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compare two values of different type (but identical underlying type)
Compare two dates with JavaScriptCompare two structs' values in C#What are the differences between type() and isinstance()?Comparing Class Types in JavaCompare two files in Visual StudioWhat is the “underlying type” in Scala?Function calls, assignment, and 'underlying types' in GoJava: comparing two Objects of different type with same value, returning truecompare two columns value in dataframeGolang's Bool Type
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How do I compare the values of two variables that have different types but the same underlying type.
type SomeID uint8
type OtherID uint8
func areEqual(sid SomeID, oid OtherID) bool
// error: mismatched types
return sid == oid
go types compare
asked Mar 27 at 20:00
octaviooctavio
1848 bronze badges
add a comment |
How do I compare the values of two variables that have different types but the same underlying type.
type SomeID uint8
type OtherID uint8
func areEqual(sid SomeID, oid OtherID) bool
// error: mismatched types
return sid == oid
go types compare
asked Mar 27 at 20:00
octaviooctavio
1848 bronze badges
4
First convert them back touint8and then compare those uints.
– mkopriva
Mar 27 at 20:02
4
Though this does raise the question of why these are different types; the point of creating primitive-based types is usually to distinguish them, meaning that comparing aSomeIDto aOtherIDshouldn't yield any meaningful result; like comparing atime.Monthto atime.Weekday, which are bothintbut have different meaning and are therefore incomparable.
– Adrian
Mar 27 at 20:27
1
exactly - and usually one adds methods to a distinct type which ultimately define its unique characteristics.
– colminator
Mar 27 at 20:29
@Adrian I agree, however this was part of an assignment so the problem is rather fabricated.
– octavio
Mar 28 at 11:03
add a comment |
How do I compare the values of two variables that have different types but the same underlying type.
type SomeID uint8
type OtherID uint8
func areEqual(sid SomeID, oid OtherID) bool
// error: mismatched types
return sid == oid
go types compare
asked Mar 27 at 20:00
octaviooctavio
1848 bronze badges
How do I compare the values of two variables that have different types but the same underlying type.
type SomeID uint8
type OtherID uint8
func areEqual(sid SomeID, oid OtherID) bool
// error: mismatched types
return sid == oid
go types compare
go types compare
asked Mar 27 at 20:00
octaviooctavio
1848 bronze badges
asked Mar 27 at 20:00
octaviooctavio
1848 bronze badges
asked Mar 27 at 20:00
octaviooctavio
1848 bronze badges
asked Mar 27 at 20:00
octaviooctavio
1848 bronze badges
asked Mar 27 at 20:00
octaviooctavio
1848 bronze badges
1848 bronze badges
4
First convert them back touint8and then compare those uints.
– mkopriva
Mar 27 at 20:02
4
Though this does raise the question of why these are different types; the point of creating primitive-based types is usually to distinguish them, meaning that comparing aSomeIDto aOtherIDshouldn't yield any meaningful result; like comparing atime.Monthto atime.Weekday, which are bothintbut have different meaning and are therefore incomparable.
– Adrian
Mar 27 at 20:27
1
exactly - and usually one adds methods to a distinct type which ultimately define its unique characteristics.
– colminator
Mar 27 at 20:29
@Adrian I agree, however this was part of an assignment so the problem is rather fabricated.
– octavio
Mar 28 at 11:03
add a comment |
4
First convert them back touint8and then compare those uints.
– mkopriva
Mar 27 at 20:02
4
Though this does raise the question of why these are different types; the point of creating primitive-based types is usually to distinguish them, meaning that comparing aSomeIDto aOtherIDshouldn't yield any meaningful result; like comparing atime.Monthto atime.Weekday, which are bothintbut have different meaning and are therefore incomparable.
– Adrian
Mar 27 at 20:27
1
exactly - and usually one adds methods to a distinct type which ultimately define its unique characteristics.
– colminator
Mar 27 at 20:29
@Adrian I agree, however this was part of an assignment so the problem is rather fabricated.
– octavio
Mar 28 at 11:03
4
4
First convert them back to
uint8 and then compare those uints.– mkopriva
Mar 27 at 20:02
First convert them back to
uint8 and then compare those uints.– mkopriva
Mar 27 at 20:02
4
4
Though this does raise the question of why these are different types; the point of creating primitive-based types is usually to distinguish them, meaning that comparing a
SomeID to a OtherID shouldn't yield any meaningful result; like comparing a time.Month to a time.Weekday, which are both int but have different meaning and are therefore incomparable.– Adrian
Mar 27 at 20:27
Though this does raise the question of why these are different types; the point of creating primitive-based types is usually to distinguish them, meaning that comparing a
SomeID to a OtherID shouldn't yield any meaningful result; like comparing a time.Month to a time.Weekday, which are both int but have different meaning and are therefore incomparable.– Adrian
Mar 27 at 20:27
1
1
exactly - and usually one adds methods to a distinct type which ultimately define its unique characteristics.
– colminator
Mar 27 at 20:29
exactly - and usually one adds methods to a distinct type which ultimately define its unique characteristics.
– colminator
Mar 27 at 20:29
@Adrian I agree, however this was part of an assignment so the problem is rather fabricated.
– octavio
Mar 28 at 11:03
@Adrian I agree, however this was part of an assignment so the problem is rather fabricated.
