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0

I am creating a program in Scala that needs to generate a fitness function based on the line that I provide it with.

To generate the fitness function I wrote a method that
takes a list of points and returns a fitness function based on those points.

This fitness function should measure the sum of the distances of each point from the line in terms of their y values. And the lower the sum the higher the fitness.

But now I am stuck, because I can't figure out how I can transform the sum of the distances from 0 to Infinite to a Double which is from 1 to 0, 1 the best fit and 0 being the worst fit line.

Any ideas or maths equation ? Thank you in advance

I have already tried to clamp this value using the tanh function only to realize that it works horribly for larger values.
I have also tried doing it using:

fitness = 1 - Math.atan(x)/(Math.PI/2);

So that I could maybe get the reverse answer, but it didn't work :'^)

This is the code that pertains to how my program runs:

//Point Class that is just a coordinate point (x, y)
class Point(val x: Double, val y: Double) 


//Line Class this is just a line with y = slope * x + yIntercept
class Line(val slope: Double, val yIntercept: Double) 

 def evaluate(x: Double): Double = 
 slope * x + yIntercept
 


def lineFitFuncGen(points: List[Point]): Line => Double = 
 //Sum of the distances using the line given
 line: Line => 
 var lineSum: Double = 0.0
 for (point <- points) 
 lineSum += Math.abs(line.evaluate(point.x) - point.y)
 
 lineSum
 
 

I run the program and I get the sum but now I don't know how to take this sum and convert it into a range of 1 to 0. And I want to make it so that my lowest sum possible, which is 0 gives me fitness of 1, while my highest sum possible, which is Infinity gives me fitness of 0

scala math fitness

share|improve this question

edited Mar 28 at 10:08

cs95

167k3232 gold badges241241 silver badges304304 bronze badges

asked Mar 28 at 10:06

Edgar UstianEdgar Ustian

122 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  One language tag at a time please, thanks
  
  – cs95
  Mar 28 at 10:07
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @MarkRotteveel Accidental.. thanks, fixed
  
  – cs95
  Mar 28 at 10:08
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  can't you just do 1 / (1 + v)?
  
  – Russ Hyde
  Mar 28 at 10:09
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  sorry, I just didn't know which language would be the right one
  
  – Edgar Ustian
  Mar 28 at 10:21
  

  
  
  
  

add a comment
 | 

0

I am creating a program in Scala that needs to generate a fitness function based on the line that I provide it with.

To generate the fitness function I wrote a method that
takes a list of points and returns a fitness function based on those points.

This fitness function should measure the sum of the distances of each point from the line in terms of their y values. And the lower the sum the higher the fitness.

But now I am stuck, because I can't figure out how I can transform the sum of the distances from 0 to Infinite to a Double which is from 1 to 0, 1 the best fit and 0 being the worst fit line.

Any ideas or maths equation ? Thank you in advance

I have already tried to clamp this value using the tanh function only to realize that it works horribly for larger values.
I have also tried doing it using:

fitness = 1 - Math.atan(x)/(Math.PI/2);

So that I could maybe get the reverse answer, but it didn't work :'^)

This is the code that pertains to how my program runs:

//Point Class that is just a coordinate point (x, y)
class Point(val x: Double, val y: Double) 


//Line Class this is just a line with y = slope * x + yIntercept
class Line(val slope: Double, val yIntercept: Double) 

 def evaluate(x: Double): Double = 
 slope * x + yIntercept
 


def lineFitFuncGen(points: List[Point]): Line => Double = 
 //Sum of the distances using the line given
 line: Line => 
 var lineSum: Double = 0.0
 for (point <- points) 
 lineSum += Math.abs(line.evaluate(point.x) - point.y)
 
 lineSum
 
 

I run the program and I get the sum but now I don't know how to take this sum and convert it into a range of 1 to 0. And I want to make it so that my lowest sum possible, which is 0 gives me fitness of 1, while my highest sum possible, which is Infinity gives me fitness of 0

scala math fitness

share|improve this question

edited Mar 28 at 10:08

cs95

167k3232 gold badges241241 silver badges304304 bronze badges

asked Mar 28 at 10:06

Edgar UstianEdgar Ustian

122 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  One language tag at a time please, thanks
  
  – cs95
  Mar 28 at 10:07
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @MarkRotteveel Accidental.. thanks, fixed
  
  – cs95
  Mar 28 at 10:08
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  can't you just do 1 / (1 + v)?
  
