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get the values form into an array


Is Java “pass-by-reference” or “pass-by-value”?Does a finally block always get executed in Java?Sort a Map<Key, Value> by valuesCreate ArrayList from arrayWhat's the simplest way to print a Java array?A Java collection of value pairs? (tuples?)How to get an enum value from a string value in Java?How do I determine whether an array contains a particular value in Java?How do I declare and initialize an array in Java?Why is processing a sorted array faster than processing an unsorted array?






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0















I filtered a map with a key using mulitihashmap, but I couldn't handle the values for a particular key.



HashMap mh1 = new HashMap();



 HashMap m2 = new HashMap(H6.getMap());

for(Object key : m2.keySet())
{
//System.out.println(key);
if(key.toString().toLowerCase().equals(keyword))
{
System.out.println(" Key : "+ key + "... value : " + m2.get(key));
String str = m2.get(key).toString();


m2 is a HashMap. for the key, it has the values like [d1.txt, d2.txt, d3.txt, d4.txt, d5.txt, d5.txt], here I need to get the values into an array, but this str is completely a string.



the answer -->
Key : the... value : [d1.txt, d2.txt, d3.txt, d4.txt, d5.txt, d5.txt]



need to get the values in any form like array or sets only the values










share|improve this question
























  • String[] arr = str.split("\s*,\s*");

    – Elliott Frisch
    Mar 26 at 3:42











  • Why is it a string? And where does multihashmap come in?

    – shmosel
    Mar 26 at 3:46











  • What are the actual objects? Are they lists? Sets? Why are you using a raw HashMap? What does H6.getMap() return? Is it also raw?

    – shmosel
    Mar 26 at 4:01











  • You can split the strings by comma using regex, so it will produce an array of strings like d1.txt, d2.txt,...

    – venkat
    Mar 26 at 4:03












  • here the H6.getMap() return the words and the name of the text files which contains the word, then I filtered the map with a keyword.

    – G Gayamini
    Mar 26 at 4:05

















0















I filtered a map with a key using mulitihashmap, but I couldn't handle the values for a particular key.



HashMap mh1 = new HashMap();



 HashMap m2 = new HashMap(H6.getMap());

for(Object key : m2.keySet())
{
//System.out.println(key);
if(key.toString().toLowerCase().equals(keyword))
{
System.out.println(" Key : "+ key + "... value : " + m2.get(key));
String str = m2.get(key).toString();


m2 is a HashMap. for the key, it has the values like [d1.txt, d2.txt, d3.txt, d4.txt, d5.txt, d5.txt], here I need to get the values into an array, but this str is completely a string.



the answer -->
Key : the... value : [d1.txt, d2.txt, d3.txt, d4.txt, d5.txt, d5.txt]



need to get the values in any form like array or sets only the values










share|improve this question
























  • String[] arr = str.split("\s*,\s*");

    – Elliott Frisch
    Mar 26 at 3:42











  • Why is it a string? And where does multihashmap come in?

    – shmosel
    Mar 26 at 3:46











  • What are the actual objects? Are they lists? Sets? Why are you using a raw HashMap? What does H6.getMap() return? Is it also raw?

    – shmosel
    Mar 26 at 4:01











  • You can split the strings by comma using regex, so it will produce an array of strings like d1.txt, d2.txt,...

    – venkat
    Mar 26 at 4:03












  • here the H6.getMap() return the words and the name of the text files which contains the word, then I filtered the map with a keyword.

    – G Gayamini
    Mar 26 at 4:05













0












0








0








I filtered a map with a key using mulitihashmap, but I couldn't handle the values for a particular key.