– octavio
Mar 28 at 11:03
add a comment |
2 Answers
2
active
oldest
votes
As mentioned by mkopriva, type-conversion is needed to compare the values.
https://tour.golang.org/basics/13
func areEqual(sid SomeID, oid OtherID) bool
return uint8(sid) == uint8(oid)
answered Mar 27 at 20:13
octaviooctavio
1848 bronze badges
add a comment |
You can be less accurate, you don't need to remember underlying type
func areEqual(sid SomeID, oid OtherID) bool
return sid == SomeID(oid)
And you can be more generic
func areEqual(x, y interface) (bool, error)
xv := reflect.ValueOf(x)
yv := reflect.ValueOf(y)
if yv.Type().ConvertibleTo(xv.Type())
return xv.Interface() == yv.Convert(xv.Type()).Interface(), nil
else
return false, errors.New("Types are mismatched")
Playground
answered Mar 28 at 13:11
UvelichitelUvelichitel
6,1591 gold badge9 silver badges29 bronze badges
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
As mentioned by mkopriva, type-conversion is needed to compare the values.
https://tour.golang.org/basics/13
func areEqual(sid SomeID, oid OtherID) bool
return uint8(sid) == uint8(oid)
answered Mar 27 at 20:13
octaviooctavio
1848 bronze badges
add a comment |
As mentioned by mkopriva, type-conversion is needed to compare the values.
https://tour.golang.org/basics/13
func areEqual(sid SomeID, oid OtherID) bool
return uint8(sid) == uint8(oid)
answered Mar 27 at 20:13
octaviooctavio
1848 bronze badges
add a comment |
As mentioned by mkopriva, type-conversion is needed to compare the values.
https://tour.golang.org/basics/13
func areEqual(sid SomeID, oid OtherID) bool
return uint8(sid) == uint8(oid)
answered Mar 27 at 20:13
octaviooctavio
1848 bronze badges
As mentioned by mkopriva, type-conversion is needed to compare the values.
https://tour.golang.org/basics/13
func areEqual(sid SomeID, oid OtherID) bool
return uint8(sid) == uint8(oid)
answered Mar 27 at 20:13
octaviooctavio
1848 bronze badges
answered Mar 27 at 20:13
octaviooctavio
1848 bronze badges
answered Mar 27 at 20:13
octaviooctavio
1848 bronze badges
answered Mar 27 at 20:13
octaviooctavio
1848 bronze badges
1848 bronze badges
add a comment |
add a comment |
You can be less accurate, you don't need to remember underlying type
func areEqual(sid SomeID, oid OtherID) bool
return sid == SomeID(oid)
And you can be more generic
func areEqual(x, y interface) (bool, error)
xv := reflect.ValueOf(x)
yv := reflect.ValueOf(y)
if yv.Type().ConvertibleTo(xv.Type())
return xv.Interface() == yv.Convert(xv.Type()).Interface(), nil
else
return false, errors.New("Types are mismatched")
Playground
answered Mar 28 at 13:11
UvelichitelUvelichitel
6,1591 gold badge9 silver badges29 bronze badges
add a comment |
You can be less accurate, you don't need to remember underlying type
func areEqual(sid SomeID, oid OtherID) bool
return sid == SomeID(oid)
And you can be more generic
func areEqual(x, y interface) (bool, error)
xv := reflect.ValueOf(x)
yv := reflect.ValueOf(y)
if yv.Type().ConvertibleTo(xv.Type())
return xv.Interface() == yv.Convert(xv.Type()).Interface(), nil
else
return false, errors.New("Types are mismatched")
Playground
answered Mar 28 at 13:11
UvelichitelUvelichitel
6,1591 gold badge9 silver badges29 bronze badges
add a comment |
You can be less accurate, you don't need to remember underlying type
func areEqual(sid SomeID, oid OtherID) bool
return sid == SomeID(oid)
And you can be more generic
func areEqual(x, y interface) (bool, error)
xv := reflect.ValueOf(x)
yv := reflect.ValueOf(y)
if yv.Type().ConvertibleTo(xv.Type())
return xv.Interface() == yv.Convert(xv.Type()).Interface(), nil
else
return false, errors.New("Types are mismatched")
Playground
answered Mar 28 at 13:11
UvelichitelUvelichitel
6,1591 gold badge9 silver badges29 bronze badges
You can be less accurate, you don't need to remember underlying type
func areEqual(sid SomeID, oid OtherID) bool
return sid == SomeID(oid)
And you can be more generic
func areEqual(x, y interface) (bool, error)
xv := reflect.ValueOf(x)
yv := reflect.ValueOf(y)
if yv.Type().ConvertibleTo(xv.Type())
return xv.Interface() == yv.Convert(xv.Type()).Interface(), nil
else
return false, errors.New("Types are mismatched")
Playground
answered Mar 28 at 13:11
UvelichitelUvelichitel
6,1591 gold badge9 silver badges29 bronze badges
answered Mar 28 at 13:11
UvelichitelUvelichitel
6,1591 gold badge9 silver badges29 bronze badges
answered Mar 28 at 13:11
UvelichitelUvelichitel
6,1591 gold badge9 silver badges29 bronze badges
answered Mar 28 at 13:11
UvelichitelUvelichitel
6,1591 gold badge9 silver badges29 bronze badges
6,1591 gold badge9 silver badges29 bronze badges
add a comment |
add a comment |
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4
First convert them back to
uint8and then compare those uints.– mkopriva
Mar 27 at 20:02
4
Though this does raise the question of why these are different types; the point of creating primitive-based types is usually to distinguish them, meaning that comparing a
SomeIDto aOtherIDshouldn't yield any meaningful result; like comparing atime.Monthto atime.Weekday, which are bothintbut have different meaning and are therefore incomparable.– Adrian
Mar 27 at 20:27
1
exactly - and usually one adds methods to a distinct type which ultimately define its unique characteristics.
– colminator
Mar 27 at 20:29
@Adrian I agree, however this was part of an assignment so the problem is rather fabricated.
– octavio
Mar 28 at 11:03