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Test errno for ENOMEM, instead of comparing a series of malloc calls to NULL


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1















Normally, one tests for the result of malloc to not be NULL to known whether memory allocation succeeded. With a series of malloc calls, this becomes a lengthy or tedious set of comparisons.



Instead, could one set errno = 0 at the top of the series of malloc calls, and then test for errno == ENOMEM at the end?

This assumes if any allocation fails, the program or function can't proceed and has to return/bail out. It also assumes the malloc calls are sequential and continuous, and that, as per the manual, malloc can only set errno to ENOMEM.



An example would be something like the following code:



#include <stdlib.h>
#include <errno.h>
#include <stdio.h>

#define N (1 << 20)

int main()

double *a = NULL;
double *b = NULL;
double *c = NULL;

errno = 0;
a = malloc(N * sizeof *a);
b = malloc(N * sizeof *b);
c = malloc(N * sizeof *c);
if (errno == ENOMEM)
perror(NULL);
free(a);
free(b);
free(c);
return EXIT_FAILURE;

errno = 0;

/* Do interesting stuff */

free(a);
free(b);
free(c);
return EXIT_SUCCESS;



(The example uses main(), but it could also be another function that simply can't be run, but the program might proceed otherwise, and no actual exit from the program happens, and the free() calls are necessary.)



I don't see any reason why this can't be done safely, but it's not an idiom I have come across, hence the question.










share|improve this question
























  • My best guess to an answer is either that this is indeed safe, or that malloc setting errno to ENOMEM is less standard across malloc implementations than malloc returning NULL.

    – 0 0
    Mar 28 at 10:07






  • 1





    If malloc for a succeded but failed for b and c, wouldn't free(b) and free(c) give error? I know it does not give error for c++ but I am not sure about C compilers.

    – Suven Pandey
    Mar 28 at 10:10







  • 1





    If your malloc implementation sets errno upon error (which may not be the case, it's platform dependent), then your code is safe.

    – Jabberwocky
    Mar 28 at 10:11







  • 2





    @suvenpandey If malloc fails, it will also return NULL. Calling freewith a NULL parameter is safe in C.

    – Gerhardh
    Mar 28 at 10:16






  • 1





    @user3629249 I can answer that last question myself, I realise: check for fp == NULL, then check the value of errno to see what the actual error is.

    – 0 0
    Mar 28 at 21:05

















1















Normally, one tests for the result of malloc to not be NULL to known whether memory allocation succeeded. With a series of malloc calls, this becomes a lengthy or tedious set of comparisons.



Instead, could one set errno = 0 at the top of the series of malloc calls, and then test for errno == ENOMEM at the end?

This assumes if any allocation fails, the program or function can't proceed and has to return/bail out. It also assumes the malloc calls are sequential and continuous, and that, as per the manual, malloc can only set errno to ENOMEM.



An example would be something like the following code:



#include <stdlib.h>
#include <errno.h>
#include <stdio.h>

#define N (1 << 20)

int main()

double *a = NULL;
double *b = NULL;
double *c = NULL;

errno = 0;
a = malloc(N * sizeof *a);
b = malloc(N * sizeof *b);
c = malloc(N * sizeof *c);
if (errno == ENOMEM)
perror(NULL);
free(a);
free(b);
free(c);
return EXIT_FAILURE;

errno = 0;

/* Do interesting stuff */

free(a);
free(b);
free(c);
return EXIT_SUCCESS;



(The example uses main(), but it could also be another function that simply can't be run, but the program might proceed otherwise, and no actual exit from the program happens, and the free() calls are necessary.)



I don't see any reason why this can't be done safely, but it's not an idiom I have come across, hence the question.










share|improve this question
























  • My best guess to an answer is either that this is indeed safe, or that malloc setting errno to ENOMEM is less standard across malloc implementations than malloc returning NULL.

    – 0 0
    Mar 28 at 10:07






  • 1





    If malloc for a succeded but failed for b and c, wouldn't free(b) and free(c) give error? I know it does not give error for c++ but I am not sure about C compilers.

    – Suven Pandey
    Mar 28 at 10:10







  • 1





    If your malloc implementation sets errno upon error (which may not be the case, it's platform dependent), then your code is safe.

