Java - Trouble understanding opacity value - parsing 64 bit long to float and adding opacityIs Java “pass-by-reference” or “pass-by-value”?How do I parse a string to a float or int?How to get an enum value from a string value in Java?Does Java support default parameter values?How do I determine whether an array contains a particular value in Java?How to convert float to int with JavaHow to parse JSON in JavaHow to parse float with two decimal places in javascript?Parse long double from stringCan IEEE 754 floating-point numbers represent the exact same value with multiple bit arrangements?

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Java - Trouble understanding opacity value - parsing 64 bit long to float and adding opacity


Is Java “pass-by-reference” or “pass-by-value”?How do I parse a string to a float or int?How to get an enum value from a string value in Java?Does Java support default parameter values?How do I determine whether an array contains a particular value in Java?How to convert float to int with JavaHow to parse JSON in JavaHow to parse float with two decimal places in javascript?Parse long double from stringCan IEEE 754 floating-point numbers represent the exact same value with multiple bit arrangements?






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0















I'm trying to understand some code that is creating an opacity value from the original color value.



 long fillColorValue = fillColor != null ? Long.parseLong(fillColor) : 0;
 //Set opacity based on alpha
 long alpha = fillColorValue >> 24;
 float opacity = (alpha > 0 ? alpha / 255.0f : 1.0f);
 shape.setFillOpacity(opacity);


  1. First the String color value is parsed to long.

  2. Then the bits of that value are being moved 24 bits with a rightshift - why?


long alpha = fillColorValue >> 24;




  1. then the long is used to create a float seemingly representing an opacity value.


float opacity = (alpha > 0 ? alpha / 255.0f : 1.0f);




It'd be great if I could have some clarity on this method of defining opacity - what's actually happening here?



The shape fill color is originally represented by a String value -1751607581.






java floating-point opacity long-integer







share|improve this question



















  • 1





    You seem to have a good handle on the bit-shifting, which seems like the more difficult concept. Are you unfamiliar with the ternary operator (` x ? p : q `), or are you asking why zero is being treated specially)

    – erickson
    Mar 26 at 3:45






  • 1





    Or maybe you are asking why a 64-bit long is used, shifting off 24 bits and apparently working with the remaining 40?

    – erickson
    Mar 26 at 4:01











  • Do you know what color format is used? It can be assumed, that first 24 bit is RGB (8 bit per channel) and remaining 40 bit is alpha channel, but in such case the subsequent operations seems strange.

    – Mikhail Ilinykh
    Mar 26 at 4:19






  • 1





    In order to retrieve the integer Alpha channel value from the fillColorValue you need to right shift bits by 24. Not really sure why fillColorValue and alpha variables are declared a long when int would have sufficed. In the code you supplied, a Ternary is used to handle the chance that the Alpha value might be 0. Odd though since an Alpha value of 0 would normally mean full transparency but in this case the Ternary is enforcing the fact that any value less than 1 would place opacity to completely opaque (1.0f). There would of course be good reason for this in many different situations.

    – DevilsHnd
    Mar 26 at 8:27












  • Not being very familiar with alpha and int/long to float conversions the method didn't make much sense to me, and the intent behind the code wan't clear. as @DevilsHnd pointed out the ternary is weird, and in fact this was the issue... transparency was showing as completely white.

    – Continuity8
    Mar 27 at 4:10


















0















I'm trying to understand some code that is creating an opacity value from the original color value.



 long fillColorValue = fillColor != null ? Long.parseLong(fillColor) : 0;
 //Set opacity based on alpha
 long alpha = fillColorValue >> 24;
 float opacity = (alpha > 0 ? alpha / 255.0f : 1.0f);
 shape.setFillOpacity(opacity);


  1. First the String color value is parsed to long.

  2. Then the bits of that value are being moved 24 bits with a rightshift - why?


long alpha = fillColorValue >> 24;




  1. then the long is used to create a float seemingly representing an opacity value.


float opacity = (alpha > 0 ? alpha / 255.0f : 1.0f);




It'd be great if I could have some clarity on this method of defining opacity - what's actually happening here?



The shape fill color is originally represented by a String value -1751607581.






java floating-point opacity long-integer







share|improve this question



















  • 1





    You seem to have a good handle on the bit-shifting, which seems like the more difficult concept. Are you unfamiliar with the ternary operator (` x ? p : q `), or are you asking why zero is being treated specially)

    – erickson
    Mar 26 at 3:45






  • 1





    Or maybe you are asking why a 64-bit long is used, shifting off 24 bits and apparently working with the remaining 40?

