MongoDB - Rewind an $unwind nested array after $lookup using $groupIf Mongo $lookup is a left outer join, then how come it excludes non-matching documents?Retrieve only the queried element in an object array in MongoDB collectionFind MongoDB records where array field is not emptyWhat's the $unwind operator in MongoDB?How to use nested grouping in MongoDBmongodb aggregation - unwind/group/project query combination$lookup on nested array of Objects$lookup nested array in mongodbUnwinding two nested array mongodb nodejs in group$unwind and $lookup with php mongodb
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MongoDB - Rewind an $unwind nested array after $lookup using $group
If Mongo $lookup is a left outer join, then how come it excludes non-matching documents?Retrieve only the queried element in an object array in MongoDB collectionFind MongoDB records where array field is not emptyWhat's the $unwind operator in MongoDB?How to use nested grouping in MongoDBmongodb aggregation - unwind/group/project query combination$lookup on nested array of Objects$lookup nested array in mongodbUnwinding two nested array mongodb nodejs in group$unwind and $lookup with php mongodb
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MongoDB aggregation gets exponentially complicated by the minute!
I am in so far as to $unwind
a nested array and then perform a $lookup
by the _id
of each object from the unwinded nested array. My final attempt is to reverse the unwinding with $group
. However, I am unable to reconstruct the original embedded array, with its original property name, along with the rest of the original immediate properties of each document.
Here is my attempt so far:
db.users.aggregate([
$unwind: "$profile",
$unwind:
path: "$profile.universities",
preserveNullAndEmptyArrays: true
,
$lookup:
from: "universities",
localField: "profile.universities._id",
foreignField: "_id",
as: "profile.universities"
,
$group:
_id: "$_id",
emails: "$first": "$emails" ,
profile: "$first": "$profile" ,
universities: "$push": "$profile.universities"
]).pretty()
What I get is something like this:
"_id" : "A_USER_ID",
"emails" : [
"address" : "AN_EMAIL_ADDRESS",
"verified" : false
],
"profile" :
"name" : "NAME",
"company" : "A COMPANY",
"title" : "A TITLE",
"phone" : "123-123-1234",
"disabled" : false,
"universities" : [
"_id" : "ID_1",
"name" : "UNIVERSITY_NAME_1",
"code" : "CODE_1",
"styles" : AN_OBJECT
]
,
"universities" : [
[
"_id" : "ID_1",
"name" : "UNIVERSITY_NAME_1",
"code" : "CODE_1",
"styles" : AN_OBJECT
],
[
"_id" : "ID_2",
"name" : "UNIVERSITY_NAME_2",
"code" : "CODE_2",
"styles" : AN_OBJECT
]
]
There are 2 issues with this result:
- The resulting
universities
is an array of arrays of one object each, since the$lookup
returned a single element array for the original$profile.universities
nested array. It should be just an array of objects. - The resulting
universities
should take its original place as nested underprofiles
. I am aware why the originalprofile.universities
is the way it is, because I am using the$first
operator. My intent behind this is to retain all of the original properties ofprofile
, in junction with retaining the original nesteduniversities
array.
Ultimately, what I need is something like this:
"_id" : "A_USER_ID",
"emails" : [
"address" : "AN_EMAIL_ADDRESS",
"verified" : false
],
"profile" :
"name" : "NAME",
"company" : "A COMPANY",
"title" : "A TITLE",
"phone" : "123-123-1234",
"disabled" : false,
"universities" : [
"_id" : "ID_1",
"name" : "UNIVERSITY_NAME_1",
"code" : "CODE_1",
"styles" : AN_OBJECT
,
"_id" : "ID_2",
"name" : "UNIVERSITY_NAME_2",
"code" : "CODE_2",
"styles" : AN_OBJECT
]
Is there another operator that I can use instead of $group
to achieve this? Or am I understanding the purpose of $group
incorrectly?
Edit: This is the original post, for context:
If Mongo $lookup is a left outer join, then how come it excludes non-matching documents?
mongodb join mongodb-query aggregation-framework mongodb-aggregation
add a comment
|
MongoDB aggregation gets exponentially complicated by the minute!
