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How to get the AlarmManager system service in Xamarin.Android


Create Generic method constraining T to an EnumHow do I enumerate an enum in C#?Can anonymous class implement interface?How do I get a consistent byte representation of strings in C# without manually specifying an encoding?Why is the Android emulator so slow? How can we speed up the Android emulator?How do I remedy the “The breakpoint will not currently be hit. No symbols have been loaded for this document.” warning?What is the simplest and most robust way to get the user's current location on Android?Try-catch speeding up my code?Dilemma: when to use Fragments vs Activities:Why not inherit from List<T>?






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I'm trying to set up an extremely simple Android application that will fire a toast message on a schedule (even if the application is no longer running). After doing some research it looks like the AlarmManager class can handle this functionality. The issue I'm having is that I simply can't get an instance of the AlarmManager class. I've looked at probably 30 different examples and they all get an instance of AlarmManager the same way. However, when I try to do the same I get the error "AlarmManager is a namespace but is used like a type".



I've tried creating an instance of the class about a dozen different ways and nothing seems to work. All the resources I've found show don't show any alternatives to what I've tried.



AlarmManager alarmManager = (AlarmManager) Context.GetSystemService (Context.AlarmService);


I expect to get an instance of AlarmManager but instead I get the error that it is a namespace being used like a type.










share|improve this question






























    0















    I'm trying to set up an extremely simple Android application that will fire a toast message on a schedule (even if the application is no longer running). After doing some research it looks like the AlarmManager class can handle this functionality. The issue I'm having is that I simply can't get an instance of the AlarmManager class. I've looked at probably 30 different examples and they all get an instance of AlarmManager the same way. However, when I try to do the same I get the error "AlarmManager is a namespace but is used like a type".



    I've tried creating an instance of the class about a dozen different ways and nothing seems to work. All the resources I've found show don't show any alternatives to what I've tried.



    AlarmManager alarmManager = (AlarmManager) Context.GetSystemService (Context.AlarmService);


    I expect to get an instance of AlarmManager but instead I get the error that it is a namespace being used like a type.










    share|improve this question


























      0












      0








      0








      I'm trying to set up an extremely simple Android application that will fire a toast message on a schedule (even if the application is no longer running). After doing some research it looks like the AlarmManager class can handle this functionality. The issue I'm having is that I simply can't get an instance of the AlarmManager class. I've looked at probably 30 different examples and they all get an instance of AlarmManager the same way. However, when I try to do the same I get the error "AlarmManager is a namespace but is used like a type".



      I've tried creating an instance of the class about a dozen different ways and nothing seems to work. All the resources I've found show don't show any alternatives to what I've tried.



      AlarmManager alarmManager = (AlarmManager) Context.GetSystemService (Context.AlarmService);


      I expect to get an instance of AlarmManager but instead I get the error that it is a namespace being used like a type.










      share|improve this question














      I'm trying to set up an extremely simple Android application that will fire a toast message on a schedule (even if the application is no longer running). After doing some research it looks like the AlarmManager class can handle this functionality. The issue I'm having is that I simply can't get an instance of the AlarmManager class. I've looked at probably 30 different examples and they all get an instance of AlarmManager the same way. However, when I try to do the same I get the error "AlarmManager is a namespace but is used like a type".



      I've tried creating an instance of the class about a dozen different ways and nothing seems to work. All the resources I've found show don't show any alternatives to what I've tried.



      AlarmManager alarmManager = (AlarmManager) Context.GetSystemService (Context.AlarmService);


      I expect to get an instance of AlarmManager but instead I get the error that it is a namespace being used like a type.







      c# android xamarin alarmmanager






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Mar 28 at 1:44









      Nickel45Nickel45

      32 bronze badges




      32 bronze badges

























          1 Answer
          1






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          0















          Not sure what your "context" is, but I am assuming you are trying to access it via a static property since you are also using Context.AlarmService in the same line of code and GetSystemService is available via an context instance.



          You can use an Application or Activity context to access GetSystemService:



          Example:



          var alarmManager = (AlarmManager) Android.App.Application.Context.GetSystemService (Context.AlarmService);





          share|improve this answer



























          • Thanks for your suggestion! I tried it and I'm still having the same issue. No matter what configuration I try to access AlarmManager, I get the same error right away. As soon as AlarmManager is typed, IntelliSense gives me the error that it's a namespace being used like a type.

            – Nickel45
            Mar 28 at 2:24











          • @Nickel45 Did you name something else AlarmManager (i.e. does your namespace contain it?... xxxxxx.AlarmManager?)

            – SushiHangover
            Mar 28 at 2:26












          • Okay so VERY embarrassing but my project itself was called AlarmManager and that's why I was getting the error. Biggest face palm ever. Thanks so much for the help!

            – Nickel45
            Mar 28 at 4:56










          Your Answer






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          active

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          0















          Not sure what your "context" is, but I am assuming you are trying to access it via a static property since you are also using Context.AlarmService in the same line of code and GetSystemService is available via an context instance.



          You can use an Application or Activity context to access GetSystemService:



          Example:



          var alarmManager = (AlarmManager) Android.App.Application.Context.GetSystemService (Context.AlarmService);





          share|improve this answer



























          • Thanks for your suggestion! I tried it and I'm still having the same issue. No matter what configuration I try to access AlarmManager, I get the same error right away. As soon as AlarmManager is typed, IntelliSense gives me the error that it's a namespace being used like a type.