    – erickson
    Mar 26 at 4:01











  • Do you know what color format is used? It can be assumed, that first 24 bit is RGB (8 bit per channel) and remaining 40 bit is alpha channel, but in such case the subsequent operations seems strange.

    – Mikhail Ilinykh
    Mar 26 at 4:19






  • 1





    In order to retrieve the integer Alpha channel value from the fillColorValue you need to right shift bits by 24. Not really sure why fillColorValue and alpha variables are declared a long when int would have sufficed. In the code you supplied, a Ternary is used to handle the chance that the Alpha value might be 0. Odd though since an Alpha value of 0 would normally mean full transparency but in this case the Ternary is enforcing the fact that any value less than 1 would place opacity to completely opaque (1.0f). There would of course be good reason for this in many different situations.

    – DevilsHnd
    Mar 26 at 8:27












  • Not being very familiar with alpha and int/long to float conversions the method didn't make much sense to me, and the intent behind the code wan't clear. as @DevilsHnd pointed out the ternary is weird, and in fact this was the issue... transparency was showing as completely white.

    – Continuity8
    Mar 27 at 4:10














0












0








0








I'm trying to understand some code that is creating an opacity value from the original color value.



 long fillColorValue = fillColor != null ? Long.parseLong(fillColor) : 0;
 //Set opacity based on alpha
 long alpha = fillColorValue >> 24;
 float opacity = (alpha > 0 ? alpha / 255.0f : 1.0f);
 shape.setFillOpacity(opacity);


  1. First the String color value is parsed to long.

  2. Then the bits of that value are being moved 24 bits with a rightshift - why?


long alpha = fillColorValue >> 24;




  1. then the long is used to create a float seemingly representing an opacity value.


float opacity = (alpha > 0 ? alpha / 255.0f : 1.0f);




It'd be great if I could have some clarity on this method of defining opacity - what's actually happening here?



The shape fill color is originally represented by a String value -1751607581.






java floating-point opacity long-integer







share|improve this question
















I'm trying to understand some code that is creating an opacity value from the original color value.



 long fillColorValue = fillColor != null ? Long.parseLong(fillColor) : 0;
 //Set opacity based on alpha
 long alpha = fillColorValue >> 24;
 float opacity = (alpha > 0 ? alpha / 255.0f : 1.0f);
 shape.setFillOpacity(opacity);


  1. First the String color value is parsed to long.

  2. Then the bits of that value are being moved 24 bits with a rightshift - why?


long alpha = fillColorValue >> 24;




  1. then the long is used to create a float seemingly representing an opacity value.


float opacity = (alpha > 0 ? alpha / 255.0f : 1.0f);




It'd be great if I could have some clarity on this method of defining opacity - what's actually happening here?



The shape fill color is originally represented by a String value -1751607581.






java floating-point opacity long-integer




java floating-point opacity long-integer






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 26 at 3:37







Continuity8

















asked Mar 26 at 3:25









Continuity8Continuity8

6182 gold badges9 silver badges27 bronze badges




6182 gold badges9 silver badges27 bronze badges







  • 1





    You seem to have a good handle on the bit-shifting, which seems like the more difficult concept. Are you unfamiliar with the ternary operator (` x ? p : q `), or are you asking why zero is being treated specially)

    – erickson
    Mar 26 at 3:45






  • 1





    Or maybe you are asking why a 64-bit long is used, shifting off 24 bits and apparently working with the remaining 40?

    – erickson
    Mar 26 at 4:01











  • Do you know what color format is used? It can be assumed, that first 24 bit is RGB (8 bit per channel) and remaining 40 bit is alpha channel, but in such case the subsequent operations seems strange.

    – Mikhail Ilinykh
    Mar 26 at 4:19






  • 1





    In order to retrieve the integer Alpha channel value from the fillColorValue you need to right shift bits by 24. Not really sure why fillColorValue and alpha variables are declared a long when int would have sufficed. In the code you supplied, a Ternary is used to handle the chance that the Alpha value might be 0. Odd though since an Alpha value of 0 would normally mean full transparency but in this case the Ternary is enforcing the fact that any value less than 1 would place opacity to completely opaque (1.0f). There would of course be good reason for this in many different situations.

    – DevilsHnd
    Mar 26 at 8:27












  • Not being very familiar with alpha and int/long to float conversions the method didn't make much sense to me, and the intent behind the code wan't clear. as @DevilsHnd pointed out the ternary is weird, and in fact this was the issue... transparency was showing as completely white.

