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How to insert Document (MongoDB) into a Collection using Pymongo with NOT Duplicated [duplicate]

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0

This question already has an answer here:

• 
  How to stop insertion of Duplicate documents in a mongodb collection
  
  3 answers
  
  


• 
  How to Ignore Duplicate Key Errors Safely Using insert_many
  
  1 answer
  
  

I insert data to document using pymongo :

client = MongoClient()
db = client['comment_data2']
collection_data = db['comments']
collection_data.insert_many(data_comment)

Each data I have an "postid" to distinguish, like:

comment1 = 
 'commentParentId': parent_content.text,
 'parentId': parent_ID,
 'posted': child_time.text,
 'postID':child_ID,
 'author':
 
 'name': child_name.text
 ,
 'content': child_content.text
 

I run my code more than 2 times and I see my data with duplicates. I want to when I run my code, each postID juch insert 1 times. I'm processing learn pymongo so I don't have any idea for solution.
I find a solution in another post on StackOverFlow:

get_db().users.update(
 '_id':ObjectId(session['user_id']),
 
 '$addToSet':
 'hme':ObjectId(id)
 
 ,
 upsert=True
)

But I dont know what does it mean.
Source : https://stackoverflow.com/questions/31043412/insert-not-duplicate-data-with-pymongo-in-mongodb

UPDATE1 :
I have tried to use collection_data.update_many(data_comment, upsert=True), but appear an Error : update_many() missing 1 required positional argument: 'update'

python mongodb pymongo

share|improve this question

edited Mar 26 at 10:49

Toan Nguyen Phuoc

asked Mar 26 at 9:54

Toan Nguyen PhuocToan Nguyen Phuoc

3166 bronze badges

marked as duplicate by Neil Lunn mongodb
Users with the  mongodb badge can single-handedly close mongodb questions as duplicates and reopen them as needed.

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Mar 26 at 10:12

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  An "upsert" is a special function of update commands in MongoDB, which alters the behavior of a normal update to not just modify but to instead insert only when the criteria provided does not match any existing document. This can be used so that when an "existing document to the conditions" ( duplicate ) is found, it only attempts updates, and only "inserts" when nothing exists. Alternately, you can specifically trap duplicate key errors. But you also need indexes to enforce that.
  
  – Neil Lunn
  Mar 26 at 10:16
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I have tried to use : collection_data.update_many(data_comment, upsert=True), but appear Error : collection_data.update_many(data_comment, upsert=True)
  
  – Toan Nguyen Phuoc
  Mar 26 at 10:47
  

  
  
  
  

add a comment | 

0

This question already has an answer here:

• 
  How to stop insertion of Duplicate documents in a mongodb collection
  
  3 answers
  
  


• 
  How to Ignore Duplicate Key Errors Safely Using insert_many
  
  1 answer
  
  

I insert data to document using pymongo :

client = MongoClient()
db = client['comment_data2']
collection_data = db['comments']
collection_data.insert_many(data_comment)

Each data I have an "postid" to distinguish, like:

comment1 = 
 'commentParentId': parent_content.text,
 'parentId': parent_ID,
 'posted': child_time.text,
 'postID':child_ID,
 'author':
 
 'name': child_name.text
 ,
 'content': child_content.text
 

I run my code more than 2 times and I see my data with duplicates. I want to when I run my code, each postID juch insert 1 times. I'm processing learn pymongo so I don't have any idea for solution.
I find a solution in another post on StackOverFlow:

get_db().users.update(
 '_id':ObjectId(session['user_id']),
 
 '$addToSet':
 'hme':ObjectId(id)
 
 ,
 upsert=True
)

But I dont know what does it mean.
Source : https://stackoverflow.com/questions/31043412/insert-not-duplicate-data-with-pymongo-in-mongodb

UPDATE1 :
I have tried to use collection_data.update_many(data_comment, upsert=True), but appear an Error : update_many() missing 1 required positional argument: 'update'

python mongodb pymongo

share|improve this question

edited Mar 26 at 10:49

Toan Nguyen Phuoc

asked Mar 26 at 9:54

Toan Nguyen PhuocToan Nguyen Phuoc

3166 bronze badges

marked as duplicate by Neil Lunn mongodb
Users with the  mongodb badge can single-handedly close mongodb questions as duplicates and reopen them as needed.