    – Jabberwocky
    Mar 28 at 10:11







  • 2





    @suvenpandey If malloc fails, it will also return NULL. Calling freewith a NULL parameter is safe in C.

    – Gerhardh
    Mar 28 at 10:16






  • 1





    @user3629249 I can answer that last question myself, I realise: check for fp == NULL, then check the value of errno to see what the actual error is.

    – 0 0
    Mar 28 at 21:05













1












1








1








Normally, one tests for the result of malloc to not be NULL to known whether memory allocation succeeded. With a series of malloc calls, this becomes a lengthy or tedious set of comparisons.



Instead, could one set errno = 0 at the top of the series of malloc calls, and then test for errno == ENOMEM at the end?

This assumes if any allocation fails, the program or function can't proceed and has to return/bail out. It also assumes the malloc calls are sequential and continuous, and that, as per the manual, malloc can only set errno to ENOMEM.



An example would be something like the following code:



#include <stdlib.h>
#include <errno.h>
#include <stdio.h>

#define N (1 << 20)

int main()

double *a = NULL;
double *b = NULL;
double *c = NULL;

errno = 0;
a = malloc(N * sizeof *a);
b = malloc(N * sizeof *b);
c = malloc(N * sizeof *c);
if (errno == ENOMEM)
perror(NULL);
free(a);
free(b);
free(c);
return EXIT_FAILURE;

errno = 0;

/* Do interesting stuff */

free(a);
free(b);
free(c);
return EXIT_SUCCESS;



(The example uses main(), but it could also be another function that simply can't be run, but the program might proceed otherwise, and no actual exit from the program happens, and the free() calls are necessary.)



I don't see any reason why this can't be done safely, but it's not an idiom I have come across, hence the question.










share|improve this question














Normally, one tests for the result of malloc to not be NULL to known whether memory allocation succeeded. With a series of malloc calls, this becomes a lengthy or tedious set of comparisons.



Instead, could one set errno = 0 at the top of the series of malloc calls, and then test for errno == ENOMEM at the end?

This assumes if any allocation fails, the program or function can't proceed and has to return/bail out. It also assumes the malloc calls are sequential and continuous, and that, as per the manual, malloc can only set errno to ENOMEM.



An example would be something like the following code:



#include <stdlib.h>
#include <errno.h>
#include <stdio.h>

#define N (1 << 20)

int main()

double *a = NULL;
double *b = NULL;
double *c = NULL;

errno = 0;
a = malloc(N * sizeof *a);
b = malloc(N * sizeof *b);
c = malloc(N * sizeof *c);
if (errno == ENOMEM)
perror(NULL);
free(a);
free(b);
free(c);
return EXIT_FAILURE;

errno = 0;

/* Do interesting stuff */

free(a);
free(b);
free(c);
return EXIT_SUCCESS;



(The example uses main(), but it could also be another function that simply can't be run, but the program might proceed otherwise, and no actual exit from the program happens, and the free() calls are necessary.)



I don't see any reason why this can't be done safely, but it's not an idiom I have come across, hence the question.







c






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 28 at 10:05









0 00 0

2,4221 gold badge8 silver badges19 bronze badges




2,4221 gold badge8 silver badges19 bronze badges















  • My best guess to an answer is either that this is indeed safe, or that malloc setting errno to ENOMEM is less standard across malloc implementations than malloc returning NULL.

    – 0 0
    Mar 28 at 10:07






  • 1





    If malloc for a succeded but failed for b and c, wouldn't free(b) and free(c) give error? I know it does not give error for c++ but I am not sure about C compilers.

    – Suven Pandey
    Mar 28 at 10:10







  • 1





    If your malloc implementation sets errno upon error (which may not be the case, it's platform dependent), then your code is safe.

    – Jabberwocky
    Mar 28 at 10:11







  • 2





    @suvenpandey If malloc fails, it will also return NULL. Calling freewith a NULL parameter is safe in C.

    – Gerhardh
    Mar 28 at 10:16






  • 1





    @user3629249 I can answer that last question myself, I realise: check for fp == NULL, then check the value of errno to see what the actual error is.

    – 0 0
    Mar 28 at 21:05

















  • My best guess to an answer is either that this is indeed safe, or that malloc setting errno to ENOMEM is less standard across malloc implementations than malloc returning NULL.

