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How to fix object set in grid?


How Vaadin-flow combobox works with value change listener?How can I see details to grid in Vaadin flow?Basic problems to use Vaadin 7 + Grails 2.3 (Persistence, domain class design, get Hibernate Session)Vaadin Flow Grid has no heightStyling Grid in VaadinFlowFilling Grid (Vaadin) with DataGrid with Viritin ListDataProvider fail randomlyHow to use ContextMenu with Grid in Vaadin Flow?How to set width of ListBox with Java in Vaadin?Vaadin Combobox does not shows nameField from databaseHow can I see details to grid in Vaadin flow?No data shown for Vaadin-flow Grid if I set the Items in backend and create a polymer-template






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








1















In my application i have a class like:



public class Team 
private Country teamId;
private Set<Player> playerSet;
private Set<Player> substitutes;
private Set<Coach> coachSet;



When i instantiate a grid like:



Grid<Team> grid = new Grid<>(Team.class);


and set allTeam() from database it shows object for playerSet and coachSet.



My question is i just want to show players name and coach name concate by ,or n.



Any idea how can i do that?As a beginner it is complicated for me










share|improve this question
























  • Possible duplicate of How can I see details to grid in Vaadin flow?

    – cfrick
    Mar 29 at 7:11

















1















In my application i have a class like:



public class Team 
private Country teamId;
private Set<Player> playerSet;
private Set<Player> substitutes;
private Set<Coach> coachSet;



When i instantiate a grid like:



Grid<Team> grid = new Grid<>(Team.class);


and set allTeam() from database it shows object for playerSet and coachSet.



My question is i just want to show players name and coach name concate by ,or n.



Any idea how can i do that?As a beginner it is complicated for me










share|improve this question
























  • Possible duplicate of How can I see details to grid in Vaadin flow?

    – cfrick
    Mar 29 at 7:11













1












1








1








In my application i have a class like:



public class Team 
private Country teamId;
private Set<Player> playerSet;
private Set<Player> substitutes;
private Set<Coach> coachSet;



When i instantiate a grid like:



Grid<Team> grid = new Grid<>(Team.class);


and set allTeam() from database it shows object for playerSet and coachSet.



My question is i just want to show players name and coach name concate by ,or n.



Any idea how can i do that?As a beginner it is complicated for me










share|improve this question














In my application i have a class like:



public class Team 
private Country teamId;
private Set<Player> playerSet;
private Set<Player> substitutes;
private Set<Coach> coachSet;



When i instantiate a grid like:



Grid<Team> grid = new Grid<>(Team.class);


and set allTeam() from database it shows object for playerSet and coachSet.



My question is i just want to show players name and coach name concate by ,or n.



Any idea how can i do that?As a beginner it is complicated for me







vaadin vaadin-flow






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 28 at 6:59









Nirob RasseenNirob Rasseen

197 bronze badges




197 bronze badges















  • Possible duplicate of How can I see details to grid in Vaadin flow?

    – cfrick
    Mar 29 at 7:11

















  • Possible duplicate of How can I see details to grid in Vaadin flow?

    – cfrick
    Mar 29 at 7:11
















Possible duplicate of How can I see details to grid in Vaadin flow?

– cfrick
Mar 29 at 7:11





Possible duplicate of How can I see details to grid in Vaadin flow?

– cfrick
Mar 29 at 7:11












2 Answers
2






active

oldest

votes


















2
















I see three options.



The first option is the one you already found yourself: concatenate their names in a single String. This can be done like this:



grid.addColumn(team -> 
Set<String> coachNames = new HashSet<>();
for (Coach coach : team.getCoaches())
coachNames.add(coach.getName());

return String.join(", ", coachNames);
);



The second one would be to make use of the Grid item Detail - you could show a coaches grid in the item details. Since you want to display both coaches and players, this option is probably not the best but I wanted to mention the possibility. (Placing two grids inside the item details is possible, but quite strange. Not optimal user experience.)



grid.setItemDetailsRenderer(new ComponentRenderer<>(team -> 
Grid<Coach> coachGrid = new Grid<>(Coach.class);
coachGrid.setItems(team.getCoaches());
return coachGrid;
));



