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How to add a column containing the date of 2019 to a dataset?
How to make a great R reproducible exampleHow to create a range of dates in RHow to sort a dataframe by multiple column(s)How to rename a single column in a data.frame?Subsetting dataset for weekday and weekend and calculating sum of columnsHow to customize axis when plot multiple time series data in 1 panel?how to transfer ts into data.frame?aggregate data in irregular groups in r (any better title?)Using an ordered list to control display control display of points in R's GGPLOT2, such as days of the weekpercentage plot when a column has specific valueHow do I change the english weekday abbreviation?Making barchart in R Programming using specific rows from csv file
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I need to predict the number of flights for 2019 per day. I already have a model to but I need to apply it for the 2019 data. So I may need to add a column contains the date for 2019 to the original data set.
I tried to create_series(), but it can't be mutated to the original data set.
Error in mutate_impl(.data, dots) :
Column "date_2019" is of unsupported class data.frame
f2019 <- create_series(~'2019', 'daily')
flight2019 <- daily %>%
mutate(date(f2019))
I also tried data$,
daily$date2019 <- create_series(~'2019', 'daily')
but the value is not normal.
date2019
<S3: tbl_time>
<S3: tbl_time>
<S3: tbl_time>
<S3: tbl_time>
<S3: tbl_time>
<S3: tbl_time>
<S3: tbl_time>
I think the problem is in create_series(), maybe I should use other function to create date variable. I except the daily has a column contains each date in 2019.
i.e,
2019-01-01
2019-01-02
...
or replace the date of daily with 2019's date. (Original date is 2013 in daily)
the data set is following:
# A tibble: 365 x 13
date n wday term residual_wday1 wday2 wday3
<date> <int> <ord> <fct> <dbl> <chr> <chr>
1 2013-01-01 842 Tue wint~ -56.3 Tue Tue
2 2013-01-02 943 Wed wint~ 25.7 Wed Wed
3 2013-01-03 914 Thu wint~ -23.7 Thu Thu
4 2013-01-04 915 Fri wint~ -17.2 Fri Fri
5 2013-01-05 720 Sat wint~ 18.6 Sat-~ Sat-~
6 2013-01-06 832 Sun wint~ 2 Sun Sun
7 2013-01-07 933 Mon wint~ -0.25 Mon Mon
8 2013-01-08 899 Tue wint~ 0.667 Tue Tue
9 2013-01-09 902 Wed wint~ -15.3 Wed Wed
10 2013-01-10 932 Thu wint~ -5.67 Thu Thu
# ... with 355 more rows, and 6 more variables:
r
asked Mar 28 at 6:50
dayucpbx7dayucpbx7
53 bronze badges
|
show 4 more comments
I need to predict the number of flights for 2019 per day. I already have a model to but I need to apply it for the 2019 data. So I may need to add a column contains the date for 2019 to the original data set.
I tried to create_series(), but it can't be mutated to the original data set.
Error in mutate_impl(.data, dots) :
Column "date_2019" is of unsupported class data.frame
f2019 <- create_series(~'2019', 'daily')
flight2019 <- daily %>%
mutate(date(f2019))
I also tried data$,
daily$date2019 <- create_series(~'2019', 'daily')
but the value is not normal.
date2019
<S3: tbl_time>
<S3: tbl_time>
<S3: tbl_time>
<S3: tbl_time>
<S3: tbl_time>
<S3: tbl_time>
<S3: tbl_time>
I think the problem is in create_series(), maybe I should use other function to create date variable. I except the daily has a column contains each date in 2019.
i.e,
2019-01-01
2019-01-02
...
