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get all text between bracket but skip nested bracket

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2

Im trying to figure out how to get the text between two bracket tags but dont stop at the first closing )

__('This is a (TEST) all of this i want') i dont want any of this;

my current pattern is __((.*?))

which gives me

__('This is a (TEST) 

but i want

__('This is a (TEST) all of this i want') 

Thanks

php regex regex-negation

share|improve this question

edited Mar 21 at 14:49

Wiktor Stribiżew

325k16146226

asked Mar 21 at 14:45

Winners2113Winners2113

132

New contributor

Winners2113 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

2

Im trying to figure out how to get the text between two bracket tags but dont stop at the first closing )

__('This is a (TEST) all of this i want') i dont want any of this;

my current pattern is __((.*?))

which gives me

__('This is a (TEST) 

but i want

__('This is a (TEST) all of this i want') 

Thanks

php regex regex-negation

share|improve this question

edited Mar 21 at 14:49

Wiktor Stribiżew

325k16146226

asked Mar 21 at 14:45

Winners2113Winners2113

132

New contributor

Winners2113 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

Im trying to figure out how to get the text between two bracket tags but dont stop at the first closing )

__('This is a (TEST) all of this i want') i dont want any of this;

my current pattern is __((.*?))

which gives me

__('This is a (TEST) 

but i want

__('This is a (TEST) all of this i want') 

Thanks

php regex regex-negation

share|improve this question

edited Mar 21 at 14:49

Wiktor Stribiżew

325k16146226

asked Mar 21 at 14:45

Winners2113Winners2113

132

New contributor

Winners2113 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

__('This is a (TEST) all of this i want') i dont want any of this;

__('This is a (TEST) 

__('This is a (TEST) all of this i want') 

share|improve this question

edited Mar 21 at 14:49

Wiktor Stribiżew

325k16146226

asked Mar 21 at 14:45

Winners2113Winners2113

132

New contributor

Winners2113 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

edited Mar 21 at 14:49

Wiktor Stribiżew

325k16146226

asked Mar 21 at 14:45

Winners2113Winners2113

132

New contributor

Winners2113 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

edited Mar 21 at 14:49

Wiktor Stribiżew

325k16146226

edited Mar 21 at 14:49

Wiktor Stribiżew

325k16146226

asked Mar 21 at 14:45

Winners2113Winners2113

132

New contributor

Winners2113 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked Mar 21 at 14:45

Winners2113Winners2113

132

3 Answers
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0

You forgot to escape two parenthesis in your regex : __((.*));

Check on regex101.com.

share|improve this answer

answered Mar 21 at 14:48

iArcadiaiArcadia

1,082619

add a comment | 

1

You may use a regex subroutine to match text inside nested parentheses after __:

if (preg_match_all('~__((((?:[^()]++|(?1))*)))~', $s, $matches)) 
 print_r($matches[2]);

See the regex demo.

Details

• 
  __ - a __ substring


• 
  ((((?:[^()]++|(?1))*))) - Group 1 (it will be recursed using the (?1) subroutine):
  
  
  • 
    ( - a ( char
  
  
  • 
    ((?:[^()]++|(?1))*) - Group 2 capturing 0 or more repetitions of any 1+ chars other than ( and ) or the whole Group 1 pattern is recursed
  
  
  • 
    ) - a ) char.
  
  

See the PHP demo:

$s = "__('This is a (TEST) all of this i want') i dont want any of this; __(extract this)";
if (preg_match_all('~__((((?:[^()]++|(?1))*)))~', $s, $matches)) 
 print_r($matches[2]);

// => Array ( [0] => 'This is a (TEST) all of this i want' [1] => extract this )

share|improve this answer

answered Mar 21 at 14:53

Wiktor StribiżewWiktor Stribiżew

325k16146226

add a comment | 

0

Use the pattern __((.*)?).

The escapes the parentheses to catch literal parentheses. This then captures all the text inside that set of parentheses.

share|improve this answer

answered Mar 21 at 14:49

k97513k97513

1,450616

add a comment | 

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0

You forgot to escape two parenthesis in your regex : __((.*));

Check on regex101.com.

share|improve this answer

answered Mar 21 at 14:48

iArcadiaiArcadia

1,082619

add a comment | 

0

You forgot to escape two parenthesis in your regex : __((.*));

Check on regex101.com.

share|improve this answer

answered Mar 21 at 14:48

iArcadiaiArcadia

1,082619

add a comment | 

You forgot to escape two parenthesis in your regex : __((.*));

Check on regex101.com.

share|improve this answer

answered Mar 21 at 14:48

iArcadiaiArcadia

1,082619

share|improve this answer

answered Mar 21 at 14:48

iArcadiaiArcadia

1,082619

answered Mar 21 at 14:48

iArcadiaiArcadia

1,082619

answered Mar 21 at 14:48

iArcadiaiArcadia

1,082619

1

You may use a regex subroutine to match text inside nested parentheses after __:

if (preg_match_all('~__((((?:[^()]++|(?1))*)))~', $s, $matches)) 
 print_r($matches[2]);

See the regex demo.