I am in so far as to $unwind
a nested array and then perform a $lookup
by the _id
of each object from the unwinded nested array. My final attempt is to reverse the unwinding with $group
. However, I am unable to reconstruct the original embedded array, with its original property name, along with the rest of the original immediate properties of each document.
Here is my attempt so far:
db.users.aggregate([
$unwind: "$profile",
$unwind:
path: "$profile.universities",
preserveNullAndEmptyArrays: true
,
$lookup:
from: "universities",
localField: "profile.universities._id",
foreignField: "_id",
as: "profile.universities"
,
$group:
_id: "$_id",
emails: "$first": "$emails" ,
profile: "$first": "$profile" ,
universities: "$push": "$profile.universities"
]).pretty()
What I get is something like this:
"_id" : "A_USER_ID",
"emails" : [
"address" : "AN_EMAIL_ADDRESS",
"verified" : false
],
"profile" :
"name" : "NAME",
"company" : "A COMPANY",
"title" : "A TITLE",
"phone" : "123-123-1234",
"disabled" : false,
"universities" : [
"_id" : "ID_1",
"name" : "UNIVERSITY_NAME_1",
"code" : "CODE_1",
"styles" : AN_OBJECT
]
,
"universities" : [
[
"_id" : "ID_1",
"name" : "UNIVERSITY_NAME_1",
"code" : "CODE_1",
"styles" : AN_OBJECT
],
[
"_id" : "ID_2",
"name" : "UNIVERSITY_NAME_2",
"code" : "CODE_2",
"styles" : AN_OBJECT
]
]
There are 2 issues with this result:
- The resulting
universities
is an array of arrays of one object each, since the$lookup
returned a single element array for the original$profile.universities
nested array. It should be just an array of objects. - The resulting
universities
should take its original place as nested underprofiles
. I am aware why the originalprofile.universities
is the way it is, because I am using the$first
operator. My intent behind this is to retain all of the original properties ofprofile
, in junction with retaining the original nesteduniversities
array.
Ultimately, what I need is something like this:
"_id" : "A_USER_ID",
"emails" : [
"address" : "AN_EMAIL_ADDRESS",
"verified" : false
],
"profile" :
"name" : "NAME",
"company" : "A COMPANY",
"title" : "A TITLE",
"phone" : "123-123-1234",
"disabled" : false,
"universities" : [
"_id" : "ID_1",
"name" : "UNIVERSITY_NAME_1",
"code" : "CODE_1",
"styles" : AN_OBJECT
,
"_id" : "ID_2",
"name" : "UNIVERSITY_NAME_2",
"code" : "CODE_2",
"styles" : AN_OBJECT
]
Is there another operator that I can use instead of $group
to achieve this? Or am I understanding the purpose of $group
incorrectly?
Edit: This is the original post, for context:
If Mongo $lookup is a left outer join, then how come it excludes non-matching documents?
mongodb join mongodb-query aggregation-framework mongodb-aggregation
add a comment
|
MongoDB aggregation gets exponentially complicated by the minute!
I am in so far as to $unwind
a nested array and then perform a $lookup
by the _id
of each object from the unwinded nested array. My final attempt is to reverse the unwinding with $group
. However, I am unable to reconstruct the original embedded array, with its original property name, along with the rest of the original immediate properties of each document.