    – Continuity8
    Mar 27 at 4:10













  • 1





    You seem to have a good handle on the bit-shifting, which seems like the more difficult concept. Are you unfamiliar with the ternary operator (` x ? p : q `), or are you asking why zero is being treated specially)

    – erickson
    Mar 26 at 3:45






  • 1





    Or maybe you are asking why a 64-bit long is used, shifting off 24 bits and apparently working with the remaining 40?

    – erickson
    Mar 26 at 4:01











  • Do you know what color format is used? It can be assumed, that first 24 bit is RGB (8 bit per channel) and remaining 40 bit is alpha channel, but in such case the subsequent operations seems strange.

    – Mikhail Ilinykh
    Mar 26 at 4:19






  • 1





    In order to retrieve the integer Alpha channel value from the fillColorValue you need to right shift bits by 24. Not really sure why fillColorValue and alpha variables are declared a long when int would have sufficed. In the code you supplied, a Ternary is used to handle the chance that the Alpha value might be 0. Odd though since an Alpha value of 0 would normally mean full transparency but in this case the Ternary is enforcing the fact that any value less than 1 would place opacity to completely opaque (1.0f). There would of course be good reason for this in many different situations.

    – DevilsHnd
    Mar 26 at 8:27












  • Not being very familiar with alpha and int/long to float conversions the method didn't make much sense to me, and the intent behind the code wan't clear. as @DevilsHnd pointed out the ternary is weird, and in fact this was the issue... transparency was showing as completely white.

    – Continuity8
    Mar 27 at 4:10








1




1





You seem to have a good handle on the bit-shifting, which seems like the more difficult concept. Are you unfamiliar with the ternary operator (` x ? p : q `), or are you asking why zero is being treated specially)

– erickson
Mar 26 at 3:45





You seem to have a good handle on the bit-shifting, which seems like the more difficult concept. Are you unfamiliar with the ternary operator (` x ? p : q `), or are you asking why zero is being treated specially)

– erickson
Mar 26 at 3:45




1




1





Or maybe you are asking why a 64-bit long is used, shifting off 24 bits and apparently working with the remaining 40?

– erickson
Mar 26 at 4:01





Or maybe you are asking why a 64-bit long is used, shifting off 24 bits and apparently working with the remaining 40?

– erickson
Mar 26 at 4:01













Do you know what color format is used? It can be assumed, that first 24 bit is RGB (8 bit per channel) and remaining 40 bit is alpha channel, but in such case the subsequent operations seems strange.

– Mikhail Ilinykh
Mar 26 at 4:19





Do you know what color format is used? It can be assumed, that first 24 bit is RGB (8 bit per channel) and remaining 40 bit is alpha channel, but in such case the subsequent operations seems strange.

– Mikhail Ilinykh
Mar 26 at 4:19




1




1





In order to retrieve the integer Alpha channel value from the fillColorValue you need to right shift bits by 24. Not really sure why fillColorValue and alpha variables are declared a long when int would have sufficed. In the code you supplied, a Ternary is used to handle the chance that the Alpha value might be 0. Odd though since an Alpha value of 0 would normally mean full transparency but in this case the Ternary is enforcing the fact that any value less than 1 would place opacity to completely opaque (1.0f). There would of course be good reason for this in many different situations.

– DevilsHnd
Mar 26 at 8:27






In order to retrieve the integer Alpha channel value from the fillColorValue you need to right shift bits by 24. Not really sure why fillColorValue and alpha variables are declared a long when int would have sufficed. In the code you supplied, a Ternary is used to handle the chance that the Alpha value might be 0. Odd though since an Alpha value of 0 would normally mean full transparency but in this case the Ternary is enforcing the fact that any value less than 1 would place opacity to completely opaque (1.0f). There would of course be good reason for this in many different situations.

– DevilsHnd
Mar 26 at 8:27














Not being very familiar with alpha and int/long to float conversions the method didn't make much sense to me, and the intent behind the code wan't clear. as @DevilsHnd pointed out the ternary is weird, and in fact this was the issue... transparency was showing as completely white.

– Continuity8
Mar 27 at 4:10






Not being very familiar with alpha and int/long to float conversions the method didn't make much sense to me, and the intent behind the code wan't clear. as @DevilsHnd pointed out the ternary is weird, and in fact this was the issue... transparency was showing as completely white.

– Continuity8
Mar 27 at 4:10













1 Answer
1






active

oldest

votes


















1














If the color are represented on 32 bits, like your example seems to, it looks like it is encoded with an alpha channel and three color channels, each on eight bits (most probably ARGB).