  – Russ Hyde
  Mar 28 at 10:09
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  sorry, I just didn't know which language would be the right one
  
  – Edgar Ustian
  Mar 28 at 10:21
  

  
  
  
  

add a comment
 | 

I am creating a program in Scala that needs to generate a fitness function based on the line that I provide it with.

To generate the fitness function I wrote a method that
takes a list of points and returns a fitness function based on those points.

This fitness function should measure the sum of the distances of each point from the line in terms of their y values. And the lower the sum the higher the fitness.

But now I am stuck, because I can't figure out how I can transform the sum of the distances from 0 to Infinite to a Double which is from 1 to 0, 1 the best fit and 0 being the worst fit line.

Any ideas or maths equation ? Thank you in advance

I have already tried to clamp this value using the tanh function only to realize that it works horribly for larger values.
I have also tried doing it using:

fitness = 1 - Math.atan(x)/(Math.PI/2);

So that I could maybe get the reverse answer, but it didn't work :'^)

This is the code that pertains to how my program runs:

//Point Class that is just a coordinate point (x, y)
class Point(val x: Double, val y: Double) 


//Line Class this is just a line with y = slope * x + yIntercept
class Line(val slope: Double, val yIntercept: Double) 

 def evaluate(x: Double): Double = 
 slope * x + yIntercept
 


def lineFitFuncGen(points: List[Point]): Line => Double = 
 //Sum of the distances using the line given
 line: Line => 
 var lineSum: Double = 0.0
 for (point <- points) 
 lineSum += Math.abs(line.evaluate(point.x) - point.y)
 
 lineSum
 
 

I run the program and I get the sum but now I don't know how to take this sum and convert it into a range of 1 to 0. And I want to make it so that my lowest sum possible, which is 0 gives me fitness of 1, while my highest sum possible, which is Infinity gives me fitness of 0

scala math fitness

share|improve this question

edited Mar 28 at 10:08

cs95

167k3232 gold badges241241 silver badges304304 bronze badges

asked Mar 28 at 10:06

Edgar UstianEdgar Ustian

122 bronze badges

fitness = 1 - Math.atan(x)/(Math.PI/2);

//Point Class that is just a coordinate point (x, y)
class Point(val x: Double, val y: Double) 


//Line Class this is just a line with y = slope * x + yIntercept
class Line(val slope: Double, val yIntercept: Double) 

 def evaluate(x: Double): Double = 
 slope * x + yIntercept
 


def lineFitFuncGen(points: List[Point]): Line => Double = 
 //Sum of the distances using the line given
 line: Line => 
 var lineSum: Double = 0.0
 for (point <- points) 
 lineSum += Math.abs(line.evaluate(point.x) - point.y)
 
 lineSum
 
 

share|improve this question

edited Mar 28 at 10:08

cs95

167k3232 gold badges241241 silver badges304304 bronze badges

asked Mar 28 at 10:06

Edgar UstianEdgar Ustian

122 bronze badges

share|improve this question

edited Mar 28 at 10:08

cs95

167k3232 gold badges241241 silver badges304304 bronze badges

asked Mar 28 at 10:06

Edgar UstianEdgar Ustian

122 bronze badges

edited Mar 28 at 10:08

cs95

167k3232 gold badges241241 silver badges304304 bronze badges

edited Mar 28 at 10:08

cs95

167k3232 gold badges241241 silver badges304304 bronze badges

asked Mar 28 at 10:06

Edgar UstianEdgar Ustian

122 bronze badges

asked Mar 28 at 10:06

Edgar UstianEdgar Ustian

122 bronze badges

2 Answers
2

active

oldest

votes

2

Maths, not programming. But...

fitness(x) = 2 / (exp(x) + 1)

is sigmoid function adapted for your requirements (fitness(0) = 1, fitness(inf) = 0).

share|improve this answer

answered Mar 28 at 10:14

AmadanAmadan

144k1414 gold badges156156 silver badges212212 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you very much for this function, but I found out that the values that it gives back are way too small for the program to not count as just 0.0. For some reason, I did not think of something as simple as fitness = 1/(1+x); Maybe it's my lack of sleep who knows, but thank you very much for your answer
  
  – Edgar Ustian
  Mar 28 at 10:28
  
  

  
  
  
  

add a comment
 | 

2

How about

fitness = 1/(1+x);

a function that goes towards 0 as x increases

share|improve this answer

answered Mar 28 at 10:14

AlanAlan

53211 silver badge1919 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Why did I not think of something this simple? I think my brain is just slowly giving up on me for all the lack of sleep that I made it go through. But thank you very much for this simple solution
  
  – Edgar Ustian
  Mar 28 at 10:30
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  i feel you bro. happens to me and my mates all the time.
  
