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Mapping a json string to an object with jackson will throw MismatchedInputException


How do I efficiently iterate over each entry in a Java Map?Sort a Map<Key, Value> by valuesHow do I read / convert an InputStream into a String in Java?Jackson with JSON: Unrecognized field, not marked as ignorableIgnoring new fields on JSON objects using JacksonHow do I convert a String to an int in Java?How to use Jackson to deserialise an array of objectsWhy is char[] preferred over String for passwords?How to tell Jackson to ignore a field during serialization if its value is null?Jackson @JsonProperty(required=true) doesn't throw an exception






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3















I have a simple class



public class AuthenticationToken 

public String token;

public AuthenticationToken(String token)
this.token = token;


public String getToken()
return token;


public void setToken(String token)
this.token = token;




With jackson I am trying to map an string to this object like this



private String input = ""token":"adf"";


@Test
public void whenJsonString_ThenCreateAuthenticationObject() throws IOException

ObjectMapper jsonMapper = new ObjectMapper();
AuthenticationToken tokenObject = jsonMapper.readValue(input, AuthenticationToken.class);
assertThat(tokenObject).isNotNull();



But it throws the following exception



com.fasterxml.jackson.databind.exc.MismatchedInputException: Cannot construct instance of `foo.AuthenticationToken` (although at least one Creator exists): cannot deserialize from Object value (no delegate- or property-based Creator)
at [Source: (String)""token":"adf""; line: 1, column: 2]


I tried to annotate the property in my AuthenticationToken as a @JsonProperty but this also resulted in in this exception.










share|improve this question



















  • 2





    You need to define a default constructor.

    – BackSlash
    Mar 27 at 13:25











  • Jackson doesn't know how to call the constructor. You probably want to annotate it using @JsonCreator and its argument(s) uisng @JsonProperty, i.e. @JsonCreator AuthenticationToken(@JsonProperty("token") String token)

    – Thomas
    Mar 27 at 13:25


















3















I have a simple class



public class AuthenticationToken 

public String token;

public AuthenticationToken(String token)
this.token = token;


public String getToken()
return token;


public void setToken(String token)
this.token = token;




With jackson I am trying to map an string to this object like this



private String input = ""token":"adf"";


@Test
public void whenJsonString_ThenCreateAuthenticationObject() throws IOException

ObjectMapper jsonMapper = new ObjectMapper();
AuthenticationToken tokenObject = jsonMapper.readValue(input, AuthenticationToken.class);
assertThat(tokenObject).isNotNull();



But it throws the following exception



com.fasterxml.jackson.databind.exc.MismatchedInputException: Cannot construct instance of `foo.AuthenticationToken` (although at least one Creator exists): cannot deserialize from Object value (no delegate- or property-based Creator)
at [Source: (String)""token":"adf""; line: 1, column: 2]


I tried to annotate the property in my AuthenticationToken as a @JsonProperty but this also resulted in in this exception.










share|improve this question



















  • 2





    You need to define a default constructor.

    – BackSlash
    Mar 27 at 13:25











  • Jackson doesn't know how to call the constructor. You probably want to annotate it using @JsonCreator and its argument(s) uisng @JsonProperty, i.e. @JsonCreator AuthenticationToken(@JsonProperty("token") String token)

    – Thomas
    Mar 27 at 13:25














3












3








3








I have a simple class



public class AuthenticationToken 

public String token;

public AuthenticationToken(String token)
this.token = token;


public String getToken()
return token;


public void setToken(String token)
this.token = token;




With jackson I am trying to map an string to this object like this



private String input = ""token":"adf"";


@Test
public void whenJsonString_ThenCreateAuthenticationObject() throws IOException

ObjectMapper jsonMapper = new ObjectMapper();
AuthenticationToken tokenObject = jsonMapper.readValue(input, AuthenticationToken.class);
assertThat(tokenObject).isNotNull();