or replace the date of daily with 2019's date. (Original date is 2013 in daily)
the data set is following:
# A tibble: 365 x 13
date n wday term residual_wday1 wday2 wday3
<date> <int> <ord> <fct> <dbl> <chr> <chr>
1 2013-01-01 842 Tue wint~ -56.3 Tue Tue
2 2013-01-02 943 Wed wint~ 25.7 Wed Wed
3 2013-01-03 914 Thu wint~ -23.7 Thu Thu
4 2013-01-04 915 Fri wint~ -17.2 Fri Fri
5 2013-01-05 720 Sat wint~ 18.6 Sat-~ Sat-~
6 2013-01-06 832 Sun wint~ 2 Sun Sun
7 2013-01-07 933 Mon wint~ -0.25 Mon Mon
8 2013-01-08 899 Tue wint~ 0.667 Tue Tue
9 2013-01-09 902 Wed wint~ -15.3 Wed Wed
10 2013-01-10 932 Thu wint~ -5.67 Thu Thu
# ... with 355 more rows, and 6 more variables:
r
asked Mar 28 at 6:50
dayucpbx7dayucpbx7
53 bronze badges
Welcome to Stack Overflow! Your question is precise, but in order for us to understand and solve it, it is necessary that you provide some sample data. There are several ways to provide data, probably adding the output ofdput(<yourData>)ordput(head(<yourData>))to your question is sufficient. Avoid adding code or alphanumeric output as images. Consider how to make a good example: stackoverflow.com/questions/5963269/… and see how you can change your question accordingly.
– heck1
Mar 28 at 6:53
Thank you so much! It's my first time to use stack overflow! I will pay attention to this in the future.
– dayucpbx7
Mar 28 at 7:02
OK, I add it in the post.
– dayucpbx7
Mar 28 at 7:16
please try adding the contents ofdput(head(<yourData>))to your question.
– heck1
Mar 28 at 7:19
I edited it, is that OK?
– dayucpbx7
Mar 28 at 7:21
|
show 4 more comments
I need to predict the number of flights for 2019 per day. I already have a model to but I need to apply it for the 2019 data. So I may need to add a column contains the date for 2019 to the original data set.
I tried to create_series(), but it can't be mutated to the original data set.
Error in mutate_impl(.data, dots) :
Column "date_2019" is of unsupported class data.frame
f2019 <- create_series(~'2019', 'daily')
flight2019 <- daily %>%
mutate(date(f2019))
I also tried data$,
daily$date2019 <- create_series(~'2019', 'daily')
but the value is not normal.
date2019
<S3: tbl_time>
<S3: tbl_time>
<S3: tbl_time>
<S3: tbl_time>
<S3: tbl_time>
<S3: tbl_time>
<S3: tbl_time>
I think the problem is in create_series(), maybe I should use other function to create date variable. I except the daily has a column contains each date in 2019.
i.e,
2019-01-01
2019-01-02
...
or replace the date of daily with 2019's date. (Original date is 2013 in daily)
the data set is following:
# A tibble: 365 x 13
date n wday term residual_wday1 wday2 wday3
<date> <int> <ord> <fct> <dbl> <chr> <chr>
1 2013-01-01 842 Tue wint~ -56.3 Tue Tue
2 2013-01-02 943 Wed wint~ 25.7 Wed Wed
3 2013-01-03 914 Thu wint~ -23.7 Thu Thu
4 2013-01-04 915 Fri wint~ -17.2 Fri Fri
5 2013-01-05 720 Sat wint~ 18.6 Sat-~ Sat-~
6 2013-01-06 832 Sun wint~ 2 Sun Sun
7 2013-01-07 933 Mon wint~ -0.25 Mon Mon
8 2013-01-08 899 Tue wint~ 0.667 Tue Tue
9 2013-01-09 902 Wed wint~ -15.3 Wed Wed
10 2013-01-10 932 Thu wint~ -5.67 Thu Thu
# ... with 355 more rows, and 6 more variables:
r
asked Mar 28 at 6:50
dayucpbx7dayucpbx7
53 bronze badges
I need to predict the number of flights for 2019 per day. I already have a model to but I need to apply it for the 2019 data. So I may need to add a column contains the date for 2019 to the original data set.
I tried to create_series(), but it can't be mutated to the original data set.
