFrame, but a Styler object. I'm using Python 3.6.4 and pandas 0.24.2.

            – halloleo
            Mar 26 at 23:58











          • @halloleo Yes df2 is a html view of the data. So no .head() or Column mainipulations. More info at pandas.pydata.org/pandas-docs/stable/user_guide/style.html

            – Tim Seed
            Mar 27 at 2:32













          1












          1








          1







          Try something like this....



          Lets create some date.... (Sorry I am too lazy)



          import pandas as pd
          from datetime import datetime
          data='1':[datetime.now(),datetime.now()],
          '2':[datetime.now(),datetime.now()],
          '3':[datetime.now(),datetime.now()]

          df=pd.DataFrame.from_dict(data,orient='index')
          df.columns=['date1','date2']


          I can see the data ....



          df.head()


          Something like



           date1 date2
          1 2019-03-26 12:28:51.080622 2019-03-26 12:28:51.080627
          2 2019-03-26 12:28:51.080628 2019-03-26 12:28:51.080628
          3 2019-03-26 12:28:51.080629 2019-03-26 12:28:51.080630


          I use a custom style



          def mydateformat(date):
          return "--".format(date.year, date.month, date.day)

          df2=df.style.format('date1':mydateformat)
          df2


          Which shows



           date1 date2
          1 2019-3-26 2019-03-26 12:41:02.834557
          2 2019-3-26 2019-03-26 12:41:02.834558
          3 2019-3-26 2019-03-26 12:41:02.834560


          To check it has not altered the date1 column



          df['diff']=-1
          df['diff']=df.date1-df.date2


          And to view again ....



          df2 


          I see - which is the new Column in df with style in df2.



           date1 date2
          1 2019-3-26 2019-03-26 12:42:14.417441 -1 days +23:59:59.999995
          2 2019-3-26 2019-03-26 12:42:14.417443 -1 days +23:59:59.999999
          3 2019-3-26 2019-03-26 12:42:14.417444 -1 days +23:59:59.999999


          The slight rounding caused by the timestamp accuracy.... not the roungind on the date1 column.



          Hope that helps.






          share|improve this answer















          Try something like this....



          Lets create some date.... (Sorry I am too lazy)



          import pandas as pd
          from datetime import datetime
          data='1':[datetime.now(),datetime.now()],
          '2':[datetime.now(),datetime.now()],
          '3':[datetime.now(),datetime.now()]

          df=pd.DataFrame.from_dict(data,orient='index')
          df.columns=['date1','date2']


          I can see the data ....



          df.head()


          Something like



           date1 date2
          1 2019-03-26 12:28:51.080622 2019-03-26 12:28:51.080627
          2 2019-03-26 12:28:51.080628 2019-03-26 12:28:51.080628
          3 2019-03-26 12:28:51.080629 2019-03-26 12:28:51.080630


          I use a custom style



          def mydateformat(date):
          return "--".format(date.year, date.month, date.day)

          df2=df.style.format('date1':mydateformat)
          df2


          Which shows



           date1 date2
          1 2019-3-26 2019-03-26 12:41:02.834557
          2 2019-3-26 2019-03-26 12:41:02.834558
          3 2019-3-26 2019-03-26 12:41:02.834560


          To check it has not altered the date1 column



          df['diff']=-1
          df['diff']=df.date1-df.date2


          And to view again ....



          df2 


          I see - which is the new Column in df with style in df2.



           date1 date2
          1 2019-3-26 2019-03-26 12:42:14.417441 -1 days +23:59:59.999995
          2 2019-3-26 2019-03-26 12:42:14.417443 -1 days +23:59:59.999999
          3 2019-3-26 2019-03-26 12:42:14.417444 -1 days +23:59:59.999999


          The slight rounding caused by the timestamp accuracy.... not the roungind on the date1 column.



          Hope that helps.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Mar 26 at 7:56

























          answered Mar 26 at 4:44









          Tim SeedTim Seed

          2,29718 silver badges19 bronze badges




          2,29718 silver badges19 bronze badges












          • Very Interesting! Not exactly what I was hoping for, but pretty close if it works. Will check it out.

