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Regular Expression to Validate if it is not a Decimal or Integer Number
How to validate an email address in JavaScript?A comprehensive regex for phone number validationWhat is the best regular expression to check if a string is a valid URL?Is there a regular expression to detect a valid regular expression?How to validate an email address using a regular expression?What are the correct version numbers for C#?Regular expression to match a line that doesn't contain a wordHow do you access the matched groups in a JavaScript regular expression?Regular Expressions: Is there an AND operator?How do you use a variable in a regular expression?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
I am trying to find a regular expression to find out the number which is not entered as proper decimal or integer number in a input box
Examples
- 1.. - Catch // consecutive Repeating dots
- ABC - Catch // All Alphabets
- 1.1.1- Catch // dots repeating in a number
- !,@,#- Catch // All Special Characters
My current below allow me to catch all examples except example -3 where decimal dots can be repeated in any combination.
void T1_HTextChanged(object sender, EventArgs e)
[.]2"))
MessageBox.Show("Please enter only numbers.");
T1_H.Text="";
c# regex
edited Mar 24 at 8:48
James Z
11.2k72037
asked Mar 24 at 5:59
Srinath SriSrinath Sri
1
add a comment |
I am trying to find a regular expression to find out the number which is not entered as proper decimal or integer number in a input box
Examples
- 1.. - Catch // consecutive Repeating dots
- ABC - Catch // All Alphabets
- 1.1.1- Catch // dots repeating in a number
- !,@,#- Catch // All Special Characters
My current below allow me to catch all examples except example -3 where decimal dots can be repeated in any combination.
void T1_HTextChanged(object sender, EventArgs e)
[.]2"))
MessageBox.Show("Please enter only numbers.");
T1_H.Text="";
c# regex
edited Mar 24 at 8:48
James Z
11.2k72037
asked Mar 24 at 5:59
Srinath SriSrinath Sri
1
you could, instead, use try Convert.ToInt32(input);catch(Exception)// not int. If yiu really want to valid using regex, then try: -?[0-9]+(.[0.9]+)? to check is the input is a number.
– Vinícius Gabriel
Mar 24 at 6:07
P.S.: You can negate the regex to check if the input is not a number... obviously
– Vinícius Gabriel
Mar 24 at 6:09
Try this regex:^[0-9]+([.][0-9]1,2)?$. Working example: regex101.com/r/iRaRPX/1. It will check for all integers and decimal numbers upto two decimal points. You can change that according to your req.
– Rahul Sharma
Mar 24 at 6:12
4
int.TryParseanddecimal.TryParseare better options than regex.
– Chetan Ranpariya
Mar 24 at 6:14
Also you can use NumericUpDown instead of TextBox.
– Alexander Petrov
Mar 24 at 9:33
add a comment |
I am trying to find a regular expression to find out the number which is not entered as proper decimal or integer number in a input box
Examples
- 1.. - Catch // consecutive Repeating dots
- ABC - Catch // All Alphabets
- 1.1.1- Catch // dots repeating in a number
- !,@,#- Catch // All Special Characters
My current below allow me to catch all examples except example -3 where decimal dots can be repeated in any combination.
void T1_HTextChanged(object sender, EventArgs e)
[.]2"))
MessageBox.Show("Please enter only numbers.");
T1_H.Text="";
c# regex
edited Mar 24 at 8:48
James Z
11.2k72037
asked Mar 24 at 5:59
Srinath SriSrinath Sri
1
I am trying to find a regular expression to find out the number which is not entered as proper decimal or integer number in a input box
Examples
- 1.. - Catch // consecutive Repeating dots
- ABC - Catch // All Alphabets
- 1.1.1- Catch // dots repeating in a number
- !,@,#- Catch // All Special Characters
My current below allow me to catch all examples except example -3 where decimal dots can be repeated in any combination.
void T1_HTextChanged(object sender, EventArgs e)
[.]2"))
MessageBox.Show("Please enter only numbers.");
T1_H.Text="";
c# regex
c# regex
edited Mar 24 at 8:48
James Z
11.2k72037
asked Mar 24 at 5:59
Srinath SriSrinath Sri
1
edited Mar 24 at 8:48
James Z
11.2k72037
asked Mar 24 at 5:59
Srinath SriSrinath Sri
1
edited Mar 24 at 8:48
James Z
11.2k72037
edited Mar 24 at 8:48
James Z
11.2k72037
edited Mar 24 at 8:48
James Z
11.2k72037
11.2k72037
asked Mar 24 at 5:59
Srinath SriSrinath Sri
1
asked Mar 24 at 5:59
Srinath SriSrinath Sri
1
asked Mar 24 at 5:59
Srinath SriSrinath Sri
1
1
you could, instead, use try Convert.ToInt32(input);catch(Exception)// not int. If yiu really want to valid using regex, then try: -?[0-9]+(.[0.9]+)? to check is the input is a number.