Error in mutate_impl(.data, dots) :
Column "date_2019" is of unsupported class data.frame
f2019 <- create_series(~'2019', 'daily')
flight2019 <- daily %>%
mutate(date(f2019))
I also tried data$,
daily$date2019 <- create_series(~'2019', 'daily')
but the value is not normal.
date2019
<S3: tbl_time>
<S3: tbl_time>
<S3: tbl_time>
<S3: tbl_time>
<S3: tbl_time>
<S3: tbl_time>
<S3: tbl_time>
I think the problem is in create_series(), maybe I should use other function to create date variable. I except the daily has a column contains each date in 2019.
i.e,
2019-01-01
2019-01-02
...
or replace the date of daily with 2019's date. (Original date is 2013 in daily)
the data set is following:
# A tibble: 365 x 13
date n wday term residual_wday1 wday2 wday3
<date> <int> <ord> <fct> <dbl> <chr> <chr>
1 2013-01-01 842 Tue wint~ -56.3 Tue Tue
2 2013-01-02 943 Wed wint~ 25.7 Wed Wed
3 2013-01-03 914 Thu wint~ -23.7 Thu Thu
4 2013-01-04 915 Fri wint~ -17.2 Fri Fri
5 2013-01-05 720 Sat wint~ 18.6 Sat-~ Sat-~
6 2013-01-06 832 Sun wint~ 2 Sun Sun
7 2013-01-07 933 Mon wint~ -0.25 Mon Mon
8 2013-01-08 899 Tue wint~ 0.667 Tue Tue
9 2013-01-09 902 Wed wint~ -15.3 Wed Wed
10 2013-01-10 932 Thu wint~ -5.67 Thu Thu
# ... with 355 more rows, and 6 more variables:
r
r
asked Mar 28 at 6:50
dayucpbx7dayucpbx7
53 bronze badges
asked Mar 28 at 6:50
dayucpbx7dayucpbx7
53 bronze badges
edited Mar 28 at 7:20
dayucpbx7
asked Mar 28 at 6:50
dayucpbx7dayucpbx7
53 bronze badges
asked Mar 28 at 6:50
dayucpbx7dayucpbx7
53 bronze badges
asked Mar 28 at 6:50
dayucpbx7dayucpbx7
53 bronze badges
53 bronze badges
Welcome to Stack Overflow! Your question is precise, but in order for us to understand and solve it, it is necessary that you provide some sample data. There are several ways to provide data, probably adding the output ofdput(<yourData>)ordput(head(<yourData>))to your question is sufficient. Avoid adding code or alphanumeric output as images. Consider how to make a good example: stackoverflow.com/questions/5963269/… and see how you can change your question accordingly.
– heck1
Mar 28 at 6:53
Thank you so much! It's my first time to use stack overflow! I will pay attention to this in the future.
– dayucpbx7
Mar 28 at 7:02
OK, I add it in the post.
– dayucpbx7
Mar 28 at 7:16
please try adding the contents ofdput(head(<yourData>))to your question.
– heck1
Mar 28 at 7:19
I edited it, is that OK?
– dayucpbx7
Mar 28 at 7:21
|
show 4 more comments
Welcome to Stack Overflow! Your question is precise, but in order for us to understand and solve it, it is necessary that you provide some sample data. There are several ways to provide data, probably adding the output ofdput(<yourData>)ordput(head(<yourData>))to your question is sufficient. Avoid adding code or alphanumeric output as images. Consider how to make a good example: stackoverflow.com/questions/5963269/… and see how you can change your question accordingly.
– heck1
Mar 28 at 6:53
Thank you so much! It's my first time to use stack overflow! I will pay attention to this in the future.
– dayucpbx7
Mar 28 at 7:02
OK, I add it in the post.
– dayucpbx7
Mar 28 at 7:16
please try adding the contents ofdput(head(<yourData>))to your question.
– heck1
Mar 28 at 7:19
I edited it, is that OK?