Here is my attempt so far:
db.users.aggregate([
$unwind: "$profile",
$unwind:
path: "$profile.universities",
preserveNullAndEmptyArrays: true
,
$lookup:
from: "universities",
localField: "profile.universities._id",
foreignField: "_id",
as: "profile.universities"
,
$group:
_id: "$_id",
emails: "$first": "$emails" ,
profile: "$first": "$profile" ,
universities: "$push": "$profile.universities"
]).pretty()
What I get is something like this:
"_id" : "A_USER_ID",
"emails" : [
"address" : "AN_EMAIL_ADDRESS",
"verified" : false
],
"profile" :
"name" : "NAME",
"company" : "A COMPANY",
"title" : "A TITLE",
"phone" : "123-123-1234",
"disabled" : false,
"universities" : [
"_id" : "ID_1",
"name" : "UNIVERSITY_NAME_1",
"code" : "CODE_1",
"styles" : AN_OBJECT
]
,
"universities" : [
[
"_id" : "ID_1",
"name" : "UNIVERSITY_NAME_1",
"code" : "CODE_1",
"styles" : AN_OBJECT
],
[
"_id" : "ID_2",
"name" : "UNIVERSITY_NAME_2",
"code" : "CODE_2",
"styles" : AN_OBJECT
]
]
There are 2 issues with this result:
- The resulting
universities
is an array of arrays of one object each, since the$lookup
returned a single element array for the original$profile.universities
nested array. It should be just an array of objects. - The resulting
universities
should take its original place as nested underprofiles
. I am aware why the originalprofile.universities
is the way it is, because I am using the$first
operator. My intent behind this is to retain all of the original properties ofprofile
, in junction with retaining the original nesteduniversities
array.
Ultimately, what I need is something like this:
"_id" : "A_USER_ID",
"emails" : [
"address" : "AN_EMAIL_ADDRESS",
"verified" : false
],
"profile" :
"name" : "NAME",
"company" : "A COMPANY",
"title" : "A TITLE",
"phone" : "123-123-1234",
"disabled" : false,
"universities" : [
"_id" : "ID_1",
"name" : "UNIVERSITY_NAME_1",
"code" : "CODE_1",
"styles" : AN_OBJECT
,
"_id" : "ID_2",
"name" : "UNIVERSITY_NAME_2",
"code" : "CODE_2",
"styles" : AN_OBJECT
]
Is there another operator that I can use instead of $group
to achieve this? Or am I understanding the purpose of $group
incorrectly?
Edit: This is the original post, for context:
If Mongo $lookup is a left outer join, then how come it excludes non-matching documents?
mongodb join mongodb-query aggregation-framework mongodb-aggregation
MongoDB aggregation gets exponentially complicated by the minute!
I am in so far as to $unwind
a nested array and then perform a $lookup
by the _id
of each object from the unwinded nested array. My final attempt is to reverse the unwinding with $group
. However, I am unable to reconstruct the original embedded array, with its original property name, along with the rest of the original immediate properties of each document.
Here is my attempt so far:
db.users.aggregate([
$unwind: "$profile",
$unwind:
path: "$profile.universities",
preserveNullAndEmptyArrays: true
,
$lookup:
from: "universities",
localField: "profile.universities._id",
foreignField: "_id",
as: "profile.universities"
,
$group:
_id: "$_id",
emails: "$first": "$emails" ,
profile: "$first": "$profile" ,
universities: "$push": "$profile.universities"
]).pretty()
What I get is something like this:
"_id" : "A_USER_ID",
"emails" : [
"address" : "AN_EMAIL_ADDRESS",
"verified" : false
],
"profile" :
"name" : "NAME",
"company" : "A COMPANY",
"title" : "A TITLE",
"phone" : "123-123-1234",
"disabled" : false,
"universities" : [
"_id" : "ID_1",
"name" : "UNIVERSITY_NAME_1",
"code" : "CODE_1",
"styles" : AN_OBJECT
]
,
"universities" : [
[
"_id" : "ID_1",
"name" : "UNIVERSITY_NAME_1",
"code" : "CODE_1",
"styles" : AN_OBJECT
],
[
"_id" : "ID_2",
"name" : "UNIVERSITY_NAME_2",
"code" : "CODE_2",
"styles" : AN_OBJECT
]
]
There are 2 issues with this result:
- The resulting
universities
is an array of arrays of one object each, since the$lookup
returned a single element array for the original$profile.universities
nested array. It should be just an array of objects. - The resulting
universities
should take its original place as nested underprofiles
. I am aware why the originalprofile.universities
is the way it is, because I am using the$first
operator. My intent behind this is to retain all of the original properties ofprofile
, in junction with retaining the original nesteduniversities
array.