A third option would be to have the team grid on one side of the view, and on the other you show some relevant stuff of the selected item of the team grid. You can have a separate Grid for the coaches, one for the players, one for the substitutes. You could implement this team detail layout also as a separate view if you wish. If your Team object will get more complicated with more sets, collections and other relative properties, the more will this option become appealing, as this is quite scalable/expandable.



grid.addSelectionListener(event -> 
if(event.getFirstSelectedItem().isPresent())
buildTeamDetails(event.getFirstSelectedItem().get())

)

private void buildTeamDetails(Team team)
// build your team detail layouts here






share|improve this answer



























  • How to set Players Name only those players which belong that team? There has a getAllPlayerBYTeamName(String s);

    – Nirob Rasseen
    Mar 29 at 13:25












  • uhm, this is a very different question, but the team object should already have only the players that are on that team?

    – Kaspar Scherrer
    Mar 29 at 13:38












  • Yes exactly. I show those players in that column

    – Nirob Rasseen
    Mar 29 at 14:29


















1
















You can configure which columns are shown in the grid by using grid.removeAllColumns() and then adding all columns you want to have in the grid with grid.addColumn(). Within addColumn() you can create a renderer that defines how the fields (coachName and playerSet) are displayed in the grid.



Let's have a class Team like



public class Team 
private String coachName;
private Set<Player> playerSet;
private Set<Object> objects;
//getters and setters



and a class Player like



public class Player 
private String firstName;
private String lastName;
// getters and setters



Now you want to only have coach and player names in the grid. So (in my example) for coachName we can just use the field's getter and we can create a comma separated String for the playerSet with java streams easily.



Configure the grid like:



 grid.setItems(team);
grid.removeAllColumns();
grid.addColumn(new TextRenderer<>((ItemLabelGenerator<Team>) Team::getCoachName))
.setHeader("Coach");
grid.addColumn(new TextRenderer<>((ItemLabelGenerator<Team>) team1 -> team1.getPlayerSet().stream()
.map(player1 -> player1.getFirstName() + " " + player1.getLastName())
.collect(Collectors.joining(", "))))
.setHeader("Players")
.setFlexGrow(1);


Then the result looks like:



enter image description here






share|improve this answer

























  • How to set Players Name only those players which belong that team? There has a getAllPlayerBYTeamName(String s);

    – Nirob Rasseen
    Mar 29 at 13:26













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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









2
















I see three options.



The first option is the one you already found yourself: concatenate their names in a single String. This can be done like this:



grid.addColumn(team -> 
Set<String> coachNames = new HashSet<>();
for (Coach coach : team.getCoaches())
coachNames.add(coach.getName());

return String.join(", ", coachNames);
);



The second one would be to make use of the Grid item Detail - you could show a coaches grid in the item details. Since you want to display both coaches and players, this option is probably not the best but I wanted to mention the possibility. (Placing two grids inside the item details is possible, but quite strange. Not optimal user experience.)



grid.setItemDetailsRenderer(new ComponentRenderer<>(team -> 
Grid<Coach> coachGrid = new Grid<>(Coach.class);
coachGrid.setItems(team.getCoaches());
return coachGrid;
));



A third option would be to have the team grid on one side of the view, and on the other you show some relevant stuff of the selected item of the team grid. You can have a separate Grid for the coaches, one for the players, one for the substitutes. You could implement this team detail layout also as a separate view if you wish. If your Team object will get more complicated with more sets, collections and other relative properties, the more will this option become appealing, as this is quite scalable/expandable.



grid.addSelectionListener(event -> 
if(event.getFirstSelectedItem().isPresent())
buildTeamDetails(event.getFirstSelectedItem().get())

)

private void buildTeamDetails(Team team)
// build your team detail layouts here






share|improve this answer



























  • How to set Players Name only those players which belong that team? There has a getAllPlayerBYTeamName(String s);

    – Nirob Rasseen
    Mar 29 at 13:25












  • uhm, this is a very different question, but the team object should already have only the players that are on that team?

    – Kaspar Scherrer
    Mar 29 at 13:38












  • Yes exactly. I show those players in that column

    – Nirob Rasseen
    Mar 29 at 14:29















2
















I see three options.



