boxplot time series by monthly average in rR adding infrequent date 'events' to a time series plotCreate Regular time series from an irregular (as.Date) time series with frequency=23Feeding an hourly zoo time-series into function stl()Insert rows for missing dates/timesHow to create a monthly time series with missing years?Analysing time series with seasonal effects at multiple frequenciesAverage values from a column on an hourly timeseriesConvert from annual to quarterly data, constrained to annual averagecreate a daily time series data from stock market value taking five days in a weekCreating a ts time series with missing values from a data frame

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boxplot time series by monthly average in r


R adding infrequent date 'events' to a time series plotCreate Regular time series from an irregular (as.Date) time series with frequency=23Feeding an hourly zoo time-series into function stl()Insert rows for missing dates/timesHow to create a monthly time series with missing years?Analysing time series with seasonal effects at multiple frequenciesAverage values from a column on an hourly timeseriesConvert from annual to quarterly data, constrained to annual averagecreate a daily time series data from stock market value taking five days in a weekCreating a ts time series with missing values from a data frame






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0















I have a time series with hourly data on energy consumption in the form of a zoo object. And there are 16 indices (in the range [1:143206]) for which the Date is NA. Here is a sample of the data:



 Date PJMW_MW
1 2002-04-01 01:00:00 4374
...
8709 2003-03-29 23:00:00 4827
8710 2003-03-30 00:00:00 4611
8711 2003-03-30 01:00:00 4421
8712 NA 4285
8713 2003-03-30 03:00:00 4212
8714 2003-03-30 04:00:00 4321
...
143206 2018-08-03 00:00:005489


The data above is a data.frame object called dat but I have it in a zoo object called hourly_ts:



1 4374
...
7709 6135
7710 6324
7711 6626
7712 6866
7713 6987
7714 7028
7715 7026
...
143206 5265


I would like to see the monthly averages, like, for which month is the consumption generally higher, and I saw that there is a simple formula for this: boxplot(hourly_ts ~ cycle(hourly_ts))



But the error Error in cycle.zoo(hourly_ts) : ‘x’is not regular appears.



The weird thing is that hourly_ts has a specified frequency (24 hours per day) and start time (April 1st 2002 01:00:00), so from that there shouldn't be any missing values in the time.



Supposing the missing values are what's causing the irregularity, is there a way I can add the values myself?



I would also like to use the aggregate function but have no idea what the by parameter should be.










share|improve this question
























  • could you provide a minimal data sample so the error could be reproduced?

    – Oka
    Mar 26 at 14:45











  • 6 rows is too minimal?

    – John Cataldo
    Mar 26 at 17:00











  • do you get the same mistake with 6 rows?

    – Oka
    Mar 26 at 17:05

















0















I have a time series with hourly data on energy consumption in the form of a zoo object. And there are 16 indices (in the range [1:143206]) for which the Date is NA. Here is a sample of the data:



 Date PJMW_MW
1 2002-04-01 01:00:00 4374
...
8709 2003-03-29 23:00:00 4827
8710 2003-03-30 00:00:00 4611
8711 2003-03-30 01:00:00 4421
8712 NA 4285
8713 2003-03-30 03:00:00 4212
8714 2003-03-30 04:00:00 4321
...
143206 2018-08-03 00:00:005489


The data above is a data.frame object called dat but I have it in a zoo object called hourly_ts:



1 4374
...
7709 6135
7710 6324
7711 6626
7712 6866
7713 6987
7714 7028
7715 7026
...
143206 5265


I would like to see the monthly averages, like, for which month is the consumption generally higher, and I saw that there is a simple formula for this: boxplot(hourly_ts ~ cycle(hourly_ts))



But the error Error in cycle.zoo(hourly_ts) : ‘x’is not regular appears.



The weird thing is that hourly_ts has a specified frequency (24 hours per day) and start time (April 1st 2002 01:00:00), so from that there shouldn't be any missing values in the time.



Supposing the missing values are what's causing the irregularity, is there a way I can add the values myself?



I would also like to use the aggregate function but have no idea what the by parameter should be.










share|improve this question
























  • could you provide a minimal data sample so the error could be reproduced?