But it throws the following exception



com.fasterxml.jackson.databind.exc.MismatchedInputException: Cannot construct instance of `foo.AuthenticationToken` (although at least one Creator exists): cannot deserialize from Object value (no delegate- or property-based Creator)
at [Source: (String)""token":"adf""; line: 1, column: 2]


I tried to annotate the property in my AuthenticationToken as a @JsonProperty but this also resulted in in this exception.










share|improve this question














I have a simple class



public class AuthenticationToken 

public String token;

public AuthenticationToken(String token)
this.token = token;


public String getToken()
return token;


public void setToken(String token)
this.token = token;




With jackson I am trying to map an string to this object like this



private String input = ""token":"adf"";


@Test
public void whenJsonString_ThenCreateAuthenticationObject() throws IOException

ObjectMapper jsonMapper = new ObjectMapper();
AuthenticationToken tokenObject = jsonMapper.readValue(input, AuthenticationToken.class);
assertThat(tokenObject).isNotNull();



But it throws the following exception



com.fasterxml.jackson.databind.exc.MismatchedInputException: Cannot construct instance of `foo.AuthenticationToken` (although at least one Creator exists): cannot deserialize from Object value (no delegate- or property-based Creator)
at [Source: (String)""token":"adf""; line: 1, column: 2]


I tried to annotate the property in my AuthenticationToken as a @JsonProperty but this also resulted in in this exception.







java jackson






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 27 at 13:22









Al PhabaAl Phaba

2,5149 gold badges35 silver badges61 bronze badges




2,5149 gold badges35 silver badges61 bronze badges










  • 2





    You need to define a default constructor.

    – BackSlash
    Mar 27 at 13:25











  • Jackson doesn't know how to call the constructor. You probably want to annotate it using @JsonCreator and its argument(s) uisng @JsonProperty, i.e. @JsonCreator AuthenticationToken(@JsonProperty("token") String token)

    – Thomas
    Mar 27 at 13:25













  • 2





    You need to define a default constructor.

    – BackSlash
    Mar 27 at 13:25











  • Jackson doesn't know how to call the constructor. You probably want to annotate it using @JsonCreator and its argument(s) uisng @JsonProperty, i.e. @JsonCreator AuthenticationToken(@JsonProperty("token") String token)

    – Thomas
    Mar 27 at 13:25








2




2





You need to define a default constructor.

– BackSlash
Mar 27 at 13:25





You need to define a default constructor.

– BackSlash
Mar 27 at 13:25













Jackson doesn't know how to call the constructor. You probably want to annotate it using @JsonCreator and its argument(s) uisng @JsonProperty, i.e. @JsonCreator AuthenticationToken(@JsonProperty("token") String token)

– Thomas
Mar 27 at 13:25






Jackson doesn't know how to call the constructor. You probably want to annotate it using @JsonCreator and its argument(s) uisng @JsonProperty, i.e. @JsonCreator AuthenticationToken(@JsonProperty("token") String token)

– Thomas
Mar 27 at 13:25













2 Answers
2






active

oldest

votes


















1














Jackson will by default expect an "empty" constructor and will automatically fill your Object by the getters and setters that are provided for each field.



So removing the arguments of your constructor will already solve your problem:



public class AuthenticationToken 

public String token;

public AuthenticationToken()

public String getToken()
return token;


public void setToken(String token)
this.token = token;




You could also just add an additional empty constructor if you want to keep your current one as it is. Tested both options for your Test Case, both work fine.






share|improve this answer


































    1














    Annotate the class constructor with @JsonCreator




    Marker annotation that can be used to define constructors and factory
    methods as one to use for instantiating new instances of the
    associated class.




    public class AuthenticationToken 
    public String token;

    @JsonCreator
    public AuthenticationToken(@JsonProperty("token") final String token)
    this.token = token;


    public String getToken()
    return token;


    public void setToken(String token)
    this.token = token;







    share|improve this answer



























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      2 Answers
      2






      active

      oldest

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      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      1














      Jackson will by default expect an "empty" constructor and will automatically fill your Object by the getters and setters that are provided for each field.