The first option is the one you already found yourself: concatenate their names in a single String. This can be done like this:



grid.addColumn(team -> 
Set<String> coachNames = new HashSet<>();
for (Coach coach : team.getCoaches())
coachNames.add(coach.getName());

return String.join(", ", coachNames);
);



The second one would be to make use of the Grid item Detail - you could show a coaches grid in the item details. Since you want to display both coaches and players, this option is probably not the best but I wanted to mention the possibility. (Placing two grids inside the item details is possible, but quite strange. Not optimal user experience.)



grid.setItemDetailsRenderer(new ComponentRenderer<>(team -> 
Grid<Coach> coachGrid = new Grid<>(Coach.class);
coachGrid.setItems(team.getCoaches());
return coachGrid;
));



A third option would be to have the team grid on one side of the view, and on the other you show some relevant stuff of the selected item of the team grid. You can have a separate Grid for the coaches, one for the players, one for the substitutes. You could implement this team detail layout also as a separate view if you wish. If your Team object will get more complicated with more sets, collections and other relative properties, the more will this option become appealing, as this is quite scalable/expandable.



grid.addSelectionListener(event -> 
if(event.getFirstSelectedItem().isPresent())
buildTeamDetails(event.getFirstSelectedItem().get())

)

private void buildTeamDetails(Team team)
// build your team detail layouts here






share|improve this answer



























  • How to set Players Name only those players which belong that team? There has a getAllPlayerBYTeamName(String s);

    – Nirob Rasseen
    Mar 29 at 13:25












  • uhm, this is a very different question, but the team object should already have only the players that are on that team?

    – Kaspar Scherrer
    Mar 29 at 13:38












  • Yes exactly. I show those players in that column

    – Nirob Rasseen
    Mar 29 at 14:29













2














2










2









I see three options.



The first option is the one you already found yourself: concatenate their names in a single String. This can be done like this:



grid.addColumn(team -> 
Set<String> coachNames = new HashSet<>();
for (Coach coach : team.getCoaches())
coachNames.add(coach.getName());

return String.join(", ", coachNames);
);



The second one would be to make use of the Grid item Detail - you could show a coaches grid in the item details. Since you want to display both coaches and players, this option is probably not the best but I wanted to mention the possibility. (Placing two grids inside the item details is possible, but quite strange. Not optimal user experience.)



grid.setItemDetailsRenderer(new ComponentRenderer<>(team -> 
Grid<Coach> coachGrid = new Grid<>(Coach.class);
coachGrid.setItems(team.getCoaches());
return coachGrid;
));



A third option would be to have the team grid on one side of the view, and on the other you show some relevant stuff of the selected item of the team grid. You can have a separate Grid for the coaches, one for the players, one for the substitutes. You could implement this team detail layout also as a separate view if you wish. If your Team object will get more complicated with more sets, collections and other relative properties, the more will this option become appealing, as this is quite scalable/expandable.



grid.addSelectionListener(event -> 
if(event.getFirstSelectedItem().isPresent())
buildTeamDetails(event.getFirstSelectedItem().get())

)

private void buildTeamDetails(Team team)
// build your team detail layouts here






share|improve this answer















I see three options.



The first option is the one you already found yourself: concatenate their names in a single String. This can be done like this:



grid.addColumn(team -> 
Set<String> coachNames = new HashSet<>();
for (Coach coach : team.getCoaches())
coachNames.add(coach.getName());

return String.join(", ", coachNames);
);



The second one would be to make use of the Grid item Detail - you could show a coaches grid in the item details. Since you want to display both coaches and players, this option is probably not the best but I wanted to mention the possibility. (Placing two grids inside the item details is possible, but quite strange. Not optimal user experience.)



grid.setItemDetailsRenderer(new ComponentRenderer<>(team -> 
Grid<Coach> coachGrid = new Grid<>(Coach.class);
coachGrid.setItems(team.getCoaches());
return coachGrid;
));