            – halloleo
            Mar 26 at 6:58











          • Mmmh, doesn't seem to work: After customising df with the df.style... declaration, displaying df still shows the full format for date1. And why do you issue df.style... a second time below creating the diff column?

            – halloleo
            Mar 26 at 7:31












          • @halloleo Try.... df2=df.style.format('date1':mydateformat) That seems to hold the value - you can modify df.... and still keep the reformatted data in df2

            – Tim Seed
            Mar 26 at 7:49











          • When I use exactly your example typing df2 on the command line outputs "<pandas.io.formats.style.Styler object at 0x7fca8965a0b8>". df2 is not a DataFrame, but a Styler object. I'm using Python 3.6.4 and pandas 0.24.2.

            – halloleo
            Mar 26 at 23:58











          • @halloleo Yes df2 is a html view of the data. So no .head() or Column mainipulations. More info at pandas.pydata.org/pandas-docs/stable/user_guide/style.html

            – Tim Seed
            Mar 27 at 2:32

















          • Very Interesting! Not exactly what I was hoping for, but pretty close if it works. Will check it out.

            – halloleo
            Mar 26 at 6:58











          • Mmmh, doesn't seem to work: After customising df with the df.style... declaration, displaying df still shows the full format for date1. And why do you issue df.style... a second time below creating the diff column?

            – halloleo
            Mar 26 at 7:31












          • @halloleo Try.... df2=df.style.format('date1':mydateformat) That seems to hold the value - you can modify df.... and still keep the reformatted data in df2

            – Tim Seed
            Mar 26 at 7:49











          • When I use exactly your example typing df2 on the command line outputs "<pandas.io.formats.style.Styler object at 0x7fca8965a0b8>". df2 is not a DataFrame, but a Styler object. I'm using Python 3.6.4 and pandas 0.24.2.

            – halloleo
            Mar 26 at 23:58











          • @halloleo Yes df2 is a html view of the data. So no .head() or Column mainipulations. More info at pandas.pydata.org/pandas-docs/stable/user_guide/style.html

            – Tim Seed
            Mar 27 at 2:32
















          Very Interesting! Not exactly what I was hoping for, but pretty close if it works. Will check it out.

          – halloleo
          Mar 26 at 6:58





          Very Interesting! Not exactly what I was hoping for, but pretty close if it works. Will check it out.

          – halloleo
          Mar 26 at 6:58













          Mmmh, doesn't seem to work: After customising df with the df.style... declaration, displaying df still shows the full format for date1. And why do you issue df.style... a second time below creating the diff column?

          – halloleo
          Mar 26 at 7:31






          Mmmh, doesn't seem to work: After customising df with the df.style... declaration, displaying df still shows the full format for date1. And why do you issue df.style... a second time below creating the diff column?

          – halloleo
          Mar 26 at 7:31














          @halloleo Try.... df2=df.style.format('date1':mydateformat) That seems to hold the value - you can modify df.... and still keep the reformatted data in df2

          – Tim Seed
          Mar 26 at 7:49





          @halloleo Try.... df2=df.style.format('date1':mydateformat) That seems to hold the value - you can modify df.... and still keep the reformatted data in df2

          – Tim Seed
          Mar 26 at 7:49













          When I use exactly your example typing df2 on the command line outputs "<pandas.io.formats.style.Styler object at 0x7fca8965a0b8>". df2 is not a DataFrame, but a Styler object. I'm using Python 3.6.4 and pandas 0.24.2.

          – halloleo
          Mar 26 at 23:58





          When I use exactly your example typing df2 on the command line outputs "<pandas.io.formats.style.Styler object at 0x7fca8965a0b8>". df2 is not a DataFrame, but a Styler object. I'm using Python 3.6.4 and pandas 0.24.2.