    – 0 0
    Mar 28 at 10:07






  • 1





    If malloc for a succeded but failed for b and c, wouldn't free(b) and free(c) give error? I know it does not give error for c++ but I am not sure about C compilers.

    – Suven Pandey
    Mar 28 at 10:10







  • 1





    If your malloc implementation sets errno upon error (which may not be the case, it's platform dependent), then your code is safe.

    – Jabberwocky
    Mar 28 at 10:11







  • 2





    @suvenpandey If malloc fails, it will also return NULL. Calling freewith a NULL parameter is safe in C.

    – Gerhardh
    Mar 28 at 10:16






  • 1





    @user3629249 I can answer that last question myself, I realise: check for fp == NULL, then check the value of errno to see what the actual error is.

    – 0 0
    Mar 28 at 21:05
















My best guess to an answer is either that this is indeed safe, or that malloc setting errno to ENOMEM is less standard across malloc implementations than malloc returning NULL.

– 0 0
Mar 28 at 10:07





My best guess to an answer is either that this is indeed safe, or that malloc setting errno to ENOMEM is less standard across malloc implementations than malloc returning NULL.

– 0 0
Mar 28 at 10:07




1




1





If malloc for a succeded but failed for b and c, wouldn't free(b) and free(c) give error? I know it does not give error for c++ but I am not sure about C compilers.

– Suven Pandey
Mar 28 at 10:10






If malloc for a succeded but failed for b and c, wouldn't free(b) and free(c) give error? I know it does not give error for c++ but I am not sure about C compilers.

– Suven Pandey
Mar 28 at 10:10





1




1





If your malloc implementation sets errno upon error (which may not be the case, it's platform dependent), then your code is safe.

– Jabberwocky
Mar 28 at 10:11






If your malloc implementation sets errno upon error (which may not be the case, it's platform dependent), then your code is safe.

– Jabberwocky
Mar 28 at 10:11





2




2





@suvenpandey If malloc fails, it will also return NULL. Calling freewith a NULL parameter is safe in C.

– Gerhardh
Mar 28 at 10:16





@suvenpandey If malloc fails, it will also return NULL. Calling freewith a NULL parameter is safe in C.

– Gerhardh
Mar 28 at 10:16




1




1





@user3629249 I can answer that last question myself, I realise: check for fp == NULL, then check the value of errno to see what the actual error is.

– 0 0
Mar 28 at 21:05





@user3629249 I can answer that last question myself, I realise: check for fp == NULL, then check the value of errno to see what the actual error is.

– 0 0
Mar 28 at 21:05












2 Answers
2






active

oldest

votes


















1

















Instead, could one set errno = 0 at the top of the series of malloc calls, and then test for errno == ENOMEM at the end?




Yes you could as long as your implementation of malloc is documented to set errno to ENOMEM. The specification in the C11 standard (§ 7.22.3.4) only mentions that the pointer returned will be NULL, not that errno will be set, so your code is technically not portable.



The default implementation of malloc in macOS, Windows and in Linux does set errno so that's most of the computers in the World covered. However, if true portability is required, at the end just write



if (a == NULL || b == NULL || c == NULL)

// Handle the failure



Addendum: There's no need to reset errno back to zero after the mallocs.






share|improve this answer



























  • Just for completeness, is there a link to the relevant section in the standard, or is that not possible?

    – 0 0
    Mar 28 at 10:31











  • @9769953 here.

    – Alexey Frunze
    Mar 28 at 10:34











  • @9769953 I've added the section number. There's no handy HTML version of the standard available on the Internet without handing over a wodge of cash. I have a PDF of a late draft which I got here and is, to all intents and purposes identical.

    – JeremyP
    Mar 28 at 10:36











  • @AlexeyFrunze and JeremyP: Thanks for the addition/link!

    – 0 0
    Mar 28 at 10:38


















2
















No, you can not safely do this in a portable manner.



Per 7.5 Errors <errno.h>, paragraph 3 of the C standard:




The value of errno in the initial thread is zero at program startup (the initial value of errno in other threads is an indeterminate value), but is never set to zero by any library function. The value of errno may be set to nonzero by a library function call whether or not there is an error, provided the use of errno is not documented in the description of the function in this International Standard.