– Vinícius Gabriel
Mar 24 at 6:07
P.S.: You can negate the regex to check if the input is not a number... obviously
– Vinícius Gabriel
Mar 24 at 6:09
Try this regex:^[0-9]+([.][0-9]1,2)?$. Working example: regex101.com/r/iRaRPX/1. It will check for all integers and decimal numbers upto two decimal points. You can change that according to your req.
– Rahul Sharma
Mar 24 at 6:12
4
int.TryParseanddecimal.TryParseare better options than regex.
– Chetan Ranpariya
Mar 24 at 6:14
Also you can use NumericUpDown instead of TextBox.
– Alexander Petrov
Mar 24 at 9:33
add a comment |
you could, instead, use try Convert.ToInt32(input);catch(Exception)// not int. If yiu really want to valid using regex, then try: -?[0-9]+(.[0.9]+)? to check is the input is a number.
– Vinícius Gabriel
Mar 24 at 6:07
P.S.: You can negate the regex to check if the input is not a number... obviously
– Vinícius Gabriel
Mar 24 at 6:09
Try this regex:^[0-9]+([.][0-9]1,2)?$. Working example: regex101.com/r/iRaRPX/1. It will check for all integers and decimal numbers upto two decimal points. You can change that according to your req.
– Rahul Sharma
Mar 24 at 6:12
4
int.TryParseanddecimal.TryParseare better options than regex.
– Chetan Ranpariya
Mar 24 at 6:14
Also you can use NumericUpDown instead of TextBox.
– Alexander Petrov
Mar 24 at 9:33
you could, instead, use try Convert.ToInt32(input);catch(Exception)// not int. If yiu really want to valid using regex, then try: -?[0-9]+(.[0.9]+)? to check is the input is a number.
– Vinícius Gabriel
Mar 24 at 6:07
you could, instead, use try Convert.ToInt32(input);catch(Exception)// not int. If yiu really want to valid using regex, then try: -?[0-9]+(.[0.9]+)? to check is the input is a number.
– Vinícius Gabriel
Mar 24 at 6:07
P.S.: You can negate the regex to check if the input is not a number... obviously
– Vinícius Gabriel
Mar 24 at 6:09
P.S.: You can negate the regex to check if the input is not a number... obviously
– Vinícius Gabriel
Mar 24 at 6:09
Try this regex:
^[0-9]+([.][0-9]1,2)?$. Working example: regex101.com/r/iRaRPX/1. It will check for all integers and decimal numbers upto two decimal points. You can change that according to your req.– Rahul Sharma
Mar 24 at 6:12
Try this regex:
^[0-9]+([.][0-9]1,2)?$. Working example: regex101.com/r/iRaRPX/1. It will check for all integers and decimal numbers upto two decimal points. You can change that according to your req.– Rahul Sharma
Mar 24 at 6:12
4
4
int.TryParse and decimal.TryParse are better options than regex.– Chetan Ranpariya
Mar 24 at 6:14
int.TryParse and decimal.TryParse are better options than regex.– Chetan Ranpariya
Mar 24 at 6:14
Also you can use NumericUpDown instead of TextBox.
– Alexander Petrov
Mar 24 at 9:33
Also you can use NumericUpDown instead of TextBox.
– Alexander Petrov
Mar 24 at 9:33
add a comment |
3 Answers
3
active
oldest
votes
If you really want to use a regexp you can use: ^[0-9]+(.[0-9]+)?$.
You can test it here https://regex101.com/r/UB6eRT/1
If you want to know if it's a valid number you can also try to convert it and check if you get an error.
answered Mar 24 at 6:12
François P.François P.
2,125716
add a comment |
Try this regex:
^[0-9]+([.][0-9]1,2)?$
Explanation:
- ^ asserts position at start of a line
- Match a single character present in the list below [0-9]+
+ Quantifier — Matches between one and unlimited times, as many times as possible,
giving back as needed (greedy)
0-9 a single character in the range between 0 (index 48) and 9 (index 57) (case sensitive)- 1st Capturing Group ([.][0-9]1,2)?
? Quantifier — Matches between zero and one times, as many times as possible, giving back as needed (greedy)- Match a single character present in the list below [.]
