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Check if class is a template specialization


C++ variadic template template argument that matches any kind of parametersCheck if class is a template specialization?c++ auto for type and nontype templatesCheck if two types are of the same templateStoring C++ template function definitions in a .CPP fileWhy can templates only be implemented in the header file?Template specialization with struct and boolC++ specialization of template function inside template classPartial specialization of variadic templatesHow to prevent specialization of std::vector<bool>Replacing a 32-bit loop counter with 64-bit introduces crazy performance deviationsHow to specialize template template parameter for std::vector in C++Define partial specialization for some external template classes with restriction for template parametersHow to specialize for template template arguments






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








8















I want to check if a class is a template specialization of another one. What I have tried is:



template <class T, template <class...> class Template>
struct is_specialization : std::false_type ;

template <template <class...> class Template, class... Args>
struct is_specialization<Template<Args...>, Template> : std::true_type ;


It works fine when all template parameters are type arguments but not when some are non-type arguments. For example it works with std::vector but not std::array (since the later accepts an non-type argument std::size_t).



It's important that the check is made at compile time. Also the solution must work for any template, not just vectors or arrays. That means that it can be any number of type arguments and any number of non-type arguments. For example it should work with template <class A, bool B, class C, int D, class... Args> class foo;










share|improve this question


























  • I'm afraid what you want is not possible: stackoverflow.com/q/25893828/5470596

    – YSC
    Mar 28 at 11:56






  • 1





    Catching both std::vector and std::array can easily be done by adding an auto... pack, but that would still only work if all type parameters comes first, and the non-types comes after. Catching a mixed pattern is AFAIK not possible.

    – super
    Mar 28 at 12:01












  • @YSC That post is old, in C++17 new features such as auto for non-type parameter deduction were introduced, now maybe is possible. I haven't been able to find a way though.

    – user28032019
    Mar 28 at 12:02






  • 1





    I think C++ compilers really really hate mixing types and values (hello most vexing parse) and tries to stay as far away as possible. Or in other words, this is impossible. Or @Quentin manages to abuse the most vexing parse again and wraps everything into one magnificent macro.

    – Passer By
    Mar 28 at 12:58







  • 1





    @PasserBy I'm sorry to disappoint, but the parser went through unscathed this time.

    – Quentin
    Mar 28 at 13:22

















8















I want to check if a class is a template specialization of another one. What I have tried is:



template <class T, template <class...> class Template>
struct is_specialization : std::false_type ;

template <template <class...> class Template, class... Args>
struct is_specialization<Template<Args...>, Template> : std::true_type ;


It works fine when all template parameters are type arguments but not when some are non-type arguments. For example it works with std::vector but not std::array (since the later accepts an non-type argument std::size_t).



It's important that the check is made at compile time. Also the solution must work for any template, not just vectors or arrays. That means that it can be any number of type arguments and any number of non-type arguments. For example it should work with template <class A, bool B, class C, int D, class... Args> class foo;










share|improve this question


























  • I'm afraid what you want is not possible: stackoverflow.com/q/25893828/5470596

    – YSC
    Mar 28 at 11:56






  • 1





    Catching both std::vector and std::array can easily be done by adding an auto... pack, but that would still only work if all type parameters comes first, and the non-types comes after. Catching a mixed pattern is AFAIK not possible.

    – super
    Mar 28 at 12:01












  • @YSC That post is old, in C++17 new features such as auto for non-type parameter deduction were introduced, now maybe is possible. I haven't been able to find a way though.

    – user28032019
    Mar 28 at 12:02






  • 1





    I think C++ compilers really really hate mixing types and values (hello most vexing parse) and tries to stay as far away as possible. Or in other words, this is impossible. Or @Quentin manages to abuse the most vexing parse again and wraps everything into one magnificent macro.

    – Passer By
    Mar 28 at 12:58







  • 1





    @PasserBy I'm sorry to disappoint, but the parser went through unscathed this time.

    – Quentin
    Mar 28 at 13:22













8












8








8


2






I want to check if a class is a template specialization of another one. What I have tried is:



template <class T, template <class...> class Template>
struct is_specialization : std::false_type ;

template <template <class...> class Template, class... Args>
struct is_specialization<Template<Args...>, Template> : std::true_type ;


It works fine when all template parameters are type arguments but not when some are non-type arguments. For example it works with std::vector but not std::array (since the later accepts an non-type argument std::size_t).



