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1

I had a nested list and a function:

a = [[2,3,4],[3,4,5],[5,7]]

def triple(a):
 return (a**2)+3

I tried to plot every point in the sublist like the first value connected to second, the second connected to the third and stop at the last value in the sublist. x is the value in the sublist, y is triple(y for y in sublist)

for g in a:
 for t in g:
 plt.scatter(t, triple(t))
for g in a:
 for o in range(len(g)):
 plt.plot([g[o],g[o+1]], [triple(g[o]), triple(g[o+1])], color = 'red')
plt.show()

I tried this but it didn't get the desire output I wanted.

What should I do to plot every sublist in a and get three different colors of line?

python list loops matplotlib

share|improve this question

asked Mar 26 at 3:20

wayne64001wayne64001

6888 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Does this achieve what you want: for sublist in a: plt.plot(sublist, [triple(s) for s in sublist], 'o-') ?
  
  – SamProell
  Mar 26 at 6:23
  
  

  
  
  
  

add a comment | 

1

I had a nested list and a function:

a = [[2,3,4],[3,4,5],[5,7]]

def triple(a):
 return (a**2)+3

I tried to plot every point in the sublist like the first value connected to second, the second connected to the third and stop at the last value in the sublist. x is the value in the sublist, y is triple(y for y in sublist)

for g in a:
 for t in g:
 plt.scatter(t, triple(t))
for g in a:
 for o in range(len(g)):
 plt.plot([g[o],g[o+1]], [triple(g[o]), triple(g[o+1])], color = 'red')
plt.show()

I tried this but it didn't get the desire output I wanted.

What should I do to plot every sublist in a and get three different colors of line?

python list loops matplotlib

share|improve this question

asked Mar 26 at 3:20

wayne64001wayne64001

6888 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Does this achieve what you want: for sublist in a: plt.plot(sublist, [triple(s) for s in sublist], 'o-') ?
  
  – SamProell
  Mar 26 at 6:23
  
  

  
  
  
  

add a comment | 

I had a nested list and a function:

a = [[2,3,4],[3,4,5],[5,7]]

def triple(a):
 return (a**2)+3

I tried to plot every point in the sublist like the first value connected to second, the second connected to the third and stop at the last value in the sublist. x is the value in the sublist, y is triple(y for y in sublist)

for g in a:
 for t in g:
 plt.scatter(t, triple(t))
for g in a:
 for o in range(len(g)):
 plt.plot([g[o],g[o+1]], [triple(g[o]), triple(g[o+1])], color = 'red')
plt.show()

I tried this but it didn't get the desire output I wanted.

What should I do to plot every sublist in a and get three different colors of line?

python list loops matplotlib

share|improve this question

asked Mar 26 at 3:20

wayne64001wayne64001

6888 bronze badges

a = [[2,3,4],[3,4,5],[5,7]]

def triple(a):
 return (a**2)+3

for g in a:
 for t in g:
 plt.scatter(t, triple(t))
for g in a:
 for o in range(len(g)):
 plt.plot([g[o],g[o+1]], [triple(g[o]), triple(g[o+1])], color = 'red')
plt.show()

share|improve this question

asked Mar 26 at 3:20

wayne64001wayne64001

6888 bronze badges

share|improve this question

asked Mar 26 at 3:20

wayne64001wayne64001

6888 bronze badges

asked Mar 26 at 3:20

wayne64001wayne64001

6888 bronze badges

asked Mar 26 at 3:20

wayne64001wayne64001

6888 bronze badges

1 Answer
1

active

oldest

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0

1. You specified color='red' so every your line is drawn with one color.


2. You use plt.scatter to draw circles. There is no need to do it, you can use marker parameter in plt.plot.


3. Your code is throwing a ValueError because when o is in the last element of g, o+1 will point to the undefined element. I rewrote this line.

I changed a a bit, just for a more distinguished view. Here is the final code:

a = [[2, 3, 4], [5, 6, 7], [8, 9]]
for g in a:
 plt.plot(g, [(x**2)+3 for x in g], marker='.')
plt.show()

share|improve this answer

answered Mar 26 at 15:07

vurmuxvurmux

5,65322 gold badges99 silver badges3131 bronze badges

add a comment | 

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0

1. You specified color='red' so every your line is drawn with one color.


2. You use plt.scatter to draw circles. There is no need to do it, you can use marker parameter in plt.plot.


3. Your code is throwing a ValueError because when o is in the last element of g, o+1 will point to the undefined element. I rewrote this line.

I changed a a bit, just for a more distinguished view. Here is the final code:

a = [[2, 3, 4], [5, 6, 7], [8, 9]]
for g in a:
 plt.plot(g, [(x**2)+3 for x in g], marker='.')
plt.show()

share|improve this answer

answered Mar 26 at 15:07

vurmuxvurmux

5,65322 gold badges99 silver badges3131 bronze badges

add a comment | 

0

1. You specified color='red' so every your line is drawn with one color.


2. You use plt.scatter to draw circles. There is no need to do it, you can use marker parameter in plt.plot.


3. Your code is throwing a ValueError because when o is in the last element of g, o+1 will point to the undefined element. I rewrote this line.

I changed a a bit, just for a more distinguished view. Here is the final code:

a = [[2, 3, 4], [5, 6, 7], [8, 9]]
for g in a:
 plt.plot(g, [(x**2)+3 for x in g], marker='.')
plt.show()

share|improve this answer

answered Mar 26 at 15:07

vurmuxvurmux

5,65322 gold badges99 silver badges3131 bronze badges

add a comment | 

1. You specified color='red' so every your line is drawn with one color.


2. You use plt.scatter to draw circles. There is no need to do it, you can use marker parameter in plt.plot.


3. Your code is throwing a ValueError because when o is in the last element of g, o+1 will point to the undefined element. I rewrote this line.

I changed a a bit, just for a more distinguished view. Here is the final code:

a = [[2, 3, 4], [5, 6, 7], [8, 9]]
for g in a:
 plt.plot(g, [(x**2)+3 for x in g], marker='.')
plt.show()

share|improve this answer

answered Mar 26 at 15:07

vurmuxvurmux

5,65322 gold badges99 silver badges3131 bronze badges

a = [[2, 3, 4], [5, 6, 7], [8, 9]]
for g in a:
 plt.plot(g, [(x**2)+3 for x in g], marker='.')
plt.show()

share|improve this answer

answered Mar 26 at 15:07

vurmuxvurmux

5,65322 gold badges99 silver badges3131 bronze badges

answered Mar 26 at 15:07

vurmuxvurmux

5,65322 gold badges99 silver badges3131 bronze badges

answered Mar 26 at 15:07

vurmuxvurmux

5,65322 gold badges99 silver badges3131 bronze badges