            – Nickel45
            Mar 28 at 2:24











          • @Nickel45 Did you name something else AlarmManager (i.e. does your namespace contain it?... xxxxxx.AlarmManager?)

            – SushiHangover
            Mar 28 at 2:26












          • Okay so VERY embarrassing but my project itself was called AlarmManager and that's why I was getting the error. Biggest face palm ever. Thanks so much for the help!

            – Nickel45
            Mar 28 at 4:56















          0















          Not sure what your "context" is, but I am assuming you are trying to access it via a static property since you are also using Context.AlarmService in the same line of code and GetSystemService is available via an context instance.



          You can use an Application or Activity context to access GetSystemService:



          Example:



          var alarmManager = (AlarmManager) Android.App.Application.Context.GetSystemService (Context.AlarmService);





          share|improve this answer



























          • Thanks for your suggestion! I tried it and I'm still having the same issue. No matter what configuration I try to access AlarmManager, I get the same error right away. As soon as AlarmManager is typed, IntelliSense gives me the error that it's a namespace being used like a type.

            – Nickel45
            Mar 28 at 2:24











          • @Nickel45 Did you name something else AlarmManager (i.e. does your namespace contain it?... xxxxxx.AlarmManager?)

            – SushiHangover
            Mar 28 at 2:26












          • Okay so VERY embarrassing but my project itself was called AlarmManager and that's why I was getting the error. Biggest face palm ever. Thanks so much for the help!

            – Nickel45
            Mar 28 at 4:56













          0














          0










          0









          Not sure what your "context" is, but I am assuming you are trying to access it via a static property since you are also using Context.AlarmService in the same line of code and GetSystemService is available via an context instance.



          You can use an Application or Activity context to access GetSystemService:



          Example:



          var alarmManager = (AlarmManager) Android.App.Application.Context.GetSystemService (Context.AlarmService);





          share|improve this answer















          Not sure what your "context" is, but I am assuming you are trying to access it via a static property since you are also using Context.AlarmService in the same line of code and GetSystemService is available via an context instance.



          You can use an Application or Activity context to access GetSystemService:



          Example:



          var alarmManager = (AlarmManager) Android.App.Application.Context.GetSystemService (Context.AlarmService);






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Mar 28 at 2:19

























          answered Mar 28 at 1:56









          SushiHangoverSushiHangover

          58k8 gold badges51 silver badges104 bronze badges




          58k8 gold badges51 silver badges104 bronze badges















          • Thanks for your suggestion! I tried it and I'm still having the same issue. No matter what configuration I try to access AlarmManager, I get the same error right away. As soon as AlarmManager is typed, IntelliSense gives me the error that it's a namespace being used like a type.

            – Nickel45
            Mar 28 at 2:24











          • @Nickel45 Did you name something else AlarmManager (i.e. does your namespace contain it?... xxxxxx.AlarmManager?)

            – SushiHangover
            Mar 28 at 2:26












          • Okay so VERY embarrassing but my project itself was called AlarmManager and that's why I was getting the error. Biggest face palm ever. Thanks so much for the help!

            – Nickel45
            Mar 28 at 4:56

















          • Thanks for your suggestion! I tried it and I'm still having the same issue. No matter what configuration I try to access AlarmManager, I get the same error right away. As soon as AlarmManager is typed, IntelliSense gives me the error that it's a namespace being used like a type.

            – Nickel45
            Mar 28 at 2:24











          • @Nickel45 Did you name something else AlarmManager (i.e. does your namespace contain it?... xxxxxx.AlarmManager?)

            – SushiHangover
            Mar 28 at 2:26












          • Okay so VERY embarrassing but my project itself was called AlarmManager and that's why I was getting the error. Biggest face palm ever. Thanks so much for the help!

            – Nickel45
            Mar 28 at 4:56
















          Thanks for your suggestion! I tried it and I'm still having the same issue. No matter what configuration I try to access AlarmManager, I get the same error right away. As soon as AlarmManager is typed, IntelliSense gives me the error that it's a namespace being used like a type.

          – Nickel45
          Mar 28 at 2:24





          Thanks for your suggestion! I tried it and I'm still having the same issue. No matter what configuration I try to access AlarmManager, I get the same error right away. As soon as AlarmManager is typed, IntelliSense gives me the error that it's a namespace being used like a type.

          – Nickel45
          Mar 28 at 2:24













          @Nickel45 Did you name something else AlarmManager (i.e. does your namespace contain it?... xxxxxx.AlarmManager?)

          – SushiHangover
          Mar 28 at 2:26






          @Nickel45 Did you name something else AlarmManager (i.e. does your namespace contain it?... xxxxxx.AlarmManager?)

          – SushiHangover
          Mar 28 at 2:26














          Okay so VERY embarrassing but my project itself was called AlarmManager and that's why I was getting the error. Biggest face palm ever. Thanks so much for the help!

          – Nickel45
          Mar 28 at 4:56





          Okay so VERY embarrassing but my project itself was called AlarmManager and that's why I was getting the error. Biggest face palm ever. Thanks so much for the help!

          – Nickel45
          Mar 28 at 4:56








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