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Multiple selection with listboxfor/listbox post only last selected item

ListBoxFor not letting me select multiple items MVCListboxfor MVC3 Razor. User selection from database fieldsMVC 3 - Getting all selected values from a listbox on postbackHow do you properly create a MultiSelect <select> using the DropdownList helper?MVC4 - Setting Initially Selected Item in DropDownListMVC 3.5/Razor: Listbox + Option 'Selected' Value is being IgnoredWhy are the initial multiple selections of an Html.ListBox not visible?Select ListBox items using comma separated values in mvc?Error while posting dropdownAjax request not returning success from controllerHow to produce 'n' no. of text boxes having different Names with respect to no. of drop down items selected?

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0

I'm trying to do a multiple selection with ListBoxFor of Razor, but the select does not allow me to select multiple items (I can do that only selecting my items with Ctr+click the second item). I've reduced my code to minimal like the exemple shown in this answer (my code is above). Anyone can help me?? I'm desperate.

My Model

public IEnumerable<int> ParoleChiave get; set; 
public IEnumerable<SelectListItem> ListaParoleChiave get; set; 

My Controller

model.ListaParoleChiave = new List<SelectListItem>() 
 new SelectListItem() Text = "Pro", Value = "2",
 new SelectListItem() Text = "Test", Value = "3"
;

My View

<div class="form-group form-group-sm">
 <label class="col-xs-12">Parole chiave</label>
 <div class="col-xs-12">
 @Html.ListBoxFor(m => m.ParoleChiave, Model.ListaParoleChiave, new @class = "form-control", style = "width: 100%" ) 
 </div>
</div>

c# razor model-view-controller multi-select html.listboxfor

share|improve this question

edited Mar 27 at 17:38

user3692982

asked Mar 27 at 17:29

user3692982user3692982

533 bronze badges

add a comment | 

0

I'm trying to do a multiple selection with ListBoxFor of Razor, but the select does not allow me to select multiple items (I can do that only selecting my items with Ctr+click the second item). I've reduced my code to minimal like the exemple shown in this answer (my code is above). Anyone can help me?? I'm desperate.

My Model

public IEnumerable<int> ParoleChiave get; set; 
public IEnumerable<SelectListItem> ListaParoleChiave get; set; 

My Controller

model.ListaParoleChiave = new List<SelectListItem>() 
 new SelectListItem() Text = "Pro", Value = "2",
 new SelectListItem() Text = "Test", Value = "3"
;

My View

<div class="form-group form-group-sm">
 <label class="col-xs-12">Parole chiave</label>
 <div class="col-xs-12">
 @Html.ListBoxFor(m => m.ParoleChiave, Model.ListaParoleChiave, new @class = "form-control", style = "width: 100%" ) 
 </div>
</div>

c# razor model-view-controller multi-select html.listboxfor

share|improve this question

edited Mar 27 at 17:38

user3692982

asked Mar 27 at 17:29

user3692982user3692982

533 bronze badges

add a comment | 

I'm trying to do a multiple selection with ListBoxFor of Razor, but the select does not allow me to select multiple items (I can do that only selecting my items with Ctr+click the second item). I've reduced my code to minimal like the exemple shown in this answer (my code is above). Anyone can help me?? I'm desperate.

My Model

public IEnumerable<int> ParoleChiave get; set; 
public IEnumerable<SelectListItem> ListaParoleChiave get; set; 

My Controller

model.ListaParoleChiave = new List<SelectListItem>() 
 new SelectListItem() Text = "Pro", Value = "2",
 new SelectListItem() Text = "Test", Value = "3"
;

My View

<div class="form-group form-group-sm">
 <label class="col-xs-12">Parole chiave</label>
 <div class="col-xs-12">
 @Html.ListBoxFor(m => m.ParoleChiave, Model.ListaParoleChiave, new @class = "form-control", style = "width: 100%" ) 
 </div>
</div>

c# razor model-view-controller multi-select html.listboxfor

share|improve this question

edited Mar 27 at 17:38

user3692982

asked Mar 27 at 17:29

user3692982user3692982

533 bronze badges

public IEnumerable<int> ParoleChiave get; set; 
public IEnumerable<SelectListItem> ListaParoleChiave get; set; 

model.ListaParoleChiave = new List<SelectListItem>() 
 new SelectListItem() Text = "Pro", Value = "2",
 new SelectListItem() Text = "Test", Value = "3"
;

<div class="form-group form-group-sm">
 <label class="col-xs-12">Parole chiave</label>
 <div class="col-xs-12">
 @Html.ListBoxFor(m => m.ParoleChiave, Model.ListaParoleChiave, new @class = "form-control", style = "width: 100%" ) 
 </div>
</div>

share|improve this question

edited Mar 27 at 17:38

user3692982

asked Mar 27 at 17:29

user3692982user3692982

533 bronze badges

share|improve this question

edited Mar 27 at 17:38

user3692982

asked Mar 27 at 17:29

user3692982user3692982

533 bronze badges

asked Mar 27 at 17:29

user3692982user3692982

533 bronze badges

asked Mar 27 at 17:29

user3692982user3692982

533 bronze badges

1 Answer
1

active

oldest

votes

0

I found the error. It's not depending from my ListBoxFor element, it was caused by the js code that I wrote to post to the server action my formData with additional data.
Basically it was like:

data: function (d) 
 var fd = new FormData(myForm[0]);
 for (var pair of fd.entries()) 
 d[pair[0]] = pair[1];
 
 return d;
 

