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2

When I attempt to execute my bash script like this:

bin/provision-pulsar-commands -t development -n provisioning

the outputs print:

TENANT =

NAMESPACE =

Here is my script (provision-pulsar-commands):

#!/bin/bash


function display_usage 
 echo "You may override the namespace and tenant for all components for testing, if desired."
 echo "usage: bin/provision-pulsar-commands [-t tenant] [-n namespace]"
 echo " -t Override tenant (e.g. development) for all components"
 echo " -n Override namespace (e.g. provisioning) for all components"
 echo " -h display help"
 exit 1
 

# check whether user had supplied -h or --help . If yes display usage
 if [[ ( $# == "--help") || $# == "-h" ]]
 then
 display_usage
 exit 0
 fi

while getopts tn option
do
case "$option"
in
t) TENANT=$OPTARG;;
n) NAMESPACE=$OPTARG;;
esac
done

echo "TENANT = $TENANT"
echo "NAMESPACE = $NAMESPACE"

Why are my parameter values not getting picked up?
I'm basing my code on these examples:

• https://www.lifewire.com/pass-arguments-to-bash-script-2200571


• https://www.poftut.com/how-to-pass-and-parse-linux-bash-script-arguments-and-parameters/

Clarification: My parameter values are optional. Also, when I pass -h or --help, my display_usage function is not called. It's not clear to me if that's related to the problem or not.

bash shell sh

share|improve this question

edited Mar 22 at 17:33

devinbost

asked Mar 22 at 17:22

devinbostdevinbost

1,8821926

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The test [[ ( $# == "--help") || $# == "-h" ]] will not work -- $# is the number of arguments (e.g. "2"), not the content of any of the arguments. You probably want $1 instead. Also, the parentheses are not needed here.
  
  – Gordon Davisson
  Mar 22 at 17:45
  

  
  
  
  

add a comment | 

2

When I attempt to execute my bash script like this:

bin/provision-pulsar-commands -t development -n provisioning

the outputs print:

TENANT =

NAMESPACE =

Here is my script (provision-pulsar-commands):

#!/bin/bash


function display_usage 
 echo "You may override the namespace and tenant for all components for testing, if desired."
 echo "usage: bin/provision-pulsar-commands [-t tenant] [-n namespace]"
 echo " -t Override tenant (e.g. development) for all components"
 echo " -n Override namespace (e.g. provisioning) for all components"
 echo " -h display help"
 exit 1
 

# check whether user had supplied -h or --help . If yes display usage
 if [[ ( $# == "--help") || $# == "-h" ]]
 then
 display_usage
 exit 0
 fi

while getopts tn option
do
case "$option"
in
t) TENANT=$OPTARG;;
n) NAMESPACE=$OPTARG;;
esac
done

echo "TENANT = $TENANT"
echo "NAMESPACE = $NAMESPACE"

Why are my parameter values not getting picked up?
I'm basing my code on these examples:

• https://www.lifewire.com/pass-arguments-to-bash-script-2200571


• https://www.poftut.com/how-to-pass-and-parse-linux-bash-script-arguments-and-parameters/

Clarification: My parameter values are optional. Also, when I pass -h or --help, my display_usage function is not called. It's not clear to me if that's related to the problem or not.

bash shell sh

share|improve this question

edited Mar 22 at 17:33

devinbost

asked Mar 22 at 17:22

devinbostdevinbost

1,8821926

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The test [[ ( $# == "--help") || $# == "-h" ]] will not work -- $# is the number of arguments (e.g. "2"), not the content of any of the arguments. You probably want $1 instead. Also, the parentheses are not needed here.
  
  – Gordon Davisson
  Mar 22 at 17:45
  

  
  
  
  

add a comment | 

When I attempt to execute my bash script like this:

bin/provision-pulsar-commands -t development -n provisioning

the outputs print:

TENANT =

NAMESPACE =

Here is my script (provision-pulsar-commands):

#!/bin/bash


function display_usage 
 echo "You may override the namespace and tenant for all components for testing, if desired."
 echo "usage: bin/provision-pulsar-commands [-t tenant] [-n namespace]"
 echo " -t Override tenant (e.g. development) for all components"
 echo " -n Override namespace (e.g. provisioning) for all components"
 echo " -h display help"
 exit 1
 

# check whether user had supplied -h or --help . If yes display usage
 if [[ ( $# == "--help") || $# == "-h" ]]
 then
 display_usage
 exit 0
 fi

while getopts tn option
do
case "$option"
in
t) TENANT=$OPTARG;;
n) NAMESPACE=$OPTARG;;
esac
done

echo "TENANT = $TENANT"
echo "NAMESPACE = $NAMESPACE"

Why are my parameter values not getting picked up?
I'm basing my code on these examples:

• https://www.lifewire.com/pass-arguments-to-bash-script-2200571


• https://www.poftut.com/how-to-pass-and-parse-linux-bash-script-arguments-and-parameters/

Clarification: My parameter values are optional. Also, when I pass -h or --help, my display_usage function is not called. It's not clear to me if that's related to the problem or not.

bash shell sh

share|improve this question

edited Mar 22 at 17:33

devinbost

asked Mar 22 at 17:22

devinbostdevinbost

1,8821926

#!/bin/bash


function display_usage 
 echo "You may override the namespace and tenant for all components for testing, if desired."
 echo "usage: bin/provision-pulsar-commands [-t tenant] [-n namespace]"
 echo " -t Override tenant (e.g. development) for all components"
 echo " -n Override namespace (e.g. provisioning) for all components"
 echo " -h display help"
 exit 1
 

