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How to get more memory for creating a large list in IronPython


How do I check if a list is empty?How can I safely create a nested directory?How to get the current time in PythonGetting the last element of a listHow to make a flat list out of list of listsHow do I get the number of elements in a list?How do I concatenate two lists in Python?How to clone or copy a list?How do I list all files of a directory?How to read a file line-by-line into a list?






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0















I'm trying to create a large array, but every time I got a memory exception.



I'm just wondering is there a way to use up all the memory of the computer ?



I've tried to use void* PyObject_Malloc(size_t n) on the documentation, but I'm not sure what's the correct way of using this method.



For example, when I try:



array = [None]*999999999


it gives me System.OutOfMemoryException



I'm expecting to use all the memory of my computer. The python process uses around 1.5 GB memory and throws the exception, while my computer has 8 GB of memory



I'm using IronPython, so I can' use libs like numpy.










share|improve this question


























  • That is not an array, that is a list. Now, I'm not sure exactly how IronPython implements list objects, but likekly, it requires some sort of array of PyObject's (whatever they are called in the IronPython implementation). Which likely requires at the minimum an underlying buffer of machine-word pointers, 8 bytes per object, so 999999999*8*1e-9 ==7.9999 gigabytes. You are simply out of memory. Note, None is likely a singleton, but if you are going to put any other objects in there, they will require even more memory.

    – juanpa.arrivillaga
    Mar 27 at 20:12


















0















I'm trying to create a large array, but every time I got a memory exception.



I'm just wondering is there a way to use up all the memory of the computer ?



I've tried to use void* PyObject_Malloc(size_t n) on the documentation, but I'm not sure what's the correct way of using this method.



For example, when I try:



array = [None]*999999999


it gives me System.OutOfMemoryException



I'm expecting to use all the memory of my computer. The python process uses around 1.5 GB memory and throws the exception, while my computer has 8 GB of memory



I'm using IronPython, so I can' use libs like numpy.










share|improve this question


























  • That is not an array, that is a list. Now, I'm not sure exactly how IronPython implements list objects, but likekly, it requires some sort of array of PyObject's (whatever they are called in the IronPython implementation). Which likely requires at the minimum an underlying buffer of machine-word pointers, 8 bytes per object, so 999999999*8*1e-9 ==7.9999 gigabytes. You are simply out of memory. Note, None is likely a singleton, but if you are going to put any other objects in there, they will require even more memory.

    – juanpa.arrivillaga
    Mar 27 at 20:12














0












0








0








I'm trying to create a large array, but every time I got a memory exception.



I'm just wondering is there a way to use up all the memory of the computer ?



I've tried to use void* PyObject_Malloc(size_t n) on the documentation, but I'm not sure what's the correct way of using this method.



For example, when I try:



array = [None]*999999999


it gives me System.OutOfMemoryException



I'm expecting to use all the memory of my computer. The python process uses around 1.5 GB memory and throws the exception, while my computer has 8 GB of memory



I'm using IronPython, so I can' use libs like numpy.










share|improve this question
















I'm trying to create a large array, but every time I got a memory exception.



I'm just wondering is there a way to use up all the memory of the computer ?



I've tried to use void* PyObject_Malloc(size_t n) on the documentation, but I'm not sure what's the correct way of using this method.



For example, when I try:



array = [None]*999999999


it gives me System.OutOfMemoryException



I'm expecting to use all the memory of my computer. The python process uses around 1.5 GB memory and throws the exception, while my computer has 8 GB of memory



I'm using IronPython, so I can' use libs like numpy.







python ironpython






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 27 at 20:06









Martin

275 bronze badges




275 bronze badges










asked Mar 27 at 19:56









whtitefallwhtitefall

216 bronze badges




216 bronze badges















  • That is not an array, that is a list. Now, I'm not sure exactly how IronPython implements list objects, but likekly, it requires some sort of array of PyObject's (whatever they are called in the IronPython implementation). Which likely requires at the minimum an underlying buffer of machine-word pointers, 8 bytes per object, so 999999999*8*1e-9 ==7.9999 gigabytes. You are simply out of memory. Note, None is likely a singleton, but if you are going to put any other objects in there, they will require even more memory.

    – juanpa.arrivillaga
    Mar 27 at 20:12


















  • That is not an array, that is a list. Now, I'm not sure exactly how IronPython implements list objects, but likekly, it requires some sort of array of PyObject's (whatever they are called in the IronPython implementation). Which likely requires at the minimum an underlying buffer of machine-word pointers, 8 bytes per object, so 999999999*8*1e-9 ==7.9999 gigabytes. You are simply out of memory. Note, None is likely a singleton, but if you are going to put any other objects in there, they will require even more memory.

    – juanpa.arrivillaga
    Mar 27 at 20:12

















That is not an array, that is a list. Now, I'm not sure exactly how IronPython implements list objects, but likekly, it requires some sort of array of PyObject's (whatever they are called in the IronPython implementation). Which likely requires at the minimum an underlying buffer of machine-word pointers, 8 bytes per object, so 999999999*8*1e-9 ==7.9999 gigabytes. You are simply out of memory. Note, None is likely a singleton, but if you are going to put any other objects in there, they will require even more memory.

– juanpa.arrivillaga
Mar 27 at 20:12






That is not an array, that is a list. Now, I'm not sure exactly how IronPython implements list objects, but likekly, it requires some sort of array of PyObject's (whatever they are called in the IronPython implementation). Which likely requires at the minimum an underlying buffer of machine-word pointers, 8 bytes per object, so 999999999*8*1e-9 ==7.9999 gigabytes. You are simply out of memory. Note, None is likely a singleton, but if you are going to put any other objects in there, they will require even more memory.

– juanpa.arrivillaga
Mar 27 at 20:12













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