          – halloleo
          Mar 26 at 23:58













          @halloleo Yes df2 is a html view of the data. So no .head() or Column mainipulations. More info at pandas.pydata.org/pandas-docs/stable/user_guide/style.html

          – Tim Seed
          Mar 27 at 2:32





          @halloleo Yes df2 is a html view of the data. So no .head() or Column mainipulations. More info at pandas.pydata.org/pandas-docs/stable/user_guide/style.html

          – Tim Seed
          Mar 27 at 2:32













          -1














          import pandas as pd
          from datetime import datetime

          data='1':[datetime.now(),datetime.now()],
          '2':[datetime.now(),datetime.now()],
          '3':[datetime.now(),datetime.now()]

          df=pd.DataFrame.from_dict(data,orient='index')
          df.columns=['date1','date2']
          df['date3'] = df['date1'].apply(datetime.date)
          df['date4'] = df['date2'].apply(datetime.date)
          df





          share|improve this answer























          • This solution does not list the existing datetime columns in the way I am asking for. It just ads new columns.

            – halloleo
            Mar 26 at 6:32











          • Here, date1, date2 are the existing columns and the date3, date4 are the new columns which are holding the values without time details. It is not having your data to work with, but you can try it with your data as well.

            – Himmat
            Mar 27 at 7:22















          -1














          import pandas as pd
          from datetime import datetime

          data='1':[datetime.now(),datetime.now()],
          '2':[datetime.now(),datetime.now()],
          '3':[datetime.now(),datetime.now()]

          df=pd.DataFrame.from_dict(data,orient='index')
          df.columns=['date1','date2']
          df['date3'] = df['date1'].apply(datetime.date)
          df['date4'] = df['date2'].apply(datetime.date)
          df





          share|improve this answer























          • This solution does not list the existing datetime columns in the way I am asking for. It just ads new columns.

            – halloleo
            Mar 26 at 6:32











          • Here, date1, date2 are the existing columns and the date3, date4 are the new columns which are holding the values without time details. It is not having your data to work with, but you can try it with your data as well.

            – Himmat
            Mar 27 at 7:22













          -1












          -1








          -1







          import pandas as pd
          from datetime import datetime

          data='1':[datetime.now(),datetime.now()],
          '2':[datetime.now(),datetime.now()],
          '3':[datetime.now(),datetime.now()]

          df=pd.DataFrame.from_dict(data,orient='index')
          df.columns=['date1','date2']
          df['date3'] = df['date1'].apply(datetime.date)
          df['date4'] = df['date2'].apply(datetime.date)
          df





          share|improve this answer













          import pandas as pd
          from datetime import datetime

          data='1':[datetime.now(),datetime.now()],
          '2':[datetime.now(),datetime.now()],
          '3':[datetime.now(),datetime.now()]

          df=pd.DataFrame.from_dict(data,orient='index')
          df.columns=['date1','date2']
          df['date3'] = df['date1'].apply(datetime.date)
          df['date4'] = df['date2'].apply(datetime.date)
          df






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Mar 26 at 6:18









          HimmatHimmat

          915 bronze badges




          915 bronze badges












          • This solution does not list the existing datetime columns in the way I am asking for. It just ads new columns.

            – halloleo
            Mar 26 at 6:32











          • Here, date1, date2 are the existing columns and the date3, date4 are the new columns which are holding the values without time details. It is not having your data to work with, but you can try it with your data as well.

            – Himmat
            Mar 27 at 7:22

















          • This solution does not list the existing datetime columns in the way I am asking for. It just ads new columns.

            – halloleo
            Mar 26 at 6:32











          • Here, date1, date2 are the existing columns and the date3, date4 are the new columns which are holding the values without time details. It is not having your data to work with, but you can try it with your data as well.

            – Himmat
            Mar 27 at 7:22
















          This solution does not list the existing datetime columns in the way I am asking for. It just ads new columns.

          – halloleo
          Mar 26 at 6:32





          This solution does not list the existing datetime columns in the way I am asking for. It just ads new columns.

          – halloleo
          Mar 26 at 6:32













          Here, date1, date2 are the existing columns and the date3, date4 are the new columns which are holding the values without time details. It is not having your data to work with, but you can try it with your data as well.

          – Himmat
          Mar 27 at 7:22





          Here, date1, date2 are the existing columns and the date3, date4 are the new columns which are holding the values without time details. It is not having your data to work with, but you can try it with your data as well.

          – Himmat
          Mar 27 at 7:22

















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