It's important that the check is made at compile time. Also the solution must work for any template, not just vectors or arrays. That means that it can be any number of type arguments and any number of non-type arguments. For example it should work with template <class A, bool B, class C, int D, class... Args> class foo;










share|improve this question
















I want to check if a class is a template specialization of another one. What I have tried is:



template <class T, template <class...> class Template>
struct is_specialization : std::false_type ;

template <template <class...> class Template, class... Args>
struct is_specialization<Template<Args...>, Template> : std::true_type ;


It works fine when all template parameters are type arguments but not when some are non-type arguments. For example it works with std::vector but not std::array (since the later accepts an non-type argument std::size_t).



It's important that the check is made at compile time. Also the solution must work for any template, not just vectors or arrays. That means that it can be any number of type arguments and any number of non-type arguments. For example it should work with template <class A, bool B, class C, int D, class... Args> class foo;







c++






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 28 at 11:48









YSC

28k6 gold badges60 silver badges115 bronze badges




28k6 gold badges60 silver badges115 bronze badges










asked Mar 28 at 11:44









user28032019user28032019

555 bronze badges




555 bronze badges















  • I'm afraid what you want is not possible: stackoverflow.com/q/25893828/5470596

    – YSC
    Mar 28 at 11:56






  • 1





    Catching both std::vector and std::array can easily be done by adding an auto... pack, but that would still only work if all type parameters comes first, and the non-types comes after. Catching a mixed pattern is AFAIK not possible.

    – super
    Mar 28 at 12:01












  • @YSC That post is old, in C++17 new features such as auto for non-type parameter deduction were introduced, now maybe is possible. I haven't been able to find a way though.

    – user28032019
    Mar 28 at 12:02






  • 1





    I think C++ compilers really really hate mixing types and values (hello most vexing parse) and tries to stay as far away as possible. Or in other words, this is impossible. Or @Quentin manages to abuse the most vexing parse again and wraps everything into one magnificent macro.

    – Passer By
    Mar 28 at 12:58







  • 1





    @PasserBy I'm sorry to disappoint, but the parser went through unscathed this time.

    – Quentin
    Mar 28 at 13:22

















  • I'm afraid what you want is not possible: stackoverflow.com/q/25893828/5470596

    – YSC
    Mar 28 at 11:56






  • 1





    Catching both std::vector and std::array can easily be done by adding an auto... pack, but that would still only work if all type parameters comes first, and the non-types comes after. Catching a mixed pattern is AFAIK not possible.

    – super
    Mar 28 at 12:01












  • @YSC That post is old, in C++17 new features such as auto for non-type parameter deduction were introduced, now maybe is possible. I haven't been able to find a way though.

    – user28032019
    Mar 28 at 12:02






  • 1





    I think C++ compilers really really hate mixing types and values (hello most vexing parse) and tries to stay as far away as possible. Or in other words, this is impossible. Or @Quentin manages to abuse the most vexing parse again and wraps everything into one magnificent macro.

    – Passer By
    Mar 28 at 12:58







  • 1





    @PasserBy I'm sorry to disappoint, but the parser went through unscathed this time.

    – Quentin
    Mar 28 at 13:22
















I'm afraid what you want is not possible: stackoverflow.com/q/25893828/5470596

– YSC
Mar 28 at 11:56





I'm afraid what you want is not possible: stackoverflow.com/q/25893828/5470596

– YSC
Mar 28 at 11:56




1




1





Catching both std::vector and std::array can easily be done by adding an auto... pack, but that would still only work if all type parameters comes first, and the non-types comes after. Catching a mixed pattern is AFAIK not possible.

– super
Mar 28 at 12:01






Catching both std::vector and std::array can easily be done by adding an auto... pack, but that would still only work if all type parameters comes first, and the non-types comes after. Catching a mixed pattern is AFAIK not possible.

– super
Mar 28 at 12:01














@YSC That post is old, in C++17 new features such as auto for non-type parameter deduction were introduced, now maybe is possible. I haven't been able to find a way though.

– user28032019
Mar 28 at 12:02





@YSC That post is old, in C++17 new features such as auto for non-type parameter deduction were introduced, now maybe is possible. I haven't been able to find a way though.

– user28032019
Mar 28 at 12:02




1




1





I think C++ compilers really really hate mixing types and values (hello most vexing parse) and tries to stay as far away as possible. Or in other words, this is impossible. Or @Quentin manages to abuse the most vexing parse again and wraps everything into one magnificent macro.

– Passer By
Mar 28 at 12:58






I think C++ compilers really really hate mixing types and values (hello most vexing parse) and tries to stay as far away as possible. Or in other words, this is impossible. Or @Quentin manages to abuse the most vexing parse again and wraps everything into one magnificent macro.