      So removing the arguments of your constructor will already solve your problem:



      public class AuthenticationToken 

      public String token;

      public AuthenticationToken()

      public String getToken()
      return token;


      public void setToken(String token)
      this.token = token;




      You could also just add an additional empty constructor if you want to keep your current one as it is. Tested both options for your Test Case, both work fine.






      share|improve this answer































        1














        Jackson will by default expect an "empty" constructor and will automatically fill your Object by the getters and setters that are provided for each field.



        So removing the arguments of your constructor will already solve your problem:



        public class AuthenticationToken 

        public String token;

        public AuthenticationToken()

        public String getToken()
        return token;


        public void setToken(String token)
        this.token = token;




        You could also just add an additional empty constructor if you want to keep your current one as it is. Tested both options for your Test Case, both work fine.






        share|improve this answer





























          1












          1








          1







          Jackson will by default expect an "empty" constructor and will automatically fill your Object by the getters and setters that are provided for each field.



          So removing the arguments of your constructor will already solve your problem:



          public class AuthenticationToken 

          public String token;

          public AuthenticationToken()

          public String getToken()
          return token;


          public void setToken(String token)
          this.token = token;




          You could also just add an additional empty constructor if you want to keep your current one as it is. Tested both options for your Test Case, both work fine.






          share|improve this answer















          Jackson will by default expect an "empty" constructor and will automatically fill your Object by the getters and setters that are provided for each field.



          So removing the arguments of your constructor will already solve your problem:



          public class AuthenticationToken 

          public String token;

          public AuthenticationToken()

          public String getToken()
          return token;


          public void setToken(String token)
          this.token = token;




          You could also just add an additional empty constructor if you want to keep your current one as it is. Tested both options for your Test Case, both work fine.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Mar 27 at 13:54

























          answered Mar 27 at 13:48









          T AT A

          8021 gold badge9 silver badges17 bronze badges




          8021 gold badge9 silver badges17 bronze badges


























              1














              Annotate the class constructor with @JsonCreator




              Marker annotation that can be used to define constructors and factory
              methods as one to use for instantiating new instances of the
              associated class.




              public class AuthenticationToken 
              public String token;

              @JsonCreator
              public AuthenticationToken(@JsonProperty("token") final String token)
              this.token = token;


              public String getToken()
              return token;


              public void setToken(String token)
              this.token = token;







              share|improve this answer





























                1














                Annotate the class constructor with @JsonCreator




                Marker annotation that can be used to define constructors and factory
                methods as one to use for instantiating new instances of the
                associated class.




                public class AuthenticationToken 
                public String token;

                @JsonCreator
                public AuthenticationToken(@JsonProperty("token") final String token)
                this.token = token;


                public String getToken()
                return token;


                public void setToken(String token)
                this.token = token;







                share|improve this answer



























                  1












                  1








                  1







                  Annotate the class constructor with @JsonCreator




                  Marker annotation that can be used to define constructors and factory
                  methods as one to use for instantiating new instances of the
                  associated class.




                  public class AuthenticationToken 
                  public String token;

                  @JsonCreator
                  public AuthenticationToken(@JsonProperty("token") final String token)
                  this.token = token;


                  public String getToken()
                  return token;


                  public void setToken(String token)
                  this.token = token;







                  share|improve this answer













                  Annotate the class constructor with @JsonCreator




                  Marker annotation that can be used to define constructors and factory
                  methods as one to use for instantiating new instances of the
                  associated class.




                  public class AuthenticationToken 
                  public String token;

                  @JsonCreator
                  public AuthenticationToken(@JsonProperty("token") final String token)
                  this.token = token;


                  public String getToken()
                  return token;


                  public void setToken(String token)
                  this.token = token;








                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Mar 27 at 13:26









                  LppEddLppEdd

                  10.5k3 gold badges20 silver badges52 bronze badges




                  10.5k3 gold badges20 silver badges52 bronze badges






























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