. matches the character . literally (case sensitive) - Match a single character present in the list below [0-9]1,2
1,2 Quantifier — Matches between 1 and 2 times, as many times as possible, giving back as needed (greedy) - 0-9 a single character in the range between 0 (index 48) and 9 (index 57) (case sensitive)
- $ asserts position at the end of a line
Working example: https://regex101.com/r/iRaRPX/1/
It will check for all integers and decimal numbers up to two decimal points. You can change that according to your requirement.
answered Mar 24 at 6:18
Rahul SharmaRahul Sharma
8301617
add a comment |
If you want to achieve this with Regular expression, you can use.
^(d*.)?d+$
Demo
But please be aware that you can use Decimal.TryParse as well. You can read more on Decimal.TryParse here
answered Mar 24 at 7:34
Anu ViswanAnu Viswan
6,2272526
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
If you really want to use a regexp you can use: ^[0-9]+(.[0-9]+)?$.
You can test it here https://regex101.com/r/UB6eRT/1
If you want to know if it's a valid number you can also try to convert it and check if you get an error.
answered Mar 24 at 6:12
François P.François P.
2,125716
add a comment |
If you really want to use a regexp you can use: ^[0-9]+(.[0-9]+)?$.
You can test it here https://regex101.com/r/UB6eRT/1
If you want to know if it's a valid number you can also try to convert it and check if you get an error.
answered Mar 24 at 6:12
François P.François P.
2,125716
add a comment |
If you really want to use a regexp you can use: ^[0-9]+(.[0-9]+)?$.
You can test it here https://regex101.com/r/UB6eRT/1
If you want to know if it's a valid number you can also try to convert it and check if you get an error.
answered Mar 24 at 6:12
François P.François P.
2,125716
If you really want to use a regexp you can use: ^[0-9]+(.[0-9]+)?$.
You can test it here https://regex101.com/r/UB6eRT/1
If you want to know if it's a valid number you can also try to convert it and check if you get an error.
answered Mar 24 at 6:12
François P.François P.
2,125716
edited Mar 24 at 6:18
answered Mar 24 at 6:12
François P.François P.
2,125716
answered Mar 24 at 6:12
François P.François P.
2,125716
answered Mar 24 at 6:12
François P.François P.
2,125716
2,125716
add a comment |
add a comment |
Try this regex:
^[0-9]+([.][0-9]1,2)?$
Explanation:
- ^ asserts position at start of a line
- Match a single character present in the list below [0-9]+
+ Quantifier — Matches between one and unlimited times, as many times as possible,
giving back as needed (greedy)
0-9 a single character in the range between 0 (index 48) and 9 (index 57) (case sensitive)- 1st Capturing Group ([.][0-9]1,2)?
? Quantifier — Matches between zero and one times, as many times as possible, giving back as needed (greedy)- Match a single character present in the list below [.]
. matches the character . literally (case sensitive) - Match a single character present in the list below [0-9]1,2
1,2 Quantifier — Matches between 1 and 2 times, as many times as possible, giving back as needed (greedy) - 0-9 a single character in the range between 0 (index 48) and 9 (index 57) (case sensitive)
- $ asserts position at the end of a line
Working example: https://regex101.com/r/iRaRPX/1/
It will check for all integers and decimal numbers up to two decimal points. You can change that according to your requirement.
answered Mar 24 at 6:18
Rahul SharmaRahul Sharma
8301617
add a comment |
Try this regex:
^[0-9]+([.][0-9]1,2)?$
Explanation:
- ^ asserts position at start of a line
- Match a single character present in the list below [0-9]+
+ Quantifier — Matches between one and unlimited times, as many times as possible,
giving back as needed (greedy)
0-9 a single character in the range between 0 (index 48) and 9 (index 57) (case sensitive)- 1st Capturing Group ([.][0-9]1,2)?
? Quantifier — Matches between zero and one times, as many times as possible, giving back as needed (greedy)- Match a single character present in the list below [.]
. matches the character . literally (case sensitive) - Match a single character present in the list below [0-9]1,2
1,2 Quantifier — Matches between 1 and 2 times, as many times as possible, giving back as needed (greedy) - 0-9 a single character in the range between 0 (index 48) and 9 (index 57) (case sensitive)
- $ asserts position at the end of a line
Working example: https://regex101.com/r/iRaRPX/1/
It will check for all integers and decimal numbers up to two decimal points. You can change that according to your requirement.
answered Mar 24 at 6:18
Rahul SharmaRahul Sharma
8301617
add a comment |
Try this regex:
^[0-9]+([.][0-9]1,2)?$
Explanation:
- ^ asserts position at start of a line
- Match a single character present in the list below [0-9]+
+ Quantifier — Matches between one and unlimited times, as many times as possible,
giving back as needed (greedy)
0-9 a single character in the range between 0 (index 48) and 9 (index 57) (case sensitive)- 1st Capturing Group ([.][0-9]1,2)?