Shifting >> 24 thus eliminates the RGB components, and keep alpha channels in low bits.



But beware of signed arithmetic! if original string is negative number, then fillColorValue will be negative, and remain negative after arithmetic >> shift...



With the guard on alpha > 0 the consequence is that all negative or null alpha values will be considered as opaque.



That means that there will be no alpha value between 128 and 255, thus no opacity value in the open interval ]0.5,1.0[.



That sounds weird. Maybe that's the true intention... Or maybe the color should have been interpreted unsigned when being printed to a string?



Or maybe there are 9 bits in alpha channel, but then it would be a very unusual format, and I don't see the point to waste half possible values for a encoding a single opacity value... It does not make good sense.






share|improve this answer
























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    1 Answer
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    active

    oldest

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    active

    oldest

    votes









    1














    If the color are represented on 32 bits, like your example seems to, it looks like it is encoded with an alpha channel and three color channels, each on eight bits (most probably ARGB).



    Shifting >> 24 thus eliminates the RGB components, and keep alpha channels in low bits.



    But beware of signed arithmetic! if original string is negative number, then fillColorValue will be negative, and remain negative after arithmetic >> shift...



    With the guard on alpha > 0 the consequence is that all negative or null alpha values will be considered as opaque.



    That means that there will be no alpha value between 128 and 255, thus no opacity value in the open interval ]0.5,1.0[.



    That sounds weird. Maybe that's the true intention... Or maybe the color should have been interpreted unsigned when being printed to a string?



    Or maybe there are 9 bits in alpha channel, but then it would be a very unusual format, and I don't see the point to waste half possible values for a encoding a single opacity value... It does not make good sense.






    share|improve this answer





























      1














      If the color are represented on 32 bits, like your example seems to, it looks like it is encoded with an alpha channel and three color channels, each on eight bits (most probably ARGB).



      Shifting >> 24 thus eliminates the RGB components, and keep alpha channels in low bits.



      But beware of signed arithmetic! if original string is negative number, then fillColorValue will be negative, and remain negative after arithmetic >> shift...



      With the guard on alpha > 0 the consequence is that all negative or null alpha values will be considered as opaque.



      That means that there will be no alpha value between 128 and 255, thus no opacity value in the open interval ]0.5,1.0[.



      That sounds weird. Maybe that's the true intention... Or maybe the color should have been interpreted unsigned when being printed to a string?



      Or maybe there are 9 bits in alpha channel, but then it would be a very unusual format, and I don't see the point to waste half possible values for a encoding a single opacity value... It does not make good sense.






      share|improve this answer



























        1












        1








        1







        If the color are represented on 32 bits, like your example seems to, it looks like it is encoded with an alpha channel and three color channels, each on eight bits (most probably ARGB).



        Shifting >> 24 thus eliminates the RGB components, and keep alpha channels in low bits.



        But beware of signed arithmetic! if original string is negative number, then fillColorValue will be negative, and remain negative after arithmetic >> shift...



        With the guard on alpha > 0 the consequence is that all negative or null alpha values will be considered as opaque.



        That means that there will be no alpha value between 128 and 255, thus no opacity value in the open interval ]0.5,1.0[.



        That sounds weird. Maybe that's the true intention... Or maybe the color should have been interpreted unsigned when being printed to a string?



        Or maybe there are 9 bits in alpha channel, but then it would be a very unusual format, and I don't see the point to waste half possible values for a encoding a single opacity value... It does not make good sense.






        share|improve this answer















        If the color are represented on 32 bits, like your example seems to, it looks like it is encoded with an alpha channel and three color channels, each on eight bits (most probably ARGB).



        Shifting >> 24 thus eliminates the RGB components, and keep alpha channels in low bits.



        But beware of signed arithmetic! if original string is negative number, then fillColorValue will be negative, and remain negative after arithmetic >> shift...



        With the guard on alpha > 0 the consequence is that all negative or null alpha values will be considered as opaque.



        That means that there will be no alpha value between 128 and 255, thus no opacity value in the open interval ]0.5,1.0[.



        That sounds weird. Maybe that's the true intention... Or maybe the color should have been interpreted unsigned when being printed to a string?



        Or maybe there are 9 bits in alpha channel, but then it would be a very unusual format, and I don't see the point to waste half possible values for a encoding a single opacity value... It does not make good sense.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Mar 26 at 21:34

























        answered Mar 26 at 21:24









        aka.niceaka.nice

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