Ultimately, what I need is something like this:
"_id" : "A_USER_ID",
"emails" : [
"address" : "AN_EMAIL_ADDRESS",
"verified" : false
],
"profile" :
"name" : "NAME",
"company" : "A COMPANY",
"title" : "A TITLE",
"phone" : "123-123-1234",
"disabled" : false,
"universities" : [
"_id" : "ID_1",
"name" : "UNIVERSITY_NAME_1",
"code" : "CODE_1",
"styles" : AN_OBJECT
,
"_id" : "ID_2",
"name" : "UNIVERSITY_NAME_2",
"code" : "CODE_2",
"styles" : AN_OBJECT
]
Is there another operator that I can use instead of $group
to achieve this? Or am I understanding the purpose of $group
incorrectly?
Edit: This is the original post, for context:
If Mongo $lookup is a left outer join, then how come it excludes non-matching documents?
mongodb join mongodb-query aggregation-framework mongodb-aggregation
mongodb join mongodb-query aggregation-framework mongodb-aggregation
edited May 23 '17 at 12:24
Community♦
11 silver badge
11 silver badge
asked Sep 14 '16 at 13:14
Sun LeeSun Lee
2241 gold badge3 silver badges15 bronze badges
2241 gold badge3 silver badges15 bronze badges
add a comment
|
add a comment
|
1 Answer
1
active
oldest
votes
Because the $lookup
operator produces an array field, you need to $unwind
the new field before the $group
pipeline to get the desired result:
db.users.aggregate([
"$unwind": "$profile" ,
"$unwind":
"path": "$profile.universities",
"preserveNullAndEmptyArrays": true
,
"$lookup":
"from": "universities",
"localField": "profile.universities._id",
"foreignField": "_id",
"as": "universities"
,
"$unwind": "$universities" ,
"$group":
"_id": "$_id",
"emails": "$first": "$emails" ,
"profile": "$first": "$profile" ,
"universities": "$push": "$universities"
,
"$project":
"emails": 1,
"profile.name" : 1,
"profile.company": 1,
"profile.title" : 1,
"profile.phone" : 1,
"profile.disabled": 1,
"profile.universities": "$universities"
]).pretty()
3
Thanks @chridam, the second$unwind
and$project
did the trick! I had to modify two parts: 1. change the second unwind to"$unwind": "path": "$profile.universities", "preserveNullAndEmptyArrays": true
, and 2. change the$group
"universities" to"universities": "$push": "$profile.universities"
and I was able to get my results.
– Sun Lee
Sep 14 '16 at 16:53
add a comment
|
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1 Answer
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1 Answer
1
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oldest
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active
oldest
votes
active
oldest
votes
Because the $lookup
operator produces an array field, you need to $unwind
the new field before the $group
pipeline to get the desired result:
db.users.aggregate([
"$unwind": "$profile" ,
"$unwind":
"path": "$profile.universities",
"preserveNullAndEmptyArrays": true
,
"$lookup":
"from": "universities",
"localField": "profile.universities._id",
"foreignField": "_id",
"as": "universities"
,
"$unwind": "$universities" ,
"$group":
"_id": "$_id",
"emails": "$first": "$emails" ,
"profile": "$first": "$profile" ,
"universities": "$push": "$universities"
,
"$project":
"emails": 1,
"profile.name" : 1,
"profile.company": 1,
"profile.title" : 1,
"profile.phone" : 1,
"profile.disabled": 1,
"profile.universities": "$universities"
]).pretty()
3
Thanks @chridam, the second$unwind
and$project
did the trick! I had to modify two parts: 1. change the second unwind to"$unwind": "path": "$profile.universities", "preserveNullAndEmptyArrays": true
, and 2. change the$group
"universities" to"universities": "$push": "$profile.universities"
and I was able to get my results.