A third option would be to have the team grid on one side of the view, and on the other you show some relevant stuff of the selected item of the team grid. You can have a separate Grid for the coaches, one for the players, one for the substitutes. You could implement this team detail layout also as a separate view if you wish. If your Team object will get more complicated with more sets, collections and other relative properties, the more will this option become appealing, as this is quite scalable/expandable.



grid.addSelectionListener(event -> 
if(event.getFirstSelectedItem().isPresent())
buildTeamDetails(event.getFirstSelectedItem().get())

)

private void buildTeamDetails(Team team)
// build your team detail layouts here







share|improve this answer














share|improve this answer



share|improve this answer








edited Mar 29 at 12:58

























answered Mar 28 at 8:38









Kaspar ScherrerKaspar Scherrer

2,4721 gold badge8 silver badges27 bronze badges




2,4721 gold badge8 silver badges27 bronze badges















  • How to set Players Name only those players which belong that team? There has a getAllPlayerBYTeamName(String s);

    – Nirob Rasseen
    Mar 29 at 13:25












  • uhm, this is a very different question, but the team object should already have only the players that are on that team?

    – Kaspar Scherrer
    Mar 29 at 13:38












  • Yes exactly. I show those players in that column

    – Nirob Rasseen
    Mar 29 at 14:29

















  • How to set Players Name only those players which belong that team? There has a getAllPlayerBYTeamName(String s);

    – Nirob Rasseen
    Mar 29 at 13:25












  • uhm, this is a very different question, but the team object should already have only the players that are on that team?

    – Kaspar Scherrer
    Mar 29 at 13:38












  • Yes exactly. I show those players in that column

    – Nirob Rasseen
    Mar 29 at 14:29
















How to set Players Name only those players which belong that team? There has a getAllPlayerBYTeamName(String s);

– Nirob Rasseen
Mar 29 at 13:25






How to set Players Name only those players which belong that team? There has a getAllPlayerBYTeamName(String s);

– Nirob Rasseen
Mar 29 at 13:25














uhm, this is a very different question, but the team object should already have only the players that are on that team?

– Kaspar Scherrer
Mar 29 at 13:38






uhm, this is a very different question, but the team object should already have only the players that are on that team?

– Kaspar Scherrer
Mar 29 at 13:38














Yes exactly. I show those players in that column

– Nirob Rasseen
Mar 29 at 14:29





Yes exactly. I show those players in that column

– Nirob Rasseen
Mar 29 at 14:29













1
















You can configure which columns are shown in the grid by using grid.removeAllColumns() and then adding all columns you want to have in the grid with grid.addColumn(). Within addColumn() you can create a renderer that defines how the fields (coachName and playerSet) are displayed in the grid.



Let's have a class Team like



public class Team 
private String coachName;
private Set<Player> playerSet;
private Set<Object> objects;
//getters and setters



and a class Player like



public class Player 
private String firstName;
private String lastName;
// getters and setters



Now you want to only have coach and player names in the grid. So (in my example) for coachName we can just use the field's getter and we can create a comma separated String for the playerSet with java streams easily.



Configure the grid like:



 grid.setItems(team);
grid.removeAllColumns();
grid.addColumn(new TextRenderer<>((ItemLabelGenerator<Team>) Team::getCoachName))
.setHeader("Coach");
grid.addColumn(new TextRenderer<>((ItemLabelGenerator<Team>) team1 -> team1.getPlayerSet().stream()
.map(player1 -> player1.getFirstName() + " " + player1.getLastName())
.collect(Collectors.joining(", "))))
.setHeader("Players")
.setFlexGrow(1);


Then the result looks like:



enter image description here






share|improve this answer

























  • How to set Players Name only those players which belong that team? There has a getAllPlayerBYTeamName(String s);

    – Nirob Rasseen
    Mar 29 at 13:26















1
















You can configure which columns are shown in the grid by using grid.removeAllColumns() and then adding all columns you want to have in the grid with grid.addColumn(). Within addColumn() you can create a renderer that defines how the fields (coachName and playerSet) are displayed in the grid.



Let's have a class Team like



public class Team 
private String coachName;
private Set<Player> playerSet;
private Set<Object> objects;
//getters and setters



and a class Player like



public class Player 
private String firstName;
private String lastName;
// getters and setters



Now you want to only have coach and player names in the grid. So (in my example) for coachName we can just use the field's getter and we can create a comma separated String for the playerSet with java streams easily.