– Passer By
Mar 28 at 12:58





1




1





@PasserBy I'm sorry to disappoint, but the parser went through unscathed this time.

– Quentin
Mar 28 at 13:22





@PasserBy I'm sorry to disappoint, but the parser went through unscathed this time.

– Quentin
Mar 28 at 13:22












1 Answer
1






active

oldest

votes


















8
















C++20 is a weird, weird world. Cross-checking is welcome as I'm a beginner with CTAD and not entirely sure I've covered all bases.



This solution uses SFINAE to check whether class template argument deduction (CTAD) succeeds between the requested class template and the mystery type. An additional is_same check is performed to prevent against unwanted conversions.



template <auto f>
struct is_specialization_of
private:
template <class T>
static auto value_impl(int) -> std::is_same<T, decltype(f.template operator()<T>())>;

template <class T>
static auto value_impl(...) -> std::false_type;

public:
template <class T>
static constexpr bool value = decltype(value_impl<T>(0))::value;
;

// To replace std::declval which yields T&&
template <class T>
T declrval();

#define is_specialization_of(...)
is_specialization_of<[]<class T>() -> decltype(__VA_ARGS__(declrval<T>())) >::value

// Usage
static_assert(is_specialization_of(std::array)<std::array<int, 4>>);


First caveat: Since we can't declare a parameter for the class template in any way without knowing its arguments, passing it around to where CTAD will be performed can only be done by jumping through some hoops. C++20 constexpr and template-friendly lambdas help a lot here, but the syntax is a mouthful, hence the helper macro.



Second caveat: this only works with movable types, as CTAD only works on object declarations, not reference declarations. Maybe a future proposal will allow things such as std::array &arr = t;, and then this will be fixed!



Actually fixed by remembering that C++17 has guaranteed copy-elision, which allows direct-initialization from a non-movable rvalue as is the case here!






share|improve this answer






















  • 1





    I'll deduce your template argument. ( I love this solution )

    – Sombrero Chicken
    Mar 28 at 13:29












  • @PasserBy I think so. Clang piles up errors on me, but GCC seems to be fine with it. If that weren't the case, I still have the option to use C++20's ability to wrap the lambda inside decltype and pass that type instead to reconstruct it later on.

    – Quentin
    Mar 28 at 13:29






  • 1





    @SombreroChicken Chicken Tortilla Argument Deduction?

    – Quentin
    Mar 28 at 13:30






  • 1





    Now we're talking about the good stuff.

    – Sombrero Chicken
    Mar 28 at 13:31






  • 1





    Just checked, expr.prim.lambda/2 is where it's forbidden, and it's gone in C++20.

    – Passer By
    Mar 28 at 13:37










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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









8
















C++20 is a weird, weird world. Cross-checking is welcome as I'm a beginner with CTAD and not entirely sure I've covered all bases.



This solution uses SFINAE to check whether class template argument deduction (CTAD) succeeds between the requested class template and the mystery type. An additional is_same check is performed to prevent against unwanted conversions.



template <auto f>
struct is_specialization_of
private:
template <class T>
static auto value_impl(int) -> std::is_same<T, decltype(f.template operator()<T>())>;

template <class T>
static auto value_impl(...) -> std::false_type;

public:
template <class T>
static constexpr bool value = decltype(value_impl<T>(0))::value;
;

// To replace std::declval which yields T&&
template <class T>
T declrval();

#define is_specialization_of(...)
is_specialization_of<[]<class T>() -> decltype(__VA_ARGS__(declrval<T>())) >::value

// Usage
static_assert(is_specialization_of(std::array)<std::array<int, 4>>);


First caveat: Since we can't declare a parameter for the class template in any way without knowing its arguments, passing it around to where CTAD will be performed can only be done by jumping through some hoops. C++20 constexpr and template-friendly lambdas help a lot here, but the syntax is a mouthful, hence the helper macro.



Second caveat: this only works with movable types, as CTAD only works on object declarations, not reference declarations. Maybe a future proposal will allow things such as std::array &arr = t;, and then this will be fixed!



Actually fixed by remembering that C++17 has guaranteed copy-elision, which allows direct-initialization from a non-movable rvalue as is the case here!






share|improve this answer






















  • 1





    I'll deduce your template argument. ( I love this solution )

    – Sombrero Chicken
    Mar 28 at 13:29












  • @PasserBy I think so. Clang piles up errors on me, but GCC seems to be fine with it. If that weren't the case, I still have the option to use C++20's ability to wrap the lambda inside decltype and pass that type instead to reconstruct it later on.