I realized that the multiple values where posting like two entries (key/value pairs) of the FormData but with the same key name, so my code was overwriting the first entry with the second. I replaced with the code above and now it works like a charm.

data: function (d) 
 var fd = new FormData(myForm[0]);
 for (var pair of fd.entries()) 
 var occurenceOfKey = Array.from(fd.keys()).reduce(function (n, val) 
 return n + (val === pair[0]);
 , 0);
 if (occurenceOfKey > 1) 
 d[pair[0]] = fd.getAll(pair[0]); 
 else
 d[pair[0]] = pair[1]; 
 
 return d;
 

share|improve this answer

answered Mar 27 at 19:08

user3692982user3692982

533 bronze badges

add a comment | 

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0

I found the error. It's not depending from my ListBoxFor element, it was caused by the js code that I wrote to post to the server action my formData with additional data.
Basically it was like:

data: function (d) 
 var fd = new FormData(myForm[0]);
 for (var pair of fd.entries()) 
 d[pair[0]] = pair[1];
 
 return d;
 

I realized that the multiple values where posting like two entries (key/value pairs) of the FormData but with the same key name, so my code was overwriting the first entry with the second. I replaced with the code above and now it works like a charm.

data: function (d) 
 var fd = new FormData(myForm[0]);
 for (var pair of fd.entries()) 
 var occurenceOfKey = Array.from(fd.keys()).reduce(function (n, val) 
 return n + (val === pair[0]);
 , 0);
 if (occurenceOfKey > 1) 
 d[pair[0]] = fd.getAll(pair[0]); 
 else
 d[pair[0]] = pair[1]; 
 
 return d;
 

share|improve this answer

answered Mar 27 at 19:08

user3692982user3692982

533 bronze badges

add a comment | 

0

I found the error. It's not depending from my ListBoxFor element, it was caused by the js code that I wrote to post to the server action my formData with additional data.
Basically it was like:

data: function (d) 
 var fd = new FormData(myForm[0]);
 for (var pair of fd.entries()) 
 d[pair[0]] = pair[1];
 
 return d;
 

I realized that the multiple values where posting like two entries (key/value pairs) of the FormData but with the same key name, so my code was overwriting the first entry with the second. I replaced with the code above and now it works like a charm.

data: function (d) 
 var fd = new FormData(myForm[0]);
 for (var pair of fd.entries()) 
 var occurenceOfKey = Array.from(fd.keys()).reduce(function (n, val) 
 return n + (val === pair[0]);
 , 0);
 if (occurenceOfKey > 1) 
 d[pair[0]] = fd.getAll(pair[0]); 
 else
 d[pair[0]] = pair[1]; 
 
 return d;
 

share|improve this answer

answered Mar 27 at 19:08

user3692982user3692982

533 bronze badges

add a comment | 

I found the error. It's not depending from my ListBoxFor element, it was caused by the js code that I wrote to post to the server action my formData with additional data.
Basically it was like:

data: function (d) 
 var fd = new FormData(myForm[0]);
 for (var pair of fd.entries()) 
 d[pair[0]] = pair[1];
 
 return d;
 

I realized that the multiple values where posting like two entries (key/value pairs) of the FormData but with the same key name, so my code was overwriting the first entry with the second. I replaced with the code above and now it works like a charm.

data: function (d) 
 var fd = new FormData(myForm[0]);
 for (var pair of fd.entries()) 
 var occurenceOfKey = Array.from(fd.keys()).reduce(function (n, val) 
 return n + (val === pair[0]);
 , 0);
 if (occurenceOfKey > 1) 
 d[pair[0]] = fd.getAll(pair[0]); 
 else
 d[pair[0]] = pair[1]; 
 
 return d;
 

share|improve this answer

answered Mar 27 at 19:08

user3692982user3692982

533 bronze badges

data: function (d) 
 var fd = new FormData(myForm[0]);
 for (var pair of fd.entries()) 
 d[pair[0]] = pair[1];
 
 return d;
 

data: function (d) 
 var fd = new FormData(myForm[0]);
 for (var pair of fd.entries()) 
 var occurenceOfKey = Array.from(fd.keys()).reduce(function (n, val) 
 return n + (val === pair[0]);
 , 0);
 if (occurenceOfKey > 1) 
 d[pair[0]] = fd.getAll(pair[0]); 
 else
 d[pair[0]] = pair[1]; 
 
 return d;
 

share|improve this answer

answered Mar 27 at 19:08

user3692982user3692982

533 bronze badges

answered Mar 27 at 19:08

user3692982user3692982

533 bronze badges

answered Mar 27 at 19:08

user3692982user3692982

533 bronze badges