# check whether user had supplied -h or --help . If yes display usage
 if [[ ( $# == "--help") || $# == "-h" ]]
 then
 display_usage
 exit 0
 fi

while getopts tn option
do
case "$option"
in
t) TENANT=$OPTARG;;
n) NAMESPACE=$OPTARG;;
esac
done

echo "TENANT = $TENANT"
echo "NAMESPACE = $NAMESPACE"

share|improve this question

edited Mar 22 at 17:33

devinbost

asked Mar 22 at 17:22

devinbostdevinbost

1,8821926

share|improve this question

edited Mar 22 at 17:33

devinbost

asked Mar 22 at 17:22

devinbostdevinbost

1,8821926

asked Mar 22 at 17:22

devinbostdevinbost

1,8821926

asked Mar 22 at 17:22

devinbostdevinbost

1,8821926

2 Answers
2

active

oldest

votes

3

You have to tell getopts that -t and -n take arguments.

while getopts t:n: option; do

Without the colons, -t is recognized as an option, but OPTARG isn't set. The next argument (development) is neither -t nor -n, so terminates the loop.

share|improve this answer

answered Mar 22 at 17:30

chepnerchepner

265k36255346

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Does that approach work for optional parameter values? (I clarified my question.)
  
  – devinbost
  Mar 22 at 17:33
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  getopts does not support options that take optional values. For example, -t either allows no argument, or it requires a single argument.
  
  – chepner
  Mar 22 at 17:35
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  $# is the number of arguments; it is not a particular argument in $@. You need to add h to your optstring and treat it like any other option.
  
  – chepner
  Mar 22 at 17:35
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks for the help! Based on your comment about getopts, it appears that the article I was following (lifewire.com/pass-arguments-to-bash-script-2200571) was incorrect about how to handle optional parameters.
  
  – devinbost
  Mar 22 at 17:37
  

  
  
  
  

add a comment | 

0

Add : to options that take arguments.

getopts t:n: option

share|improve this answer

answered Mar 22 at 17:29

John KugelmanJohn Kugelman

250k54407461

add a comment | 

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3

You have to tell getopts that -t and -n take arguments.

while getopts t:n: option; do

Without the colons, -t is recognized as an option, but OPTARG isn't set. The next argument (development) is neither -t nor -n, so terminates the loop.

share|improve this answer

answered Mar 22 at 17:30

chepnerchepner

265k36255346

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Does that approach work for optional parameter values? (I clarified my question.)
  
  – devinbost
  Mar 22 at 17:33
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  getopts does not support options that take optional values. For example, -t either allows no argument, or it requires a single argument.
  
  – chepner
  Mar 22 at 17:35
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  $# is the number of arguments; it is not a particular argument in $@. You need to add h to your optstring and treat it like any other option.
  
  – chepner
  Mar 22 at 17:35
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks for the help! Based on your comment about getopts, it appears that the article I was following (lifewire.com/pass-arguments-to-bash-script-2200571) was incorrect about how to handle optional parameters.
  
  – devinbost
  Mar 22 at 17:37
  

  
  
  
  

add a comment | 

3

You have to tell getopts that -t and -n take arguments.

while getopts t:n: option; do

Without the colons, -t is recognized as an option, but OPTARG isn't set. The next argument (development) is neither -t nor -n, so terminates the loop.

share|improve this answer

answered Mar 22 at 17:30

chepnerchepner

265k36255346

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Does that approach work for optional parameter values? (I clarified my question.)
  
  – devinbost
  Mar 22 at 17:33
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  getopts does not support options that take optional values. For example, -t either allows no argument, or it requires a single argument.
  
  – chepner
  Mar 22 at 17:35
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  $# is the number of arguments; it is not a particular argument in $@. You need to add h to your optstring and treat it like any other option.
  
  – chepner
  Mar 22 at 17:35
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks for the help! Based on your comment about getopts, it appears that the article I was following (lifewire.com/pass-arguments-to-bash-script-2200571) was incorrect about how to handle optional parameters.
  
  – devinbost
  Mar 22 at 17:37
  

  
  
  
  

add a comment | 

You have to tell getopts that -t and -n take arguments.

while getopts t:n: option; do

Without the colons, -t is recognized as an option, but OPTARG isn't set. The next argument (development) is neither -t nor -n, so terminates the loop.

share|improve this answer

answered Mar 22 at 17:30

chepnerchepner

265k36255346

while getopts t:n: option; do

share|improve this answer

answered Mar 22 at 17:30

chepnerchepner

265k36255346

answered Mar 22 at 17:30

chepnerchepner

265k36255346

answered Mar 22 at 17:30

chepnerchepner

265k36255346

0

Add : to options that take arguments.

getopts t:n: option

share|improve this answer

answered Mar 22 at 17:29

John KugelmanJohn Kugelman

250k54407461

add a comment | 

0

Add : to options that take arguments.

getopts t:n: option

share|improve this answer

answered Mar 22 at 17:29

John KugelmanJohn Kugelman

250k54407461

add a comment | 

Add : to options that take arguments.

getopts t:n: option

share|improve this answer

answered Mar 22 at 17:29

John KugelmanJohn Kugelman

250k54407461

getopts t:n: option

share|improve this answer

answered Mar 22 at 17:29

John KugelmanJohn Kugelman

250k54407461

answered Mar 22 at 17:29

John KugelmanJohn Kugelman

250k54407461

answered Mar 22 at 17:29

John KugelmanJohn Kugelman

250k54407461