    – Quentin
    Mar 28 at 13:29






  • 1





    @SombreroChicken Chicken Tortilla Argument Deduction?

    – Quentin
    Mar 28 at 13:30






  • 1





    Now we're talking about the good stuff.

    – Sombrero Chicken
    Mar 28 at 13:31






  • 1





    Just checked, expr.prim.lambda/2 is where it's forbidden, and it's gone in C++20.

    – Passer By
    Mar 28 at 13:37















8
















C++20 is a weird, weird world. Cross-checking is welcome as I'm a beginner with CTAD and not entirely sure I've covered all bases.



This solution uses SFINAE to check whether class template argument deduction (CTAD) succeeds between the requested class template and the mystery type. An additional is_same check is performed to prevent against unwanted conversions.



template <auto f>
struct is_specialization_of
private:
template <class T>
static auto value_impl(int) -> std::is_same<T, decltype(f.template operator()<T>())>;

template <class T>
static auto value_impl(...) -> std::false_type;

public:
template <class T>
static constexpr bool value = decltype(value_impl<T>(0))::value;
;

// To replace std::declval which yields T&&
template <class T>
T declrval();

#define is_specialization_of(...)
is_specialization_of<[]<class T>() -> decltype(__VA_ARGS__(declrval<T>())) >::value

// Usage
static_assert(is_specialization_of(std::array)<std::array<int, 4>>);


First caveat: Since we can't declare a parameter for the class template in any way without knowing its arguments, passing it around to where CTAD will be performed can only be done by jumping through some hoops. C++20 constexpr and template-friendly lambdas help a lot here, but the syntax is a mouthful, hence the helper macro.



Second caveat: this only works with movable types, as CTAD only works on object declarations, not reference declarations. Maybe a future proposal will allow things such as std::array &arr = t;, and then this will be fixed!



Actually fixed by remembering that C++17 has guaranteed copy-elision, which allows direct-initialization from a non-movable rvalue as is the case here!






share|improve this answer






















  • 1





    I'll deduce your template argument. ( I love this solution )

    – Sombrero Chicken
    Mar 28 at 13:29












  • @PasserBy I think so. Clang piles up errors on me, but GCC seems to be fine with it. If that weren't the case, I still have the option to use C++20's ability to wrap the lambda inside decltype and pass that type instead to reconstruct it later on.

    – Quentin
    Mar 28 at 13:29






  • 1





    @SombreroChicken Chicken Tortilla Argument Deduction?

    – Quentin
    Mar 28 at 13:30






  • 1





    Now we're talking about the good stuff.

    – Sombrero Chicken
    Mar 28 at 13:31






  • 1





    Just checked, expr.prim.lambda/2 is where it's forbidden, and it's gone in C++20.

    – Passer By
    Mar 28 at 13:37













8














8










8









C++20 is a weird, weird world. Cross-checking is welcome as I'm a beginner with CTAD and not entirely sure I've covered all bases.



This solution uses SFINAE to check whether class template argument deduction (CTAD) succeeds between the requested class template and the mystery type. An additional is_same check is performed to prevent against unwanted conversions.



template <auto f>
struct is_specialization_of
private:
template <class T>
static auto value_impl(int) -> std::is_same<T, decltype(f.template operator()<T>())>;

template <class T>
static auto value_impl(...) -> std::false_type;

public:
template <class T>
static constexpr bool value = decltype(value_impl<T>(0))::value;
;

// To replace std::declval which yields T&&
template <class T>
T declrval();

#define is_specialization_of(...)
is_specialization_of<[]<class T>() -> decltype(__VA_ARGS__(declrval<T>())) >::value

// Usage
static_assert(is_specialization_of(std::array)<std::array<int, 4>>);


First caveat: Since we can't declare a parameter for the class template in any way without knowing its arguments, passing it around to where CTAD will be performed can only be done by jumping through some hoops. C++20 constexpr and template-friendly lambdas help a lot here, but the syntax is a mouthful, hence the helper macro.



Second caveat: this only works with movable types, as CTAD only works on object declarations, not reference declarations. Maybe a future proposal will allow things such as std::array &arr = t;, and then this will be fixed!



Actually fixed by remembering that C++17 has guaranteed copy-elision, which allows direct-initialization from a non-movable rvalue as is the case here!






share|improve this answer















C++20 is a weird, weird world. Cross-checking is welcome as I'm a beginner with CTAD and not entirely sure I've covered all bases.



