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Program to find a pair with the given number in array

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-2

#include <stdio.h>

int main() 
 int num[] = 6, 8, 4, -5, 7, 9 ;
 int sum = 0;
 for (int i = 0; i < 6; i++) 
 for (int j = i + 1; j < 6; j++) 
 sum = num[i] + num[j];
 if (sum == 15) 
 printf("%dn%d", num[i], num[j]);
 
 
 
 return 0;

I'm trying to find a pair of numbers in the array with a sum of 15. The expected output is 6 & 9. But I'm getting output as 6, 98, 7. What is wrong?

EDIT: The issue was not giving a new line after the first result. Sorry.

c arrays sum

share|improve this question

edited 2 days ago

chqrlie

61.9k848105

asked Mar 21 at 14:45

CombospiritCombospirit

83117

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  8 + 7 = 15 I don't see the issue here.
  
  – Joel Trauger
  Mar 21 at 14:48
  

  
  
  
  

add a comment | 

-2

#include <stdio.h>

int main() 
 int num[] = 6, 8, 4, -5, 7, 9 ;
 int sum = 0;
 for (int i = 0; i < 6; i++) 
 for (int j = i + 1; j < 6; j++) 
 sum = num[i] + num[j];
 if (sum == 15) 
 printf("%dn%d", num[i], num[j]);
 
 
 
 return 0;

I'm trying to find a pair of numbers in the array with a sum of 15. The expected output is 6 & 9. But I'm getting output as 6, 98, 7. What is wrong?

EDIT: The issue was not giving a new line after the first result. Sorry.

c arrays sum

share|improve this question

edited 2 days ago

chqrlie

61.9k848105

asked Mar 21 at 14:45

CombospiritCombospirit

83117

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  8 + 7 = 15 I don't see the issue here.
  
  – Joel Trauger
  Mar 21 at 14:48
  

  
  
  
  

add a comment | 

#include <stdio.h>

int main() 
 int num[] = 6, 8, 4, -5, 7, 9 ;
 int sum = 0;
 for (int i = 0; i < 6; i++) 
 for (int j = i + 1; j < 6; j++) 
 sum = num[i] + num[j];
 if (sum == 15) 
 printf("%dn%d", num[i], num[j]);
 
 
 
 return 0;

I'm trying to find a pair of numbers in the array with a sum of 15. The expected output is 6 & 9. But I'm getting output as 6, 98, 7. What is wrong?

EDIT: The issue was not giving a new line after the first result. Sorry.

c arrays sum

share|improve this question

edited 2 days ago

chqrlie

61.9k848105

asked Mar 21 at 14:45

CombospiritCombospirit

83117

#include <stdio.h>

int main() 
 int num[] = 6, 8, 4, -5, 7, 9 ;
 int sum = 0;
 for (int i = 0; i < 6; i++) 
 for (int j = i + 1; j < 6; j++) 
 sum = num[i] + num[j];
 if (sum == 15) 
 printf("%dn%d", num[i], num[j]);
 
 
 
 return 0;

share|improve this question

edited 2 days ago

chqrlie

61.9k848105

asked Mar 21 at 14:45

CombospiritCombospirit

83117

share|improve this question

edited 2 days ago

chqrlie

61.9k848105

asked Mar 21 at 14:45

CombospiritCombospirit

83117

edited 2 days ago

chqrlie

61.9k848105

edited 2 days ago

chqrlie

61.9k848105

asked Mar 21 at 14:45

CombospiritCombospirit

83117

asked Mar 21 at 14:45

CombospiritCombospirit

83117

2 Answers
2

active

oldest

votes

3

The issue was not giving a new line after the first result.

replace

printf("%dn%d",num[i],num[j]);

by

printf("%d,%dn",num[i],num[j]);

share|improve this answer

answered Mar 21 at 14:51

brunobruno

11.6k31326

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Yeah,got that.Stupid mistake from my side.
  
  – Combospirit
  Mar 21 at 14:52
  

  
  
  
  

add a comment | 

0

i find nothing wrong here 9+6=15 and 8+7=15
and also in printf instead of

printf("%dn%d",num[i],num[j]);

use

printf("%d %dn",num[i],num[j]);

you will get well suited output

share|improve this answer

edited Mar 21 at 15:15

answered Mar 21 at 14:58

Anand YeoleAnand Yeole

11

add a comment | 

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3

The issue was not giving a new line after the first result.

replace

printf("%dn%d",num[i],num[j]);

by

printf("%d,%dn",num[i],num[j]);

share|improve this answer

answered Mar 21 at 14:51

brunobruno

11.6k31326

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Yeah,got that.Stupid mistake from my side.
  
  – Combospirit
  Mar 21 at 14:52
  

  
  
  
  

add a comment | 

3

The issue was not giving a new line after the first result.

replace

printf("%dn%d",num[i],num[j]);

by

printf("%d,%dn",num[i],num[j]);

share|improve this answer

answered Mar 21 at 14:51

brunobruno

11.6k31326

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Yeah,got that.Stupid mistake from my side.
  
  – Combospirit
  Mar 21 at 14:52
  

  
  
  
  

add a comment | 

The issue was not giving a new line after the first result.

replace

printf("%dn%d",num[i],num[j]);

by

printf("%d,%dn",num[i],num[j]);

share|improve this answer

answered Mar 21 at 14:51

brunobruno

11.6k31326

printf("%d,%dn",num[i],num[j]);

share|improve this answer

answered Mar 21 at 14:51

brunobruno

11.6k31326

answered Mar 21 at 14:51

brunobruno

11.6k31326

answered Mar 21 at 14:51

brunobruno

11.6k31326

0

i find nothing wrong here 9+6=15 and 8+7=15
and also in printf instead of

printf("%dn%d",num[i],num[j]);

use

printf("%d %dn",num[i],num[j]);

you will get well suited output

share|improve this answer

edited Mar 21 at 15:15

answered Mar 21 at 14:58

Anand YeoleAnand Yeole

11

add a comment | 

0

i find nothing wrong here 9+6=15 and 8+7=15
and also in printf instead of

printf("%dn%d",num[i],num[j]);

use

printf("%d %dn",num[i],num[j]);

you will get well suited output

share|improve this answer

edited Mar 21 at 15:15

answered Mar 21 at 14:58

Anand YeoleAnand Yeole

11

add a comment | 

i find nothing wrong here 9+6=15 and 8+7=15
and also in printf instead of

printf("%dn%d",num[i],num[j]);

use

printf("%d %dn",num[i],num[j]);

you will get well suited output

share|improve this answer

edited Mar 21 at 15:15

answered Mar 21 at 14:58

Anand YeoleAnand Yeole

11

share|improve this answer

edited Mar 21 at 15:15

answered Mar 21 at 14:58

Anand YeoleAnand Yeole

11

answered Mar 21 at 14:58

Anand YeoleAnand Yeole

11

answered Mar 21 at 14:58

Anand YeoleAnand Yeole

11