Configure the grid like:



 grid.setItems(team);
grid.removeAllColumns();
grid.addColumn(new TextRenderer<>((ItemLabelGenerator<Team>) Team::getCoachName))
.setHeader("Coach");
grid.addColumn(new TextRenderer<>((ItemLabelGenerator<Team>) team1 -> team1.getPlayerSet().stream()
.map(player1 -> player1.getFirstName() + " " + player1.getLastName())
.collect(Collectors.joining(", "))))
.setHeader("Players")
.setFlexGrow(1);


Then the result looks like:



enter image description here






share|improve this answer

























  • How to set Players Name only those players which belong that team? There has a getAllPlayerBYTeamName(String s);

    – Nirob Rasseen
    Mar 29 at 13:26













1














1










1









You can configure which columns are shown in the grid by using grid.removeAllColumns() and then adding all columns you want to have in the grid with grid.addColumn(). Within addColumn() you can create a renderer that defines how the fields (coachName and playerSet) are displayed in the grid.



Let's have a class Team like



public class Team 
private String coachName;
private Set<Player> playerSet;
private Set<Object> objects;
//getters and setters



and a class Player like



public class Player 
private String firstName;
private String lastName;
// getters and setters



Now you want to only have coach and player names in the grid. So (in my example) for coachName we can just use the field's getter and we can create a comma separated String for the playerSet with java streams easily.



Configure the grid like:



 grid.setItems(team);
grid.removeAllColumns();
grid.addColumn(new TextRenderer<>((ItemLabelGenerator<Team>) Team::getCoachName))
.setHeader("Coach");
grid.addColumn(new TextRenderer<>((ItemLabelGenerator<Team>) team1 -> team1.getPlayerSet().stream()
.map(player1 -> player1.getFirstName() + " " + player1.getLastName())
.collect(Collectors.joining(", "))))
.setHeader("Players")
.setFlexGrow(1);


Then the result looks like:



enter image description here






share|improve this answer













You can configure which columns are shown in the grid by using grid.removeAllColumns() and then adding all columns you want to have in the grid with grid.addColumn(). Within addColumn() you can create a renderer that defines how the fields (coachName and playerSet) are displayed in the grid.



Let's have a class Team like



public class Team 
private String coachName;
private Set<Player> playerSet;
private Set<Object> objects;
//getters and setters



and a class Player like



public class Player 
private String firstName;
private String lastName;
// getters and setters



Now you want to only have coach and player names in the grid. So (in my example) for coachName we can just use the field's getter and we can create a comma separated String for the playerSet with java streams easily.



Configure the grid like:



 grid.setItems(team);
grid.removeAllColumns();
grid.addColumn(new TextRenderer<>((ItemLabelGenerator<Team>) Team::getCoachName))
.setHeader("Coach");
grid.addColumn(new TextRenderer<>((ItemLabelGenerator<Team>) team1 -> team1.getPlayerSet().stream()
.map(player1 -> player1.getFirstName() + " " + player1.getLastName())
.collect(Collectors.joining(", "))))
.setHeader("Players")
.setFlexGrow(1);


Then the result looks like:



enter image description here







share|improve this answer












share|improve this answer



share|improve this answer










answered Mar 28 at 7:49









codinghauscodinghaus

1,3511 gold badge6 silver badges17 bronze badges




1,3511 gold badge6 silver badges17 bronze badges















  • How to set Players Name only those players which belong that team? There has a getAllPlayerBYTeamName(String s);

    – Nirob Rasseen
    Mar 29 at 13:26

















  • How to set Players Name only those players which belong that team? There has a getAllPlayerBYTeamName(String s);

    – Nirob Rasseen
    Mar 29 at 13:26
















How to set Players Name only those players which belong that team? There has a getAllPlayerBYTeamName(String s);

– Nirob Rasseen
Mar 29 at 13:26





How to set Players Name only those players which belong that team? There has a getAllPlayerBYTeamName(String s);

– Nirob Rasseen
Mar 29 at 13:26


















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