This solution uses SFINAE to check whether class template argument deduction (CTAD) succeeds between the requested class template and the mystery type. An additional is_same check is performed to prevent against unwanted conversions.



template <auto f>
struct is_specialization_of
private:
template <class T>
static auto value_impl(int) -> std::is_same<T, decltype(f.template operator()<T>())>;

template <class T>
static auto value_impl(...) -> std::false_type;

public:
template <class T>
static constexpr bool value = decltype(value_impl<T>(0))::value;
;

// To replace std::declval which yields T&&
template <class T>
T declrval();

#define is_specialization_of(...)
is_specialization_of<[]<class T>() -> decltype(__VA_ARGS__(declrval<T>())) >::value

// Usage
static_assert(is_specialization_of(std::array)<std::array<int, 4>>);


First caveat: Since we can't declare a parameter for the class template in any way without knowing its arguments, passing it around to where CTAD will be performed can only be done by jumping through some hoops. C++20 constexpr and template-friendly lambdas help a lot here, but the syntax is a mouthful, hence the helper macro.



Second caveat: this only works with movable types, as CTAD only works on object declarations, not reference declarations. Maybe a future proposal will allow things such as std::array &arr = t;, and then this will be fixed!



Actually fixed by remembering that C++17 has guaranteed copy-elision, which allows direct-initialization from a non-movable rvalue as is the case here!







share|improve this answer














share|improve this answer



share|improve this answer








edited Mar 28 at 13:48

























answered Mar 28 at 13:08









QuentinQuentin

49.2k6 gold badges97 silver badges154 bronze badges




49.2k6 gold badges97 silver badges154 bronze badges










  • 1





    I'll deduce your template argument. ( I love this solution )

    – Sombrero Chicken
    Mar 28 at 13:29












  • @PasserBy I think so. Clang piles up errors on me, but GCC seems to be fine with it. If that weren't the case, I still have the option to use C++20's ability to wrap the lambda inside decltype and pass that type instead to reconstruct it later on.

    – Quentin
    Mar 28 at 13:29






  • 1





    @SombreroChicken Chicken Tortilla Argument Deduction?

    – Quentin
    Mar 28 at 13:30






  • 1





    Now we're talking about the good stuff.

    – Sombrero Chicken
    Mar 28 at 13:31






  • 1





    Just checked, expr.prim.lambda/2 is where it's forbidden, and it's gone in C++20.

    – Passer By
    Mar 28 at 13:37












  • 1





    I'll deduce your template argument. ( I love this solution )

    – Sombrero Chicken
    Mar 28 at 13:29












  • @PasserBy I think so. Clang piles up errors on me, but GCC seems to be fine with it. If that weren't the case, I still have the option to use C++20's ability to wrap the lambda inside decltype and pass that type instead to reconstruct it later on.

    – Quentin
    Mar 28 at 13:29






  • 1





    @SombreroChicken Chicken Tortilla Argument Deduction?

    – Quentin
    Mar 28 at 13:30






  • 1





    Now we're talking about the good stuff.

    – Sombrero Chicken
    Mar 28 at 13:31






  • 1





    Just checked, expr.prim.lambda/2 is where it's forbidden, and it's gone in C++20.

    – Passer By
    Mar 28 at 13:37







1




1





I'll deduce your template argument. ( I love this solution )

– Sombrero Chicken
Mar 28 at 13:29






I'll deduce your template argument. ( I love this solution )

– Sombrero Chicken
Mar 28 at 13:29














@PasserBy I think so. Clang piles up errors on me, but GCC seems to be fine with it. If that weren't the case, I still have the option to use C++20's ability to wrap the lambda inside decltype and pass that type instead to reconstruct it later on.

– Quentin
Mar 28 at 13:29





@PasserBy I think so. Clang piles up errors on me, but GCC seems to be fine with it. If that weren't the case, I still have the option to use C++20's ability to wrap the lambda inside decltype and pass that type instead to reconstruct it later on.

– Quentin
Mar 28 at 13:29




1




1





@SombreroChicken Chicken Tortilla Argument Deduction?

– Quentin
Mar 28 at 13:30





@SombreroChicken Chicken Tortilla Argument Deduction?

– Quentin
Mar 28 at 13:30




1




1





Now we're talking about the good stuff.

– Sombrero Chicken
Mar 28 at 13:31





Now we're talking about the good stuff.

– Sombrero Chicken
Mar 28 at 13:31




1




1





Just checked, expr.prim.lambda/2 is where it's forbidden, and it's gone in C++20.

– Passer By
Mar 28 at 13:37





Just checked, expr.prim.lambda/2 is where it's forbidden, and it's gone in C++20.

– Passer By
Mar 28 at 13:37








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