? Quantifier — Matches between zero and one times, as many times as possible, giving back as needed (greedy)- Match a single character present in the list below [.]
. matches the character . literally (case sensitive) - Match a single character present in the list below [0-9]1,2
1,2 Quantifier — Matches between 1 and 2 times, as many times as possible, giving back as needed (greedy) - 0-9 a single character in the range between 0 (index 48) and 9 (index 57) (case sensitive)
- $ asserts position at the end of a line
Working example: https://regex101.com/r/iRaRPX/1/
It will check for all integers and decimal numbers up to two decimal points. You can change that according to your requirement.
answered Mar 24 at 6:18
Rahul SharmaRahul Sharma
8301617
Try this regex:
^[0-9]+([.][0-9]1,2)?$
Explanation:
- ^ asserts position at start of a line
- Match a single character present in the list below [0-9]+
+ Quantifier — Matches between one and unlimited times, as many times as possible,
giving back as needed (greedy)
0-9 a single character in the range between 0 (index 48) and 9 (index 57) (case sensitive)- 1st Capturing Group ([.][0-9]1,2)?
? Quantifier — Matches between zero and one times, as many times as possible, giving back as needed (greedy)- Match a single character present in the list below [.]
. matches the character . literally (case sensitive) - Match a single character present in the list below [0-9]1,2
1,2 Quantifier — Matches between 1 and 2 times, as many times as possible, giving back as needed (greedy) - 0-9 a single character in the range between 0 (index 48) and 9 (index 57) (case sensitive)
- $ asserts position at the end of a line
Working example: https://regex101.com/r/iRaRPX/1/
It will check for all integers and decimal numbers up to two decimal points. You can change that according to your requirement.
answered Mar 24 at 6:18
Rahul SharmaRahul Sharma
8301617
edited Mar 24 at 6:57
answered Mar 24 at 6:18
Rahul SharmaRahul Sharma
8301617
answered Mar 24 at 6:18
Rahul SharmaRahul Sharma
8301617
answered Mar 24 at 6:18
Rahul SharmaRahul Sharma
8301617
8301617
add a comment |
add a comment |
If you want to achieve this with Regular expression, you can use.
^(d*.)?d+$
Demo
But please be aware that you can use Decimal.TryParse as well. You can read more on Decimal.TryParse here
answered Mar 24 at 7:34
Anu ViswanAnu Viswan
6,2272526
add a comment |
If you want to achieve this with Regular expression, you can use.
^(d*.)?d+$
Demo
But please be aware that you can use Decimal.TryParse as well. You can read more on Decimal.TryParse here
answered Mar 24 at 7:34
Anu ViswanAnu Viswan
6,2272526
add a comment |
If you want to achieve this with Regular expression, you can use.
^(d*.)?d+$
Demo
But please be aware that you can use Decimal.TryParse as well. You can read more on Decimal.TryParse here
answered Mar 24 at 7:34
Anu ViswanAnu Viswan
6,2272526
If you want to achieve this with Regular expression, you can use.
^(d*.)?d+$
Demo
But please be aware that you can use Decimal.TryParse as well. You can read more on Decimal.TryParse here
answered Mar 24 at 7:34
Anu ViswanAnu Viswan
6,2272526
answered Mar 24 at 7:34
Anu ViswanAnu Viswan
6,2272526
answered Mar 24 at 7:34
Anu ViswanAnu Viswan
6,2272526
answered Mar 24 at 7:34
Anu ViswanAnu Viswan
6,2272526
6,2272526
add a comment |
add a comment |
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you could, instead, use try Convert.ToInt32(input);catch(Exception)// not int. If yiu really want to valid using regex, then try: -?[0-9]+(.[0.9]+)? to check is the input is a number.
– Vinícius Gabriel
Mar 24 at 6:07
P.S.: You can negate the regex to check if the input is not a number... obviously
– Vinícius Gabriel
Mar 24 at 6:09
Try this regex:
^[0-9]+([.][0-9]1,2)?$. Working example: regex101.com/r/iRaRPX/1. It will check for all integers and decimal numbers upto two decimal points. You can change that according to your req.– Rahul Sharma
Mar 24 at 6:12
4
int.TryParseanddecimal.TryParseare better options than regex.– Chetan Ranpariya
Mar 24 at 6:14
Also you can use NumericUpDown instead of TextBox.
– Alexander Petrov
Mar 24 at 9:33