    – Oka
    Mar 26 at 14:45











  • 6 rows is too minimal?

    – John Cataldo
    Mar 26 at 17:00











  • do you get the same mistake with 6 rows?

    – Oka
    Mar 26 at 17:05













0












0








0








I have a time series with hourly data on energy consumption in the form of a zoo object. And there are 16 indices (in the range [1:143206]) for which the Date is NA. Here is a sample of the data:



 Date PJMW_MW
1 2002-04-01 01:00:00 4374
...
8709 2003-03-29 23:00:00 4827
8710 2003-03-30 00:00:00 4611
8711 2003-03-30 01:00:00 4421
8712 NA 4285
8713 2003-03-30 03:00:00 4212
8714 2003-03-30 04:00:00 4321
...
143206 2018-08-03 00:00:005489


The data above is a data.frame object called dat but I have it in a zoo object called hourly_ts:



1 4374
...
7709 6135
7710 6324
7711 6626
7712 6866
7713 6987
7714 7028
7715 7026
...
143206 5265


I would like to see the monthly averages, like, for which month is the consumption generally higher, and I saw that there is a simple formula for this: boxplot(hourly_ts ~ cycle(hourly_ts))



But the error Error in cycle.zoo(hourly_ts) : ‘x’is not regular appears.



The weird thing is that hourly_ts has a specified frequency (24 hours per day) and start time (April 1st 2002 01:00:00), so from that there shouldn't be any missing values in the time.



Supposing the missing values are what's causing the irregularity, is there a way I can add the values myself?



I would also like to use the aggregate function but have no idea what the by parameter should be.










share|improve this question
















I have a time series with hourly data on energy consumption in the form of a zoo object. And there are 16 indices (in the range [1:143206]) for which the Date is NA. Here is a sample of the data:



 Date PJMW_MW
1 2002-04-01 01:00:00 4374
...
8709 2003-03-29 23:00:00 4827
8710 2003-03-30 00:00:00 4611
8711 2003-03-30 01:00:00 4421
8712 NA 4285
8713 2003-03-30 03:00:00 4212
8714 2003-03-30 04:00:00 4321
...
143206 2018-08-03 00:00:005489


The data above is a data.frame object called dat but I have it in a zoo object called hourly_ts:



1 4374
...
7709 6135
7710 6324
7711 6626
7712 6866
7713 6987
7714 7028
7715 7026
...
143206 5265


I would like to see the monthly averages, like, for which month is the consumption generally higher, and I saw that there is a simple formula for this: boxplot(hourly_ts ~ cycle(hourly_ts))



But the error Error in cycle.zoo(hourly_ts) : ‘x’is not regular appears.



The weird thing is that hourly_ts has a specified frequency (24 hours per day) and start time (April 1st 2002 01:00:00), so from that there shouldn't be any missing values in the time.



Supposing the missing values are what's causing the irregularity, is there a way I can add the values myself?



I would also like to use the aggregate function but have no idea what the by parameter should be.







r time-series






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 22 at 17:36







John Cataldo

















asked Mar 22 at 17:30









John CataldoJohn Cataldo

1055




1055












  • could you provide a minimal data sample so the error could be reproduced?

    – Oka
    Mar 26 at 14:45











  • 6 rows is too minimal?

    – John Cataldo
    Mar 26 at 17:00











  • do you get the same mistake with 6 rows?

    – Oka
    Mar 26 at 17:05

















  • could you provide a minimal data sample so the error could be reproduced?

    – Oka
    Mar 26 at 14:45











  • 6 rows is too minimal?

    – John Cataldo
    Mar 26 at 17:00











  • do you get the same mistake with 6 rows?

    – Oka
    Mar 26 at 17:05
















could you provide a minimal data sample so the error could be reproduced?

– Oka
Mar 26 at 14:45





could you provide a minimal data sample so the error could be reproduced?

– Oka
Mar 26 at 14:45













6 rows is too minimal?

– John Cataldo
Mar 26 at 17:00





6 rows is too minimal?

– John Cataldo
Mar 26 at 17:00













do you get the same mistake with 6 rows?

– Oka
Mar 26 at 17:05





do you get the same mistake with 6 rows?

– Oka
Mar 26 at 17:05












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