Since malloc() is not documented to set errno by the C standard, it's free to munge errno on success.






share|improve this answer



























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    2 Answers
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    active

    oldest

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    1

















    Instead, could one set errno = 0 at the top of the series of malloc calls, and then test for errno == ENOMEM at the end?




    Yes you could as long as your implementation of malloc is documented to set errno to ENOMEM. The specification in the C11 standard (§ 7.22.3.4) only mentions that the pointer returned will be NULL, not that errno will be set, so your code is technically not portable.



    The default implementation of malloc in macOS, Windows and in Linux does set errno so that's most of the computers in the World covered. However, if true portability is required, at the end just write



    if (a == NULL || b == NULL || c == NULL)

    // Handle the failure



    Addendum: There's no need to reset errno back to zero after the mallocs.






    share|improve this answer



























    • Just for completeness, is there a link to the relevant section in the standard, or is that not possible?

      – 0 0
      Mar 28 at 10:31











    • @9769953 here.

      – Alexey Frunze
      Mar 28 at 10:34











    • @9769953 I've added the section number. There's no handy HTML version of the standard available on the Internet without handing over a wodge of cash. I have a PDF of a late draft which I got here and is, to all intents and purposes identical.

      – JeremyP
      Mar 28 at 10:36











    • @AlexeyFrunze and JeremyP: Thanks for the addition/link!

      – 0 0
      Mar 28 at 10:38















    1

















    Instead, could one set errno = 0 at the top of the series of malloc calls, and then test for errno == ENOMEM at the end?




    Yes you could as long as your implementation of malloc is documented to set errno to ENOMEM. The specification in the C11 standard (§ 7.22.3.4) only mentions that the pointer returned will be NULL, not that errno will be set, so your code is technically not portable.



    The default implementation of malloc in macOS, Windows and in Linux does set errno so that's most of the computers in the World covered. However, if true portability is required, at the end just write



    if (a == NULL || b == NULL || c == NULL)

    // Handle the failure



    Addendum: There's no need to reset errno back to zero after the mallocs.






    share|improve this answer



























    • Just for completeness, is there a link to the relevant section in the standard, or is that not possible?

      – 0 0
      Mar 28 at 10:31











    • @9769953 here.

      – Alexey Frunze
      Mar 28 at 10:34











    • @9769953 I've added the section number. There's no handy HTML version of the standard available on the Internet without handing over a wodge of cash. I have a PDF of a late draft which I got here and is, to all intents and purposes identical.

      – JeremyP
      Mar 28 at 10:36











    • @AlexeyFrunze and JeremyP: Thanks for the addition/link!

      – 0 0
      Mar 28 at 10:38













    1














    1










    1










    Instead, could one set errno = 0 at the top of the series of malloc calls, and then test for errno == ENOMEM at the end?




    Yes you could as long as your implementation of malloc is documented to set errno to ENOMEM. The specification in the C11 standard (§ 7.22.3.4) only mentions that the pointer returned will be NULL, not that errno will be set, so your code is technically not portable.



    The default implementation of malloc in macOS, Windows and in Linux does set errno so that's most of the computers in the World covered. However, if true portability is required, at the end just write



    if (a == NULL || b == NULL || c == NULL)

    // Handle the failure



    Addendum: There's no need to reset errno back to zero after the mallocs.






    share|improve this answer
















    Instead, could one set errno = 0 at the top of the series of malloc calls, and then test for errno == ENOMEM at the end?




    Yes you could as long as your implementation of malloc is documented to set errno to ENOMEM. The specification in the C11 standard (§ 7.22.3.4) only mentions that the pointer returned will be NULL, not that errno will be set, so your code is technically not portable.



    The default implementation of malloc in macOS, Windows and in Linux does set errno so that's most of the computers in the World covered. However, if true portability is required, at the end just write



    if (a == NULL || b == NULL || c == NULL)

    // Handle the failure



    Addendum: There's no need to reset errno back to zero after the mallocs.







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Mar 28 at 10:34

























    answered Mar 28 at 10:26









    JeremyPJeremyP

    76.2k14 gold badges109 silver badges150 bronze badges




    76.2k14 gold badges109 silver badges150 bronze badges















    • Just for completeness, is there a link to the relevant section in the standard, or is that not possible?

      – 0 0
      Mar 28 at 10:31











    • @9769953 here.

