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0

I'd like to write a function in pure Javascript, the function should compare 2 objects and detect differences. The objects can contain arrays and objects inside arrays.

Specifically, given the 3 objects shown in the code below:

• If I compare firstObject and secondObject, my function should detect that b.b[1].b is "k" instead of "b"


• If I compare firstObject and thirdObject, my function should detect that b.a doesn't exist


• The order of keys in "object2" should not matter, however, in arrays, it does (In arrays, the order of values inside the arrays should be the same as in "object1")

What I'm trying:

//Recursive function
function compare1(object1, object2) 
 Object.keys(object1).forEach(function (k) 
 if (typeof object1 !== 'object') 
 if (object1[k] != object2[k])
 console.log('Different value found, expected ' + object1[k] + ", found " + object2[k])
 
 else 
 compare1(object1[k], object2[k]);
 
 );
 

 const firstObject = 
 a: 1,
 b: 
 a: 1,
 b: [4, a: "a", b: "b" , 2],
 c: 2
 ,
 c: 2,
 d: 3
 ;

 const secondObject = 
 a: 1,
 b: 
 a: 1,
 b: [4, a: "a", b: "n" , 2],
 c: 2
 ,
 c: 2,
 d: 3
 ;

 const thirdObject = 
 a: 1,
 b: 

 b: [4, a: "a", b: "b" , 2],
 c: 2
 ,
 c: 2,
 d: 3
 ;

 compare1(firstObject, secondObject);

This code prints:

Different value found, expected b, found n

Which is the expected behavior, however, there are 2 things I can't seem to figure out

1. 
   

   In the console log shown above, I would like to also show the position of the differing key: so the log should instead be:

   
   
   

   
   

   Different value found, expected b, found n at b.b[1].b

   
   

   
   


2. 
   

   The existence of the key should be checked before checking for equality, so that, if I run:

   
   
   

   
   

   compare1(firstObject, thirdObject);

   
   

   
   
   

   The console should log:

   
   
   

   
   

   Key not found at b.a

   
   

   
   

I know that there are JS libraries that make deep comparison of objects, however, I'd like to do this in pure Javascript

javascript-objects object-comparison

share|improve this question

asked Mar 21 at 14:30

TomTom

265

add a comment | 

0

I'd like to write a function in pure Javascript, the function should compare 2 objects and detect differences. The objects can contain arrays and objects inside arrays.

Specifically, given the 3 objects shown in the code below:

• If I compare firstObject and secondObject, my function should detect that b.b[1].b is "k" instead of "b"


• If I compare firstObject and thirdObject, my function should detect that b.a doesn't exist


• The order of keys in "object2" should not matter, however, in arrays, it does (In arrays, the order of values inside the arrays should be the same as in "object1")

What I'm trying:

//Recursive function
function compare1(object1, object2) 
 Object.keys(object1).forEach(function (k) 
 if (typeof object1 !== 'object') 
 if (object1[k] != object2[k])
 console.log('Different value found, expected ' + object1[k] + ", found " + object2[k])
 
 else 
 compare1(object1[k], object2[k]);
 
 );
 

 const firstObject = 
 a: 1,
 b: 
 a: 1,
 b: [4, a: "a", b: "b" , 2],
 c: 2
 ,
 c: 2,
 d: 3
 ;

 const secondObject = 
 a: 1,
 b: 
 a: 1,
 b: [4, a: "a", b: "n" , 2],
 c: 2
 ,
 c: 2,
 d: 3
 ;

 const thirdObject = 
 a: 1,
 b: 

 b: [4, a: "a", b: "b" , 2],
 c: 2
 ,
 c: 2,
 d: 3
 ;

 compare1(firstObject, secondObject);

This code prints:

Different value found, expected b, found n

Which is the expected behavior, however, there are 2 things I can't seem to figure out

1. 
   

   In the console log shown above, I would like to also show the position of the differing key: so the log should instead be:

   
   
   

   
   

   Different value found, expected b, found n at b.b[1].b

   
   

   
   


2. 
   