StackExchange.ready(function()
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function()
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function()
$hover.showInfoMessage('',
messageElement: $msg.clone().show(),
transient: false,
position: my: 'bottom left', at: 'top center', offsetTop: -7 ,
dismissable: false,
relativeToBody: true
);
,
function()
StackExchange.helpers.removeMessages();

);
);
);
Mar 26 at 10:12

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  An "upsert" is a special function of update commands in MongoDB, which alters the behavior of a normal update to not just modify but to instead insert only when the criteria provided does not match any existing document. This can be used so that when an "existing document to the conditions" ( duplicate ) is found, it only attempts updates, and only "inserts" when nothing exists. Alternately, you can specifically trap duplicate key errors. But you also need indexes to enforce that.
  
  – Neil Lunn
  Mar 26 at 10:16
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I have tried to use : collection_data.update_many(data_comment, upsert=True), but appear Error : collection_data.update_many(data_comment, upsert=True)
  
  – Toan Nguyen Phuoc
  Mar 26 at 10:47
  

  
  
  
  

add a comment | 

This question already has an answer here:

• 
  How to stop insertion of Duplicate documents in a mongodb collection
  
  3 answers
  
  


• 
  How to Ignore Duplicate Key Errors Safely Using insert_many
  
  1 answer
  
  

I insert data to document using pymongo :

client = MongoClient()
db = client['comment_data2']
collection_data = db['comments']
collection_data.insert_many(data_comment)

Each data I have an "postid" to distinguish, like:

comment1 = 
 'commentParentId': parent_content.text,
 'parentId': parent_ID,
 'posted': child_time.text,
 'postID':child_ID,
 'author':
 
 'name': child_name.text
 ,
 'content': child_content.text
 

I run my code more than 2 times and I see my data with duplicates. I want to when I run my code, each postID juch insert 1 times. I'm processing learn pymongo so I don't have any idea for solution.
I find a solution in another post on StackOverFlow:

get_db().users.update(
 '_id':ObjectId(session['user_id']),
 
 '$addToSet':
 'hme':ObjectId(id)
 
 ,
 upsert=True
)

But I dont know what does it mean.
Source : https://stackoverflow.com/questions/31043412/insert-not-duplicate-data-with-pymongo-in-mongodb

UPDATE1 :
I have tried to use collection_data.update_many(data_comment, upsert=True), but appear an Error : update_many() missing 1 required positional argument: 'update'

python mongodb pymongo

share|improve this question

edited Mar 26 at 10:49

Toan Nguyen Phuoc

asked Mar 26 at 9:54

Toan Nguyen PhuocToan Nguyen Phuoc

3166 bronze badges

client = MongoClient()
db = client['comment_data2']
collection_data = db['comments']
collection_data.insert_many(data_comment)

comment1 = 
 'commentParentId': parent_content.text,
 'parentId': parent_ID,
 'posted': child_time.text,
 'postID':child_ID,
 'author':
 
 'name': child_name.text
 ,
 'content': child_content.text
 

get_db().users.update(
 '_id':ObjectId(session['user_id']),
 
 '$addToSet':
 'hme':ObjectId(id)
 
 ,
 upsert=True
)

share|improve this question

edited Mar 26 at 10:49

Toan Nguyen Phuoc

asked Mar 26 at 9:54

Toan Nguyen PhuocToan Nguyen Phuoc

3166 bronze badges

share|improve this question

edited Mar 26 at 10:49

Toan Nguyen Phuoc

asked Mar 26 at 9:54

Toan Nguyen PhuocToan Nguyen Phuoc

3166 bronze badges

asked Mar 26 at 9:54

Toan Nguyen PhuocToan Nguyen Phuoc

3166 bronze badges

asked Mar 26 at 9:54

Toan Nguyen PhuocToan Nguyen Phuoc

3166 bronze badges