– dayucpbx7
Mar 28 at 7:21
Welcome to Stack Overflow! Your question is precise, but in order for us to understand and solve it, it is necessary that you provide some sample data. There are several ways to provide data, probably adding the output of
dput(<yourData>) or dput(head(<yourData>)) to your question is sufficient. Avoid adding code or alphanumeric output as images. Consider how to make a good example: stackoverflow.com/questions/5963269/… and see how you can change your question accordingly.– heck1
Mar 28 at 6:53
Welcome to Stack Overflow! Your question is precise, but in order for us to understand and solve it, it is necessary that you provide some sample data. There are several ways to provide data, probably adding the output of
dput(<yourData>) or dput(head(<yourData>)) to your question is sufficient. Avoid adding code or alphanumeric output as images. Consider how to make a good example: stackoverflow.com/questions/5963269/… and see how you can change your question accordingly.– heck1
Mar 28 at 6:53
Thank you so much! It's my first time to use stack overflow! I will pay attention to this in the future.
– dayucpbx7
Mar 28 at 7:02
Thank you so much! It's my first time to use stack overflow! I will pay attention to this in the future.
– dayucpbx7
Mar 28 at 7:02
OK, I add it in the post.
– dayucpbx7
Mar 28 at 7:16
OK, I add it in the post.
– dayucpbx7
Mar 28 at 7:16
please try adding the contents of
dput(head(<yourData>)) to your question.– heck1
Mar 28 at 7:19
please try adding the contents of
dput(head(<yourData>)) to your question.– heck1
Mar 28 at 7:19
I edited it, is that OK?
– dayucpbx7
Mar 28 at 7:21
I edited it, is that OK?
– dayucpbx7
Mar 28 at 7:21
|
show 4 more comments
1 Answer
1
active
oldest
votes
have you seen this post:
How to create a range of dates in R
and function: seq(as.Date("2014/09/04"), by = "day", length.out = 5)
then you can just add new rows with function rbind()
answered Mar 28 at 9:05
Luke ChodzacyponiebieLuke Chodzacyponiebie
162 bronze badges
add a comment |
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1 Answer
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1 Answer
1
active
oldest
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votes
have you seen this post:
How to create a range of dates in R
and function: seq(as.Date("2014/09/04"), by = "day", length.out = 5)
then you can just add new rows with function rbind()
answered Mar 28 at 9:05
Luke ChodzacyponiebieLuke Chodzacyponiebie
162 bronze badges
add a comment |
have you seen this post:
How to create a range of dates in R
and function: seq(as.Date("2014/09/04"), by = "day", length.out = 5)
then you can just add new rows with function rbind()
answered Mar 28 at 9:05
Luke ChodzacyponiebieLuke Chodzacyponiebie
162 bronze badges
add a comment |
have you seen this post:
How to create a range of dates in R
and function: seq(as.Date("2014/09/04"), by = "day", length.out = 5)
then you can just add new rows with function rbind()
answered Mar 28 at 9:05
Luke ChodzacyponiebieLuke Chodzacyponiebie
162 bronze badges
have you seen this post:
How to create a range of dates in R
and function: seq(as.Date("2014/09/04"), by = "day", length.out = 5)
then you can just add new rows with function rbind()
answered Mar 28 at 9:05
Luke ChodzacyponiebieLuke Chodzacyponiebie
162 bronze badges
answered Mar 28 at 9:05
Luke ChodzacyponiebieLuke Chodzacyponiebie
162 bronze badges
answered Mar 28 at 9:05
Luke ChodzacyponiebieLuke Chodzacyponiebie
162 bronze badges
answered Mar 28 at 9:05
Luke ChodzacyponiebieLuke Chodzacyponiebie
162 bronze badges
162 bronze badges
add a comment |
add a comment |
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Welcome to Stack Overflow! Your question is precise, but in order for us to understand and solve it, it is necessary that you provide some sample data. There are several ways to provide data, probably adding the output of
dput(<yourData>)ordput(head(<yourData>))to your question is sufficient. Avoid adding code or alphanumeric output as images. Consider how to make a good example: stackoverflow.com/questions/5963269/… and see how you can change your question accordingly.– heck1
Mar 28 at 6:53
Thank you so much! It's my first time to use stack overflow! I will pay attention to this in the future.
– dayucpbx7
Mar 28 at 7:02
OK, I add it in the post.
– dayucpbx7
Mar 28 at 7:16
please try adding the contents of
dput(head(<yourData>))to your question.– heck1
Mar 28 at 7:19
I edited it, is that OK?
– dayucpbx7
Mar 28 at 7:21