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Matplotlib Fancy arrow/Patch edge width

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0

The following code will produce a fancy arrow with matplotlib :

import matplotlib.pyplot as plt

xy = [0.2,0.2]
xytext =[0.5,0.5]

plt.figure()
ax = plt.gca()
ax.annotate("", xy=xy, xytext=xytext,arrowprops=dict(arrowstyle="<|-", edgecolor = 'k', facecolor = 'r', shrinkA = 0, shrinkB = 0))

The arrow is red, with black edges. How can I control the width of the black edges ?

python matplotlib

share|improve this question

asked Mar 21 at 14:45

LirisLiris

12513

add a comment | 

0

The following code will produce a fancy arrow with matplotlib :

import matplotlib.pyplot as plt

xy = [0.2,0.2]
xytext =[0.5,0.5]

plt.figure()
ax = plt.gca()
ax.annotate("", xy=xy, xytext=xytext,arrowprops=dict(arrowstyle="<|-", edgecolor = 'k', facecolor = 'r', shrinkA = 0, shrinkB = 0))

The arrow is red, with black edges. How can I control the width of the black edges ?

python matplotlib

share|improve this question

asked Mar 21 at 14:45

LirisLiris

12513

add a comment | 

The following code will produce a fancy arrow with matplotlib :

import matplotlib.pyplot as plt

xy = [0.2,0.2]
xytext =[0.5,0.5]

plt.figure()
ax = plt.gca()
ax.annotate("", xy=xy, xytext=xytext,arrowprops=dict(arrowstyle="<|-", edgecolor = 'k', facecolor = 'r', shrinkA = 0, shrinkB = 0))

The arrow is red, with black edges. How can I control the width of the black edges ?

python matplotlib

share|improve this question

asked Mar 21 at 14:45

LirisLiris

12513

import matplotlib.pyplot as plt

xy = [0.2,0.2]
xytext =[0.5,0.5]

plt.figure()
ax = plt.gca()
ax.annotate("", xy=xy, xytext=xytext,arrowprops=dict(arrowstyle="<|-", edgecolor = 'k', facecolor = 'r', shrinkA = 0, shrinkB = 0))

share|improve this question

asked Mar 21 at 14:45

LirisLiris

12513

share|improve this question

asked Mar 21 at 14:45

LirisLiris

12513

asked Mar 21 at 14:45

LirisLiris

12513

asked Mar 21 at 14:45

LirisLiris

12513

1 Answer
1

active

oldest

votes

0

You can use the linewidth argument. Below is an example

import matplotlib.pyplot as plt

xy = [0.2,0.2]
xytext =[0.5,0.5]

plt.figure()
ax = plt.gca()
ax.annotate("Text", xy=xy, xytext=xytext, arrowprops=dict(arrowstyle="<|-, 
 head_width=2, head_length=2", edgecolor = 'k', facecolor = 'r',
 linewidth=4))

share|improve this answer

edited Mar 21 at 14:54

answered Mar 21 at 14:49

BazingaaBazingaa

14.8k21230

add a comment | 

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0

You can use the linewidth argument. Below is an example

import matplotlib.pyplot as plt

xy = [0.2,0.2]
xytext =[0.5,0.5]

plt.figure()
ax = plt.gca()
ax.annotate("Text", xy=xy, xytext=xytext, arrowprops=dict(arrowstyle="<|-, 
 head_width=2, head_length=2", edgecolor = 'k', facecolor = 'r',
 linewidth=4))

share|improve this answer

edited Mar 21 at 14:54

answered Mar 21 at 14:49

BazingaaBazingaa

14.8k21230

add a comment | 

0

You can use the linewidth argument. Below is an example

import matplotlib.pyplot as plt

xy = [0.2,0.2]
xytext =[0.5,0.5]

plt.figure()
ax = plt.gca()
ax.annotate("Text", xy=xy, xytext=xytext, arrowprops=dict(arrowstyle="<|-, 
 head_width=2, head_length=2", edgecolor = 'k', facecolor = 'r',
 linewidth=4))

share|improve this answer

edited Mar 21 at 14:54

answered Mar 21 at 14:49

BazingaaBazingaa

14.8k21230

add a comment | 

You can use the linewidth argument. Below is an example

import matplotlib.pyplot as plt

xy = [0.2,0.2]
xytext =[0.5,0.5]

plt.figure()
ax = plt.gca()
ax.annotate("Text", xy=xy, xytext=xytext, arrowprops=dict(arrowstyle="<|-, 
 head_width=2, head_length=2", edgecolor = 'k', facecolor = 'r',
 linewidth=4))

share|improve this answer

edited Mar 21 at 14:54

answered Mar 21 at 14:49

BazingaaBazingaa

14.8k21230

import matplotlib.pyplot as plt

xy = [0.2,0.2]
xytext =[0.5,0.5]

plt.figure()
ax = plt.gca()
ax.annotate("Text", xy=xy, xytext=xytext, arrowprops=dict(arrowstyle="<|-, 
 head_width=2, head_length=2", edgecolor = 'k', facecolor = 'r',
 linewidth=4))

share|improve this answer

edited Mar 21 at 14:54

answered Mar 21 at 14:49

BazingaaBazingaa

14.8k21230

answered Mar 21 at 14:49

BazingaaBazingaa

14.8k21230

answered Mar 21 at 14:49

BazingaaBazingaa

14.8k21230