   The existence of the key should be checked before checking for equality, so that, if I run:

   
   
   

   
   

   compare1(firstObject, thirdObject);

   
   

   
   
   

   The console should log:

   
   
   

   
   

   Key not found at b.a

   
   

   
   

I know that there are JS libraries that make deep comparison of objects, however, I'd like to do this in pure Javascript

javascript-objects object-comparison

share|improve this question

asked Mar 21 at 14:30

TomTom

265

add a comment | 

I'd like to write a function in pure Javascript, the function should compare 2 objects and detect differences. The objects can contain arrays and objects inside arrays.

Specifically, given the 3 objects shown in the code below:

• If I compare firstObject and secondObject, my function should detect that b.b[1].b is "k" instead of "b"


• If I compare firstObject and thirdObject, my function should detect that b.a doesn't exist


• The order of keys in "object2" should not matter, however, in arrays, it does (In arrays, the order of values inside the arrays should be the same as in "object1")

What I'm trying:

//Recursive function
function compare1(object1, object2) 
 Object.keys(object1).forEach(function (k) 
 if (typeof object1 !== 'object') 
 if (object1[k] != object2[k])
 console.log('Different value found, expected ' + object1[k] + ", found " + object2[k])
 
 else 
 compare1(object1[k], object2[k]);
 
 );
 

 const firstObject = 
 a: 1,
 b: 
 a: 1,
 b: [4, a: "a", b: "b" , 2],
 c: 2
 ,
 c: 2,
 d: 3
 ;

 const secondObject = 
 a: 1,
 b: 
 a: 1,
 b: [4, a: "a", b: "n" , 2],
 c: 2
 ,
 c: 2,
 d: 3
 ;

 const thirdObject = 
 a: 1,
 b: 

 b: [4, a: "a", b: "b" , 2],
 c: 2
 ,
 c: 2,
 d: 3
 ;

 compare1(firstObject, secondObject);

This code prints:

Different value found, expected b, found n

Which is the expected behavior, however, there are 2 things I can't seem to figure out

1. 
   

   In the console log shown above, I would like to also show the position of the differing key: so the log should instead be:

   
   
   

   
   

   Different value found, expected b, found n at b.b[1].b

   
   

   
   


2. 
   

   The existence of the key should be checked before checking for equality, so that, if I run:

   
   
   

   
   

   compare1(firstObject, thirdObject);

   
   

   
   
   

   The console should log:

   
   
   

   
   

   Key not found at b.a

   
   

   
   

I know that there are JS libraries that make deep comparison of objects, however, I'd like to do this in pure Javascript

javascript-objects object-comparison

share|improve this question

asked Mar 21 at 14:30

TomTom

265

//Recursive function
function compare1(object1, object2) 
 Object.keys(object1).forEach(function (k) 
 if (typeof object1 !== 'object') 
 if (object1[k] != object2[k])
 console.log('Different value found, expected ' + object1[k] + ", found " + object2[k])
 
 else 
 compare1(object1[k], object2[k]);
 
 );
 

 const firstObject = 
 a: 1,
 b: 
 a: 1,
 b: [4, a: "a", b: "b" , 2],
 c: 2
 ,
 c: 2,
 d: 3
 ;

 const secondObject = 
 a: 1,
 b: 
 a: 1,
 b: [4, a: "a", b: "n" , 2],
 c: 2
 ,
 c: 2,
 d: 3
 ;

 const thirdObject = 
 a: 1,
 b: 

 b: [4, a: "a", b: "b" , 2],
 c: 2
 ,
 c: 2,
 d: 3
 ;

 compare1(firstObject, secondObject);

share|improve this question

asked Mar 21 at 14:30

TomTom

265

share|improve this question

asked Mar 21 at 14:30

TomTom

265

asked Mar 21 at 14:30

TomTom

265

asked Mar 21 at 14:30

TomTom

265