– Sun Lee
Sep 14 '16 at 16:53
add a comment
|
Because the $lookup
operator produces an array field, you need to $unwind
the new field before the $group
pipeline to get the desired result:
db.users.aggregate([
"$unwind": "$profile" ,
"$unwind":
"path": "$profile.universities",
"preserveNullAndEmptyArrays": true
,
"$lookup":
"from": "universities",
"localField": "profile.universities._id",
"foreignField": "_id",
"as": "universities"
,
"$unwind": "$universities" ,
"$group":
"_id": "$_id",
"emails": "$first": "$emails" ,
"profile": "$first": "$profile" ,
"universities": "$push": "$universities"
,
"$project":
"emails": 1,
"profile.name" : 1,
"profile.company": 1,
"profile.title" : 1,
"profile.phone" : 1,
"profile.disabled": 1,
"profile.universities": "$universities"
]).pretty()
3
Thanks @chridam, the second$unwind
and$project
did the trick! I had to modify two parts: 1. change the second unwind to"$unwind": "path": "$profile.universities", "preserveNullAndEmptyArrays": true
, and 2. change the$group
"universities" to"universities": "$push": "$profile.universities"
and I was able to get my results.
– Sun Lee
Sep 14 '16 at 16:53
add a comment
|
Because the $lookup
operator produces an array field, you need to $unwind
the new field before the $group
pipeline to get the desired result:
db.users.aggregate([
"$unwind": "$profile" ,
"$unwind":
"path": "$profile.universities",
"preserveNullAndEmptyArrays": true
,
"$lookup":
"from": "universities",
"localField": "profile.universities._id",
"foreignField": "_id",
"as": "universities"
,
"$unwind": "$universities" ,
"$group":
"_id": "$_id",
"emails": "$first": "$emails" ,
"profile": "$first": "$profile" ,
"universities": "$push": "$universities"
,
"$project":
"emails": 1,
"profile.name" : 1,
"profile.company": 1,
"profile.title" : 1,
"profile.phone" : 1,
"profile.disabled": 1,
"profile.universities": "$universities"
]).pretty()
Because the $lookup
operator produces an array field, you need to $unwind
the new field before the $group
pipeline to get the desired result:
db.users.aggregate([
"$unwind": "$profile" ,
"$unwind":
"path": "$profile.universities",
"preserveNullAndEmptyArrays": true
,
"$lookup":
"from": "universities",
"localField": "profile.universities._id",
"foreignField": "_id",
"as": "universities"
,
"$unwind": "$universities" ,
"$group":
"_id": "$_id",
"emails": "$first": "$emails" ,
"profile": "$first": "$profile" ,
"universities": "$push": "$universities"
,
"$project":
"emails": 1,
"profile.name" : 1,
"profile.company": 1,
"profile.title" : 1,
"profile.phone" : 1,
"profile.disabled": 1,
"profile.universities": "$universities"
]).pretty()
edited Aug 7 at 15:21
answered Sep 14 '16 at 13:56
chridamchridam
73.1k16 gold badges122 silver badges160 bronze badges
73.1k16 gold badges122 silver badges160 bronze badges
3
Thanks @chridam, the second$unwind
and$project
did the trick! I had to modify two parts: 1. change the second unwind to"$unwind": "path": "$profile.universities", "preserveNullAndEmptyArrays": true
, and 2. change the$group
"universities" to"universities": "$push": "$profile.universities"
and I was able to get my results.
– Sun Lee
Sep 14 '16 at 16:53
add a comment
|
3
Thanks @chridam, the second$unwind
and$project
did the trick! I had to modify two parts: 1. change the second unwind to"$unwind": "path": "$profile.universities", "preserveNullAndEmptyArrays": true
, and 2. change the$group
"universities" to"universities": "$push": "$profile.universities"
and I was able to get my results.
– Sun Lee
Sep 14 '16 at 16:53
3
3
Thanks @chridam, the second
$unwind
and $project
did the trick! I had to modify two parts: 1. change the second unwind to "$unwind": "path": "$profile.universities", "preserveNullAndEmptyArrays": true
, and 2. change the $group
"universities" to "universities": "$push": "$profile.universities"
and I was able to get my results.– Sun Lee
Sep 14 '16 at 16:53
Thanks @chridam, the second
$unwind
and $project
did the trick! I had to modify two parts: 1. change the second unwind to "$unwind": "path": "$profile.universities", "preserveNullAndEmptyArrays": true
, and 2. change the $group
"universities" to "universities": "$push": "$profile.universities"
and I was able to get my results.– Sun Lee
Sep 14 '16 at 16:53
add a comment
|
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