      – Alexey Frunze
      Mar 28 at 10:34











    • @9769953 I've added the section number. There's no handy HTML version of the standard available on the Internet without handing over a wodge of cash. I have a PDF of a late draft which I got here and is, to all intents and purposes identical.

      – JeremyP
      Mar 28 at 10:36











    • @AlexeyFrunze and JeremyP: Thanks for the addition/link!

      – 0 0
      Mar 28 at 10:38

















    • Just for completeness, is there a link to the relevant section in the standard, or is that not possible?

      – 0 0
      Mar 28 at 10:31











    • @9769953 here.

      – Alexey Frunze
      Mar 28 at 10:34











    • @9769953 I've added the section number. There's no handy HTML version of the standard available on the Internet without handing over a wodge of cash. I have a PDF of a late draft which I got here and is, to all intents and purposes identical.

      – JeremyP
      Mar 28 at 10:36











    • @AlexeyFrunze and JeremyP: Thanks for the addition/link!

      – 0 0
      Mar 28 at 10:38
















    Just for completeness, is there a link to the relevant section in the standard, or is that not possible?

    – 0 0
    Mar 28 at 10:31





    Just for completeness, is there a link to the relevant section in the standard, or is that not possible?

    – 0 0
    Mar 28 at 10:31













    @9769953 here.

    – Alexey Frunze
    Mar 28 at 10:34





    @9769953 here.

    – Alexey Frunze
    Mar 28 at 10:34













    @9769953 I've added the section number. There's no handy HTML version of the standard available on the Internet without handing over a wodge of cash. I have a PDF of a late draft which I got here and is, to all intents and purposes identical.

    – JeremyP
    Mar 28 at 10:36





    @9769953 I've added the section number. There's no handy HTML version of the standard available on the Internet without handing over a wodge of cash. I have a PDF of a late draft which I got here and is, to all intents and purposes identical.

    – JeremyP
    Mar 28 at 10:36













    @AlexeyFrunze and JeremyP: Thanks for the addition/link!

    – 0 0
    Mar 28 at 10:38





    @AlexeyFrunze and JeremyP: Thanks for the addition/link!

    – 0 0
    Mar 28 at 10:38













    2
















    No, you can not safely do this in a portable manner.



    Per 7.5 Errors <errno.h>, paragraph 3 of the C standard:




    The value of errno in the initial thread is zero at program startup (the initial value of errno in other threads is an indeterminate value), but is never set to zero by any library function. The value of errno may be set to nonzero by a library function call whether or not there is an error, provided the use of errno is not documented in the description of the function in this International Standard.




    Since malloc() is not documented to set errno by the C standard, it's free to munge errno on success.






    share|improve this answer





























      2
















      No, you can not safely do this in a portable manner.



      Per 7.5 Errors <errno.h>, paragraph 3 of the C standard:




      The value of errno in the initial thread is zero at program startup (the initial value of errno in other threads is an indeterminate value), but is never set to zero by any library function. The value of errno may be set to nonzero by a library function call whether or not there is an error, provided the use of errno is not documented in the description of the function in this International Standard.




      Since malloc() is not documented to set errno by the C standard, it's free to munge errno on success.






      share|improve this answer



























        2














        2










        2









        No, you can not safely do this in a portable manner.



        Per 7.5 Errors <errno.h>, paragraph 3 of the C standard:




        The value of errno in the initial thread is zero at program startup (the initial value of errno in other threads is an indeterminate value), but is never set to zero by any library function. The value of errno may be set to nonzero by a library function call whether or not there is an error, provided the use of errno is not documented in the description of the function in this International Standard.




        Since malloc() is not documented to set errno by the C standard, it's free to munge errno on success.






        share|improve this answer













        No, you can not safely do this in a portable manner.



        Per 7.5 Errors <errno.h>, paragraph 3 of the C standard:




        The value of errno in the initial thread is zero at program startup (the initial value of errno in other threads is an indeterminate value), but is never set to zero by any library function. The value of errno may be set to nonzero by a library function call whether or not there is an error, provided the use of errno is not documented in the description of the function in this International Standard.




        Since malloc() is not documented to set errno by the C standard, it's free to munge errno on success.







        share|improve this answer












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        answered Mar 28 at 12:42









        Andrew HenleAndrew Henle

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