HashMap mh1 = new HashMap();



 HashMap m2 = new HashMap(H6.getMap());

for(Object key : m2.keySet())
{
//System.out.println(key);
if(key.toString().toLowerCase().equals(keyword))
{
System.out.println(" Key : "+ key + "... value : " + m2.get(key));
String str = m2.get(key).toString();


m2 is a HashMap. for the key, it has the values like [d1.txt, d2.txt, d3.txt, d4.txt, d5.txt, d5.txt], here I need to get the values into an array, but this str is completely a string.



the answer -->
Key : the... value : [d1.txt, d2.txt, d3.txt, d4.txt, d5.txt, d5.txt]



need to get the values in any form like array or sets only the values










share|improve this question
















I filtered a map with a key using mulitihashmap, but I couldn't handle the values for a particular key.



HashMap mh1 = new HashMap();



 HashMap m2 = new HashMap(H6.getMap());

for(Object key : m2.keySet())
{
//System.out.println(key);
if(key.toString().toLowerCase().equals(keyword))
{
System.out.println(" Key : "+ key + "... value : " + m2.get(key));
String str = m2.get(key).toString();


m2 is a HashMap. for the key, it has the values like [d1.txt, d2.txt, d3.txt, d4.txt, d5.txt, d5.txt], here I need to get the values into an array, but this str is completely a string.



the answer -->
Key : the... value : [d1.txt, d2.txt, d3.txt, d4.txt, d5.txt, d5.txt]



need to get the values in any form like array or sets only the values







java






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 26 at 3:54







G Gayamini

















asked Mar 26 at 3:41









G GayaminiG Gayamini

11 bronze badge




11 bronze badge












  • String[] arr = str.split("\s*,\s*");

    – Elliott Frisch
    Mar 26 at 3:42











  • Why is it a string? And where does multihashmap come in?

    – shmosel
    Mar 26 at 3:46











  • What are the actual objects? Are they lists? Sets? Why are you using a raw HashMap? What does H6.getMap() return? Is it also raw?

    – shmosel
    Mar 26 at 4:01











  • You can split the strings by comma using regex, so it will produce an array of strings like d1.txt, d2.txt,...

    – venkat
    Mar 26 at 4:03












  • here the H6.getMap() return the words and the name of the text files which contains the word, then I filtered the map with a keyword.

    – G Gayamini
    Mar 26 at 4:05

















  • String[] arr = str.split("\s*,\s*");

    – Elliott Frisch
    Mar 26 at 3:42











  • Why is it a string? And where does multihashmap come in?

    – shmosel
    Mar 26 at 3:46











  • What are the actual objects? Are they lists? Sets? Why are you using a raw HashMap? What does H6.getMap() return? Is it also raw?

    – shmosel
    Mar 26 at 4:01











  • You can split the strings by comma using regex, so it will produce an array of strings like d1.txt, d2.txt,...

    – venkat
    Mar 26 at 4:03












  • here the H6.getMap() return the words and the name of the text files which contains the word, then I filtered the map with a keyword.

    – G Gayamini
    Mar 26 at 4:05
















String[] arr = str.split("\s*,\s*");

– Elliott Frisch
Mar 26 at 3:42





String[] arr = str.split("\s*,\s*");

– Elliott Frisch
Mar 26 at 3:42













Why is it a string? And where does multihashmap come in?

– shmosel
Mar 26 at 3:46





Why is it a string? And where does multihashmap come in?

– shmosel
Mar 26 at 3:46













What are the actual objects? Are they lists? Sets? Why are you using a raw HashMap? What does H6.getMap() return? Is it also raw?

– shmosel
Mar 26 at 4:01





What are the actual objects? Are they lists? Sets? Why are you using a raw HashMap? What does H6.getMap() return? Is it also raw?

– shmosel
Mar 26 at 4:01













You can split the strings by comma using regex, so it will produce an array of strings like d1.txt, d2.txt,...

– venkat
Mar 26 at 4:03






You can split the strings by comma using regex, so it will produce an array of strings like d1.txt, d2.txt,...

– venkat
Mar 26 at 4:03














here the H6.getMap() return the words and the name of the text files which contains the word, then I filtered the map with a keyword.

– G Gayamini
Mar 26 at 4:05





here the H6.getMap() return the words and the name of the text files which contains the word, then I filtered the map with a keyword.

– G Gayamini
Mar 26 at 4:05












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