Details

• 
  __ - a __ substring


• 
  ((((?:[^()]++|(?1))*))) - Group 1 (it will be recursed using the (?1) subroutine):
  
  
  • 
    ( - a ( char
  
  
  • 
    ((?:[^()]++|(?1))*) - Group 2 capturing 0 or more repetitions of any 1+ chars other than ( and ) or the whole Group 1 pattern is recursed
  
  
  • 
    ) - a ) char.
  
  

See the PHP demo:

$s = "__('This is a (TEST) all of this i want') i dont want any of this; __(extract this)";
if (preg_match_all('~__((((?:[^()]++|(?1))*)))~', $s, $matches)) 
 print_r($matches[2]);

// => Array ( [0] => 'This is a (TEST) all of this i want' [1] => extract this )

share|improve this answer

answered Mar 21 at 14:53

Wiktor StribiżewWiktor Stribiżew

325k16146226

add a comment | 

1

You may use a regex subroutine to match text inside nested parentheses after __:

if (preg_match_all('~__((((?:[^()]++|(?1))*)))~', $s, $matches)) 
 print_r($matches[2]);

See the regex demo.

Details

• 
  __ - a __ substring


• 
  ((((?:[^()]++|(?1))*))) - Group 1 (it will be recursed using the (?1) subroutine):
  
  
  • 
    ( - a ( char
  
  
  • 
    ((?:[^()]++|(?1))*) - Group 2 capturing 0 or more repetitions of any 1+ chars other than ( and ) or the whole Group 1 pattern is recursed
  
  
  • 
    ) - a ) char.
  
  

See the PHP demo:

$s = "__('This is a (TEST) all of this i want') i dont want any of this; __(extract this)";
if (preg_match_all('~__((((?:[^()]++|(?1))*)))~', $s, $matches)) 
 print_r($matches[2]);

// => Array ( [0] => 'This is a (TEST) all of this i want' [1] => extract this )

share|improve this answer

answered Mar 21 at 14:53

Wiktor StribiżewWiktor Stribiżew

325k16146226

add a comment | 

You may use a regex subroutine to match text inside nested parentheses after __:

if (preg_match_all('~__((((?:[^()]++|(?1))*)))~', $s, $matches)) 
 print_r($matches[2]);

See the regex demo.

Details

• 
  __ - a __ substring


• 
  ((((?:[^()]++|(?1))*))) - Group 1 (it will be recursed using the (?1) subroutine):
  
  
  • 
    ( - a ( char
  
  
  • 
    ((?:[^()]++|(?1))*) - Group 2 capturing 0 or more repetitions of any 1+ chars other than ( and ) or the whole Group 1 pattern is recursed
  
  
  • 
    ) - a ) char.
  
  

See the PHP demo:

$s = "__('This is a (TEST) all of this i want') i dont want any of this; __(extract this)";
if (preg_match_all('~__((((?:[^()]++|(?1))*)))~', $s, $matches)) 
 print_r($matches[2]);

// => Array ( [0] => 'This is a (TEST) all of this i want' [1] => extract this )

share|improve this answer

answered Mar 21 at 14:53

Wiktor StribiżewWiktor Stribiżew

325k16146226

if (preg_match_all('~__((((?:[^()]++|(?1))*)))~', $s, $matches)) 
 print_r($matches[2]);

$s = "__('This is a (TEST) all of this i want') i dont want any of this; __(extract this)";
if (preg_match_all('~__((((?:[^()]++|(?1))*)))~', $s, $matches)) 
 print_r($matches[2]);

// => Array ( [0] => 'This is a (TEST) all of this i want' [1] => extract this )

share|improve this answer

answered Mar 21 at 14:53

Wiktor StribiżewWiktor Stribiżew

325k16146226

answered Mar 21 at 14:53

Wiktor StribiżewWiktor Stribiżew

325k16146226

answered Mar 21 at 14:53

Wiktor StribiżewWiktor Stribiżew

325k16146226

0

Use the pattern __((.*)?).

The escapes the parentheses to catch literal parentheses. This then captures all the text inside that set of parentheses.

share|improve this answer

answered Mar 21 at 14:49

k97513k97513

1,450616

add a comment | 

0

Use the pattern __((.*)?).

The escapes the parentheses to catch literal parentheses. This then captures all the text inside that set of parentheses.

share|improve this answer

answered Mar 21 at 14:49

k97513k97513

1,450616

add a comment | 

Use the pattern __((.*)?).

The escapes the parentheses to catch literal parentheses. This then captures all the text inside that set of parentheses.

share|improve this answer

answered Mar 21 at 14:49

k97513k97513

1,450616

share|improve this answer

answered Mar 21 at 14:49

k97513k97513

1,450616

answered Mar 21 at 14:49

k97513k97513

1,450616

answered Mar 21 at 14:49

k97513k97513

1,450616