  – Alan
  Mar 28 at 11:08
  

  
  
  
  

add a comment
 | 

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2

Maths, not programming. But...

fitness(x) = 2 / (exp(x) + 1)

is sigmoid function adapted for your requirements (fitness(0) = 1, fitness(inf) = 0).

share|improve this answer

answered Mar 28 at 10:14

AmadanAmadan

144k1414 gold badges156156 silver badges212212 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you very much for this function, but I found out that the values that it gives back are way too small for the program to not count as just 0.0. For some reason, I did not think of something as simple as fitness = 1/(1+x); Maybe it's my lack of sleep who knows, but thank you very much for your answer
  
  – Edgar Ustian
  Mar 28 at 10:28
  
  

  
  
  
  

add a comment
 | 

2

Maths, not programming. But...

fitness(x) = 2 / (exp(x) + 1)

is sigmoid function adapted for your requirements (fitness(0) = 1, fitness(inf) = 0).

share|improve this answer

answered Mar 28 at 10:14

AmadanAmadan

144k1414 gold badges156156 silver badges212212 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you very much for this function, but I found out that the values that it gives back are way too small for the program to not count as just 0.0. For some reason, I did not think of something as simple as fitness = 1/(1+x); Maybe it's my lack of sleep who knows, but thank you very much for your answer
  
  – Edgar Ustian
  Mar 28 at 10:28
  
  

  
  
  
  

add a comment
 | 

Maths, not programming. But...

fitness(x) = 2 / (exp(x) + 1)

is sigmoid function adapted for your requirements (fitness(0) = 1, fitness(inf) = 0).

share|improve this answer

answered Mar 28 at 10:14

AmadanAmadan

144k1414 gold badges156156 silver badges212212 bronze badges

fitness(x) = 2 / (exp(x) + 1)

share|improve this answer

answered Mar 28 at 10:14

AmadanAmadan

144k1414 gold badges156156 silver badges212212 bronze badges

answered Mar 28 at 10:14

AmadanAmadan

144k1414 gold badges156156 silver badges212212 bronze badges

answered Mar 28 at 10:14

AmadanAmadan

144k1414 gold badges156156 silver badges212212 bronze badges

2

How about

fitness = 1/(1+x);

a function that goes towards 0 as x increases

share|improve this answer

answered Mar 28 at 10:14

AlanAlan

53211 silver badge1919 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Why did I not think of something this simple? I think my brain is just slowly giving up on me for all the lack of sleep that I made it go through. But thank you very much for this simple solution
  
  – Edgar Ustian
  Mar 28 at 10:30
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  i feel you bro. happens to me and my mates all the time.
  
  – Alan
  Mar 28 at 11:08
  

  
  
  
  

add a comment
 | 

2

How about

fitness = 1/(1+x);

a function that goes towards 0 as x increases

share|improve this answer

answered Mar 28 at 10:14

AlanAlan

53211 silver badge1919 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Why did I not think of something this simple? I think my brain is just slowly giving up on me for all the lack of sleep that I made it go through. But thank you very much for this simple solution
  
  – Edgar Ustian
  Mar 28 at 10:30
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  i feel you bro. happens to me and my mates all the time.
  
  – Alan
  Mar 28 at 11:08
  

  
  
  
  

add a comment
 | 

How about

fitness = 1/(1+x);

a function that goes towards 0 as x increases

share|improve this answer

answered Mar 28 at 10:14

AlanAlan

53211 silver badge1919 bronze badges

fitness = 1/(1+x);

share|improve this answer

answered Mar 28 at 10:14

AlanAlan

53211 silver badge1919 bronze badges

answered Mar 28 at 10:14

AlanAlan

53211 silver badge1919 bronze badges

answered Mar 28 at 10:14

AlanAlan

53211 silver badge1919 bronze badges